ELECTRICAL INSTALLATION PLANNING
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Transcript of ELECTRICAL INSTALLATION PLANNING
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LSEGG307A9080F
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• Describe the acceptable methods for determining the maximum demand on an installation’s consumer’s mains.
• Calculate the maximum demand for the consumer's mains for given installations up to 400 A per phase.
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What is What is Maximum Demand?Maximum Demand?
Is the “Maximum continuous current that flows in a circuit for a period of 15 minutes or longer”
AS/NZS 30001.6.3
Why not just put a cable size in, that will handle the current rating for the maximum current rating
of the appliance?
MD
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WWhat is Maximum Demand?hat is Maximum Demand?Domestic stove rated at 5kW
Max current = 22A
Min cable size = 6mm2
By calculation
Max current = 16A
AS/NZS 3000Table C4
Min cable size = 2.5mm2
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Calculation Assessment Measurement Limitation
AS/NZS 30002.2.2.
“If the measured current is larger than any of the listed methods, then the MD is considered the
measured value”
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“… may be the ….sum of the current settings of the circuit breakers protecting the
associated final sub-circuits….”
AS/NZS 3000Clause 2.2.2 (d)
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10AL2
16AP1
16AP2
32AStove
10AL1
MD = ?
10+10+16+16+32 =84 Amps
By Calculation
36 Amps
Domestic House
10mm2 2.5mm2
Most su
pply authorit
ies specif
y a minim
um
mains cable si
ze of 1
6 mm
2
20 metres 46 metres
16mm2
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Domestic Non-domestic Non- domestic Energy Demand
Table C1Table C2
Table C3
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Single House Table C1Column 2LightingLighting
Load groups Ai & Aii
Batten holder =
1 light point
25 lighting points = 1 -20 =
3 A
21 -25 =
2 A
5 A
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Single House Table C1Column 2LightingLighting
Load groups Ai & AiiChandelier or Multi-globe
fitting =Number of points =
= 3 points
Number of globes
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Single House Table C1Column 2LightingLighting
Load groups Ai & AiiPower points above 2.3 m for
lighting =1 point
Note “e”
Exhaust fans below 150W =
1 point
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Single House Table C1Column 2LightingLighting
Load groups Ai & AiiTrack lights
=Every metre =
Note “d”2 points
2 x 2.6 metres track light =
5 points per track =
10 points
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Single House Table C1Column 2LightingLighting
Load groups Ai & AiiIXL Tastics, Heat lamps
etc
Not regarded as “Lighting”Fixed Space HeatingLoad Group “D”
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Single House Table C1Column 2LightingLighting
Load groups Ai & Aii
Outside LightingFloodlighting,
Swimming Pool, Tennis courts, etc
Not lighting around house walls
Load Group “Aii”
If total bigger than 1000W
If less than 1000W
Load Group “Ai”
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A house consists of the following:
36 light fittings, 3 consisting of 3 lamp combinations3 bathroom exhaust fans
2 x 750W heat lamp, fan, light combinations3 x 2metre track lights
12 wall lights around the veranda6 x 100W bollard lights on driveway
6 x 400W metal halide flood lights for pool
Ai
Ai
DAi
Ai
Aii
Aii
Assume to be <150W
6 x 100 = 600
6 x 400 = 2400
33 + (3 x 3) = 42P3P-3 x 2 x 2 = 12P12P
13.04A
3000 W
230V
Determine the lighting load in Amps
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A house consists of the following:
