Do an Chi Tiet1234

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SVTH: NGUYỄN ĐÌNH TRUNG GVHD: TRẦN ĐẠI HIẾU NHẬN XÉT CỦA GIÁO VIÊN HƯỚNG DẪN Về nội dung đồ án: ............................................................................................................................ ............................................................................................................................ ............................................................................................................................ ............................................................................................................................ ............................................................................................................................ Về trình bày hình thức ............................................................................................................................ ............................................................................................................................ ............................................................................................................................ ............................................................................................................................ Về thái độ ............................................................................................................................ ............................................................................................................................ ............................................................................................................................ ............................................................................................................................ Điểm đánh giá: Sinh viên thực hiện : Giáo viên hướng dẫn: NGUYỄN ĐÌNH TRUNG TRẦN ĐẠI HIẾU 1 ĐỒ ÁN CHI TIẾT MÁY

Transcript of Do an Chi Tiet1234

SVTH: NGUYN NH TRUNG GVHD: TRN I HIU

SVTH: NGUYN NH TRUNG GVHD: TRN I HIU

NHN XT CA GIO VIN HNG DN V ni dung n:V trnh by hnh thcV thi im nh gi:Sinh vin thc hin : Gio vin hng dn: NGUYN NH TRUNG TRN I HIU

Li ni u:Thit k v pht trin h thng truyn ng l vn ct li trong ngnh c kh. Mt khc mt nn cng nghip pht trin mnh m khng th thiu mt nn c kh pht trin. v vy vic thit k v ci tin ti u cc h thng truyn ng l cng vic rt quan trng v thng xuyn. n thit k hp gim tc gip chng ta tm hiu v thit k c mt hp gim tc. qua ta c th cng c li kin thc vi mt s mn hc c s nghnh nh: nguyn l my, chi tit my, dung sai lp ghp v k thut o lng, sc bn vt liu, c l thuyt v v k thut. gip sinh vin c ci nhn tng quan v vc thit k trong c kh. Hp gim tc l mt trong nhng b phn in hnh gip chng ta l quen bc u vi vic thit k bnh rng, trc , v chn c ln thch hp. thm vo l gip sinh vin hon thin kh nng v auto cad. n thit k nay ch mi dng li dai on thit k, cha thc s ti u v thit k c kh cha mang tnh kinh t v cng ngh cao v trnh gii hn ca ngi thit k.Em xin trn thnh cm n thy :TRN I HIU hng dn em hon thnh n ny, cng cc bn v thy c gip v to iu kin tt cho em thc hn n ny,Vi kin thc cn hn hp ca mt sinh vin km theo vic y l n u tin nn khng th trnh khi nhng sai st. Em mong nhn c nhng kin ng gp ca quthy c v cc bnSinh vin thc hin: NGUYN NH TRUNG

BNG THUYT MINH N CHI TT MY HP GIM TC HAI TC

PHN 1: CHN NG C V PHN PHI T S TRUYNI. Chn ng cXc nh cng sut yu cu trn trc ng cGi l cng sut cn thit trn trc ca my cng tc (kw) F = 2500 N V = 0.62 = = 1,55 (kw)c - h/s chung ca b truyn.1 - h/s ca cp bnh rng nn.2 - h/s ca cp bnh tr rng thng.3 - h/s ca mt cp trc.c = 1.2.34.Vi iu kin lm vic nh nu ta tin hnh che kn cho cc b truyn ngoi, b truyn trong tt nhin c che kn.Chn 1 = 0,95 2 = 0,96 3 = 0,97 4 =0,99c = 1.2.34. c = 0, 95. 0,97.(0,97)4 = 0,85 Gi l cng sut cn thit trn trc ng c.c = kw Cn c vo cng sut cn thit iu kin lm vic. Chn ng c m hiu: A02-32-4.Cng sut ng c: kw. S vng quay = 1420 vng/pht.1.2.: Cch phn phi t s truyn Tc quay ca my cng tc = [v (m/s)D (mm) ]. Thay s = = 39,5 (vg/ph). T s truyn c tnh theo cng thc sau: = Vi s vng quay trc vo HGT. s vng quay trc ra HGT. t s truyn chung ca HGT.T s truyn ca HGT cng c tnh theo cng thc : (2) m bo iu kin bi trn cc b truyn bnh rang trong HGT bng phng php ngm du ta chn Ly thay vo (2) ta c

1.2 Cng sut, s vng quay v momen xon trn cc trc :Cng sut truyn ng: P = 1,55kwTra bng 2-1 sch thit k chi tit my ta c :

: hiu sut truyn ng ca bnh rng.

: hiu sut truyn ng ca ln.

