Digital Voltmeter \(DVM\)

17
Digital Multimeter (DMM) Hand-held DMM Portable Analog Multimeter Bench-top DMM

Transcript of Digital Voltmeter \(DVM\)

Page 1: Digital Voltmeter \(DVM\)

Digital Multimeter (DMM)

Hand-held DMM

Portable Analog Multimeter

Bench-top DMM

Page 2: Digital Voltmeter \(DVM\)

Digital Voltmeter (DVM)

DVM is essentially an Analog to digital converter (A/D) with a digital display

Digital voltmeter

AttenuatorAmplifier

Analog to DigitalConverter

Digital display

Digital MultiMeter (DMM)

= electronic Volt Ohm Millimeter with digital display

Page 3: Digital Voltmeter \(DVM\)

Comparison of Digital and Analog Meter

Can be damaged when dropped from bench level

No usually damaged by rough treatment

Pointer attempts to deflect to the left when the polarity is reversed

Indicates a negative quantity when the terminal polarity is reversed

Inferior resolution and accuracy.(±3% in common)

Superior resolution and accuracy. (±0.5% or better)

Wrong scale might be used or might be read incorrectly.

Leaves no doubt about the measured quantity.

Analog meterDigital meter

Page 4: Digital Voltmeter \(DVM\)

Analog to Digital ConversionA/D converts an analog signal into the digital code which is proportional to the magnitude of the coming signal.

Vin ≈ k ×Digital output

Where k is step size or resolution

Ex. Signal from 800-1500 mV may be converted to 8-bit binary codes starting from 010100002 (8010) to 100101102 (15010). In this case, the step size k is equal to 10 mV.

Quantization error or Conversion error of a A/D

100%12

1100

scale fullsize step

error onQuantizatiN

×−

=×=

Where N is the number of bit

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Analog to Digital Conversion

Conversion time, Tc time requires to convert an analog signal to the corresponding digital code.

1.5 2.5

Dig

ital o

utpu

t

Analog input (V)

000

001

010

011

100

101

110

111

0 1 2 3 4 5 6 7 (Full scale)

step size = 1 V

A/D will give 010 digital code.

Quantization error = 1/7 × 100 =14.3%

Ex. An analog inputs 1.5-2.5 V will be represented by digital output 010

An example of 3 bit ADC

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Ramp-type Digital Voltmeter(also called single slope)

Vin

Ramp signalStart measurement

Coincindence

Time

∆tGating

time interval

Clock pulsesto counter

Voltage-to-time conversion using gated clock pulses.

Operation principle: The measurement of the time it takes for a linear ramp voltage to rise from O V to the level of the input voltage, or to decrease from the level of the input voltage to zero. This time interval is measured with an electronic time-interval counter.

Vramp(t) = Vo – m t

Where m is the ramp rate

Vramp(t1) = Vin = Vo –m t1

Vramp(t2) = 0 = Vo – m t2

∆t = t2- t1 = Vin/m

n pulse

If the period of the clock is T, then during the time interval ∆t1, the number of pulses is

∆t ≈ nT or Vin ≈ nmT

•Accuracy depends on both the ramp rate and clock period.

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V+>V-; Vo = V(1) Logic highComparator V+<V-; Vo = V(0) Logic low

VrefVin

VoV(1)

V(0)

+Vref

Vin Vo

Vo

Vin

V(1)

V(0)Vref

+Vref

Vin

Vo

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Ramp-type Digital Voltmeter

Voltage-to-time conversion

Rangingand

Attenuator

DC inputvoltage

-+

inputcomparator

groundcomparatorRamp

Generator

SampleRateMV

Oscillator Gate Counter

Digitaldisplay

startcount

stopcount

-+

vin

vramp

0 Vstart ramp

reset

clk

Time measurement unit

Block diagram of a ramp-type digital voltmeter.

Page 9: Digital Voltmeter \(DVM\)

Staircase Ramp Digital Voltmeter(also called digital ramp)

•The most simple A/D•Slow conversion and conversion time depends on the magnitude of input signal.

D/A

out

put

time

VAX

clock period

Vin

period Clock1)(2T NmaxC, ×−=

Clock

Comp.

D/A

Counter

Control circuit

Vin+

-

VAX

Digital output

Compare the input voltage to the internally generated stair case ramp.

Block diagram

Page 10: Digital Voltmeter \(DVM\)

Successive Approximation Digital Voltmeter

Ex. To determine a number between 0 – 511 (9 bit binary), given, the number to be determined is 301

987654321

No.