36 light fittings, 3 consisting of 3 lamp combinations3 bathroom exhaust fans
2 x 750W heat lamp, fan, light combinations3 x 2metre track lights
12 wall lights around the veranda6 x 100W bollard lights on driveway
6 x 400W metal halide flood lights for pool
Ai
Ai
DAi
Ai
Aii
Aii
33 + (3 x 3) = 42P3P-3 x 2 x 2 = 12P12P
13.04A
42P3P12P12P
69P
1 – 20 =21 – 40 =41 – 60 =61 – 69 =
3A2A2A2A
9A + 13.04A =22.04A
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36 light fittings
Should indicate how it is to be broken up across the three phases
Broken up evenly
312 Fittings / 3A
NOTNOT
A B C3A 3A
36 light fittings = 3A + 2A = 5A
31.6
A B C1.6 1.6
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A house consists of the following:
36 light fittings, 3 consisting of 3 lamp combinations3 bathroom exhaust fans
2 x 750W heat lamp, fan, light combinations3 x 2metre track lights
12 wall lights around the veranda6 x 100W bollard lights on driveway
6 x 400W metal halide flood lights for pool
Ai
Ai
DAi
Ai
Aii
Aii
11 + (1 x 3) = 14P1P-1 x 2 x 2 = 4P4P
4.35A
14P1P4P4P
23P
1 – 20 =21 – 23 =
3A2A
5A + 4.35A = 9.35A /
Broken up evenly over 3 Phases
Divide by 3
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Power Power PointsPoints
Double Power Points Notes h
36 Double Power Points6 Single power points
36 x 2 =72P6P
78P1 – 20 =
21 – 40= 41 – 60 =61 – 78 =
10A5A5A5A
25A
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Power Power PointsPoints
Double Power Points Notes h
36 Double Power Points6 Single power points
36 x 2 =72P6P
78P
1 – 20 =21 – 40= 41 – 60 =61 – 78 =
10A5A5A5A
25AOther Direct Wired
Equipment that is <10A• Air conditioners• Cook tops• Water heaters
AND
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Power Power PointsPoints
15 A Power PointsNOTOther Equipment that is Covered in Load Groups
below
C Ranges, Laundry equipmentD Fixed Space Heating or cooling
equipmentE & F Water HeatersG Spa & Swimming Pool Heaters15 A Power Points suppling this equipment is covered
under each load group
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A house consists of the following:
20 Double power points8 Single power points
8A swimming pool pump4 x 15A power points
12A Air-conditioner supplied via a 15A power point14A Pool heater direct wired
Bi
Bi
Bi
Bii
DG
20 x 2 = 40P8P1P10A--
3
Determine the Power point load in Amps
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20 Double power points8 Single power points
8A swimming pool pump3 x 15A power points
12A Air-conditioner supplied via a 15A power point14A Pool heater direct wired
A house consists of the following:
Bi
Bi
Bi
Bii
DG
20 x 2 = 40P8P1P10A--
40P8P1P
49P
1 – 20 =21 – 40 =41 – 49 =
10A5A5A
20A + 10A = 30A
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• Cook tops• Wall ovens• Washing machines• Clothes driers
Must be over 10A
If supplied via a power point That power point is NOT included in Bi, Bii or Biii
An installation has:2.3 kW Cook top4 kW Wall oven 6.3 kW of Load Group C
(6300/230) 13.7Ax 0.5 =
50% of connected Load
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• IXL Tastics Heat lamps• Air conditioners• Heaters• Under floor heating
Must be over 10A
If supplied via a power point That power point is NOT included in Bi, Bii or Biii
75% of connected LoadIf reverse cycle Air-conditioner is used only the
highest system is to be taken into account
Unless it is multi zone, when both heating and cooling could operate simultaneously
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Water Water HeatersHeaters
If greater than 100W/L
Load Group E
33.3% of connected load
Load Group F
100% of connected load
• Instantaneous• Quick recovery
• Storage• Off peak
300 litre heaterwith a 2.4kW element
2400/300 = 8 W/L
15 litre heaterwith a 2.4kW element
2400/15 = 160 W/L
