Ejercicio 2 - Dijkstra
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Transcript of Ejercicio 2 - Dijkstra
Leonardo Navarro23,903,871
ALGORITMO DE DIJKSTRA
A→B
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)
A→C
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)
A→D
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)
A→E
El nodo ‘E’ no es accesible
A→F
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)
A
F
E D
C
B
1
1
1
22
3
3
35[A,0](0)
[A,3](1)
[B,4](2)
[B,4](2)
[C,6](3)
[A,5](1)
[A,6](1)
[F,6](2)
[F,5](3)
6
[D,9](2)
[B,10](3)