Elect Magnet 6

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    4. 4. 4.1. , 4.1. , 4.2. 4.2. 4.3. 4.3. 4.4. 4.4. 4.5. 4.5. 4.6. 4.6. 4.7.4.7. D D

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    4.1. , 4.1. ,

    (( )):: 11 =1=1 /B /B. ,. , , , R R ,, QQ

    R=1 R=1 : : C=10C=10 --1212 ; R=6370; R=6370 :: C=0,7 C=0,7 1010 --33

    V V , , 2 2 , , : : Q=CV Q=CV C C::

    QQ V V Q/V Q/V

    QC

    V

    0Q Q R

    C 4 RV kQ / R k

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    2 2

    QQ 2 2 d d +Q+Q QQ s s =Q/A=Q/A , ,

    QC V

    ,

    0 0

    Q E

    As

    0

    Qd V Ed A

    0

    0

    AQ QC C

    V Qd / A d

    d = A

    +Q -Q

    +++

    ++

    +

    - --

    -

    -

    -

    -

    -

    -

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    23.2 23.2 ,, +Q+Q , , bb QQ . . l l . .

    :: l>a, l>bl>a, l>b , ,

    E E a

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    , , V=V V=V aa--V V bb : : 2 2 : : , , (( , , , ..., ... ))

    E E r r --

    l l =Q/l =Q/l

    b b

    b a r a a

    dr bV V E dr 2k 2k ln

    r al l

    Q Q l C

    2kQ b bV ln 2k lnl a a

    C 1bl

    2kln a

    +

    +++ ++

    +++Q

    -Q

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    23.3 23.3The spherical The spherical capacitor capacitor

    A sphericalA sphericalcapacitorcapacitorconsists of aconsists of asphericalsphericalconducting shellconducting shellof radiusof radius

    bbandand

    chargecharge QQ thatthatis concentricis concentricwith a smallerwith a smallerconductingconductingsphere of radiussphere of radiusaa and chargeand charge +Q+Q(Fig.).(Fig.).Find itsFind itscapacitance.capacitance.

    bb QQ

    ,, aa +Q+Q .. . .

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    :: , , kQ/r kQ/r 22

    :: bb a/k=4a/k=4 00aa ..

    bb b

    b a r 2a aa

    dr 1 1 1V V E dr kQ kQ kQ ;r r b a

    a b ( b a )V V kQ ab

    Q abC

    V k( b a )

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    4.2. 4.2. 2 2

    V V : : QQ11=C =C 11V, QV, Q 22=C =C 22V V Q=QQ=Q 11+Q+Q 22=(C =(C 11+C +C 22 )V )V

    33-- C C eqeq=C =C 11+C +C 22+C +C 33++

    1 2eq

    ( C C )V QC ;

    V V

    eq 1 2C C C

    C eq=C 1+C 2

    Q1 C 1

    Q2 C 2

    a b a ba bV

    C 1

    + _

    C 2

    + _

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    . .

    2 2

    C C eqeq=Q/V =Q/V V=Q/C V=Q/C eqeq

    33--

    eq 1 2 3

    1 1 1 1...

    C C C C

    eq 1 2

    1 1 1

    C C C

    1 2eq

    1 2

    C C C

    C C

    1 21 2

    Q QV ; V C C

    1 21 2

    1 1V V V Q

    C C

    ba

    C 1

    +Q -Q

    C 2

    +Q -Q

    C 1 C 2a b

    V 1 V 2

    V

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    1111

    23.4 23.4Find the equivalent capacitance betweenFind the equivalent capacitance between aa andand bb forforthe combination of capacitors shown in Fig. Allthe combination of capacitors shown in Fig. Allcapacitances are incapacitances are in m m F. F. bb -- . . -- ..:: , ,

    4 4

    8 8

    41

    3

    6

    2

    8a b a ab b

    2

    4

    a b

    6

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    1212

    4.3. 4.3.

    (V=0)(V=0) QQ,, V=Q/C V=Q/C V=0V=0 , , V/2=Q/2C V/2=Q/2C QV/2=QQV/2=Q 22 /2C /2C qq,, V=q/C V=q/C dqdq qq +q+q

    q=0q=0 q=Qq=Q

    qdW Vdq dq

    C

    2Q

    0

    q 1 QW dqC 2 C

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    1313

    ~C ~C ~V ~V

    V=Ed V=Ed

    Ad Ad

    C C --

    21 QU ;2 C Q CV ;

    2 2 200

    A1 1U ( E d ) ( Ad )E

    2 d 2

    2

    0

    U 1u E Ad 2

    21 1U QV CV 2 2

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    , , 1414

    23.5 23.5C C 11 C C 22 (( C C 11>C >C 22 )) V V 00 . . (( )) S S 11 , S , S 22 (( )) . .

    11)) aa bb . . C C QQ11=C =C 11V V 00 QQ22==--C C 22V V 00

    Q=QQ=Q 11+Q+Q 22=(C =(C 11--C C 22 )V )V 002 2

    a b+

    +

    _

    _

    S 1 S 2

    Q1 C 1

    Q2 C 2( )

    ab

    +

    +

    _

    _S 1 S 2

    C 1

    C 2

    ( )

    1 2

    01 2 1 2

    C C Q

    V V C C C C

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    22)) . .

    2 2 2i 1 0 2 0 1 2 0

    1 1 1U C V C V ( C C )V

    2 2 2

    2 2 2

    f 1 2 1 2

    1 1 1U C V C V ( C C )V 2 2 2

    2 2

    21 2 1 21 2 0 i

    1 2 1 2

    C C C C 1( C C ) V U2 C C C C

    2

    f 1 2

    i 1 2

    U C C U C C

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    4.4. 4.4.