:hiu sut khp ni.1.2.1: Trc I:

=1,55.0,99.0,98.1=1,5(kw)1.2.2: Trc II:

=1,5.0,99.0,982=1,43 (kw).1.2.3: Trc III:

=1,43.0,99.0,982 =1,36(kw).S vng quay trn cc trc nh sau:- S vng quay ca ng c l nc = 1420 (v/ph)- S vng quay trn trc I : nI = 1420/1 = 1420- S vng quay tren trc II : nII = / = 1420/5,36= 265 (v/ph)- S vng quay trn trc III:nIII = nII / ibn =265/6,7 = 40 (v/ph)1.3: Momen xon cng thc 3.53 trang 53 sch Thit k chi tit my(TKCTM).Trc I: 10088,03Trc II Trc III

Bng thng s:

Thng s/trc Trc ng c Trc I Trc II Trc III

T s truyn iIkn = 1Ibn = 6,7Ibc = 5,36

S vng quay n(v/ph)1420142026540

Cng sut P(kW) 1,551,51,431,36

Momen M(N.mm) 10424,3010088.0351533,96324700

PHN II: THIT K B TRUYN BNH RNGChng: I.Thit k b truyn bnh rng tr thng cp nhanh.Ta c s liu sau:Cng sut:P1=1,5(kw)S vng quay trong mt pht ca trc dn n1=1420(v/p) v trc b dn n2=265(v/p).Yu cu lm vic trong 5 nm. Mi nm lm vic 250 ngy v mi ngy lm 8 gi. Ti trng rung ng nh.

2.1.1. Chn vt liu:a. bnh nh: (chn thp 45 thng ho, gi s ng knh k = ktt. K = 1.1,2 = 1,2do v tr s k chnh ch t so vi d on nn ta khng tnh li khong cch trc A ta p dng cng thc: =111 mm Ly A=111 mm.

2.1.8.xc nh modum ,s rng v chiu rng bnh rng:Modum: Ly m = 2S rng bnh nh rngLy Z1 = 14 rng.S rng bnh ln:rngLy Z2 = 94 rng.Chiu rng bnh rng Ly b = 35mm.2.1.9.Kim nghim bn un ca rng.Theo bng (3-16) Trong : m = 2 l moum n l s vng quay trc I. N l cng sut b truyn trc I.Z l s rng bnh nh.Y l h s dng rng.m l mum.K= 1,4 h s trong ti.b l b rng.

Ly h s Tra bng 3-18 trang 52 sch TKCTM ta c h s dng rng bnh nh. h s dng rng bnh ln n = 1420 v/ph.ng sut un ti chn rng:Bnh nh : Bnh ln : vt liu tha mn yu cu vt liu tha mn yu cu2.1.10.Cc thng s hnh hc Modum m = 2S rng Z1 =14,Z2 =94Gc n khp ng knh vng chia Khong cch trc ng knh vng nh rng

ng knh vng chn rng :

2.1.11.Lc tc dng ln trc:Lc vng Lc hng tm: Bng thng s hnh hc ca b truyn bnh rng tr rng thng cp nhanhThng sK hiuCch xc nh Tr sn v

Modum m 2mm

S rng bnh nhZ114Rng

S rng bnh lnZ294Rng

Gc n khpTra bng20

ng knh vng ln28Mm

188Mm

Khong cch trc A108Mm

Chiu rng bnh rngB33,3Mm

ng knh vng nh rngDe132Mm

De2 192 Mm

ng knh vng chn rngDi123Mm

Di2183Mm

Chng II. Thit k b truyn bnh rng cp chm: 2.2.1. Chn vt liu:a. bnh nh: (chn thp 45 thng ho, gi s ng knh Ly A = 225 mm2.2.6.tnh vn tc vng v chn cp chnh xc ch to bnh rng: Vi v = 0,15m/s Theo bng (3-11) trang 46 sch TKCTM ta chn cp chnh xc l 9.2.2.7.nh chnh xc ti trng K v khong cch trc A:H s ti trng k c tnh theo cng thc : k = ktt.kTrong : ktt l h s tp trung ti trng: V ti trng khng i rn ca bnh rng HB < 350 nn ly ktt=1K l h s ti trng ng.Theo bng (3-14) trang 48 sch TKCTM chn k = 1,2=>k = ktt. K = 1.1,2 = 1,2do v tr s k chnh ch t so vi d on nn ta khng tnh li khong cch trc A ta p dng cng thc: =225 mm Ly A= 225 mm.

2.2.8.xc nh modum ,s rng v chiu rng bnh rng:Modum: 4,5)Ly m = 3 mmS rng bnh nh Ly Z1 = 24 rng.S rng bnh ln: RngLy Z2=129 rngChiu rng bnh rng 67,5 mmLy b =68mm.2.2.9.Kim nghim bn un ca rng.Theo bng (3-16) Trong k l h s ti trng.P = 1,36 cng sut trc dn.Tnh s rng tng ng bnh nh : ZTD1=Z1=24 rngTnh s rng tng ng ca bnh ln: ZTD2=Z2=129 rngm = 3.Tra bng 3-18 ta c h s dng rng bnh nh. h s dng rng bnh ln n = 40 v/ph.ng sut un ti chn rng:Bnh nh : Bnh ln : vt liu tha mn yu cu vt liu tha mn yu cu2.2.10.Cc thng s hnh hc.Modum m = 3S rng Z1 =24,Z2 =129Gc n khp ng knh vng chia Khong cch trc ng knh vng nh rng

ng knh vng chn rng :

