EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28...
Transcript of EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28...
![Page 1: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/1.jpg)
EE 230
Lecture 28
Nonlinear Circuits using Diodes– Rectifiers
– Precision Rectifiers
– Nonlinear function generators
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Quiz 18
If a diode has a value of IS=1E-14A and the diode voltage is .65V, what will be
the diode current if operating at T=300K?
Id=?
0.65V
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And the number is ?
1 3 8
4
6
7
5
2
9
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And the number is ?
1 3 8
4
6
7
5
2
93
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Quiz 18
If a diode has a value of IS=1E-14A and the diode voltage is .65V, what will be
the diode current if operating at T=300K?
Id=?
0.65V
1eII t
d
V
V
Sd
800uA8E1014-1Ee14-1EI 58.63E300
0.65
d
Solution:
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The Real Electronics World
Resistive
Networks
Passive Filters
(RLC Networks)
Active FiltersWaveform
Generators
Linear Circuits Nonlinear Circuits
Comparators
Nonlinear
Amplifiers
Linearized Nonlinear Circuits
(small signal model)
Sensor
Interfaces
Digital to Analog
Converters (DAC)Analog to Digital
Converters (ADC)
Amplifiers
(Dependent Sources)
Waveform
Generators
All Logic Circuits
MOSFET Diode BJT
Review from Last Time:
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The Diode
IDVD
Anode
Cathode n-type
p-type
Anode
Cathode
Review from Last Time:
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Types of Diodes
Vd
Id Id
Vd
Id
VdVd
Id
Vd
Id
Vd
Id
Vd
Id
Vd
Id
pn junction diodes
Metal-semiconductor junction diodes
Signal or
Rectifier
Pin or
Photo
Light Emitting
LED
Laser Diode
Zener Varactor or
Varicap
Schottky Barrier
Vd
Id
Review from Last Time:
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0
0
D D
D D
I 0 if V
V if I 0
“OFF”
“ON”
The Ideal Diode
ID
VD
I
ID VD
“ON” “OFF”
ID >0 VD ≤0Valid for
Review from Last Time:
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Diode equation (silicon pn junction diodes)
Diode Characteristics
0
0.002
0.004
0.006
0.008
0.01
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7
Vd (volts)
Id (
am
ps)
Widely Used Piecewise Linear Model
1eII t
d
V
V
Sd
Review from Last Time:
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A more accurate approximation to the diode equation
Diode Characteristics
0
0.002
0.004
0.006
0.008
0.01
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7
Vd (volts)
Id (
am
ps)
0I0.6VV
0.6VV0I
dd
dd
1eII t
d
V
V
Sd
More accurate pn junction
diode model:
Review from Last Time:
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0I0.6VV
0.6VV0I
dd
dd
1eII t
d
V
V
Sd
Piecewise Linear Model
Vd
Id0.6V
A
A
C
C
Off State
On State
Equivalent Circuit
Vd
Id
A C
A more accurate approximation to the diode equation
Review from Last Time:
![Page 13: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/13.jpg)
VIN R
ID
VD
VOUTI
Diode rectifier circuit
VIN
t
VOUT
t
If VIN=VMsinωt
Serves as a rectifier – very useful function !
