EEE207 Tutorial Solutions.doc
-
Upload
earljaysonalvaran -
Category
Documents
-
view
261 -
download
1
Transcript of EEE207 Tutorial Solutions.doc
-
8/16/2019 EEE207 Tutorial Solutions.doc
1/42
Communications
Module Code: EEE207
Tutorial No 1 Solutions
-
8/16/2019 EEE207 Tutorial Solutions.doc
2/42
Communications Tutorial 1 – Modulation – Solutions
1)
a) )102cos(5)( 4 t t m π = , i.e. V m = 5 Volts, f m = 10!"
t
V
t
V
t V t v mcm
mc
m
c DC s )cos(2)cos(2cos)( ω ω ω ω ω −+++=
V DC
= 0
5/2 5/2
m = ∞
90 110100 kHz
-
8/16/2019 EEE207 Tutorial Solutions.doc
3/42
#)
+5
-5
d (t )
Condition Waveform = Type
Input
+5
-5
t
t
Input
PSK/PRK
Carrier
2kHz
V DC = 0
1 mse
t t d V c DC ω cos))(( +
+10
-10
t
!SK/""KV DC = 5
+15
-15
t
!SKV DC = 10+5
-5
2.
a) Modulation $e%t& 5'010
5===
DC
m
V
V m
#) T&e total aerae side#and %o*er +a #e deter+ined # one o- t*o +ain
*as:
A. . a%%lication o- t&e e/uation
+=
21
2m P P C T
i.e.
Side#andTotal
2
Carrier 2
m P P P cC T +=
i.e. Total side#and %o*er =2
2m P c
-
8/16/2019 EEE207 Tutorial Solutions.doc
4/42
*&ere ( )
≡
=2
22
RMS DC
L
DC
c
V
R
V
P
!ence,att1
50
2
10 2
=
=c P
∴Total side#and %o*er =( )
att
1
2
5'0
21
22
==
m
B. 3lternatie +et&od is to consider diara+e/uation, i.e.
+#
0#
V DC
m(t )
( )
( )
( )t V
t V
t V
t t V V t v
mcm
mcm
c DC
cmm DC s
ω ω
ω ω ω
ω ω
−+
++=
+=
cos2
cos2
cos
coscos)(
t cω cost V mm ω cos
∴Total side#and %o*er = ( )
L
m
L
m
L
m
R
V
R
V
R
V
222222
22
=
+
!ence, total side#and %o*er = att
1
50
)5(2 2
=×
c) Total aerae %o*er = carrier %o*er total side#and %o*er
= 1 att 1 att = 11 atts
3. 6o*er out%ut = 24 *&en +odulation de%t& m = 1
a) - t&e carrier is un+odulated, 6o*er out = P carrier onl since P USB and P LSB = 0
i.e. )1(since18
2
11
24
21
242
1
22
2
==
+
=
+
=∴
=
+=
mm
P P
m P P
T c
cT
Power output = 16 kW (unmodulated carrier)
#) - m is reduced to 0'9 t&en
2
)9'0(118
21
22
+=
+= m P P cT
Total output power P T = 16.7 kW
-
8/16/2019 EEE207 Tutorial Solutions.doc
5/42
c) #sere -ro+ a#oe t&at total side#and %o*er = 0'72 or -ro+
44
22m P m P
P P cccT ++=
∴ 6o*er in one side#and = 98'0
4
)9'0)(18(
4
22
==m P c
∴ ;atio = 0215'072'18
98'0= , (i.e. 2'15< o- total %o*er in one side#and *&en
m=0'9)
d) SS. di+inis&ed carrier %roduced *it& SS. %o*er = 0'98 and P c = 18
reduced # 28d. (%o*er)' To deter+ine P c (reduced)
Met!od 1"
P c = 18 × 109 atts
P c d. = d.42 att1
atts)(lo10 10 =
c P (relatie to 1 att)
;educed # 28 d. ies P c reduced = 18 d.
∴ P c reduced = '9=101018
= atts
∴ Total 6o*er = carrier side#and = 9' atts
Met!od "
=
reduced
10lo1028c
c
P
P dB , 11'9=10
8'2
reduced
==∴c
c
P
P
∴ P c reduced = atts2'4011'9=
000,18=
P T ≈ 400 atts
4.