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41 x 50 W down lights2 x 60 W exhaust fans4 x Single 10 A socket outlets22 x Double 10 A socket outlets1 x 10kW range1 x Permanently connected air conditioner (full load current of 13 A)1 x 4.6 kW continuous HWS
A house consists of the following:Ai
Ai
Bi
Bi
CDF
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41 x 50 W down lights2 x 60 W exhaust fans4 x Single 10 A socket outlets22 x Double 10 A socket outlets1 x 10kW range1 x Permanently connected air conditioner (full load current of 13 A)1 x 4.6 kW continuous HWS
A house consists of the following:Ai
Ai
Bi
Bi
CDF
43P 3 + 2 + 2 = 7A
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41 x 50 W down lights2 x 60 W exhaust fans4 x Single 10 A socket outlets22 x Double 10 A socket outlets1 x 10kW range1 x Permanently connected air conditioner (full load current of 13 A)1 x 4.6 kW continuous HWS
A house consists of the following:Ai
Ai
Bi
Bi
CDF
7A
44P44 + 4 = 48P 10 + 5 + 5 = 20A
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41 x 50 W down lights2 x 60 W exhaust fans4 x Single 10 A socket outlets22 x Double 10 A socket outlets1 x 10kW range1 x Permanently connected air conditioner (full load current of 13 A)1 x 4.6 kW continuous HWS
A house consists of the following:Ai
Ai
Bi
Bi
CDF
7A
20A
(10000/230) x 0.5 = 21.7A
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41 x 50 W down lights2 x 60 W exhaust fans4 x Single 10 A socket outlets22 x Double 10 A socket outlets1 x 10kW range1 x Permanently connected air conditioner (full load current of 13 A)1 x 4.6 kW continuous HWS
A house consists of the following:Ai
Ai
Bi
Bi
CDF
7A
20A
13 x 0.75 =
21.7A9.75A
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41 x 50 W down lights2 x 60 W exhaust fans4 x Single 10 A socket outlets22 x Double 10 A socket outlets1 x 10kW range1 x Permanently connected air conditioner (full load current of 13 A)1 x 4.6 kW continuous HWS
A house consists of the following:Ai
Ai
Bi
Bi
CDF
7A
20A
4600/230 =
21.7A9.75A20A
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41 x 50 W down lights2 x 60 W exhaust fans4 x Single 10 A socket outlets22 x Double 10 A socket outlets1 x 10kW range1 x Permanently connected air conditioner (full load current of 13 A)1 x 4.6 kW continuous HWS
A house consists of the following:Ai
Ai
Bi
Bi
CDF
7A
20A
21.7A9.75A20A
78.45A
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Not all single phase loads will break up evenly over three phases
But the phases must not be unbalanced by more than 25A
NSW S&IRClause 1.10.3
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30 x Light points + 2 x Exhaust fans
18 x Lights
6 x 400W mercury vapour flood lights
15 x Double power points (p/p)
10 x Single p/p & 15 x Double p/p
3 x 15A Single p/p
1 x 4.1kW wall oven
1 x 4.6kW cook top
1 x 3.6kW heat pump HWS
1 x 5.7kW 3 Air conditioner
A house consists of the following:Ai
Ai
Aii
Bi
Bi
Bii
C
C
F
D
A
B
C
A
B
C
A
B
C
A
B
C
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30 x Light points + 2 x Exhaust fans
18 x Lights
6 x 400W mercury vapour flood lights
15 x Double power points (p/p)
10 x Single p/p & 15 x Double p/p
3 x 15A Single p/p
1 x 4.1kW wall oven
1 x 4.6kW cook top
1 x 3.6kW heat pump HWS
1 x 5.7kW 3 Air conditioner
A house consists of the following:Ai
Ai
Aii
Bi
Bi
Bii
C
C
F
D
32P 3+2A = 5A
15A
8.91A
28.9A
A
B
C
A
B
C
A
B
C
A
B
C
3A
20A
10A
7.83A
10A
15.65A
10A
18P
((6x400)230)x0.75 =
30P+1 10+5A =
10+30P+110+5+5A =
(4100230)x0.5 =
(4600230)x0.5 =
3600230 =
5700(√3 x400) =
33A 43.5A
1P of Bi = 10A
8.23A
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Submains to individual units
Columns 3, 4 or 5
MSB
Unit 1
Unit 2
Unit 3
Column 2
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How many units are there?
How are they spread across the 3 phases?