Review from Last Time:
VOUT
VIN
1
1
Ideal Rectifier
Characteristics
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VIN R
Id
Vd
VOUT
Consider again the basic rectifier circuit
Analyze with piecewise linear modeld d
d d
I 0 V 0.6V
V 0.6V I 0Case 1 Id = 0
VIN R
Vd
VOUT
VOUT=0
valid for Vd≤0.6V
but Vd=VIN
valid for VIN≤0.6V
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VIN R
Id
Vd
VOUT
Consider again the basic rectifier circuit
Analyze with piecewise linear model
0I0.6VV
0.6VV0I
dd
dd
Case 2 Vd =0.6V
VIN R
IdVOUT
0.6V
VOUT=VIN - 0.6V
valid for Id > 0
but IN
d
V -0.6VI =
R
VIN>0.6Vvalid for
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Consider again the basic rectifier circuit
VIN R
Id
Vd
VOUT
Solution summary:
Analyze with piecewise linear model
IN
OUT
IN IN
0 V 0.6VV =
V -0.6V V >0.6V
0.6V
VOUT
VIN
1
1
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VIN R
ID
VD
VOUTI
Diode rectifier circuit
VOUT
VIN
Performance Limitations of Diode Rectifier Circuit
ID
VD
ID
VD
0.6V 0.6V
VOUT
VIN
1
1
shift in break point
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VIN R
ID
VD
VOUTI
Diode rectifier circuit
Performance Limitations of Diode Rectifier CircuitID
VD
0.6V
0.6V
VOUT
VIN
1
1
IN
OUT
IN IN
0 V 0.6VV =
V -0.6V V >0.6V
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VIN R
ID
VD
VOUTI
Diode rectifier circuit
Performance Limitations of Diode Rectifier CircuitID
VD
0.6V
IN
OUT
IN IN
0 V 0.6VV =
V -0.6V V >0.6V
Consider VIN=VMsinωt for VM=50V, VM=1V and VM=0.5V
VIN
t
VOUT
t
VM
VM
Desired output:
![Page 20: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/20.jpg)
VIN R
ID
VD
VOUTI
Performance Limitations of Diode Rectifier CircuitID
VD
0.6V
Consider VIN=VMsinωt for VM=50V, VM=1V and VM=0.5VVIN
t
VOUT
t
VM
VMDesired output:
VOUT
t
0.6V
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VIN R
ID
VD
VOUTI
Performance Limitations of Diode Rectifier CircuitID
VD
0.6V
Consider VIN=VMsinωt for VM=50V, VM=1V and VM=0.5V
VOUT
t
0.6V
If VM=50V, the 0.6V drop causes very little degradation in performance
If VM=1V, the 0.6V drop causes dramatic degradation in performance
VOUT
t
0.6V
Amplitude shift and duty cycle degradation
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VIN R
ID
VD
VOUTI
Performance Limitations of Diode Rectifier CircuitID
VD
0.6V
Consider VIN=VMsinωt for VM=50V, VM=1V and VM=0.5V
VOUT
t
0.6V
If VM=0.5V, the 0.6V drop provides no output !
VOUT
t
Actual
output
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Precision Rectifier Circuit
Case 1 D1 Conducting, Op Amp operating linearly
ID
VD
0.6V
D D
D D
I 0 V 0.6V
V 0.6V I 0
(with nonideal diode)
VIN
VOUTR VD
ID
VX
VOUT = VIN
Valid for ID>0 and VSATL<VX<VSATH
ID=VIN/R
ID > 0 when VIN>0
VX=VOUT+0.6V
VSATL-0.6 <VIN< VSATH - 0.6and
0 < VIN< VSATH - 0.6
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Precision Rectifier Circuit
Case 1 D1 Conducting, Op Amp operating linearly
ID
VD
0.6V
D D
D D
I 0 V 0.6V
V 0.6V I 0
(with nonideal diode)
VIN
VOUTR VD
ID
VX
VOUT = VIN 0 < VIN< VSATH - 0.6
VOUT
VIN
1
1
VSATH- 0.6
Case 1
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Precision Rectifier Circuit
Case 2 D1 Not Conducting, Op Amp saturated low
ID
VD
0.6V
D D
D D
I 0 V 0.6V
V 0.6V I 0
(with nonideal diode)
VIN
VOUTR VD
ID
VX
VOUT = 0
Valid for VD<0.6V and V+ < V-
VD=VX -0VIN<VOUT
and
(since no current flowing through R)
VX= VSATL
VSATL<0.6V VIN< 0
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Precision Rectifier Circuit
Case 2 D1 Not Conducting, Op Amp saturated low
ID
VD
0.6V
D D
D D
I 0 V 0.6V
V 0.6V I 0
(with nonideal diode)
VIN
VOUTR VD
ID
VX
VOUT = 0 VIN< 0valid for VOUT
VIN
1
1
VSATH- 0.6
Case 1
Case 2
VOUT
VIN
VSATH- 0.6
Case 2
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Precision Rectifier Circuit
ID
VD
0.6V
D D
D D
I 0 V 0.6V
V 0.6V I 0
(with nonideal diode)
VIN
VOUTR VD
ID
VX
VOUT
VIN
1
1
VSATH- 0.6
Case 1
Case 2
This is the transfer characteristics of an ideal rectifier!
Need a buffer on VOUT if any current is to be provided to a load !
Can be used to rectify very small signals !
