Dodge Nitro 4.0
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Projektni zadatak iz motora i motornih vozila
Transcript of Dodge Nitro 4.0
1
1. Proračun stalnih otpora1.1. Koef. otpora kotrljanja (f) za brzine 30, 60, 90, 120, 150, 180
f=fo (1+ V 2
20000¿
f 30= 0.01 (1+ 302
20000¿ = 0.0105
f 60= 0.01 (1+ 602
20000¿ = 0.01 (1+
360020000
)= 0.01 (1+0.18) = 0.01 = 0.01 ∙ 1.18 = 0.0118
f 90= 0.01 (1+ 902
20000¿ = 0.0140
f 120= 0.01 (1+ 1202
20000¿ = 0.0172
f 150= 0.01 (1+ 1502
20000¿ = 0.0212
f 180= 0.01 (1+ 1802
20000¿ = 0.0262
Tabela 1. – koeficijenti otpora kotrljanjaV(km/h) 30 60 90 120 150 180
f 0,0105 0,0118 0,0140 0,0172 0,0212 0,0262
1.2. Otpor kotrljanja (R f)R f=G ∙ f (N)G= m∙ g; G= 2000 ∙ 9.81G= 19620
R f 30= 19620 ∙ 0.0105= 206 NR f 60= 19620 ∙ 0.0105 = 231 NR f 90= 19620 ∙ 0.0105 = 274 NR f 120= 19620 ∙ 0.0105 = 337 NR f 150= 19620 ∙ 0.0105 =415 NR f 180= 19620 ∙ 0.0105 = 514 N
1.3. Otpor vazduha R v
R v30= 3.38 ∙ 0.30 ∙ 1.25 ∙ 302
26 = 44 N
R v60= 3.38 ∙ 0.30 ∙ 1.25 ∙ 602
26 = 175 N
R v = A∙ C x ∙ ρ ∙ V2
26 (N)
2
R v90= 3.38 ∙ 0.30 ∙ 1.25 ∙ 902
26 = 395 N
R v120= 3.38 ∙ 0.30 ∙ 1.25 ∙ 1202
26 = 702 N
R v150= 3.38 ∙ 0.30 ∙ 1.25 ∙ 1502
26 = 1097 N
R v180= 3.38 ∙ 0.30 ∙ 1.25 ∙ 1802
26 = 1579 N
1.4. Fiktivna vucna sila (F v) za brzine 30, 60, 90, 120, 150, 180gde je: P(W), a v (m/s)
F v 30= 520008.33
= 6242.496N
F v 60= 5200016.6
= 3132.530 N
F v 90= 5200025
= 2080 N
F v 120= 5200033.333
= 1560.015 N
F v 150= 5200041.666
= 1248.019 N
F v 180= 5200050
= 1040 N
Tabela 2. Otpori i vučna silaV(km/h) 30 60 90 120 150 180
Rf(N) 206 231 274 337 415 360Rv(N) 44 175 395 702 1097 1579
Rv + Rf(N) 250 406 699 1039 1512 1939Fv(N) 6242.496 3132.530 2080 1560.015 1248.019 1040
2. Spoljašnja brzinska karakteristika:2.1. Snaga motora – Lajdermanov obrazac
P=Pmax [C1(nnn
)+C2(nnn
)2
-1 (nnn
)3
] (Kw)C1=C2=1
P1=157 [1(10005200
)+1( 10005200
)2
-1 ( 10005200
)3
]= 0.1923 + 0.0369 - 0.00711 = 157 ∙0.222 = 34.8 Kw
P2=157 [1(20005200
)+1( 20005200
)2
-1 ( 20005200
)3
]=0.384 + 0.147 – 0.0568= 157 ∙ 0.474 = 74.4 Kw
P3=157 [1(30005200
)+1( 30005200