V DC
t cω cos
t V t V t mmm
ω ω coscos)( 11 +=
( ) t t V t V V t v cmm DC s ω ω ω coscoscos)( 2211 ++=
-
8/16/2019 EEE207 Tutorial Solutions.doc
6/42
-
8/16/2019 EEE207 Tutorial Solutions.doc
7/42
φ φ ω
ω φ ω ω φ ω
φ ω ω
cos2
)()2cos(
2
)(
))cos((2
)())cos((
2
)(
)cos(cos)(
t mt
t m
t t t m
t t t m
t t t mV
c
cccc
cc x
++=
−++++=
+=
>6@ re+oes 2ωc co+%onents, &ence φ cos2
)(t mV UT
= B -or $S.SC
Note, i- t V t m mm ω cos)( = , t V
V mm
UT ω φ coscos2
=
cos φ a--ects t&e a+%litude o- t&e out%ut -or $S.SC'
i) - φ = 0, cos φ = 1, i.e. carrier %&ase o--set = 0
∴ 2
)(t mV UT =
ii) - φ = π2 (00), 02cos =π
0cos2
)(== φ
t mV UT B i.e. "ero out%ut
n eneral, as t&e local oscillator %&ase aries (assu+in t&e -re/uenc is o) t&e
amplitude o- t&e out%ut aries' 3s φ increases -ro+ 0 → π2 t&e out%ut a+%litude
decreases to "ero' (no*n as #adin$)' &en φ = ± !π2, *it& ! odd, t&e out%ut *ill #e
"ero'
". T&e in%ut to t&e snc&ronous de+odulator no* is SS.SC'
a)
t cω cos
P&
#*V OUT
SSSC
t V
V
t V
t V
t t V
t t V
V
mm
UT
m
m
mc
m
Differe!ce
mcc
S#m
mccm
cmcm
x
c
ω
ω ω ω
ω ω ω ω ω ω
ω ω ω
ω
cos4
cos4
)2cos(4
))(cos())(cos(2
1
2
cos')cos(
2
sinalMessaere+oes>[email protected]
=∴
+−=
−−+−+=
−=
∆Σ
-
8/16/2019 EEE207 Tutorial Solutions.doc
8/42
6arts #) and c) can #e soled # considerin ∆ω and t&en φ' @or a eneral
solution consider a eneral local oscillator ))cos(('' φ ω ω +∆+= t L c , *&ere∆ω and φ +a #e %ositie or neatie'
[ ]
φ ω ω
φ ω ω φ ω ω ω
ω ω φ ω ω ω ω φ ω ω
φ ω ω ω ω
+∆+=∴
+∆+++−∆+=
−−+∆++−++∆+=∴
+∆+−=∴
t V
V
t V
t t t V
t t t t V
V
t t V
V
m
m
UT
m
m
mc
m
mccmcc
m
x
cmc
m
x
)cos((4
)cos((4
)2cos(4
)()cos(()()cos((2
1
2
))cos((')cos(
2
re+oes>6@
Note t&is is -or SS.SC (co+%are $S.SC in D8)' n t&is case ∆ω and φ o--sets
cause t&e out%ut to s&i-t in -re/uenc and %&ase'
#) @re/uenc o--set ∆ω, #ut %&ase o--set φ = 0'
t V
V mm
UT )cos(4
ω ω ∆+=∴
n t&is case t&e de+odulated out%ut is s&i-ted in -re/uenc # ∆ω
co+%ared to t&e in%ut t V mm ω cos '
@or ea+%le, i- ω+ = 1!" and ∆ω *as 200!" t&en t&e out%ut -re/uenc
*ould #e a sinal at 1200!"' @or s%eec& sinals, i- ∆ω is s+all #ut sta#le,
t&e -re/uenc s&i-t at t&e out%ut +a #e tolera#le'
c) No* consider ∆ω = 0 *it& a %&ase o--set φ
)cos(4
φ ω +=∴ t V
V mm
UT
n t&is case, i.e. -or SS., t&e out%ut is o--set # φ (Note -or $S., a %&ase
o--set *ill a--ect t&e a+%litude and cause -adin' @or s%eec& sinals a
%&ase o--set +a not #e er serious #ecause t&e ear is relatiel
insensitie to %&ase'
Note: n snc&ronous de+odulation *it& SS.SC in%ut, -re/uenc and
%&ase o--sets in t&e >'' can #e tolerated +uc& +ore t&an in $S.SC'
SS.SC is a %o%ular -or+ o- +odulation'
-
8/16/2019 EEE207 Tutorial Solutions.doc
9/42
Communications
Module Code: EEE207
Tutorial No 2 Solutions
-
8/16/2019 EEE207 Tutorial Solutions.doc
10/42
1) a)
T&e s%ectru+ at eac& %oint is s&o*n #elo*:
T&e out%ut, , is a sinle side#and su%%ressed carrier, SS.SC sinal, in t&is
case t&e lo*er side#and' T&e sinal is -re/uenc inerted'
%)
&' F &'( )t m
Carrier t C$s cω
f c=4G!"
ut%ut
( )t v s & C
( )t m
fre%
&
fre%
.and li+ited( )t m
fre%
f c
4 G!"
C
>S. HS.
*
f c
fre%
ut%ut ( )t v s
F &'
