Electron Paramagnetic Resonance (EPR)

21
Electron Paramagnetic Resonance (EPR) Dr. Nicolai Lehnert University of Michigan

Transcript of Electron Paramagnetic Resonance (EPR)

Page 1: Electron Paramagnetic Resonance (EPR)

Electron Paramagnetic Resonance (EPR)

Dr. Nicolai LehnertUniversity of Michigan

Page 2: Electron Paramagnetic Resonance (EPR)

Theory

Angular Momentum and Magnetic MomentElectrons that perform a circular movement with an angular momentum l have a magnetic dipol moment µl:

is called the gyromagnetic constant. The magnetic moment is usually refered to in units of Bohr‘s magneton µB:

l = I where = e/2me

l = Bl B = 9.27402 * 10-24 J/Tħ

Page 3: Electron Paramagnetic Resonance (EPR)

Schroedinger Equation

Quantization of Spin and Angular Momentum

l

( 1)

m 0, 1, 2,...,z l

l l l

l m l

z

z s

( 1)

s ms

s s s

m s

s = geBsħ

ge = 2.00232Landé factor

Page 4: Electron Paramagnetic Resonance (EPR)

Theory Interaction of the Electron with an External Magnetic Field

µl aligns with respect to the axis of the external magnetic field (z) Precission of µl along z Quantization of

( angle between µl along z)

coslE B

Page 5: Electron Paramagnetic Resonance (EPR)

Russel-Saunders (LS) Coupling

Fine Structure of AtomsFor atoms in the gas phase of light elements, the total angular (L) and spin (S) momenta couple to give a total momentum (J) and a corresponding magnetic moment J:

This generates the so-called fine structure in the electronic spectra of atoms.

2J Je

eg Jm

,...,J L S L S where

Page 6: Electron Paramagnetic Resonance (EPR)

Zeeman Effect

Magnitude of energetic splitting depends linearly on the magnetic field strength→ Electron Paramagnetic Resonance: transitions between the magnetically split MJ levels→ frequencies in the microwave region→ selection rule: ΔJ=0, MJ =± 1)→ E = h =gJµBB

Interaction of the magnetic moment µJ with the external field lifts the energetic degeneracy of the (2J + 1) electronic MJ states

Page 7: Electron Paramagnetic Resonance (EPR)

Example

16O-Atom: l = 1, s = 1 (J = 2, 1)MJ

3P1

1

0

-1

3P2

2

1

0

-1

-2

Page 8: Electron Paramagnetic Resonance (EPR)

Hyperfine Splitting Interaction of the magnetic moment of the electron

with that of the nucleus (angular momentum: I). Requirement: I≠0. The hyperfine splitting constant a is easily obtained from the spectra:

S = 1/2I = 3/2

J BBga

h

Page 9: Electron Paramagnetic Resonance (EPR)

g shifts For atoms in the gase phase, the g value is simply defined as:

Experimentally, this value is accessible from the spectra:

g factors are characteristic for the angular momentum J of the atom and hence, allow for the easy determination of this value experimentally (compare to d in NMR)

[ ( 1) ( 1) ( 1)]1

2 ( 1)J J S S L Lg

J J

1.

hBg

Page 10: Electron Paramagnetic Resonance (EPR)

Example

Spectrum von NO.

20 G

7232.80 G

Page 11: Electron Paramagnetic Resonance (EPR)

Example: NO

10

-1

10

-1

1/2

3/2

2

MJ

MI

-1/2

-3/2-101

-101

3/2 a

1/2 a

16O, I=014N, I=1

L=0S=3/2J=3/2

a=32,63 MHzgJ=0,7759

MJ = ± 1MI = 0

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Example: Organic Radical

EPR spectrum of(MeO)3PBH2: 21 lines!!

31P, I=1/21H, I=1/2

11B, I=3/2

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Spin-Only Approximation

In molecules with more than 2 atoms, especially in coordination compounds, the ground state is usually non-degenerate (Jahn-Teller Effect)→ L = 0!! (but excited states can be degenerate)

Examples for Jahn-Teller active electron configurations:

Page 14: Electron Paramagnetic Resonance (EPR)

g Anisotropy in Coordination Compounds

The anisotropy of g values in coordination compounds is due to spin-orbit coupling→ gx gy gz

From perturbation theory, the g values are calculated:

Example: spin-orbit coupling similar in x and y direction, but different in z: → gx gy (g) gz (g//)

0 0

002ggn n

inniei EE

LLLi: angular momentum

operatori = x, y, z: spin-orbit coupling

constant

Page 15: Electron Paramagnetic Resonance (EPR)

The Instrument Design of an EPR Spectrometer

EPR transitions:E = h = gµBB

Page 16: Electron Paramagnetic Resonance (EPR)

Example: tetragonal [CuCl4]2-

xy

xz, yz

z 2

x 2 y 2 Ground State: 2B1g

0 0

002ggn n

inniei EE

LL

gz = ? Lz

Only one contribution!

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Example: tetragonal [CuCl4]2-

xy

xz, yz

z 2

x 2 y 2 Ground State: 2B1g

0 0

002ggn n

inniei EE

LL

gz = g// = 2.023 - 8 / E(x2-y2) – E(xy)

gx, = g = 2.023 - 2 / E(x2-y2) – E(yz)

gy, = g = 2.023 - 2 / E(x2-y2) – E(xz)

Two transitions!

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Example: tetragonal [CuCl4]2-

2.222.04 Cu: I = 3/2

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Example: low-spin ferric heme

xy

xz, yz

Rhombicg-values: 2.8, 2.3, 1.6

Parallel IM orientation

xy

xz, yz

Axialg-values: 2.2, 1.94

?

xy

xz, yz

Large gmaxg-values: 3.4 (1.8, 0.9)

Perpendicular IM orientation

Relevant for Cytochrome C

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A1g5A1g6

|±5/2>

|±3/2>

|±½> |±5/2>

|±3/2>

|±½>

S > ½: Zero-field splitting

Example: high-spin Fe(III)

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S > ½: Zero-field splitting

Solomon et al., Chemistry & Biology, 1997, 4, 795-808