Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x...

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Transcript of Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x...

Page 1: Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x (A —S . lim n lim 7 sin x lim e . lim n lim 1 + — n 00 sin x lim e2x 00
Page 2: Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x (A —S . lim n lim 7 sin x lim e . lim n lim 1 + — n 00 sin x lim e2x 00
Page 3: Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x (A —S . lim n lim 7 sin x lim e . lim n lim 1 + — n 00 sin x lim e2x 00
Page 4: Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x (A —S . lim n lim 7 sin x lim e . lim n lim 1 + — n 00 sin x lim e2x 00
Page 5: Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x (A —S . lim n lim 7 sin x lim e . lim n lim 1 + — n 00 sin x lim e2x 00
Page 6: Egyetemünk - Miskolci Egyetemmathk/hatarertek.pdf · lim -30 v) lim 4+— n 00 cos x — 1 lim e2x (A —S . lim n lim 7 sin x lim e . lim n lim 1 + — n 00 sin x lim e2x 00

ESERCIZI SUL CALCOLO DI LIMITI CON GLI SVILUPPI DI TAYLOR · lim x!0 4 h cos(2x) + sin 2 p 2 x 1 i x(e2x cosh(2x) 2x): Svolgimento. Osserviamo che il limite si presenta nella forma

ESERCIZI SUL CALCOLO DI LIMITI CON GLI SVILUPPI DI TAYLOR · lim x!0 4 h cos(2x) + sin 2 p 2 x 1 i x(e2x cosh(2x) 2x): Svolgimento. Osserviamo che il limite si presenta nella forma

Möclöc - NmhieuPDP...Chuy n˜•5.Nguy nH€m-T‰chPh¥n V“yI= 1 2 x2e2x 1 1 2 xe2x 1 1 4 e2x 1 +C= 1 4 2x2 2x+1 e2x 1 +C. d)˚ t ˆ u= x2 dv= cosxdx) ˆ du= 2xdx v= sinx,tacâ:

Möclöc - NmhieuPDP...Chuy n˜•5.Nguy nH€m-T‰chPh¥n V“yI= 1 2 x2e2x 1 1 2 xe2x 1 1 4 e2x 1 +C= 1 4 2x2 2x+1 e2x 1 +C. d)˚ t ˆ u= x2 dv= cosxdx) ˆ du= 2xdx v= sinx,tacâ:

§لمتتاليات-العددية-توجيه-برو.pdflim sin — — x x lim aeo (n limna=ð + I + n j ... „ - (11 f (x) 4 . lim

§لمتتاليات-العددية-توجيه-برو.pdflim sin — — x x lim aeo (n limna=ð + I + n j ... „ - (11 f (x) 4 . lim

ESERCIZI AGGIUNTIVI SUI LIMITIE0… · 294 lim 295 lim senn x sen x n 1 — e2x sen x tg3x senx 2] lim 2 311 012 lim lim 1 — cos2 x tgx — COS X t 76 . 313 lim 314 lim 2.x2 + I

ESERCIZI AGGIUNTIVI SUI LIMITIE0… · 294 lim 295 lim senn x sen x n 1 — e2x sen x tg3x senx 2] lim 2 311 012 lim lim 1 — cos2 x tgx — COS X t 76 . 313 lim 314 lim 2.x2 + I

01 lcn 2019 l.i±lim Xn=a ) 71+00 a N,ffiß n>N ( xo xo ( ) …zj.offcn.com/dl/2019/0823/20190823095006810.pdf · 2019. 8. 23. · 01 lcn 2019 l.i±lim Xn=a ) 71+00 a N,ffiß n>N

01 lcn 2019 l.i±lim Xn=a ) 71+00 a N,ffiß n>N ( xo xo ( ) …zj.offcn.com/dl/2019/0823/20190823095006810.pdf · 2019. 8. 23. · 01 lcn 2019 l.i±lim Xn=a ) 71+00 a N,ffiß n>N

LIM Lavagna interattiva multimediale. Che cos’è la LIM?LIM.

