Diat Htt Lect 7 8 9

download Diat Htt Lect 7 8 9

of 11

Transcript of Diat Htt Lect 7 8 9

  • 8/11/2019 Diat Htt Lect 7 8 9

    1/11

    HeatTreatment

    Dr.SantoshS.Hosmani

    Tem erature Time Transformation TTT dia rams

    Phase Transformation

    SolidSolid state phase

    Solid 21

    Physical metallurgy

    Liquid Gascondensation

    evaporation

    What is the driving force for any phase

    transformation?

    > Decrease in Gibbs free energy

    -

    -

    Gs - Gl = G If this isve, then only this transformation

    will occur.

  • 8/11/2019 Diat Htt Lect 7 8 9

    2/11

    G

    nergy

    ,

    G1

    Energy barrierEa

    Free

    Reactants

    G = G2 G1

    ProductsG2

    GGL

    Gibbs free energy as a function of temperature,

    GSG S

    T

    G

    p

    =

    T

    C

    T

    G p

    p

    =

    2

    2

    Liquid is stableSolid is stable

    GS < GL GL < GS

    G

    GL

    TmTTfreesing

    The second derivative of a function measures the

    concavity of the graph of .

    A function whose second deri vati ve i s osi ti ve will be

    concave up, meaning that the tangent l ine wil l l ie below the

    graph of the function.

    Similarly, a function whose second derivat ive is negative

    wil l be concave down, and its tangent l ines wil l l ie above

    the graph of the function.

    ef.:Wiki

    The tangent line is blue where the curve is concave up, green

    where the curve is concave down, and red at the inflection poin ts

    How does solidification

    egns

    Usually at the walls of the

    container

    Heterogeneous

    nucleation.

    Why?

    To be discussed later.

  • 8/11/2019 Diat Htt Lect 7 8 9

    3/11

    Spherical ball of solid of radius r

    in the middle of the liquid at a

    temperature below Tm

    Homogeneous nucleation

    =

    L

    per unit volume

    =per unit volume

    = -

    Change in free energy of the

    system due to formation of the )(4 3

    Ls GGrf = 2

    4 r+so a o ra us r :

    +ve: barrier to

    nucleation

    2

    4 r+

    rAt constant

    Temperature

    r

    f

    r*

    )(3

    4 3Ls

    GGr

    V

    34 Grf = 24 r+Solid balls of radius r < r*canno grow as w ea

    to increase in the free

    energy of the system !!!

    24 r+

    Solid balls of radii r > r*

    At constant

    Temperature

    r

    f

    *

    r*

    CRITICAL RADIUS OF

    HOMOGENEOUS

    V

    3

    3

    4Gr

    V

    34 Grf = 24 r+

    24 r+

    f 0

    *

    =

    =r

    f*f

    r

    r*

    V

    34 Gr V

    *G

    r

    =

    3

    16*f =

    V

  • 8/11/2019 Diat Htt Lect 7 8 9

    4/11

    Driving force for solidification:

    LS GGG = V )()()( TSTTHTG =

    == mmmm

    mm

    T

    THTS

    )()(

    =

    G (T)

    )()(mTHTH = )()( mTSTS =

    TSTTHTG =

    m

    mm

    T

    THTTH

    )()(

    =

    GL GS

    )(m

    m

    m THT

    TT =

    TTmT mm

    HT

    TG = )(

    Grf = 34

    24 r+

    f

    4 3= 2f1*

    3

    rr *

    f2*

    r *

    m

    m

    HT

    TG = )(

    r = 2

    * mTr =

    2*

    T1T2