Ekscentricno Naprezanje
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Transcript of Ekscentricno Naprezanje
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7/23/2019 Ekscentricno Naprezanje
1/8
1
4
u a33,3I = 4
v a982,0I = kN166F
4
u a917,15I = 4
v a917,8I = kN26F
4
u a908,40I = 4
v a864,8I = a62,0an = a015,1bn = kN7,35F
4
u cm1081I = 4
v cm175I = cm953,0an =
cm697,3bn = kN5,60F
4
u cm1027I = 4
v cm583I = cm17,3an = =nb
kN144F
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2
4
u cm3,7704I = 4
v cm7,518I =
cm38,0uD = cm65,5vD = kN676F
4
u a17,26I = 4
v a56,4I = kN03,4F
4
u cm7,462I = 4
v cm105I = kN101F
4
u a48I = 4
v a3
20I = kN6,106F
4
u a65,454I = 4
v a6,57I = a85,0an = a12,2bn = 2
max cm/kN34=
4
u a3
20I = 4v a
6
37I = a
36
37an = a
6
5bn =
2
max cm/kN88,4=
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3
4
u cm4507I = 4
v cm1595I = cm84,3an =
cm124,5bn = kN6,121F
4
u cm412I = 4
v cm55,123I = kN50F
4
u a3
68I = 4v a
3
8I = a33,0an = a83,2bn =
kN3,182F
4
u a60I = 4
v a4I = a33,0an = a745,0bn =
kN5,201F
4
u a17,25I = 4
v a1,16I = a68,2an = a6,3bn =
kN4,96F
4
u a17,6I = 4
v a82,3I = a37,11an = a88,0bn =
cm2a
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7/23/2019 Ekscentricno Naprezanje
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4
4
u a667,1I = 4
v a333,1I = a666,0uD = a834,0vD =
4
u a5I = 4
v a2I = cm33,1uD = cm33,3vD =
4u cm7,273I =
4v cm2,179I = kN5,77F
4
u cm5,134I = 4
v cm3,98I = kN44,59F
4
u cm3904I = 4
v cm777I = cm077,2an =
cm78,4bn = kN6,154F
4
u cm9844I = 4
v cm1546I = cm48,2an =
cm41,6bn = kN6,219F
4
u cm1210I = 4
v cm35,205I = kN48F
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7/23/2019 Ekscentricno Naprezanje
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5
4
u cm33,37I =4
v cm33,21I = 2cm/kN6,11=
kN1,73Fkr =
4
u cm460I = 4
v cm3,285I = 2
D cm/kN9,33=
4
u cm3,4338I = 4
v cm2,3366I = cm92,2an =
cm95,2bn = 2
max cm/kN317,0=
4
u cm15,5894I = 4
v cm95,2993I = cm045,13an =
cm56,8bn = 2
max cm/kN73,2=
4
u a1710I = 4
v a1674I = a599,1an1 = =n1b
a599,1an2 = =n2b 2
max cm/kN42,6=
4
ucm1228I = 4
vcm34,550I = cm594,1a
n=
cm3,2bn = kN65,69F
4
u cm2962I = 4
v cm7,622I = cm615,1an =
cm19,4bn = kN431F
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7/23/2019 Ekscentricno Naprezanje
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7
4
u a333,57I = 4
v a0833,27I = a71,2an1 =
a896,0bn1 = a231,1an2 = a583,3bn2 = 575,0F
F
2
1 =
4
u a667,698I = 4
v a667,162I = a4525,1an =
a159,4bn = cm7325,0a
Greda AB zadatog poprenog preseka optereena silom F
prema slici.
a) Odrediti jednainu neutralne linije i skicirati dijagram
normalnih napona
b) Odrediti veliinu sile F ako je: l=100 cm, a=2 cm, ||d=10 kN/cm2
4
u a6,20I = 4
v a6,2I = u25,4v = kN6,5F
4
u cm4064I = 4
v cm3284I = cm5,2a n = cm68,3bn = kN6,132F
4
u cm4064I = 4
v cm3284I = cm574,1an =
cm31265bn = cm067,1a
4
u a052,11I = 4
v a448,1I = cm301,0an = cm658,0bn = kN584,7F
4
u a8I = 4
v a286,1I = a30
31uD = a2vD = kN44,4F
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8
4
u a134I = 4
v a5,53I = a981,1an1 =
a4889,1bn1 = cm981,1an2 = acm722,3bn2 =
5458,0F/F 2D1D =
4
u a67,56I = 4
v a01,24I = a19,2a n1 =
a01,1bn1 = a41,1an2 = a05,4bn =
53,064/34F/F 2D1D ==
4
u cm4,869I = 4
v cm317I = cm177,2an = cm199,2bn = kN58,90Fp kN5,208Fe