2.2.11.Lc tc dng ln trc:Lc vng Lc hng tm:

Bng thng s hnh hc ca b truyn bnh rng tr rng thng cp nhanhThng sK hiuCch xc nhTr sn v

Modum3mm

S rng bnh nhZ124rng

S rng bnh lnZ2129rng

Gc n khpTra bng20

ng knh vng ln72mm

387mm

Khong cch trcA 229,5mm

Chiu rng bnh rngB68mm

ng knh vng nh rngDe178mm

De2393mm

ng knh vng chn rngDi164,5mm

Di2379,5mm

Phn III Thit k trc v thenChngI Thit k trc3.1.1.:Chn vt liu ch to Cc trc thp 45 c b=600(N.mm2) , ng sut cho php l:[]= 1220(N.mm2)3.1.2.:Xc nh ng knh s bdk= Trong Tk momen xon N.mm, [] ng sut xon cho php MPA []=1550.ly tr s nh i vi truc vo ca hp gim tc,tr s ln trc ra theo kt qu:3.1.3. Tnh dng knh s b ca cc trcTheo cng thc (7-2) sch thit k chi tit my trang 114 ta c:dC. trong : d: ng knh trc n:s vng quay trong mt pht ca trc P:cng sut C:h s ph thuc ng sut xon cho php,C=120 3.1.3.1.: i vi trc 1P1=3,8808(kw), C=120, n1=1450(v/ph)Suy ra : d1120. .ly d1=17( mm)3.1.3.2.: i vi trc 2P2=3,68(kw), C=120, n2=372(v/ph)Suy ra: d2120. ly d2=26(mm)3.1.3.3.: i vi trc 3P3=3,5(kw),C=120,n3=120(v/ph)Suy ra: d3120. ly d3=37(mm)+ chun b cho bc tnh gn ng trong 3 tr s trn ta c th ly tr s d2=26mm chn loi bi c trung bnh theo bng 14P trang 337 ta c chiu rng ca bi l: B=19 (mm)Chng II. Tnh gn ng trc:- tnh kch thc chiu di ca trc ta c th tham kho, bng 7-1 sch thit k chi tit mytrang 118 v hnh 3-1ta chn kch thc:+Khe h gia cc bnh rng l c= 10mm+Khe h gia bnh rng v thnh trong ca hp l =10mm +Khong cch t thnh trong ca hp n mt bn ln l:a= 10mm -S d ly nh vy l v sau ny ta cn thit k bc chn du m, v khng th dng phng php bi trn bng cch bn to du m do vn tc b truyn nh.+chiu rng : B=19(mm)Chiu rng bnh rng cp nhanh bn= 40mmChiu rng bnh rng cp chm bc = 60mmTng kch thc trn ta tm c chiu di cc on trc

Hnh 3-1Tng cc kch thc trn ta tm c chiu di cc on trc cn thit v khong cch gia cc gi (hnh 3-1)

Pr1I Pa1 P1Pa2 Pr2 P Pr3II P3 Pa4 Pa3 P4 Pr4 III

3.2.1 Thit k trc I:Xc nh phn lc hai gi A v B:Ta c: a=59,5mm;b=60mm;c=49,5mmd=17mm

Ta c :

Tnh momen un ti tit din nguy him n-n:Ta c

ng knh trc ti tit din nguy him n-n: theo cng thc 7-4 trang 117 TKCTM ta c

V vt liu l thp C45 theo bng 7-2 ta c

V trc c lm rnh then nn ng knh trc tng ln so vi tnh ton , ly ng knh ch lp bnh rng d1= 22mm, ch lp ln

3.2.2 Thit k trc IIXc nh phn lc hai gi C v D:Ta c: Lc vng Lc hng tm Lc vng Lc hng tm Ta c :

Tnh momen un ti tit din nguy him e-e:Ta c

Ti tit din i-i:

ng knh trc ti tit din nguy him e-e: theo cng thc 7-4 trang 117 TKCTM ta c

V vt liu l thp C45 theo bng 7-2 ta c

V trc c lm rnh then nn ng knh trc tng ln so vi tnh ton , ly ng knh ch lp bnh rng d1= 47mm, ch lp ln

2.2.3 Thit k trc III:Lc vng Lc hng tm Momen xon Tnh phn lc ti E v F

Tnh momen un ti tit din n-n:Ta c

ng knh trc ti tit din nguy him n-n:

Vi

V trc c rnh then nn ta ly ng knh trc ln hn so vi tnh ton m bo iu kin bn,ng knh ln

RfyMuyMuxYXZOPr4ac+bPa4P4RexRfx736466268049278541

PHN IV :TNH CHNH XC TRC

4.1 Kim nghim sc bn trc I:Theo cng thc (7-5) trang 120 TKCTM

V trc quay nn ng sut thay i theo chu k i xng

V b truyn lm vic mt chiu nn ng sut tip thay i theo chu k mch ng.