t C$s cω
4 G!"
( )t v sSS&SC
Vout
(t)V
( )t v s
-
8/16/2019 EEE207 Tutorial Solutions.doc
11/42
T&e s%ectru+ at eac& %oint is s&o*n #elo*'
T&e out%ut sinal is t&e oriinal #andli+ited +essae sinal, '
a)
$iara+ to ie ( ) ( ) t C$st C$sV t V cm DC s ω ω '01+=
i'e' ( ) ( ) t C$st C$sV V t V cm DC DC s ω ω '0+=
%)
@ro+ a#oe , ( ) t C$sV t C$sV t m m DC mm ω ω '0==
i'e' ( )( ) v$&tsV V DC m 10'0'0 ===
Note also t&at +odulation de%t& = '0= DC
m
V
V
i'e' ( ) ( ) '0,1 =+= mt C$st C$smV t V cm DC s ω ω
f c
fre%
( )t v s
f c
fre%
V
fre%
Carrier
f c
fre%
fre%
Vout
(t)
F
t C$sV m DC ω '0 t C$s cω
( )t v s DC V
( )t m
-
8/16/2019 EEE207 Tutorial Solutions.doc
12/42
c)
+ormali,ed a-era$e power"
1) 3%%l E/uation
21
2m
C T +Ρ =Ρ
&ere,
( )
2
2
DC C
V =Ρ
( ) ( ) ( ) ( )
( ) $'mi!(atts
mV
T
DC T
18892'150284'01
2100
2
'01
2
10
21
2
222
2
== +=Ρ
+=+=Ρ
Total 6o*er = 88 *atts (Nor+ali"ed 3erae 6o*er)
2)
6T = Carrier 6o*er HS. %o*er >S. %o*er
i'e'
( ) ( ) ( )
)(8850
84
84
2100
22222
22222
a)$veas(atts
V V V
t C$sV
t C$sV
t C$sV t V
T
mm DC T
mc
m
mc
m
c DC s
=++=Ρ
++= + + =Ρ
−+++= ω ω ω ω ω
d)
G!"10
G!"100
=
=
m
c
f
f
G!"0=
B mc f f
G!"110
mc f f +
G!"100
c f
vV m 42
=v4
vV DC
10=
fre%#e!c*
-
8/16/2019 EEE207 Tutorial Solutions.doc
13/42
9'
a)
&m1(t )
!1
f 1 = 100kHz
&m2(t )1
f 2 = 110kHz
&m,(t )C1
f , = 120kHz
!2
2
C2
S".
S%ectru+ at eac& %oint
m1(t )
5kHz f ,kHz f
!1
10, f f c1
100
9
!2
5kHz f
m2(t )
,kHz f
1
11, f f c2
110
10
2
m,(t )
5kHz f ,kHz f
C1
12, f f c3
120
11
C2
-
8/16/2019 EEE207 Tutorial Solutions.doc
14/42
10,f c1
100kHz
9 11,f c2
110kHz
10 12, f f c1120kHz
11
S".
Note t&is is si+ilar to >on ae (>) or Mediu+ ae (M) radio'
#) ;eceier
P&
"
0-,kHz
#".
SI
n t&e receier, *e +a tune t&e -re/uenc o- t&e local oscillator to select
*&ic& +essae *e *is& to receie'
>et >'' = t L ''cosω , i.e. -re/uenc = f L..
i) Tune t&e >'' to f L.. = f c2, i.e. f L.. = 110!"ii)
&
0-,kHz
#".
SI
t L ''cosω
#*
( )
t t t mt t t mt t t m
t t t mt t mt t m
t S V
Lc Lc Lc
Lccc
L +, x
''99''22''11
''992211
''
coscos)(coscos)(coscos)(
coscos)(cos)(cos)(
cos
ω ω ω ω ω ω
ω ω ω ω
ω
++=++=
=
-
8/16/2019 EEE207 Tutorial Solutions.doc
15/42
t t m
t t m
t t m
t t m
t t m
t t m
V
Lc Lc
c Lc L
c Lc L x
)cos(2
)()cos(
2
)(
)cos(2
)()cos(
2
)(
)cos(2
)()cos(
2
)(
!"10110120
''99
!"290110120
''99
!"0110110
2''2
!"220110110
2''2
!"10100110
1''1
!"210100110
1''1
=−=+
=+=+
=−=+
−+++
−+++
−++=
ω ω ω ω
ω ω ω ω
ω ω ω ω
it& >'' set to 100!" s%ectru+ at V
P&
m2(t )
m1(t ) m,(t )
10
#*m1(t ) m2(t ) m,(t )
210 220 2,0 kHz
3-ter t&e >6@
2
)(2 t mV UT =
f
4'
a) Sste+
SS
t cω cos
#*
t 0cosω
#
m(t )
#C S".
t t t mt t V
t t t mV V
t t mV V
cc DC
c DC *
c DC x
00
0
coscos)(coscos
coscos))((
cos))((
ω ω ω ω
ω ω
ω
+=
+=
+=
-
8/16/2019 EEE207 Tutorial Solutions.doc
16/42
t t m
t t m
t V
t V
V ccc DC
c DC
* )cos(2
)()cos(
2
)()cos(
2)cos(
2 0000 ω ω ω ω ω ω ω ω −+++−++=
.e-ore considerin t&e s%ectru+ ien # t&is e/uation, consider t&e sinals
#elo*'
50Hz 15kHzf
#C + m(t )
f c
f
f
Carrier f c
#*
"sf 0
#
SS
&i%ter
S".
f c
103Hzf c 415kHz f
c +15kHz
f 0
1003Hz
f 0
+ f c
1103Hz
f
f
f
f
f 0
1003Hz
f 0 4 f
c
903Hz
f 0
+ f c
1103Hz
2
DC V
2
DC V
T&e e/uation -or V * a#oe +a#e seen to #e consistent *it& t&e s%ectru+ -or
V *' T&e SS. %asses t&e su+ -re/uencies to t&e out%ut sinal S UT as s&o*n,
*&ere
t t m
t V
S cc DC
UT )cos(2
)()cos(
2 00 ω ω ω ω +++=
Note t&at t&e #ase#and sinal &as #een +odulated # a 10M!" carrier to
%roduce t&e $S.3M sinal at V x, t&en u%Bconerted (anot&er +odulation
stae) # a 100M!" oscillator to %roduce t&e dou#le side#and sinal centred
on 100 M!" at V *, t&en -iltered to %ass t&e HS., *&ic& in t&is case is t&e u%B
conerted $S.3M sinal, centred on 110M!"'