Finished 1 0010 1101300+1 = 301<1 0010 1110300+2 = 302>1 0010 1100296+4 = 300>1 0010 1000288+8 = 296<1 0011 0000288+16 = 304>1 0010 0000256+32 = 288<1 0100 0000256+64 = 320<1 1000 0000256+128 = 384

Vin > VAX1 0000 0000256ResultsEstimate

Page 11: Digital Voltmeter \(DVM\)

Successive Approximation Digital Voltmeter

Compare the input voltage to the internally generated voltage•The most common A/D for general applications

•Conversion time is fixed (not depend on the signal magnitude) and relatively fast

Comp.

D/A

SuccesiveApproximation

Register

Control circuit

Vin+

-

VAX

Digital output

Clock

period ClockNTC ×=

where N is the number of bits

D/A

out

put

Clock period

VAX

Vin

Fullscale

14

Fullscale

12

Fullscale

34

Fullscale

1 2 3 4 5 6 7 8

Block diagram

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Digital Ramp VS Successive approximation

Successive approximation methodDigital Ramp method

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Dual-slope Digital Voltmeter

Vin

Vref

Vout-+

R

C

Vin

Vref

Vout-+

R

C

Phase 2: discharging C with the reference voltage until the output voltage goes to zero.

Phase 1: charging C with the unknown input for a given time.

RCTV

V inout1 −=

where T is the charging time

Vout

timeCharge Discharge

Phase 1 Phase 2

Assume Vc(0) = 0

out1xref

out VRC

TVV +=

find Tx at which Vout becomes zero

ref

inx V

TVT =

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Dual-slope Digital Voltmeter

Vout

timeSmall input voltage

Large input voltage

0DischargeCharge

Conversion time

variableconstC TT T +=

•Accuracy does not depend on R C and Clock(high accuracy)•Relatively slow•Capable to reject noise

Vin -+

R

C

Counter

Clockgenerator

Display

Control logic

Vrefcount

Vin -+

R

C

Counter

Clockgenerator

Display

Control logic

Vref

reset

count-+

VoutVout

Zerocrossingdetector

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Ex A dual slope A/D has R= 100 kΩ and C = 0.01 µF . The reference voltage is 10 volts and the fixed integration time is 10 ms. Find the conversion time for a 6.8 volt input.

ms 6.8 V)(10

ms) V)(10(6.8V

TVT

ref

inx ===

The total conversion time is then 10 ms + 6.8 ms = 16.8 ms Ans

Ex Find the successive approximation A/D output for a 4-bit converter to a 3.217 volt input if the reference is 5 volts.

(1) Set D3 = 1 VAX = 5/2 = 2.5 VoltsVin > VAX leave D3 = 1

(2) Set D2 = 1 VAX = 5/2 + 5/4 = 3.75 VoltsVin < VAX reset D2 = 0

(3) Set D1 = 1 VAX = 5/2 +5/8= 3.125 VoltsVin > VAX leave D1 = 1

(4) Set D0 = 1 VAX = 5/2+5/8+5/16 = 3.4375 VoltsVin < VAX reset D0 = 0

By this procedure, we find the output is a binary word of 10102 Ans

Page 16: Digital Voltmeter \(DVM\)

Typical specification of DMM

General

“-” displayed for negative polarityPolarity indication

Only figure “1” on the displayOver range indicationDual-slope integrationMeasuring method

:LCD 31/2 digits, updates 2-3/ sec.:10 MΩ:40-400 Hz

DisplayInput impedanceFrequency range

:9V batteryPower:200mA/250VFuse protection

:600 VMaximum voltage between terminals

Ex. ± (0.5% of rdg + 1 digits) sometimes simplify as ± (0.5 + 1)

Indicate as ± (% of reading + No. of digits)Accuracy of DMM

Ex. For an accuracy of ± (0.5 + 1) , calculate the maximum error of in the 1.800 V readingerror = ± (0.5% of 1.800 + 0.001 V)

= ± (0.009 + 0.001 V) = ± 0.01 V or ± 0.56% of reading

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Ex A 20 V dc voltage is measured by analog and digital multimeters. The analog instrument is on its 25 V range , and its specified accuracy is ± 2%. The digital meter has 3 ½ digit display and an accuracy of ±(0.6+1). Determine the measurement accuracy in each case.

Analog instrument:Voltage error = ± 2% of 25 V

= ± 0.5 Verror = ± 0.5 V × 100%

20 V= ± 2.5%

Digital instrument:For 20 V displayed on a 3 ½ digit display

1 Digit = 0.1 VVoltage error = ± (0.6% of reading + 1 Digit)

= ± (1.2 V + 0.1 V)= ± 0.22 V

error = ± 0.22 V × 100% 20 V

= ± 1.1%

½ digit

3½ digit display