Gii hn mi un v mi xon:

Trong l gii hn bn ca vt liu thp 45 theo bng (7-3b) trang 122 v bng 7-23 trang 143 sch thit k chi tit my ng vi ng knh trc d1=21mm ta c Chiu rng then b=6, chiu cao then h=6.W=1855 (mm3) Mu=45343,41 N.mm W0=4010(mm3)Mx=25559,75N.mmVy

Chn gii hn mi ng vi chu k dao ng

H s tng bn Theo bng 7-4 trang 123 TKCTM ta chn Theo bng 7-8 trang Cc t s Tp trung ng sut do lp cng vi kiu ta chn T3 p sut sinh ra trn b mt ghp tra bng 7-10 trang 128 ta c

Thay s vo cng thc 7-6 v 7-7 trang 120

Vy tha mn iu kin nn ng knh trc d1 =22mm.l chnh xc4.2 Kim nghim sc bn trc IIa) Ti tit din e-e:Theo cng thc 7-5 trang 120 TKCTM

V trc quay nn ng sut thay i theo chu k i xng

V b truyn lm vic mt chiu nn ng sut tip thay i theo chu k mch ng.

Gii hn mi un v mi xon:

Trong l gii hn bn ca vt liu thp 45 theo bng (7-3b) trang 122 TKCTM ng vi ng knh trc d1=45mm ta c Chiu rng then b=14, chiu cao then h=9.W=8980 (mm3) Mu=502365,9 Nmm W0=19170(mm3)Mx=94729,83NmmVy

Chn gii hn mi ng vi chu k dao ng

H s tng bn Theo bng 7-4 trang 123 TKCTM ta chn Theo bng 7-8 Cc t s Tp trung ng sut do lp cng vi kiu ta chn T3 p sut sinh ra trn b mt ghp tra bng 7-10 trang 128 ta c

Thay s vo cng thc 7-6 v 7-7 trang 120

Vy tha mn iu kin nn ng knh trc de-e =47mm.l chnh xcb) ti tit din i-i:Theo cng thc 7-5 trang 120 TKCTM

V trc quay nn ng sut thay i theo chu k i xng

V b truyn lm vic mt chiu nn ng sut tip thay i theo chu k mch ng.

Gii hn mi un v mi xon:

Trong l gii hn bn ca vt liu thp 45 theo bng (7-3b) trang 122 TKCTM ng vi ng knh trc d2=45mm ta c Chiu rng then b=14, chiu cao then h=9.W=8980 (mm3) Mu= 19717,6Nmm W0=19170(mm3)Mx=94729,83NmmVy

Chn gii hn mi ng vi chu k dao ng

H s tng bn Theo bng 7-4 trang 123 TKCTM ta chn Theo bng 7-8 Cc t s Tp trung ng sut do lp cng vi kiu ta chn T3 p sut sinh ra trn b mt ghp tra bng 7-10 trang 128 ta c

Thay s vo cng thc 7-6 v 7-7 trang 120

Vy tha mn iu kin nn ng knh trc di-i =47mm.l chnh xc

4.3 Kim nghim sc bn trc III:theo cng thc 7-5 trang 120 TKCTM

V trc quay nn ng sut thay i theo chu k i xng

V b truyn lm vic mt chiu nn ng sut tip thay i theo chu k mch ng.

Gii hn mi un v mi xon:

Trong l gii hn bn ca vt liu thp 45 theo bng (7-3b) trang 122 TKCTM ng vi ng knh trc d3=55mm ta c Chiu rng then b=16, chiu cao then h=10.W=14510 (mm3) Mu=783731,02Nmm W0=30800 (mm3)Mx=278541,67 NmmVy

Chn gii hn mi ng vi chu k dao ng

H s tng bn Theo bng 7-4 trang 123 TKCTM ta chn Theo bng 7-8 trang 127 h s tp trung ng sut ti rnh then Cc t s Tp trung ng sut do lp cng vi kiu ta chn T3 p sut sinh ra trn b mt ghp tra bng 7-10 trang 128 ta c 6Thay s vo cng thc 7-6 v 7-7 trang 120

Vy tha mn iu kin nn ng knh trc di-i =55mm.l chnh xcPHN V :TNH THEN c nh bnh rng theo phng tip tuyn hay truyn momen v truyn chuyn ng t trc n bnh rng ta dng then.5.1.Tnh then ti trc I

lp then ng knh trc I l l 22 mm theo bng (7-23)trang 143 sch TKCTM ta chn loi then bng c cc kch thc: b = 6; h = ; t=3,5 ; t1=2,6; k = 2,9- Chiu di ca then : l =17 mm

Kim nghim sc bn dp theo cng thc (7-11) trang 139 sch thit k chi tit my. Trong o: Mx=25559,75N.mm ; d1=22mm ; k=2,9Chiu di then l=17 mmSuy ra N/Tra bang (7-20) trang 142 sch thit k chi tit my vi ng sut mi ghep c inh tai trong rung ng nhe vt liu thep ta chon.[]d=100N/

d d tho iu kin dp khi truyn ti. * Kim nghim sc bn ct theo cng thc (7-12) trang 139 sch TKCTM :