#) ;eceier$e+odulator si+%le'
-
8/16/2019 EEE207 Tutorial Solutions.doc
17/42
P&
0-,kHz
#".
SI
t L1cosω t cω cos
#*
$a%
"si%%at$r f "1 = 1003Hz
4))(( DC V t m +
+++++=
+
++=
+=
==+=+=
t t t t mV
t t t mV
t t t mV V
t t f f
t t t t t mV V
t t t mV S
cc DC
c DC
c DC x
L L
c Lc DC x
c DC +,
)(2cos2
1
4
12cos
4
12cos
4
1
4
1))((
2cos2
1
2
12cos
2
1
2
1))((
cos'cos))((
)cos(cos*it&
cos'cos'cos'cos))((
cos'cos))((
00
0
0
22
1001
10
0
ω ω ω ω
ω ω
ω ω
ω ω
ω ω ω ω
ω ω
>6@ -ilter re+oes all co+%onents at 2ω0, 2ωc, etc. to ie
4
)(
4
t mV V DC UT +=
n t&is case >1 do*nBconerts t&e receied sinal to 10M!" and cos ωct and>6@ de+odulate to recoer m(t )'
-
8/16/2019 EEE207 Tutorial Solutions.doc
18/42
Communications
Module Code: EEE207
Tutorial No 9 Solutions
-
8/16/2019 EEE207 Tutorial Solutions.doc
19/42
1)
3udio sinal ( ) t C$st m mω 10= , V+ = 10 olts@re/uenc +odulator, α = 10 -/ %er olt'
a) 6ea deriation
I- c = α V+ = 10olt
G!"' 10 olts = 100 G!"
6ea deriation I- c = 100 G!"
#) Modulation inde, J =+-
-c∆=
+-
V+ α
+- 2π ω =m i'e' +- = 104 G!" = 10 G!", J = 10
G!"10
G!"100=
Modulation inde, J = 10
)
I- c = 1G!" *&en +- = 1 G!" , t&ere-ore Mod' nde, J =+-
-c∆= 1
Modulation inde, J = 1
a) Co+%onents in t&e @M s%ectru+ are -ound -ro+:
( ) ( ) ( )∑∞
−∞=
+=!
mc!c s t !C$s 0 V t v ω ω β
&ere Vc = 10 olts, J =+-
-c∆= 1
G!"1
G!"1=
T&e nt& %air o- t&e co+%onent is ( ) ( )t !C$s 0 V mc!c ω ω β + (n = e)
and ( ) ( )t !C$s 0 V mc!c ω ω β −− (n = B e)
@ro+ t&e ta#le o- t&e .essel -unctions and in t&is case usin t&e identit
( )β ! 0 − = ( ) ( ) 11 =− β β f$r 0 !!
n ( )β
!
0
Amp =( )β
!c
0 V
Frequency Hz
-
8/16/2019 EEE207 Tutorial Solutions.doc
20/42
0 0'7852 7'852 fc
1 0'4400 4'40 mc f f +
B1 B0'4400 B4'40 mc f f −
2 0'114 1'14 mc f f 2+
B2 0'114 1'14 mc f f 2−
9 0'018 0'18 mc f f 9+
B9 B0'018 B0'18 mc f f 9−
Co+%onent -or n a#oe 9 &ae ( )β ! 0 K 0'01 and are considered insini-icant, andinored' T&e (B1) sin in t&e a+%litude indicates a %&ase o- 100'
#)
CarlsonLs rule a%%roi+ation . = 2(I- c - +) = 2 (1 G!" 1 G!")
CarlsonLs rule ies .= 4 G!" (Note a%%roi+ation)
c) >oad resistance ; > = 50 o&+s, Vc = 10 olts'
-
8/16/2019 EEE207 Tutorial Solutions.doc
21/42
i) C&annel #and*idt& sini-icant @M s%ectru+, 8 G!" co+%onents outside
t&is #and*idt& are cutBo--L' To -ind t&e aerae %o*er receied need to -ind t&e
%o*er in t&e sini-icant s%ectru+'
Eac& co+%onent in t&e sinal &as a %ea a+%litude ( )β !c 0 V or ( )β !c 0 V −
3erae %o*er = ( ) ( )>
2
%ea
2
>
2
;MS
; 2
V2
;
V=
= L
1ea2
R
V
i'e 3erae %o*er =( )( )
>
2
; 2
β !c 0 V
-or n = e or e since O ( )( ) 2β ! 0 = ( )( ) 2
β ! 0 − P
Total %o*er in s%ectru+ 6T =( )( )∑
∞
∞−=!
!c 0 V
>
2
; 2
β
@or sini-icant side#and to n = a±
6o*er in s%ectru+ 6s =( )( )∑
−=
a
>
2
; 2
a!