    QQ00 , ,

    d d

    QQ00 , C , C 00

    V V 00=Q=Q 00 /C /C 00 , , , ,

    ,, V=V V=V 00 / /

    0 0 0

    0 0

    Q Q QC V V / V 0C C

    0 AC d

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    d d --

    ::, , , , E, E, / /

    11,000 ,0001,000591,0005980803,7 3,7

    3,783,785,6 5,6 233233

    33 10106 6

    --16 16 10106 6

    88 10106 6 1414 10106 6

    88 10106 6

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    23.6 23.6 22 3 3 . . 1 1 . . ))

    . . =3,7 =3,7 ..

    )) ? ? E=16 E=16 10106 6 / /

    2 4 212 120

    2 3

    A 6 10 C 3,7 8,85 10 19,6 10 19,6

    d 1 10

    6 3 3max max

    V E d (16 10 ) 1 10 16 10

    12 3 6 max maxQ CV (19,6 10 )(16 10 ) 0,31 10 0,31

    2 12 3 2 3

    max max

    1 1U CV (19,6 10 )(16 10 ) 2,5 10

    2 2

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    , , 1919

    23.7 23.7

    :: V V 00=Q=Q 00 /C /C 00

    C C

    C=C= C C 00

    >1>1

    QQ00 . . . . . .V 0

    C 0 Q0+ -

    20 0 0

    1U C V

    2200

    0

    QU 2C

    20Q

    U 2C 20 0

    0

    Q U U

    2 C

    C

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    2020

    . . . .

    ++ -- Fasin Fasin q q, , asinasin q q : : t t =2Fasin=2Fasin q q . F=. F=qE qE, p=2aq , p=2aq t t =2aqEsin=2aqEsin q q ==pEsin pEsin q q .. 2 2

    ? ? , , 22, 2 , 2 :: p=2aq p=2aq ,, -- ++ E E

    q q 2 2 , , F=qE F=qE

    --q

    +

    +q

    2a

    p

    - -q

    ++q

    E -F

    +F

    q O

    p E t

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    2121

    ++ d d q q dW=dW= t t d d q q t t =pEsin=pEsin q q , , U U . . q q 0 0 -- q q

    coscosq q 00 q q 00=90=90 cos90cos90 =0=0

    . .

    0 0 0U d pE sin d pE sin d

    q q q

    q q q t q q q q q 0 0 pE cos pE(cos cos )q

    q q q q

    U pE cos q U p E

    p E

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    2222

    , , , , (( ))

    :: HClHCl

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    2323

    23.8 23.8TheThe HCl HCl molecule has amolecule has adipole moment of dipole moment of 3,43,4 1010 --3030C C mm.. A sample containsA sample contains 10102121

    such molecules, whosesuch molecules, whosedipole moments are alldipole moments are alloriented in the direction of oriented in the direction of an electric field of an electric field of 2,52,5 101055

    N/C N/C .. How much work isHow much work is

    required to rotate therequired to rotate thedipoles from this orientationdipoles from this orientation(( q q =0=0 ) to one in which all of ) to one in which all of the moments arethe moments areperpendicular to the fieldperpendicular to the field(( q q =90=90 ))??

    HCl HCl 3,43,4 1010 --3030 . . 10102121

    2,52,5 101055 / / . .

    (( q q =0=0 )) (( q q =90=90 )) ??

    : 90 90 0

    W=U 90-U 0=(-pEcos90 )-(-pEcos0 )=pE=8,5 )=pE=8,5 1010 --2525 10102121

    W t =1021

    8,58,5 1010--2525

    =8,5=8,5 1010--44

    4 6 4 6

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    4.6. 4.6.

    , ,

    : : . : . :

    0 E E

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    2525

    : : E E 00== s/ s/ 0 0 : : E E ii== s s i i / / 0 0 E=E E=E 00 / / == s/ s/ 0 0

    >1>1 s s i i

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    23.9 23.9 C C 00 . . d/3d/3

    . . . .:: 2 2 d/3d/3 ,,

    2d/32d/3 , ,

    2 2

    0 01 2

    A AC ; C

    d / 3 2d / 3

    1 2 0 0

    1 1 1 d / 3 2d / 3C C C A A

    0 A3C 2 1 d

    00

    AC

    d

    0

    3C C

    2 1

    d

    13 d 23 d

    C 1

    C 2

    13 d

    23 d

    23 10 23 10

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    23.10 23.10

    :: 2 2

    , , 2 2 (d (d--a)/2a)/2

    aa d d C C .. ??

    d d ,, A A. . aa

    . . . .

    0 01 2

    1 1 1 1 1 A AC C C

    ( d a ) / 2 ( d a ) / 2

    0 AC d a

    d a

    ++ + ++ s

    -- - -- s ++ + ++-- - --

    s s

    C 1

    C 2

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    4.7.4.7. D D

    :: 2 : 2 :

    , , ::

    E E : :c c -- , , ,, c >1 c >1

    q , , s

    0 E E E

    0 E E

    ii

    1 P p

    V

    0 P E c

    0 P E c

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    P P P P P P : , : , P P E E (( ))E E

    D D D D 2 2 , ,

    in P dA q

    0 in E dA ( q q )

    0 in E dA P dA q

    0 D E P

    in D dA q

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    -- 1 c 1 c >1 >1 ,, 1 1 ,, 81 81 D D , , , , D D : : D D

    0 D E P,

    in D dA q

    0 0 0 0 D E P E E (1 )E; c c

    0 D E

    D

    in D dA q