- Tra bng (7-21)trang 142 sch TKCTM ta c: ng sut ct cho php ca ti trng tnh l: []c = 87 N/mm2 Vy tho mn iu kin bn ct []c > c 2. Then ti ng knh de-e = 47 mm- Theo bng (7-23)trang 143 sch TKCTM ta chn: b = 14 ; h = 9; t = 5,0 ; t1=4,1 ; k = 5,0 - Chiu di ca then : l = 43 mm* Kim nghim sc bn dp theo cng thc (7-11) trang 139 sch TKCTM :

Ta c:Mx2 = 94729,,83 Nmm k = 5l = 43 mm d = 47 mmVy :

- Tra bng (7-20) trang 142 sch TKCTM vi ng sut mi ghp c nh, ti trng tnh vt liu thp ta chn: []d = 150 N/mm2Vy []d > d tho iu kin dp khi truyn ti. * Kim nghim sc bn ct theo cng thc (7-12) trang 139 sch TKCTM :

- Tra bng (7-21)trang 142 sch TKCTM ta c: ng sut ct cho php ca ti trng tnh l: []c = 87 N/mm2 Vy tho mn iu kin bn ct []c > c

3.4.3. Tnh then ti trc III.

Then ti ng knh d = 55 mm- Theo bng (7-23)trang 143 sch TKCTM ta chn b = 16; h = 10; t= 5 ; t1= 5,1; k = 6,2 - Chiu di ca then : l = 61,6 mm* Kim nghim sc bn dp theo cng thc (7-11) trang 139 sch TKCTM :

Ta c:Mx3 = 278541,67Nmm k = 6,2l = 45 mm d = 55 mmVy :

- Tra bng (7-20) trang 142 sch TKCTM vi ng sut mi ghp c nh, ti trng tnh vt liu thp ta chn: []d = 100 N/mm2Vy []d > d tho mn iu kin dp khi truyn ti. * Kim nghim sc bn ct theo cng thc (7-12) trang 139 sch TKCTM :

- Tra bng (7-21)trang 142 sch TKCTM ta c: ng sut ct cho php ca ti trng tnh l: []c = 87 N/mm2 Vy tho mn iu kin bn ct []c > PHN VI: THIT K GI TRC

6.1. ln trc I:

- H s kh nng lm vic tnh theo cng thc (8-1)trang 158 sch TKCTM. C = Q(n.h)0,3 CbngTrong : n1 = 1450 v/p s vng quay h = 250.8.5=10000 gi: thi gian lm vic ca my. - Theo cng thc 8-2 trang 159 sch TKCTM Q=(Kv .R+mA)Kn .Kt Tai trong tng ng (daN) theo cng thc (8-2) trang 159 TKCTM.Trong o .-R: L tai trong hng tm (tng phan lc gi ) daN-A : Ti trng dc trc, daN. y A=0-m=1,5 : H s chuyn ti trng dc v ti trng hng tm theo (bng 8-2)_TKCTM trang 161.-Kt=1: H s ti trng ng theo bng (8-3)_TKCTM trang 162.-Kn=1: Nhit lm vic di 1000C theo bng (8-4)_TKCTM trang 162.-Kv=1: H s xt n vng trong ca l vng quay, theo bng (8-5)_TKCTM trang 162.

Tnh cho gi A v c lc RA ln. Tnh C theo cng thc (8-1) v tnh Q theo cng thc (8-2) Q=(R.Kv +mA)Kn .Kt y A=0 nn ta c Q=R.Kv .Kn .Kt =82,92daN n =1450 vg/ph C=82,92.(1450.10000)0,3 = 11669,968N-Theo bng 14p trang 338 sch TKCTM dng cho c nh , ng vi d= 20 mm : Chn bi k hi 204 c nh c Cbng = 15000 C ng knh ngoi D = 47 mm , chiu rng B = 14 mm ln gi B ly cung c nh trn. Vy bi tho mn iu kin : C Cbng nn ta khng cn chn li bi.6.2. ln trc II:- S :

- H s kh nng lm vic tnh theo cng thc (8-1)trang 158 sch TKCTM. C = Q(n.h)0,3 Cbngn = 372 v/p : s vng quayh=10000 gi : thi gian lm vic ca my. -Ti trng tng ng ca chn c tnh theo cng thc (8-6)trang 159 sch TKCTM :

Trong o :-R: L tai trong hng tm (tng phan lc gi ) daN-A : Ti trng dc trc, daN. y A=0-m=1,5 : H s chuyn ti trng dc v ti trng hng tm theo (bng 8-2)_TKCTM trang 161.-Kt=1: H s ti trng ng theo bng (8-3)_TKCTM trang 162.-Kn=1: Nhit lm vic di 1000C theo bng (8-4)_TKCTM trang 162.-Kv=1: H s xt n vng trong ca l vng quay, theo bng (8-5)_TKCTM trang 162. Ta c:

Tnh cho gi C v c lc CD ln.Tnh D theo cng thc (8-1) v tnh Q theo cng thc (8-2) Q=(R.Kv +mA)Kn .Kt y A=0 nn ta c Q=R.Kv .Kn .Kt =859,9daN n =372 vg/ph C=859,92.(372.10000)0,3 =Tra bng 14P_TKCTM trang 338, ng vi d=80mm chn bi k hiu 216 loai c nng , co Cbng=84000ng knh ngoi D=140mmChiu rng B=26 ln gi C ly cung c nh trnVy bi tho mn iu kin : C Cbng6.3. ln trc III

S chn cho trc :H s kha nng lam vic c tinh theo cng thc (8-1) trang158 TKCTM.