!c 0 V β
6s =
( ) ( ) ( ) ( )
9210
)2((50)2
1=8'0)2(
(50)2
14='1)2(
(50)2
4'4
(50)2
852'72222
±=±=±==+++
!!!!
= 0'55591 0'972 0'028404 7'892 10B4
= 0'099 *atts
6o*er receied (i'e in t&e sini-icant s%ectru+) = 0'099 *atts
ii) &en t&e carrier is not +odulated'
-
8/16/2019 EEE207 Tutorial Solutions.doc
22/42
6o*er = ( )*att1
)(502
102 2
2
==
L
1ea2
R
V
6o*er in un+odulated carrier = 1 *att
.ut Note in @M t&e carrier a+%litude is constant at Vc, onl - cL c&anes (i'e' - c ±
I- c ) and t&e %o*er is inde%endent o- -re/uenc'
T&ere-ore
( )( ) ( )*att1
2; 2
2
>
2
=== ∑∞
∞−= L
c
!
!cT
R
V 0 V P
β
)
Qien Vc= 10 olts, J =2 and also since *e are to -ind t&e %o*er, *e +a use( ) ( )β β !! 0 0 =− '
@ro+ .essel ta#les -or ( ) 01'02 ≥! 0
( ) 29='220 = 0 V c
( ) 878'521 = 0 V c
( ) 52'922 = 0 V c
( ) 2='129 = 0 V
c
( ) 940'024 = 0 V c
!ence s%ectru+ s&o*in +odulus o- a+%litudes is:
T&ere-ore, %o*er in s%ectru+ -or n u% to ± 4, -or ( ) 01'0≥β ! 0
-
8/16/2019 EEE207 Tutorial Solutions.doc
23/42
( )( )∑−=
=4
4 >
2
; 2
!
!c s
0 V P
β
( ) ( ) ( ) ( ) ( )[ ]22222 94'022='1252'92878'5229='22
1×+×+×+×+=
L
s
R
P
*atts=47442'4
2
=49'=7
L L
s R R
P ==
Total %o*er in @M sinal
( ) ( )( )∑∞
∞−=
=
==!
!c
L
12
L
RMS T
0 V
R
V
R
V P
>
2
2
2
;
2 β
( ) *atts502100
210
2
L L L
T R R R
P ===
!ence,
( )
50
=47442'4
%o*er Total
01'0R-ors%ectru+in6o*er n =≥β
= 0'74
!ence, %ro%ortion o- total %o*er in s%ectru+ -or *&ic& onl sini-icant co+%onent
included 0'7 (7'
-
8/16/2019 EEE207 Tutorial Solutions.doc
24/42
#) Vc= 10 olts' @ro+ .essel ta#les -or β =2
n Amp = ( )β !c 0 V FrequencyK Hz
0 2'29 fc = 100
1 5'787 mc f f + = 110
B1 5'787 mc f f − =0
2 9'52 mc f f 2+ =120
B2 9'52 mc f f 2− =0
9 1'2 mc f f 9+ =190
B9 1'2 mc f f 9− =70
4 0'940 mc f f 4+ =140
B4 0'940 mc f f 4− =80
c) Since Vc= 10olts %ea, 3erae %o*er = ( )>
2
;MS
; V
@M Sinal 6o*er =*att1
E502
0012
2
==
L
c
R
V
'
T&e %o*er in t&e s%ectru+ dra*n a#oe, *it& 4 side#and %airs *ill #e less t&an 1
*att, and is ien #
-
8/16/2019 EEE207 Tutorial Solutions.doc
25/42
( )( )∑−=
=4
4 >
2
; 2
!
!c s
0 V P
β (See Duestion 9)
0)
a) Since Modulation nde β =+-
-c∆ and β = 5 is re/uired *it&
f m = 15 G!" (-ro+ ( ) t C$st m 9
101525 ×= π )
6ea $eiation I f c = β f m = (5) (15) = 75 G!"
#) Since I f c = α V m and V m = 5 olts,
@re/uenc conersion -actor α =+V-c
∆
=olts5G!"75 = 15 G!" %er olt'
c) @ro+ .essel ta#les, -or β =5 , ( ) 01'05 ≥is 0 ! -or n = 0 to , i'e t&ere *ill #e %airs o- sini-icant side#ands'
i'e'
-
8/16/2019 EEE207 Tutorial Solutions.doc
26/42
CommunicationsModule Code: EEE207
Tutorial No 4 Solutions
1)
a)
-
8/16/2019 EEE207 Tutorial Solutions.doc
27/42
P$er
3eter m = 13Hz
1 = 1kHz
2 = 10kHz
, = 103Hz
p0= 10-6
7atts/Hz
6o*er = ! B 10 , *&ere B! is t&e noise #and*idt&' e &ae to tae note *&ic&
is t&e s+allest #and*idt&'
6o*er +easured at (i) 101 B 1 , = (since B Bm)98
1 1010 ×= −
, = 1+att (0d.+)
6o*er +easured at (ii) 202 B 1 , = (since B2 Bm)98
2 101010 ××= −
, = 10+att (10d.+)
6o*er +easured at (iii) m B 1 , 09 = (since Bm B3)88
2 1010 ×= −
, = 1att (90d.+ or 0d.)
3ctual noise %o*er at (iii)88
90 1010 ×= − B 1 = 10atts (10d.)