6 Units
3 = 2 Units / Phase Use Colum 3
18 Units
3 = 6 Units / Phase Use Colum 4
66 Units
3 = 22 Units / Phase Use Colum 5
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26 x Light points
2 metres of light track
2 x 750W flood lights
26 x Double 10 A socket outlets
5 x Single 10 A socket outlets
1 x 15A Single socket outlet
1 x 5.6kW wall oven / cook top
1 x 3.6kW air conditioner
1 x 2.4kW storage HWS (Heat pump)
A house consists of the following:
Ai
Ai
Aii
Bi
Bi
Bii
C
D
F
2 x 2 = 4P
1500W
26 + 4 = 30P 3A + 2A =
26 x 2 = 52P52 + 5 = 57P
10A + 5A + 5A =
(5600W/230V)x0.5
5A
4.9A
20A
10A
12.2A
11.7A
10.4A
(3600W/230V)x0.75
(2400W/230V)
74.2A
(1500W/230V)x0.75
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26 x Light points
2 metres of light track
2 x 750W flood lights
26 x Double 10 A socket outlets
5 x Single 10 A socket outlets
1 x 15A Single socket outlet
1 x 5.6kW wall oven / cook top
1 x 3.6kW air conditioner
1 x 2.4kW storage HWS (Heat pump)
9 Units consists of the following:
Ai
Ai
Aii
Bi
Bi
Bii
C
D
F
10A + (5A x 3) =
6A
25A
10A
15A
35.2A
18A
(3600W/230V) x 0.75 x 3
6A x 3 =
109A
9 Units
3 = 3 Units / Phase Use Colum 3
Not counted
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26 x Light points
2 metres of light track
2 x 750W flood lights
26 x Double 10 A socket outlets
5 x Single 10 A socket outlets
1 x 15A Single socket outlet
1 x 5.6kW wall oven / cook top
1 x 3.6kW air conditioner
1 x 2.4kW storage HWS (Heat pump)
30 Units consists of the following:
Ai
Ai
Aii
Bi
Bi
Bii
C
D
F
15A + (3.75A x 10) =
7.5A
52.5A
10A
28A
117A
60A
(3600W/230V) x 0.75 x 10
6A x 10 =
275A
30 Units
3 = 10 Units / Phase Use Colum 4
Not counted
5A + (0.25A x 10) =
2.8A x 10 =
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26 x Light points
2 metres of light track
2 x 750W flood lights
26 x Double 10 A socket outlets
5 x Single 10 A socket outlets
1 x 15A Single socket outlet
1 x 5.6kW wall oven / cook top
1 x 3.6kW air conditioner
1 x 2.4kW storage HWS (Heat pump)
66 Units consists of the following:
Ai
Ai
Aii
Bi
Bi
Bii
C
D
F
50A + (1.9A x 22) =
11A
91.8A
10A
61.6A
258A
118A
(3600W/230V) x 0.75 x 22100A + (0.8A x 22)
=
550A
66 Units
3 = 22 Units / Phase Use Colum 5
Not counted
0.5A x 22 =
2.8A x 22 =
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16 Units
3 = 5.33 Units / Phase
A5 Units
Col 3
But the phases must not be unbalanced by more than 25A
B C5 Units 6 Units
Col 3 Col 4
NSW S&IRClause 1.10.3
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26 x Light points
26 x Double 10 A socket outlets
5 x Single 10 A socket outlets
1 x 15A Single socket outlet
1 x 5.6kW wall oven / cook top
1 x 3.6kW air conditioner
1 x 2.4kW storage HWS (Heat pump)
16 Units consists of the following:
Ai
Bi
Bi
Bii
C
D
F
10A + (5A x 5) =
6A
35A
10A
15A
58.7A
30A
(3600W/230V) x 0.75 x 5
154.7A
5 Units / A & B Use Column 3
6A x 5 =
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26 x Light points
26 x Double 10 A socket outlets
5 x Single 10 A socket outlets
1 x 15A Single socket outlet
1 x 5.6kW wall oven / cook top
1 x 3.6kW air conditioner
1 x 2.4kW storage HWS (Heat pump)
16 Units consists of the following:
Ai
Bi
Bi
Bii
C
D
F
15A + (3.75A x 6) =
6.5A
37.5A
10A
16.8A
70.4A
36A
(3600230) x 0.75 x 6
177.2A
6 Units / C Use Column 4
6A x 6 =
5A + (0.25A x 6) =
2.8A x 6 =
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16 Units
3 = 5.33 Units / Phase
A5 Units
Col 3
B C5 Units 6 Units
Col 3 Col 4
154.7A 154.7A 177.2A
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Loads that are used by all the unit dwellers
• Driveway/ parking lighting
• Stairwell lighting
• Power points for cleaners
• Lifts
• Swimming pool pumps
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20 x 80 W bollard Lights
30 x light points
15 x Single 10 A socket outlets
1 x 3.6kW HWS for cleaners room
1 x 3.6kW Air conditioner for lobby
1 x 12A pool pump/filter
1 x 15A lift motor
16 Units have a communal load consists of the following:
H
H
I
Ji
Jii
D
E
2A x15= 30 but maximum of 15A
14.78A
15A
7.8A
15A
12A
18.75A
(3600230) x 0.5 =
83.33A
15 x 1.25 =
Table C2 Colum 2
((20x80)230) + ((30x 60)230) =
(3600230) x 0.75 =
These circuits could also be divided across three phases