LIM Lavagna interattiva multimediale. Che cos’è la LIM?LIM.

Document1...lim f(x) —Inx) Jim f lim f lim : lim n f (x) (3 lim lim c lim c I-INX-I (I —In x): F (I —Inx): x: Inx f : eddirasa.com

Document1...lim f(x) —Inx) Jim f lim f lim : lim n f (x) (3 lim lim c lim c I-INX-I (I —In x): F (I —Inx): x: Inx f : eddirasa.com

لول-تمارين... · -o lim — — 45 0 lim un lim u lim lim 3x2 lim Il 200 u lim u - lim (1 _ lim u 04 05 —5un n JS +100q -698 = 7 = uo +15q 15 - + 2007q = 8027

لول-تمارين... · -o lim — — 45 0 lim un lim u lim lim 3x2 lim Il 200 u lim u - lim (1 _ lim u 04 05 —5un n JS +100q -698 = 7 = uo +15q 15 - + 2007q = 8027

enastava.matf.bg.ac.rs - π 10enastava.matf.bg.ac.rs/~milinko/integral.pdf" + - 4 % # Zadatak 9. $ ! lim n→∞ 17 +27 +···+n7 n8 Zadatak 8. $ ! lim n→∞ 1 nk+m+1 n −1 j=1

enastava.matf.bg.ac.rs - π 10enastava.matf.bg.ac.rs/~milinko/integral.pdf" + - 4 % # Zadatak 9. $ ! lim n→∞ 17 +27 +···+n7 n8 Zadatak 8. $ ! lim n→∞ 1 nk+m+1 n −1 j=1

wdown.ebsi.co.krwdown.ebsi.co.kr/W61001/01exam/20090604/mathga_mun.pdf · 2016-03-09 · lim → lim → lim ln lim → lim ∠AOB ∠OAB OA OAB OB OC C ABC lim

wdown.ebsi.co.krwdown.ebsi.co.kr/W61001/01exam/20090604/mathga_mun.pdf · 2016-03-09 · lim → lim → lim ln lim → lim ∠AOB ∠OAB OA OAB OB OC C ABC lim

Mathematischer Vorkurs NAT-ING1 · n) in Dnfx^gmit lim n!1 x n= ^xgilt lim n!1 f(x n) = ^y. Man schreibt dann lim x!^x f(x) = ^y. Die De nition l asst sich auch auf x^ = 1 oder y^

Mathematischer Vorkurs NAT-ING1 · n) in Dnfx^gmit lim n!1 x n= ^xgilt lim n!1 f(x n) = ^y. Man schreibt dann lim x!^x f(x) = ^y. Die De nition l asst sich auch auf x^ = 1 oder y^

CHAPTER 11 INFINITE SEQUENCES AND SERIES · 698 Chapter 11 Infinite Sequences and Series 24. lim lim 1 1 converges nnÄ_ Ä_ n( ) (1) nn" nnœœÊ 25. lim lim lim 1 converges nn nÄ_

CHAPTER 11 INFINITE SEQUENCES AND SERIES · 698 Chapter 11 Infinite Sequences and Series 24. lim lim 1 1 converges nnÄ_ Ä_ n( ) (1) nn" nnœœÊ 25. lim lim lim 1 converges nn nÄ_

Gjusen-LiU4-20160107115928 del1... · 2016. 1. 7. · x3 — 2x2 —x +2 a) lim x3 — 2x2 + x —2 sin(2x) b) lim e2x _ c) +2x + 1) — In(x2 + 1)). 5. Rita grafen till funktionen