Note 1: t is i+%ortant to #e a*are o- *&at #and*idt& noise is +easured in
(e.. *it& %o*er +eter or s%ectru+ analser), i.e. t&e sste+ #and*idt& or t&e
test #and*idt&'
Note 2: #sere &o* control o- t&e #and*idt& can reduce t&e noise (10atts
at 10M!" → 1 +att at 1!")' t is i+%ortant to &ae a #and*idt& Uust *ide
enou& -or t&e sinal, #ut no *ider in order to +ini+ise t&e noise %o*er and
+ai+ise t&e (SN),
#) .ot& -ilters are ideal, noise -ree, *it& power ains and 2, and #and*idt& B and B2'
811
822
!
p0 I ".
1 = 13Hz 2 = 1kHz
110 B5 1 , +, = = noise at
-
8/16/2019 EEE207 Tutorial Solutions.doc
28/42
2210 )( B55 1 ,
UT = , since B2 B and since 1 is t&e sa+e an*&ere in t&e %at&,
allo*in -or ains'
.ut11
0 B5
, 1 +, =
=
=∴
1
22
11
221
B
B5 , ,
B5
B55 , ,
+, UT
+, UT
Note: , UT is not si+%l 2 , +, t&e #and*idt&s +ust #e taen into account'
Since( )
UT
UT UT
R
V ,
2
≡ ,( )
+,
+, +,
R
V ,
2
=
( ) ( )2
1
2
22
'' 5 B
B
R
V
R
V
+,
+,
UT
UT =
Matc&ed Sste+, i.e. RUT = R +,
2
1
2 5 B
BV V +, UT =
2)
8ain
8
(S/)".(S/)I
+,
UT
+,
UT
+,
+,
UT
UT
+,
+,
5,
,
5S
,
,
S
S
,
,
S 7 === ''
I ". = 8I + a8
a
, a is added noise *&ic& a%%ears at t&e out%ut'
I ". = 8(I + e)
8
e
, e is t&e e/uialent noise re-erred to t&e in%ut, *&ic& ies , a at out%ut, i.e. , a = , e
-
8/16/2019 EEE207 Tutorial Solutions.doc
29/42
)(, e +, UT +,
UT , , 5 , 5,
, 7 +≡=
i.e.
+=
+=
+,
e
+,
e +,
,
,
5,
, , 5 7 1
)(
i.e. +, e , 7 , )1( −=
Since , = TB, assu+in sa+e #and*idt& B
B2T 7 B2T +, e )1( −=
+, e T 7 T )1( −= (*&ere T +, is t&e source te+%erature T s)i.e. se T 7 T )1( −= , *&ere T +, = T s is usuall taen to #e 20G'
9)a)
!
1
$ss = ,
1 = 2
81 = :&1 = 2
.e1 = 290K
28 = 10
& = 6
82 = 10
&2 = ;
.e2 =
-
8/16/2019 EEE207 Tutorial Solutions.doc
30/42
-
55
T
5
T T T T T
c s2*
eeee s2* s*s
1=501450500
947701455004
1'10
70
10
7070
2
12=0
2
11000
;e
92
4
2
921
=+=++++=
+++
+
=
++++=
;e-erred to & (sste+ e/uialent noise te+%erature)
Note: as *e *ould e%ect t&is is eactl &al- t&e sste+ te+%erature
re-erred to t&e ca#le &as ain o- (9d. loss) and noise %o*er is
%ro%ortional to T s*s, i.e. %o*er at & = %o*er at '
#) >o* noise %rea+% installed:
%tion (a) note reBnu+#er t&e ele+ents
!
1
&1 = 2
81 = 10
.e1 = 290K
2
&2 = 2
82 = :
.e2 = 290K
,
&, = ;
8, = 10.e, =
-
8/16/2019 EEE207 Tutorial Solutions.doc
31/42
-
5555
T
555
T
55
T
5
T T T T
c s2*
eeeee s2* s*s
219111911000
8'8=4'17174502=01000
4
1'10'10'
2
1
70
10'10'2
1
70
10'2
1
70
2
1
2=0
2=01000
;e
4921
5
921
4
21
9
1
21
=+=+++++=
+
+
+
++=
+++++=
;e-erred to , o%tion (#)' T&is is #etter t&an no %reBa+% #ut not as ood as
o%tion (a)
%tion (a) T s*s = 150G
%tion (#) T s*s = 2191G
No %rea+% T s*s = 900G
!ence, -or #est noise %er-or+ance, t&e +ast &eadL location is t&e #est
solution'
T&is solution can also #e in-erred -ro+ t&e e/uation
+++=21
9
1
21;e
55
T
5
T T T eeec
To ee% T Rec s+all, t&e ain o- t&e -irst stae s&ould #e W 1 (i.e. an a+%li-ier rat&er t&an a ca#le)' Successie noise contri#utions are t&en reduced'
Note: >o* noise (receiers) is not t&e onl consideration' Too +uc& ain at
t&e -ront end, *&ic& is wide open (a *ide #and*idt&) to noise and
inter-erence can oerdrie or saturate later staes, e.. t&e +ier, and cause
%ro#le+s due to nonBlinear distortion and inter+odulation %roducts' n so+e
receiers t&e aerial is connected strai&t to t&e -irst +ier' T&e %ri+e
considerations are t&e /ualit o- t&e sinal at t&e out%ut in ter+s o- (SN) and
distortion'
4)
a) n eneral eac& T e is re-erred to in%ut'
-
8/16/2019 EEE207 Tutorial Solutions.doc
32/42
81.e1
82.e2
8,.e,
8;.e;
÷ 81
÷ 8182
÷ 81828,
A
Noise %o*er is %ro%ortional to T e ( , = T e B)' T&ere-ore, to re-er to T e earlier
staes, diide # ain o- %recedin staes as s&o*n'
i.e. T Rec re-erred to is ++++=921
4
21
9
1
21;ec
555
T
55
T
5
T T T eeee
#)
i) Note: conert all d.L to ratios'
A
= ;& = 28 = 10 =6 & = 6n = 250kHz
1&1 = 2512
1 = 2512
.e1 = ;,
-
8/16/2019 EEE207 Tutorial Solutions.doc
33/42
iii) T&e receier, T Rec, at includes t&e ca#le'
A
R>C
Since T e = (1 7 )T +, , +,
e
T
T 7 +=1
@actor)(Noise47'20100
1=4711
;ec
;ec =+=+= +,
e
T
T 7
Noise -iure 7 d. = dB 7 1'19)47'20(lo10lo10 1010 ==
c)
i)
A
R>C
.sk = 100K
7 = ,03Hz = ae
! = 250kHz
(S/)".
