Diap. 1Prof. Fabrizio Camuso Divina proportione … Divina proportione … 1:a=a:b 0,618.
EE105 Fall 2007Lecture 20, Slide 1Prof. Liu, UC Berkeley Lecture 20 OUTLINE Review of MOSFET...
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Transcript of EE105 Fall 2007Lecture 20, Slide 1Prof. Liu, UC Berkeley Lecture 20 OUTLINE Review of MOSFET...
EE105 Fall 2007 Lecture 20, Slide 1 Prof. Liu, UC Berkeley
Lecture 20
OUTLINE• Review of MOSFET Amplifiers• MOSFET Cascode Stage• MOSFET Current Mirror
Reading: Chapter 9
ANNOUNCEMENTS• HW#11 is due in 2 weeks, on 11/20.• Review session: Fri. 11/9, 3-5PM in 306 Soda (HP Auditorium)• Midterm #2 (Thursday 11/15 in Sibley Auditorium):
• Material of Lectures 11-18 (HW# 7-10; Chapters 6,9,11)• 4 pgs of notes (double-sided, 8.5”×11”), calculator allowed
EE105 Fall 2007 Lecture 20, Slide 2 Prof. Liu, UC Berkeley
Review: MOSFET Amplifier Design• A MOSFET amplifier circuit should be designed to
1. ensure that the MOSFET operates in the saturation region, 2. allow the desired level of DC current to flow, and3. couple to a small-signal input source and to an output “load”.
Proper “DC biasing” is required!(DC analysis using large-signal MOSFET model)
• Key amplifier parameters: (AC analysis using small-signal MOSFET model)– Voltage gain Av vout/vin
– Input resistance Rin resistance seen between the input node and ground (with output terminal floating)
– Output resistance Rout resistance seen between the output node and ground (with input terminal grounded)
EE105 Fall 2007 Lecture 20, Slide 3 Prof. Liu, UC Berkeley
MOSFET Models• The large-signal model is used to determine the DC
operating point (VGS, VDS, ID) of the MOSFET.
• The small-signal model is used to determine how the output responds to an input signal.
EE105 Fall 2007 Lecture 20, Slide 4 Prof. Liu, UC Berkeley
Comparison of Amplifier TopologiesCommon Source
• Large Av < 0- degraded by RS
• Large Rin
– determined by biasing circuitry
• Rout RD
• ro decreases Av & Rout
but impedance seenlooking into the draincan be “boosted” by source degeneration
Common Gate
• Large Av > 0-degraded by RS
• Small Rin
- decreased by RS
• Rout RD
• ro decreases Av & Rout
but impedance seenlooking into the drain can be “boosted” by source degeneration
Source Follower
• 0 < Av ≤ 1
• Large Rin– determined by
biasing circuitry
• Small Rout
- decreased by RS
• ro decreases Av & Rout
EE105 Fall 2007 Lecture 20, Slide 5 Prof. Liu, UC Berkeley
Common Source Stage
Dout
in
Sm
D
Gv
RR
RRR
Rg
R
RRR
RRA
21
21
21
||
1||
||
0
0
SOmODout RrgrRR
EE105 Fall 2007 Lecture 20, Slide 6 Prof. Liu, UC Berkeley
Common Gate Stage
Dm
GmS
mSv Rg
RgR
gRA
/1||
/1||
Sm
in Rg
R1
Dout RR SOmODout RrgrRR
0
0
EE105 Fall 2007 Lecture 20, Slide 7 Prof. Liu, UC Berkeley
Source Follower
Sm
Sv
Rg
RA
1
Gin RR
Som
out
Gin
SOm
SOv
Rrg
R
RR
Rrg
RrA
||||1
||1
||
0 0
Sm
out Rg
R ||1
EE105 Fall 2007 Lecture 20, Slide 8 Prof. Liu, UC Berkeley
CS Stage Example 1• M1 is the amplifying device; M2 and M3 serve as the load.
1233
1233
1
||||||1
||||||1
OOOm
out
OOOm
mv
rrrg
R
rrrg
gA
Equivalent circuit for small-signal analysis, showing resistances connected to the drain
EE105 Fall 2007 Lecture 20, Slide 9 Prof. Liu, UC Berkeley
CS Stage Example 2• M1 is the amplifying device; M3 serves as a source (degeneration)
resistance; M2 serves as the load.