)2
-1 ( 30005200
)3
]= 112.4 Kw
F v=PV (N)
3
P4=157 [1(40005200
)+1( 40005200
)2
-1 ( 40005200
)3
]= 142 Kw
P5=157 [1(50005200
)+1( 50005200
)2
-1 ( 50005200
)3
]= 156.5 Kw
P6=157 [1(60005200
)+1( 60005200
)2
-1 ( 60005200
)3
]= 148.8 Kw
2.2. Obrtni moment motora:
M o= 9554∙ Pnn
(Nm)
M o1= 9554∙ 34,81000
(Nm) = 9554 ∙ 0.0348 = 332,4
M o2= 9554∙ 74.41000
(Nm) = 9554 ∙ 0.0372 = 355.4 Nm
M o3= 9554∙ 112.41000
(Nm) = 9554 ∙ 0.0374 = 357.4
M o4= 9554∙ 1421000
(Nm) = 9554 ∙ 0.0355 = 339.1
M o5= 9554∙ 156.51000
(Nm) = 9554 ∙ 0.0313 = 299
M o6= 9554∙ 148.81000
(Nm) = 9554 ∙ 0.0248 = 236.9
M o7= 9554∙ 112.81000
(Nm) = 9554 ∙ 0.0161 = 153.9
Tabela 3. Snaga i obrtni momentn(o/min) 1000 2000 3000 4000 5000 6000 7000
P(kW) 34.8 74.4 112.4 142 156.5 148.8 112.8Mo(Nm) 332.4 355.4 357.4 339.1 299 236.9 153.9
3. Bilans vuce
Fo= M o ∙ iM ∙ ig ∙ ηTrD
(N)
3.1.1. Obimna sila na tockovima u prvom stepenu prenosa
FoI1=¿ 332,4 ∙3.73 ∙3.73∙0.9
0.45 = 9249.2N
FoI2=¿ 355.4 ∙3.73 ∙3.73∙0.9
0.45 = 9889.2N
FoI3=¿ 357.4 ∙3.73 ∙3.73∙0.9
0.45 = 9944.9N
FoI 4=¿ 339.1 ∙3.73 ∙3.73∙0.9
0.45 =9435.7N
FoI5=¿ 299 ∙3.73 ∙3.73∙0.9
0.45 =8319.9N
FoI6=¿ 236.9 ∙3.73 ∙3.73∙0.9
0.45 =6591.9N
4
FoI7=¿ 159.9 ∙3.73 ∙3.73∙0.9
0.45 =4449.3N
3.2. Obimna sila na tockovima u drugom stepenu prenosa
FoII1=¿ 332.4 ∙2.84 ∙3.73 ∙0.9
0.45 = 7042.3N
FoII2=¿ 355.4 ∙2.84 ∙3.73 ∙0.9
0.45 = 7529.6 N
FoII3=¿ 357.4 ∙2.84 ∙3.73 ∙0.9
0.45 = 7572.01N
FoII 4=¿ 339.1 ∙2.84 ∙3.73 ∙0.9
0.45 = 7184.3N
FoII5=¿ 299 ∙2.84 ∙3.73 ∙0.9
0.45 = 6334.7N
FoII 6=¿ 236.9 ∙2.84 ∙3.73 ∙0.9
0.45 = 5019.05N
FoII7=¿ 159.9 ∙2.84 ∙3.73 ∙0.9
0.45 = 3387.7N
3.3. Obimna sila na tockovima u trecem stepenu prenosa
FoIII 1=¿ 332.4 ∙1.57 ∙3.73 ∙0.9
0.45 = 3893.1N
FoIII 2=¿ 355.4 ∙1.57 ∙3.73 ∙0.9
0.45 = 4162.5N
FoIII 3=¿ 357.4 ∙1.57 ∙3.73 ∙0.9
0.45 = 4185.9N
FoIII 4=¿ 339.1 ∙1.57 ∙3.73 ∙0.9
0.45 = 3971.6N
FoIII 5=¿ 299 ∙1.57 ∙3.73 ∙0.9
0.45 = 3501.9N
FoIII 6=¿ 236.9 ∙1.57 ∙3.73 ∙0.9
0.45 = 2774.6N
FoIII 7=¿ 159.9 ∙1.57 ∙3.73 ∙0.9
0.45 = 1872.7N
3.4. Obimna sila na tockovima u cetvrtom stepenu prenosa
FoIV 1=¿ 332.4 ∙1.00 ∙3.73∙0.9