3ctual (SN) at = 5=4'1
1090100101'9
atts108'8829B
14
=
××××
×=
−
ae s2* B2T
S
3ctual (SN) at is 1'5, i.e. sinal Uust a#oe t&e noise'
(SN) at +easured *it& an instru+ent *it& a 250!" #and*idt& is:
9'1=1000,250100109'1
108'829
14
=×××
×−
−
i.e. in t&e sa+e #and*idt& (SN)N WW (SN)HT, as *ill #e s&o*n'
ii)( )
)7'=(948'=000,2502047109'1
108'8
3tore-erred
3at+easured
29
14
dB
T
S
B2T
S , S
s*s s*s
UT
≡=×××
×=
=
−
−
iii) Noise %o*er s%ectral densit re-erred to in%ut, -ro+ , = T s*s B,
1 = T s*s = 1'9×10B29×2047 = 2'25×10B20 atts!"
3ctual %o*er s%ectral densit at out%ut *ill #e 1 HT = 1×ain o- receier
-
8/16/2019 EEE207 Tutorial Solutions.doc
34/42
atts!"1011'2)1000(4
1)10(
512'2
110525'2 1720
−− ×=
××=
T&e ratio (S 1) re-erred to is (also sa+e at out%ut)
)8'89(109989'21025'2
108'8 820
14
dB≡×=××
−
−
-
8/16/2019 EEE207 Tutorial Solutions.doc
35/42
-
8/16/2019 EEE207 Tutorial Solutions.doc
36/42
-
8/16/2019 EEE207 Tutorial Solutions.doc
37/42
ii)
Sinle #it error correction i'e success-ul trans-er i- no errors or 1 error in
+essae' t&er*ise -alse trans-er since -urt&er error detection not carried out'
6ro#a#ilit o- success-ul trans-er = %(0) %(1) = 6sucess = 0'4904872 0'928975
6ro#a#ilit o- Success-ul trans-er = 0'191047
3ll ot&er +essaes are acce%ted, i'e' none reUected
6ro#' o- -alse trans-er = 18=59'01)(1
=−=∑=
s#ccess
,
R
P R 1
ONote 1< o- t&e in-or+ation acce%ted is *ron t&is is #etter t&an (i) #ut
still not oodP
iii)
Code *&ic& can correct sinle error in #loc and detect 2 errors'
i'e' No errors +essae acce%ted correct
1 error +essae correctedacce%ted correct
2 errors errors detected +essae reUected lost
9 or +ore errors errors not detected +essae acce%ted -alse
6ro#a#ilit o- success-ul trans-er = %(0) %(1) = 0'19047
6ro#a#ilit o- lost trans-er = 1(2) (2 errors detected, +essae reUected)
1(2) = 0'14094
@alse trans-er occurs i- t&ere are 9 or +ore errors'
6ro#a#ilit o- -alse trans-er = )P2()1()0(O1)()9(9
1 1 1 R 1 1 ,
R
++−==≥ ∑=
6ro#a#ilit o- -alse trans-er = 0'0901
ONote in t&is case 9'< o- t&e +essaes trans+itted are acce%ted and are
-alse t&is is a#out 4'47< o- t&e +essae acce%tedP
)
T&e +ini+u+ distance o- t&e code is t&e +ini+u+ no' o- #its c&ane, to
conert one alid code*ord in t&e code to anot&er alid code*ord'
@or ea+%le Code 1 Code 2 Code 9
Valid Code*ord 3 01101 1111 010101
Valid Code*ord . 00001 0000 101010
!a++in $istance 2 4 8
-
8/16/2019 EEE207 Tutorial Solutions.doc
38/42
T&e distance #et*een alid code*ord in a code is called t&e &a++in
distance' 3ll code *ords in a code are not se%arated # t&e sa+e !a++in
distance T&e +ini+u+ alue o- t&e &a++in distance in a code is called t&e
+ini+u+ distance (d+in or d )'
@or a code *it& d+in=5, usin d+in = t 8 & 8 1, t K & *&ere t = no o- #itscorrected, &= no o- #it error detected'
d+in = t 8 & 8 1
5 = 0 4 1 detect u%to 4 errors (dB1)
5 = 1 9 1 detect u%to 9 errors , correct 1 error
5 = 2 2 1 detect and correct u%to 2 errors
n eneral a code can
$etect u% to (d+in B1) errors,
Correct u% to NT
−
2
1+ind errors'
)
% = 10B2 =0'01
SXNCL N@ and C!ECGL
a)