3
31
2
||11
O
mm
Ov
rgg
rA
Equivalent circuit for small-signal analysis
01
EE105 Fall 2007 Lecture 20, Slide 10 Prof. Liu, UC Berkeley
CS Stage vs. CG Stage• With the input signal applied at different locations, these circuits
behave differently, although they are identical in other aspects.
Sm
Ov
Rg
rA
2
1
1 12221 ||)1( OOSOmmv rrRrggA
Common source amplifier Common gate amplifier
02
01
EE105 Fall 2007 Lecture 20, Slide 11 Prof. Liu, UC Berkeley
Composite Stage Example 1• By replacing M1 and the current source with a Thevenin
equivalent circuit, and recognizing the right side as a CG stage, the voltage gain can be easily obtained.
12
11
mm
Dv
gg
RA
01 02
EE105 Fall 2007 Lecture 20, Slide 12 Prof. Liu, UC Berkeley
Composite Stage Example 2• This example shows that by probing different nodes in a circuit,
different output signals can be obtained.• Vout1 is a result of M1 acting as a source follower, whereas Vout2 is a
result of M1 acting as a CS stage with degeneration.
221
4332
||11
||||1
Omm
OOm
in
out
rgg
rrg
v
v
01
221
221
||11
||1
Omm
Om
in
out
rgg
rg
v
v
EE105 Fall 2007 Lecture 20, Slide 13 Prof. Liu, UC Berkeley
NMOS Cascode Stage
211
12111
OOmout
OOOmout
rrgR
rrrgR
• Unlike a BJT cascode, the output impedance is not limited by .
EE105 Fall 2007 Lecture 20, Slide 14 Prof. Liu, UC Berkeley
PMOS Cascode Stage
211
12111
OOmout
OOOmout
rrgR
rrrgR
EE105 Fall 2007 Lecture 20, Slide 15 Prof. Liu, UC Berkeley
Short-Circuit Transconductance• The short-circuit transconductance is a measure of the
strength of a circuit in converting an input voltage signal into an output current signal:
• The voltage gain of a linear circuit is(Rout is the output resistance of the circuit)
0
outvin
outm v
iG
outmv RGA
EE105 Fall 2007 Lecture 20, Slide 17 Prof. Liu, UC Berkeley
MOS Cascode Amplifier
2211
21221 )1(
OmOmv
OOOmmv
outmv
rgrgA
rrrggA
RGA
EE105 Fall 2007 Lecture 20, Slide 18 Prof. Liu, UC Berkeley
PMOS Cascode Current Source as Load• A large load impedance can be achieved by using a PMOS
cascode current source.
oPoNout
OOmoP
OOmoN
RRR
rrgR
rrgR
||433
122
EE105 Fall 2007 Lecture 20, Slide 19 Prof. Liu, UC Berkeley
MOS Current Mirror• The motivation behind a current mirror is to duplicate a
(scaled version of the) “golden current” to other locations.
Current mirror concept Generation of required VGS Current Mirror Circuitry
REF
REFcopy I
LW
LWI
/
/ 11 1
1/
2TH
oxn
REFX V
LWC
IV
2
2
1THX
REFoxnREF VV
L
WCI
2
11 2
1THXoxncopy VV
L
WCI
EE105 Fall 2007 Lecture 20, Slide 20 Prof. Liu, UC Berkeley
MOS Current Mirror – NOT!• This is not a current mirror, because the relationship between
VX and IREF is not clearly defined.
• The only way to clearly define VX with IREF is to use a diode-connected MOS since it provides square-law I-V relationship.
EE105 Fall 2007 Lecture 20, Slide 21 Prof. Liu, UC Berkeley
Example: Current Scaling • MOS current mirrors can be used to scale IREF up or down
– I1 = 0.2mA; I2 = 0.5mA
:0
EE105 Fall 2007 Lecture 20, Slide 22 Prof. Liu, UC Berkeley
Impact of Channel-Length Modulation
0
THTHXREF
oxn
satDGSTHXREF
oxnREF
VVVL
WC
VVVVL
WCI
12
1
12
1
2
,2
THGSDSTHXoxn
satDDSTHXoxncopy
VVVVVL
WC
VVVVL
WCI
12
1
,12
11
12
1
12
1
TH
GSDSREF
REFTH
THGSDSREF
REFcopy V
VVI
LW
LW
V
VVVI
LW
LWI
11
/
/
1
1
/
/ 11111