Do Now: If y = 2sin 2x, fill in the table below Aim: How do we sketch y = A(sin Bx) and y = A(cos...
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Transcript of Do Now: If y = 2sin 2x, fill in the table below Aim: How do we sketch y = A(sin Bx) and y = A(cos...
Do Now: If y = 2sin 2x, fill in the table below
xy
0 4
4
32
4
52
34
7
Aim: How do we sketch y = A(sin Bx) and y = A(cos Bx)?
2
0 2 0 2 0 2 0 02
HW: Handout
Math Composer 1. 1. 5http: / / www. mathcomposer. com
2 74 3
2 5
4 1 3
4 1
2 1
4 1
4 1
2 3
4 1 5
4 3
2 7
4 2
-2.5
-2.0
-1.5
-1.0
-0.5
0.5
1.0
1.5
2.0
2.5
x
y
Math Composer 1. 1. 5http: / / www. mathcomposer. com
Math Composer 1. 1. 5http: / / www. mathcomposer. com
y = 2sin2x
When we multiply x, the measure of the angle, by some value, B, we change the frequency of the curve.
Frequency: The number of complete curves in every 2π radians.
In the form of BxAy sin
This means we have more “complete” curves in the interval 0 2 x
So the frequency of y = sin 2x is 2
BxAy sin or BxAy cos
A implies the amplitude
To find the amplitude of sine or cosine function, we simply take absolute value of A ( )A
We only use positive number for amplitude. For example: the amplitude of y = 2 sin x and y = –2 sin x are both 2
2B
the amplitude of y = ½ sin x and y = -1/2 sin x are both ½
The rule to find the period is
In
For y = sin x, the frequency is 1 since the value of B is 1, and the period is 2. That means there is only one complete curve within 2 radians also means to have a complete curve, the angle measure is 2 radians.
xy2
1cos
The amplitude is 1 and the period is
4
21
2
xy2
3sin2
The amplitude is 2 and the period is 3
4
23
2
Determining the Period and Amplitude of y = a sin bx
Given the function y = 3sin 4x, determine the period and the amplitude.
The period of the function is2b
Therefore, the period is24
2
The amplitude of the function is | a |. Therefore, the amplitude is 3.
y = 3sin 4x
Writing the Equation of the Periodic Function
| maximum minimum|2
Amplitude
| 2 ( 2) |
2= 2
Period 2b
2b
b = 2
Therefore, the equation as a function of sine isy = 2sin 2x.
Writing the Equation of the Periodic Function
| maximum minimum|2
Amplitude Period 2b
| 3 ( 3) |2
= 3
4 2b
b = 0.5
Therefore, the equation as a function of cosine isy = 3cos 0.5x.
xy2
1cos3 0 4 x a) Sketch the graph of , over
xy2
1cos
b) Find the value(s) of x in the interval so that the
value of
(1) a maximum (2) a minimum (3) 0
Find the amplitude and period for the following functions:
xy3
1sin3
xy 3cos2
1
xy4
1sin4
a)
c)
b)