Snc&roni"ation #its are not included in t&e error detection correction %rocedures, i'e' all snc #its are to #e receied error -ree -or sncL'
6ro#' o- Success-ul snc= 6ro# o- no errors in #its = %(0)
&ere %(0) = (1B%)S = (1B%) = (1B0'01)
6ro#' o- Success-ul snc = 0'227447
#)
Success-ul %acet trans-er re/uires success-ul snc and a correct %acet'
@or correct %acet, re/uire 24 #its *it& no errors, or 1 error (*&ic& can #e
corrected)'
6ro#' o- correct %acet = %(0) %(1)
= (1B%)24 124C %1 (1B%)24B1
= (0')24 24 (0'01) (0')29
= 0'781455
6ro#a#ilit o- success-ul %acet trans-er = 6ro#' o- success-ul snc and 6ro#'
o- correct %acet= %(succ' snc ) ' %(correct %acet)
= / %itsS= 2 %its
-
8/16/2019 EEE207 Tutorial Solutions.doc
39/42
= 0'227447 Y 0'781455
= 0'007991
6ro#a#ilit o- success-ul %acet trans-er = 0'007991
/)
TV sets, -ailure rate = 10B2
a)
50 TV sets %roduced, i'e N=50 , % = 10B2
6ro#a#ilit t&at all 50 are ood in t&e %ro#a#ilit o- no -ault ones, i'e'
6(0) = (1B%) N
6(0) = (1B10B2)50 = 0'805008
T&e %ro#a#ilit o- #ein a#le to delier an order -or 50 V sets i- onl 50 are+ade is onl 0'805 (80'5
-
8/16/2019 EEE207 Tutorial Solutions.doc
40/42
Communications
Module Code: EEE207
Tutorial No 8 Solutions
1) $iscussion &o* sinle %arit #it codes +a #e used -or error detection see
notes'
-
8/16/2019 EEE207 Tutorial Solutions.doc
41/42
2) $iscussion on re%etition codes +aUorit ote decodin and a%%lication to
error detectioncorrection see notes'
9) Messae, #its M 9 M 2 9 M 3 9 :9 M " 9 P trans-erred ia a c&annel *it& error
rate 1 = 10B2 = 0'01
a) n t&is case, success-ul trans-er occurs i- t&e ei&t #it +essae is
receied *it& no errors, i.e. =227448=5'0)1()0( =−== 1 P P s
#) @alse trans-er occurs i- errors are not detected, i.e. t&e +essae is
acce%ted, #ut it contains undetected errors' n t&is case, -or a sinle
%arit #it:
∑=
=+++=eve! R
7 R P P P P P P )()()8()4()2(
Since t&e %arit code cannot detect een errors, i.e. 2, 4, 8,
180
111928
8
7=44
4
9582
2
10)01'0()1()(
107442'21001'=2)1()8(
1072417207'810805=801'=70)1()4(
1089814441'210414'=2)1()2(
−
−−
−−
−−
===−=
×=××=−=
×=××=−=
×=××=−=
1 1 1C P
1 1C P
1 1C P
1 1C P
i.e. 9
108981889'2)( −
=
×== ∑eve! R
7 R P P
c) Messaes are lost or reUected i- errors are detected' n t&is case a %arit
code can detect all odd errors
)7()5()9()1()( P P P P R P P $dd R
L +++== ∑=
e could calculate t&ese as -or P 7 , #ut since
( ))()8()4()2()0(1)7()5()9()1(
1)()7()8()5()4()9()2()1()0(
P P P P P P P P P
P P P P P P P P P
++++−=+++
=++++++++
i.e. P L = 1 ( P S P 7 ) = 1 (0'2274485 2'898189×10B9)
P L = 0'074815
4)
a) @or a ;e%B5 code, *it& 1 = 0'1
9554
5429
1058'1010=5101'10
)1(5)1(10)5()4()9(
−−−− ×=+××+××=
+−+−=++=
UT
UT
P
1 1 1 1 1 P P P P
n t&is case, all +essaes are no* acce%ted, eit&er correct or -alse
-
8/16/2019 EEE207 Tutorial Solutions.doc
42/42
i.e. P S = P (0), %ro#a#ilit o- no errors in an ei&t #it +essae su#Uect to
an error rate P UT .
6ro#a#ilit o- success P S = P (0) = (1 P UT ) = 0'995980
#) 6ro#a#ilit o- -alse trans-er = P (1) P (2) P (9) Z P ()
.ut P s P 7 = 1, i.e. P 7 = 1 P S = 0'0884890