Ta co n=120h=10000 gi thi gian phuc vu cua b truyn.Q=(Kv .R+mA)Kn .Kt Tai trong tng ng (daN) theo cng thc (8-2) trang 159 TKCTM.Trong o .-R: L tai trong hng tm (tng phan lc gi ) daN-A : Ti trng dc trc, daN. y A=0-m=1,5 : H s chuyn ti trng dc v ti trng hng tm theo (bng 8-2)_TKCTM trang 161.-Kt=1: H s ti trng ng theo bng (8-3)_TKCTM trang 162.-Kn=1: Nhit lm vic di 1000C theo bng (8-4)_TKCTM trang 162.-Kv=1: H s xt n vng trong ca l vng quay, theo bng (8-5)_TKCTM trang 162. Ta c:

Tnh cho gi E v c lc EF ln.Tnh C theo cng thc (8-1) v tnh Q theo cng thc (8-2) Q=(R.Kv +mA)Kn .Kt y A=0 nn ta c Q=R.Kv .Kn .Kt =1583,294daN n =120 vg/ph C=1583,294.(120.10000)0,3 =105515,4Tra bng 14P_TKCTM trang 338, ng vi d=90mm chn bi k hiu 218 loai c nng , co Cbng=112000ng knh ngoi D=160mmChiu rng B=30 ln gi E ly cung c nh trnVy bi tho mn iu kin : C Cbng

6.4: C nh v bi trn ln6.4.1. C nh trc: c nh trc c th dung np v iu chnh khe h ca bng cc tm m kim loi gia np v thn hp gim tc.Np ln vi hp gim tc bng vt, loi np ny d ch to v d lp rp.6.4.2. Bi trn ln B phn c bi trn bng m, v vn tc truyn bnh rng nn khng th dung phng php te ht du trong hp v bi trn ca b phn c th dng loi m T tng ng nhit lm vic t 600-1000 v vn tc di 1500v/pht.Bng 8-28 TKCTM trang 198.6.4.3. phn che chn : che kn cc phn trc,trnh xa s xm nhp ca bi v tp cht vo ,cng nh ngn m chy ra ngoi, y dng loi vng pht 1 n gin nht,bng 8-29 TKCTM trang 203 cho kch thc vng pht .6.4.4.Chn kiu lp ln :Lp ln vo trc theo h l vo hp theo h trc.Lp theo TC TCT OCT520-55 sai lch cho php ca vng trong ca l m( KT nh hn KT danh ngha v sai lch cho php trn l theo h l l dng ).C- chn kiu lp tra bng 8-18 v 8-19.

PHN VII: THIT K V HP V CC B PHN KHC

7.1 V hp:V hp chn v hp c ,vt liu lm v l gang xm, mt ghp gia np v thn l mt phng i ngang qua ng lm cc trc vic lp ghp c d dng.Bng 10-9 TKCTM trang 268 cho php ta tnh c kch thc ca phn t v hp sau y:- Chiu rng thnh thn hp;

Chn Chiu dy thnh np hp:

Ly Chiu di mt bch di ca thn:

Chiu dy mt bch trc trn ca np:

Chn b1= 14mm.Chiu dy hp khng c phn li.

Chn P = 24mm.Chiu dy gn thn hp:Chiu dy gn np hp:

ng knh bulng nn:

Ly dn = 20.ng knh cc bulng khc:+ cnh : Ly dn= 16mm Ghp np vo thm Ghp np Ghp np ca thm ng knh bulng vng theo trng lng ca hp gim tc vi kch thc trc A hai cp.174 x 289.Tra bng 10-11b-TKCTM trang 176 ta chn M20 vi s lng 12 ci.S lng bu lng nn :Trong L l chiu dy hp, ly s b bng 900 mm.B chiu rng hp, ly s b bng 350 mm

Ly n =6; bu lng M20.

