ELECTRICITY & MAGNETISM (Fall 2011) LECTURE # 13 BY MOEEN GHIYAS.
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Transcript of ELECTRICITY & MAGNETISM (Fall 2011) LECTURE # 13 BY MOEEN GHIYAS.
![Page 1: ELECTRICITY & MAGNETISM (Fall 2011) LECTURE # 13 BY MOEEN GHIYAS.](https://reader030.fdocuments.net/reader030/viewer/2022032600/56649dbd5503460f94aaf435/html5/thumbnails/1.jpg)
ELECTRICITY & MAGNETISM (Fall 2011)
LECTURE # 13
BY
MOEEN GHIYAS
![Page 2: ELECTRICITY & MAGNETISM (Fall 2011) LECTURE # 13 BY MOEEN GHIYAS.](https://reader030.fdocuments.net/reader030/viewer/2022032600/56649dbd5503460f94aaf435/html5/thumbnails/2.jpg)
TODAY’S LESSON
(Parallel Circuits – Chapter 6)
Introductory Circuit Analysis by Boylested (10th Edition)
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Today’s Lesson Contents
• Parallel Elements
• Total Conductance and Total Resistance
• Parallel Circuits
• Kirchhoff’s Current Law (KCL)
• Solution to Problems
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Parallel Elements
• Two elements, branches, or networks are in
parallel if they have two points in common.
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Parallel Elements
• Different ways in which three parallel elements may
appear.
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Parallel Elements
• In fig,
• Elements 1 and 2 are in parallel because they have
terminals a and b in common. The parallel
combination of 1 and 2 is then in series with element
3 due to the common terminal point b.
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Parallel Elements
• In fig, elements 1 and 2 are in series because they
have only terminal b in common. The series
combination of 1 and 2 is then in parallel with element
3 due to the common terminals point b and c.
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Total Conductance and Total Resistance
• For parallel elements,
the total conductance
is the sum of the
individual
conductances
• Note that the equation
is for 1 divided by the
total resistance rather
than total resistance.
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Total Conductance and Total Resistance
• Example – Determine the total conductance and
resistance for the parallel network of Fig
• Solution:
![Page 10: ELECTRICITY & MAGNETISM (Fall 2011) LECTURE # 13 BY MOEEN GHIYAS.](https://reader030.fdocuments.net/reader030/viewer/2022032600/56649dbd5503460f94aaf435/html5/thumbnails/10.jpg)
Total Conductance and Total Resistance
• Example – Determine the effect on total conductance
and resistance of the network of fig if another resistor of
10Ω were added in parallel with the other elements
• Solution:
Note that adding additional terms Note that adding additional terms
increases the conductance level increases the conductance level
and decreases the resistance level.and decreases the resistance level.
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Total Conductance and Total Resistance
• Recall for series circuits that the total resistance will
always increase as additional elements are added in
series.
• For parallel resistors, the total resistance will always
decrease as additional elements are added in parallel.
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Total Conductance and Total Resistance
• Example – Determine the total resistance for the
network of Fig
• Solution:
![Page 13: ELECTRICITY & MAGNETISM (Fall 2011) LECTURE # 13 BY MOEEN GHIYAS.](https://reader030.fdocuments.net/reader030/viewer/2022032600/56649dbd5503460f94aaf435/html5/thumbnails/13.jpg)
Total Conductance and Total Resistance
• The total resistance of parallel resistors is always less
than the value of the smallest resistor.
• The wider the spread in numerical value between two
parallel resistors, the closer the total resistance will be
to the smaller resistor.
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Total Conductance and Total Resistance
• For equal resistors in parallel, the equation becomes,
• For same conductance levels, we have
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Total Conductance and Total Resistance
• For two parallel resistors,
• For three parallel resistors,
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Total Conductance and Total Resistance
• Example – Find the total resistance of the network of
Fig
• Solution:
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Total Conductance and Total Resistance
• Example – Calculate the total resistance for the network
of Fig
• Solution:
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Total Conductance and Total Resistance
• Parallel elements can be interchanged without changing
the total resistance or input current.
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Total Conductance and Total Resistance
• Example – Determine the values of R1, R2, and R3 in fig
if R2 = 2R1 and R3 = 2R2 and total resistance is 16 kΩ.
• Solution:
• . =
• Since
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Parallel Circuits
• The voltage across parallel elements is the same.
• or
• But and
• Take the equation for the total resistance and multiply
both sides by the applied voltage, For single-source For single-source
parallel networks, the parallel networks, the
source current (Isource current (Iss) is ) is
equal to the sum of the equal to the sum of the
individual branch individual branch
currents.currents.
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Parallel Circuits
• The power dissipated by the resistors and delivered
by the source can be determined from
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Parallel Circuits
• Example – Given the information provided in fig:
a) Determine R3.
b) Calculate E.
c) Find Is.
d) Find I2.
e) Determine P2.
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Parallel Circuits
a) Determine R3.
Solution:
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Parallel Circuits
b) Calculate E.
c) Find Is.
Solution:
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Parallel Circuits
d) Find I2.
e) Determine P2.
Solution:
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Kirchhoff’s Current Law (KCL)
• Kirchhoff’s current law (KCL) states that
the algebraic sum of the currents
entering and leaving an area, system, or
junction is zero.
• In other words, the sum of the currents
entering an area, system, or junction
must equal the sum of the currents
leaving the area, system, or junction.
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Kirchhoff’s Current Law (KCL)
• In technology the term node is commonly used to
refer to a junction of two or more branches. Therefore,
this term will be used frequently in future.
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Kirchhoff’s Current Law (KCL)
• At node a:
• At node b:
• At node c:
• At node d:
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Kirchhoff’s Current Law (KCL)
• Example – Determine unknown current I1.
• Solution:
• I1 is 5mA and leaving system.
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Kirchhoff’s Current Law (KCL)
• Example – Determine the currents I3 and I5 of fig using
Kirchhoff’s current law (KCL).
• Solution:
• . At node a: I1 + I2 = I3
• . At node b: I3 = I4 + I5
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Summary / Conclusion
• Parallel Elements
• Total Conductance and Total Resistance
• Parallel Circuits
• Kirchhoff’s Current Law (KCL)
• Solution to Problems
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