0.45 = 2479.7N
FoIV 2=¿ 355.4 ∙1.00 ∙3.73∙0.9
0.45 = 2651.2N
FoIV 3=¿ 357.4 ∙1.00 ∙3.73∙0.9
0.45 = 2666.2N
FoIV 4=¿ 339.1 ∙1.00 ∙3.73∙0.9
0.45 = 2529.6N
FoIV 5=¿ 299 ∙1.00 ∙3.73∙0.9
0.45 = 2230.5N
FoIV 6=¿ 236.9 ∙1.00 ∙3.73∙0.9
0.45 = 1767.2N
5
FoIV 7=¿ 159.9 ∙1.00 ∙3.73∙0.9
0.45 = 1192.8N
3.5. Obimna sila na tockovima u petom stepenu prenosa
FoV1=¿ 332.4 ∙0.69 ∙3.73 ∙0.9
0.45 = 1710.9N
FoV 2=¿ 355.4 ∙0.69 ∙3.73 ∙0.9
0.45 = 1829.3N
FoV3=¿ 357.4 ∙0.69 ∙3.73 ∙0.9
0.45 = 1839.6N
FoV 4=¿ 339.1 ∙0.69 ∙3.73 ∙0.9
0.45 = 1745.4N
FoV5=¿ 299 ∙0.69 ∙3.73 ∙0.9
0.45 = 1539.07N
FoV 6=¿ 236.9 ∙10.69 ∙3.73∙0.9
0.45 = 1219.4N
FoV7=¿ 159.9 ∙0.69 ∙3.73 ∙0.9
0.45 = 823.06N
3.6. Brzina vozila u prvom stepenu prenosa
V = 0.37 rDiM ∙ ig
∙ nM (km/h)
V I1= 0.37 0.45
3.73∙3.73∙1000 = 11.9
V I2= 0.37 0.45
3.73∙3.73∙2000 = 23.9
V I3= 0.37 0.45
3.73∙3.73∙3000 = 35.9
V I 4= 0.37 0.45
3.73∙3.73∙4000 = 47.8
V I5= 0.37 0.45
3.73∙3.73∙5000 = 59.8
V I6= 0.37 0.45
3.73∙3.73∙6000 = 71.8
V I7= 0.37 0.45
3.73∙3.73∙7000 = 83.7
3.6. Brzina vozila u drugom stepenu prenosa
V II1= 0.37 0.45
2.84 ∙3.73∙1000 = 15.7
V II 2= 0.37 0.45
2.84 ∙3.73∙2000 = 31.4
V II 3= 0.37 0.45
2.84 ∙3.73∙3000 = 47.1
V II 4= 0.37 0.45
2.84 ∙3.73∙4000 = 62.8
6
V II5= 0.37 0.45
2.84 ∙3.73∙5000 = 78.5
V II 6= 0.37 0.45
2.84 ∙3.73∙6000 = 94.3
V II7= 0.37 0.45
2.84 ∙3.73∙7000 = 110.02
3.6. Brzina vozila u trecem stepenu prenosa
V III1= 0.37 0.45
1.57 ∙3.73∙1000 = 28.4
V III 2= 0.37 0.45
1.57 ∙3.73∙2000 = 56.8
V III3= 0.37 0.45
1.57 ∙3.73∙3000 = 85.2
V III4= 0.37 0.45
1.57 ∙3.73∙4000 = 113.7
V III 5= 0.37 0.45
1.57 ∙3.73∙5000 = 142.1
V III 6= 0.37 0.45
1.57 ∙3.73∙6000 = 170.5
V III7= 0.37 0.45
1.57 ∙3.73∙7000 = 199.02
3.6. Brzina vozila u cetvrtom stepenu prenosa
V IV 1= 0.37 0.45
1.00∙3.73∙1000 = 44.6
V IV 2= 0.37 0.45
1.00∙3.73∙2000 = 89.2
V IV 3= 0.37 0.45
1.00∙3.73∙3000 = 133.9
V IV 4= 0.37 0.45
1.00∙3.73∙4000 = 178.5
V IV 5= 0.37 0.45
1.00∙3.73∙5000 = 223.1
V IV 6= 0.37 0.45
1.00∙3.73∙6000 = 267.8
V IV 7= 0.37 0.45
1.00∙3.73∙7000 = 312.4
3.6. Brzina vozila u petom stepenu prenosa
V V 1= 0.37 0.45