Gjusen-LiU4-20160107115928 del1... · 2016. 1. 7. · x3 — 2x2 —x +2 a) lim x3 — 2x2 + x —2 sin(2x) b) lim e2x _ c) +2x + 1) — In(x2 + 1)). 5. Rita grafen till funktionen

moutamadris.ma...limf (x ) — ex 12/27 — lim 2x + D -1#0} -4-00 limf (x ) — — lim 2x + lim 2x — — —00 lim ex = lim2x + lim 2x — lim e lime X = lim2x + lim 2x — lim

moutamadris.ma...limf (x ) — ex 12/27 — lim 2x + D -1#0} -4-00 limf (x ) — — lim 2x + lim 2x — — —00 lim ex = lim2x + lim 2x — lim e lime X = lim2x + lim 2x — lim

1 Beskonačni redovi - UNS5 Za harmonijski red, + + +L+ +L k 1 3 1 2 1 1 Dalamberov kriterium: Košijev kriterijum: 1 1 lim 1 1 1 lim = + = ρ= + →∞ →∞ n n n n n n, pa nema

1 Beskonačni redovi - UNS5 Za harmonijski red, + + +L+ +L k 1 3 1 2 1 1 Dalamberov kriterium: Košijev kriterijum: 1 1 lim 1 1 1 lim = + = ρ= + →∞ →∞ n n n n n n, pa nema

DELTA-FUNCTIONS AND DISTRIBUTIONS€¦ · lim — =-=- = lim I Im:) (shown in Fig. l.ld). (1.5) H^n(l + n 2x2) H^\ n nx+jj l * l 1.2 Test functions and distributions The notion of

DELTA-FUNCTIONS AND DISTRIBUTIONS€¦ · lim — =-=- = lim I Im:) (shown in Fig. l.ld). (1.5) H^n(l + n 2x2) H^\ n nx+jj l * l 1.2 Test functions and distributions The notion of

 · 2015-09-23 · +1, x.0 lim sin3x tan2x-----+2,.1 lim cos8 9 p 2 x x-1!!!!!"3# n.* lim 8 1-9n 4 n! "4# x.0 lim log013+ x1 2x!!!!"5#.* lim2x6log0 x+2log1- x7!"6# x.0 lim esin 32

 · 2015-09-23 · +1, x.0 lim sin3x tan2x-----+2,.1 lim cos8 9 p 2 x x-1!!!!!"3# n.* lim 8 1-9n 4 n! "4# x.0 lim log013+ x1 2x!!!!"5#.* lim2x6log0 x+2log1- x7!"6# x.0 lim esin 32

MAN10_56010E201-01_S-LIM 1.11_AP_V03_2014.pdf€¦ · lumiplus s-lim projector projecteur lumiplus s-lim proyector lumiplus s-lim proiettore lumiplus s-lim strahler lumiplus s-lim

MAN10_56010E201-01_S-LIM 1.11_AP_V03_2014.pdf€¦ · lumiplus s-lim projector projecteur lumiplus s-lim proyector lumiplus s-lim proiettore lumiplus s-lim strahler lumiplus s-lim

nenomatica · 2018. 9. 12. · lim lim lim lim u l) lim v) lim u) lim 3) tim lim x lim lim = lim = lim 2- cos 2x = lim 1 + = lim tim cosr:r 2 — cost) 2-1 o

nenomatica · 2018. 9. 12. · lim lim lim lim u l) lim v) lim u) lim 3) tim lim x lim lim = lim = lim 2- cos 2x = lim 1 + = lim tim cosr:r 2 — cost) 2-1 o

MathsPhysicsmathsphysics.altervista.org/alterpages/files/Limitidifunzionialgebriche.pdf · lim (x2 lim (x — lim (2 — lim (x — an lim lim (I X2)2 ... (Uk) 3 — 23) e semplificando

MathsPhysicsmathsphysics.altervista.org/alterpages/files/Limitidifunzionialgebriche.pdf · lim (x2 lim (x — lim (2 — lim (x — an lim lim (I X2)2 ... (Uk) 3 — 23) e semplificando