BNG S LIU V HP V CC CHI TIT MY KHC.TN GICNG THC TNHKT QU

Chiu dy thn hp10 ( mm )

Chiu dy thnh np hp

8 ( mm )

Chiu dy mt trc bch di ca thn15 ( mm )

Chiu dy mt trn ca np14 ( mm )

Chiu dy hp khng c phn li.24 (mm )

Chiu dy gn thn hp10 ( mm )

Chiu dy gn np hp8 ( mm )

ng knh bu lng nn 20 (mm )

ng knh cc bu lng khc : cnh 16 ( mm )

Ghp np vo thn10 ( mm )

Ghp np 10 ( mm )

Ghp np ca thm6 ( mm )

Bu lngM208 ( ci )

S lng bu lng nn6 ( ci )

7.2. Cc thng s khc.Cc chi tit ph.7.2.1. Vng chn du :Khng cho du v m tip xc nhau.7.2.2.Cht nh v:C tc dng nh v chnh xc v tr ca np v thn hp gim tc, dng 2 cht nh v khi xit cht bu lng m khng lm bin dng vng ngoi ca .Do vy lp ghp hp gim tc d dng hn.Cht nh v dng cht cn theo ISO.2339.lm bng thp CT3.7.2.3.Np quan st ( ca thm ).C tc dng kim tra, quan st cc chi tit my trong hp gim tc khi lp ghp v khi du vo trong hp, quan st s n khp gia cc bnh rng , ca thm c y bng np.Np ca thm ch to kt hp vi b phn thng hi tay cm.kch thc np ly theo tiu chun bng 10-12 trang 277 sch thit k chi tit my Bng thng s np ca thmABA1B1CC1KRKch thc vtS lng vt

15010019014017512012M8 x 204

7.2.4. Nt thng hi:Khi lm vic, nhit trong hp tng ln, iu ha khng kh trong v ngoi ngi ta dng nt thng hi bng ( 10-16 sch thit k chi tit my trang 279.Bng cc thng s ca nt thng hi.ABCDEGHIKLMNOPQRS

M27x21530154536326410822632183632

7.2.5.Nt tho du:Dng tho du c, bn ra ngoi hp gim tc. chn loi nt theo tiu chun DIN910, kch thc M20x2 theo bng 10-14 sch thit k chi tit my trang278.Bng cc thng s ca nt tho du.dbmafLeqD1Dsl

M20x215943282,517,821302225,4

PHN VIII : BNG DUNG SAI LP GHP.Cn c vo yu cu ln vic ca tng chi tit trong hp gim tc chn cc kiu ghp sau:8.1.Dung sai ln.Vng trong ln chu ti t tun hon, lp ghp theo h thng trc, vng khng trt trn b mt trc khi lm vic nn ta chn mi ghp trung gian c di rt nh ,k6 theo h thng trc.Vng ngoi lp ghp theo h thng l, vng ngoi khng chu quay nn chu ti cc b c th di chuyn c trc mt lng nh khi lm vic, khi tng nhit trong qu trnh ln vic nn ta chn kiu lp trung gian D11.8.2. Dung sai lp ghp bnh rng:B truyn chu ti va p nh mi lp ghp khng yu cu phi tho lp thng xuyn nn chon kiu lp H7/k6.;8.3. Lp ghp np thn vo thn:Do mi ghp cn tho lp d dng v c th iu chnh c nn chn kiu lp H7/k6.8.4. Lp ghp vng chn du ln trc: d dng tho lp ta chn kiu lp trung gian H7/js6.8.5. Lp cht nh v Chn kiu lp cht m bo ng tm cao v khng chu ng sut: H7/h6.8.6. Lp ghp then:- Theo chiu rng chn kiu lp trn trc l N9/h9.- Trn cc chi tit my nh bnh rng chn kiu lp Js9/h6.- Theo chiu cao sai lch gii hn khch thc then l h11- Theo chiu di sai lch gii hn kch thc then l h14.8.7. Cc kiu lp ghp trong b truyn.Bng c tra trong gio trnh dung sai lp ghp k thut o t bng ph lc 1 bng 1 n bng 4( trang 176 -188) nh xut bn gio dcBNG CAC KIU DUNG SAI LP GHPCc chi tit Kiu lp ghpKt qu

Dung sai lp ghp ln -vng trong lp ghp trung gian c di-vng ngoi lp ghp trung gian k6 D11

Dung sai lp ghp Bnh rngTrung gian H7/k6

Lp ghp vng chn du trn trcTrung gianH7/js6

Lp ghp cht nh vLp chtH7/h6

Lp ghp thenTheo chiu rng chn kiu lp trung gianMt s chi tit my khcTheo chiu cao sai lch then gii hnTheo chiu rng sai lch then gii hnN9/h9js9/h6h11h14

