Dr Andrew French. October 2020. of a wire...electrodes lcm 10 15 20 25 30 35 40 45 50 55 60 65 70 75...

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Dr Andrew French. October 2020. TEACHER NOTES l R A =

Transcript of Dr Andrew French. October 2020. of a wire...electrodes lcm 10 15 20 25 30 35 40 45 50 55 60 65 70 75...

  • Dr Andrew French. October 2020.

    TEACHER NOTES

    lR

    A

    =

  • Equipment

    Digital calliper(for measuring wirediameter)

    Wooden mounting rigwith metre ruler attached

    Electrodes(with electrically insulated handles)

    2V DC power supply

    1.00m of steelwire stretchedbetween terminalsWire terminals

    Ammeter

    Voltmeter

  • Steel wire

  • Place the wire between the jaws of the digital calliper to measure the diameter.

    Don’t forget to zero the calliper (when closed) first!

    I measured: ( )0.29 0.1 mmd =

  • Measure the potential difference between afixed separation of wire. Using two electrodes connected to the voltmeter

    Note if you use a single electrode, you need to be careful about the contact resistance of therest of the circuit. So using two electrodes is preferable.

  • https://hypertextbook.com/facts/2006/UmranUgur.shtml

    https://hypertextbook.com/facts/2006/UmranUgur.shtml

  • Circuit schematic

    Steel wire of diameter d

    If we plot V vs d then we should get a straight line from the origin. From the gradient we can findthe resistivity .

  • ( )

    2

    23

    7

    4

    1.6105 1.6105

    0.29 10 1.6105

    4 0.1173

    9.07 10 Ωm

    V kl

    d k

    I

    V l k

    =

    =

    = =

    =

    =

    Which appears to be a plausible result