![Page 28: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/28.jpg)
Consider this circuitVIN
VOUTR
VM
t
VIN
-VM
VIN
1
1
VOUT
VM
t
VIN
-VM
Following an almost identical
analysis, can show
This serves as a precision negative rectifier (not inverting rectifier)
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Consider this circuit
VINVOUT
R
R1 R2
VIN VOUT
R
R1 R1
Precision
Rectifier
![Page 30: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/30.jpg)
Consider this circuit
VOUT
VIN
11
1 1
VIN VOUT
R
R1 R1
Precision
Rectifier
VX
If VIN>0
VX=VIN so VOUT=VIN
If VIN<0
VX=0 so VOUT= -VIN
This is a precision full-wave rectifier(rectifies positive signals, inverts and rectifies negative signals)
![Page 31: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/31.jpg)
VM
t
VIN
-VM
VM
t
VX
-VM
VM
t
VOUT
-VM
Precision Full-Wave Rectifier
VIN VOUT
R
R1 R1
Precision
Rectifier
VX
VOUT
VIN
11
1 1
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Consider this circuit
4KVIN
1K
5K
VOUT
(assume diode is ideal)
If diode is OFF, VOUT=0
If diode is ON, VOUT= -10VIN
VIN
4
1
VOUT
• Serves as a two-segment function generator
• But no control of the first slope
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Consider this circuit
10K
VIN
+2V
-1V
1K
5K
2KVOUT
D1
D2
If VIN< -1V, D1 ON, D2 OFF
(assume diodes are ideal)
OUT IN
10K 10KV = V 1+ +2 -
1K//2K 1K
OUT INV = V 16 -20
If 2V >VIN > -1V, D1 ON, D2 ONOUT IN
10K 10K 10KV = V 1+ +2 - 1V -
1K//2K//5K 1K 5K
OUT INV = V 18 -18
If VIN > 2V, D1 OFF, D2 ONOUT IN
10K 10KV = V 1+ + 1V -
2K//5K 5K
OUT INV = V 8 +2
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Consider this circuit
10K
VIN
+2V
-1V
1K
5K
2KVOUT
D1
D2
(assume diodes are ideal)
IN IN
OUT IN IN
IN IN
16V -20 V <-1
V = 18V -18 -1<V <2
8V +2 V >2VIN
VOUT
m=18
m=16
m=8
-1
2
(not to scale)
This is a nonlinear function generator
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Nonlinear Function Generator
VOUT
RF
R1
R2
R-2
V1
V2
VIN
V-1
V-2
R0
R-1
D-2
D-1
D1
D2
(assume diodes are ideal)
Assume V2 > V1 > V-1 > V-2
• Provides a 5-segment nonlinear function generator
• Analysis straightforward but tedious
• Diode function generators like this can be used to convert a triangle wave to a
very good sine wave
• Performance actually usually better with actual diodes since transition between
regions is smoother
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Generalized Nonlinear Function Generator
VOUT
RF
RnVn
VIN
R0
Dn
Rn-1Vn-1 Dn-1
R-mV-m
R-m+1V-m+1
D-m
D-m+1
Dk OR
Assume Vn > Vn-1 >...V1 > 0 > V-1 >… > V-m
• Provides m+n+1 segment nonlinear function
• Slopes are always positive and greater than 1
• Can generate arbitrary nonlinear transfer characteristic
• Actually works better with nonideal diodes
• Can be extended to provide slopes less than 1
• Can be further extended to provide slopes of arbitrary sign and arbitrary magnitude
![Page 37: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/37.jpg)
Generalized Nonlinear Function Generator
Dk OR
• Provides m+n+r+s+2 segment nonlinear function
• Slopes can be positive or negative of any magnitude
• Analysis and design tedious but straight forward
VOUT1
RF
RsVs
R0
Ds
Rs-1Vs-1 Ds-1
R-rV-r
R-r+1V-r+1
D-r
D-r+1
VOUT
RF
RnVn
VIN
R0
Dn
Rn-1Vn-1 Dn-1
R-mV-m
R-m+1V-m+1
D-m
D-m+1
RX
θR
(1-θ)R
VIN
θR
(1-θ)R
^
^
^
^
^
^
^
^
^
^
^
^
![Page 38: EE 230 Lecture 28 - Iowa State Universityclass.ece.iastate.edu/ee230/lectures/EE 230 Lecture 28 Spring 2010.… · 1 3 4 6 7 5 2 9. Quiz 18 If a diode has a value of I S =1E-14A and](https://reader033.fdocuments.net/reader033/viewer/2022050507/5f985ffd84d21c49340fea33/html5/thumbnails/38.jpg)
End of Lecture 28