Bng dung sai lp ghp

SttMi ghp gia cc chi tit

TrcKch thc danh ngha

Kiu lpSai lch gii hnDung sai

LTrc

ESEIeseiTDTd

1Vng trong trc vi trcIIIIII22

47

5522k6

47k6

55k6000000+15+18+21+2+2+2000131619

2Vng ngoi vi v hpIIIIII47

62

6247H7/e8

62H7/e8

62H7/e8+25+30+30000-50-50-50-89-106-106253030394646

3Vng chn m vi trcIIIIII22

47

5522H7/js6

47H7/js6

55H7/js6+21+21+25000+6,5+6,5+8-6,5-6,5-8212125131316

4bnh rng vi trcIII

III22

47

47

5522H7/k6

47H7/k6

47H7/k6

55H7/k6+21+21+21+250000+15+15+15+18+2+2+2+22121212513131316

PHN VIIII. BI TRN HP GIAM TC

- Bi trn b trn b truyn bnh rng: do vn tc nh nn ta chn phng php ngm bnh rng trong hp du mc du thp nht phi ngp chn rng ca bnh rng dn trc I, nh vy s c hao ph nng lng do lc cn ca du, tuy nhin do vn tc rng trong hp nh nn hao ph khng ng k. -Theo bng (10-17)/sch thit k chi tit my chn nht ca du bi trn bnh rng l 116 centistc hoc 16 Engle v theo bng (10-20) chn loi du AK20.- Bi trn ln: B phn c bi trn bng m, v vn tc b truyn bnh rng thp nn du khng th bn to ln . Ta c th dng m loi T ng vi nhit lm vic t 600C : 1000C v vn tc vng di 1500v/ph bng (8-28).Lng m cha 2/3 ch trng ca b phn .

Ti liu tham kho- Thit k chi tit my nguyn trng hip-nguyn vn lm NXB gio dc-Dung sai lp ghp v k thut o lng PGS.TS ninh c tn GVC. Nguyn th xun by NXB gio dc-Hng dn tnh ton thit k chi tit my PGS.TS ng vn quyt NXB giao thng vn ti-Chi tit my tp 1,2 nguyn trong hip NXB gio dc

MC LC

PHN I: Phn Phi T S Truyn1.1.: cch phn phi t s truyn31.2.: cng sut, s vng quay v momen xon trn cc trc1.2.1.: cng sut:1.2.2.: momen xon trn cc trc:PHN II: THIT K B TRUYN BNH RNG2.1.1.: Chn vt liu:2.1.2.: xc nh ng sut cho php62.1.3.:S b ly h s ti trng: k=1,37

2.1.4.:Chn s b chiu rng bnh rng: 72.1.5.: Tnh khong cch trc72.1.6.: Tnh vn tc vng v chn cp chnh xc ch to bnh rng vn tc vng:2.1.7.: nh chnh xc h s ti trng K82.1.8.: Xc nh Mun, s rng v chiu rng bnh rng:82.1.9.: Kim nghim sc bn un ca rng92.1.10.:Cc thng s hnh hc ch yu ca b truyn:92.1.11.:Tnh lc tc dng ln trc:10CHNG II:Thit k b truyn bnh rng cp chm112.2.1.:Chn vt liu:112.2.2.:nh ng sut cho php:.2.2.3.:S b ly h s ti trng: K=1,3

2.2.4.:Chn s b chiu rng bnh rng: 2.2.5.: Tnh khong cch trc.2.2.6.: Tnh vn tc vng v chn cp chnh xc ch to bnh rng2.2.7.: nh chnh xc h s ti trng K2.2.8.: Xc nh Mun, s rng ,gc nghing ca rng v chiu rng bnh rng:2.2.9.: Kim nghim sc bn un ca rng.2.2.10.:Cc thng s hnh hc ch yu ca b truyn:2.2.11.:Tnh lc tc dng ln trc:PHN III: THIT K TRC V THENCHNG I: THIT K3.1.1.:chn vt liu ch to183.1.2.:xc nh ng knh s b183.1.3.: tnh dng knh s b ca cc trc183.1.3.1.: i vi trc 1183.1.3.2.: i vi trc 2193.1.3.3.: i vi trc 319CHNG II : TNH GN NG TRC3.2.1.: Thit k trc I:203.2.2.: Thit k trc II3.2.3.: Thit k trc III:PHN IV :TNH CHNH XC TRC274.1.: kim nghim sc bn trc I4.2.: Kim nghim sc bn trc II4.3.: Kim nghim sc bn trc IIIPHN V :TNH THEN355.1.:tnh then truc I5.2.:tnh then truc II 5.3.:tnh then truc III.PHN VI : THIT K GI TRC 6.1 .: ln trc I406.2.: ln truc II6.3.: ln truc III6.4.: c nh v bi trn ln6.4.1.: C nh trc:6.4.2.: Bi trn ln6.4.3.: phn che chn :PHN VII: THIT K V HP V CC B PHN KHC477.1. Vo hp7.2.: Cc thng s khc.507.2.1.: Vng chn du507.2.2.:Cht nh v:507.2.3.:Np quan st ( ca thm ).517.2.4.: Nt thng hi:517.2.5.:Nt tho du:527.2.6.: Que thm du.52PHN VIII : BNG DUNG SAI LP GHP.538.1.: Dung sai ln.538.2.: Dung sai lp ghp bnh rng:538.3.: Lp ghp np thn vo thn:538.4.: Lp ghp vng chn du ln trc:548.5.: Lp cht nh v548.6.: Lp ghp then:548.7.:Cc kiu lp ghp trong b truyn.54PHN VIIII. BI TRN HP GIAM TC57Ti liu tham kho58

1 N CHI TIT MY