0.69 ∙3.73∙1000 = 64.6
V V 2= 0.37 0.45
0.69 ∙3.73∙2000 = 129.3
V V 3= 0.37 0.45
3.73∙3.73∙3000 = 194.07
7
V V 4= 0.37 0.45
0.69 ∙3.73∙4000 = 258.7
V V 5= 0.37 0.45
0.69 ∙3.73∙5000 = 323.4
V V 6= 0.37 0.45
0.69 ∙3.73∙6000 = 388.1
V V 7= 0.37 0.45
0.69 ∙3.73∙7000 = 452.8
Tabela 4. Obimna sila i brzina vozilan 1000 2000 3000 4000 5000 6000 7000FoI 9249.2 9889.2 9944.9 9435.7N 8319.9 6591.9 4449.3
V I 11.9 23.9 35.9 47.8 59.8 71.8 83.7
FoII 7042.3 7529.6 7572.01 7184.3 6334.7 5019.05 3387.7
V II 15.7 31.4 47.1 62.8 78.5 94.3 110.02
FoIII 3893.1 4162.5 4185.9 3971.6 3501.9 2774.6 1872.7
V III 28.4 56.8 85.2 113.7 142.1 170.5 199.02
FoIV 2479.7 2651.2 2666.2 2529.6 2230.5 1767.2 1192.8
V IV 44.6 89.2 133.9 178.5 223.1 267.8 312.4
FoV 1710.9 1829.3 1839.6 1745.4 1539.07 1219.4 823.06
V V 64.6 129.3 194.07 258.7 323.4 388.1 452.8
4. Dinamicki faktor
D=Fo−¿RV
G¿
R v=C x ∙ A ∙ ρ ∙V 2
26(n)
4.1. Dinamicki faktor u prvom stepenu prenosa
8
R vI1=0.30 ∙3.38 ∙1.25 ∙11.92
26= 6.903
D I1 = 9249.2−6.903
19620 = 0.471
R vI 2=0.30 ∙3.38∙1.25 ∙23.92
26= 27.846
D I2 = 9249.2−27.846
19620 = 0.469
R vI 3=0.30 ∙3.38 ∙1.25 ∙35.92
26= 62.829
D I3 = 9249.2−62.829
19620 = 0.468
R vI 4=0.30 ∙3.38∙1.25 ∙47.82
26= 111.38
D I 4 = 9249.2−111.38
19620 = 0.465
R vI5=0.30 ∙3.38∙1.25 ∙59.82
26= 174.331
D I5 = 9249.2−174.331
19620 = 0.462
R vI 6=0.30 ∙3.38 ∙1.25 ∙71.82
26= 251.317
D I6 = 9249.2−251.317
19620 = 0.458
R vI7=0.30 ∙3.38 ∙1.25 ∙83.72
26= 341.527
D I7 = 9249.2−341.527
19620 = 0.454
4.2. Dinamicki faktor u drugom stepenu prenosa
R vI1=0.30 ∙3.38 ∙1.25 ∙15.72
26= 12.016
D I1 = 9249.2−12.016
19620 = 0.470
R vI 2=0.30 ∙3.38∙1.25 ∙31.42
26= 48.065
9
D I2 = 9249.2−48.065
19620 = 0.468
R vI 3=0.30 ∙3.38 ∙1.25 ∙47.12
26= 108.147
D I3 = 9249.2−108.147
19620 = 0.465
R vI 4=0.30 ∙3.38∙1.25 ∙62.82
26= 192.262
D I 4 = 9249.2−192.262
19620 = 0.461
R vI5=0.30 ∙3.38∙1.25 ∙78.52
26= 300.409
D I5 = 9249.2−300.409
19620 = 0.456
R vI 6=0.30 ∙3.38 ∙1.25 ∙94.32
26= 433.508
D I6 = 9249.2−433.508
19620 = 0.449
R vI7=0.30 ∙3.38 ∙1.25 ∙110.022
26= 590.089
D I7 = 9249.2−590.089
19620 = 0.441
