Derive Formulae Involving Backward Differences

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1. Derive formulae involving backward differences for the first and second derivatives of a function. 2. The function is tabulated for x = 1.00(0.05)1.30 to 5D: 1. Estimate the values of f'(1.00) and f"(1.00), using Newton's forward difference formula. 2. Estimate f'(1.30) and f"(1.30), using Newton's backward difference formula. 18. Find the missing value from the following table. X : 2 3 4 5 6 Y : 45.0 49.2 54.1 - 67.4 20. Form the divided difference table for the following data: X : -2 0 3 5 7 8 F(x) : -792 108 -72 48 -144 -252 Example This example interpolates at the point x=0.28 from the function values xi- 1.00 0.50 0.00 0.50 1.00 1.50 yi - 0.00 0.53 1.00 0.46 2.00 11.09 .

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Transcript of Derive Formulae Involving Backward Differences

Page 1: Derive Formulae Involving Backward Differences

1. Derive formulae involving backward differences for the first and second derivatives of a function.

2. The function   is tabulated for x = 1.00(0.05)1.30 to 5D:

1. Estimate the values of f'(1.00) and f"(1.00), using Newton's forward difference formula.

2. Estimate f'(1.30) and f"(1.30), using Newton's backward difference formula.

18. Find the missing value from the following table.X : 2 3 4 5 6 Y : 45.0 49.2 54.1 - 67.4

20. Form the divided difference table for the following data:X : -2 0 3 5 7 8F(x) : -792 108 -72 48 -144 -252

 ExampleThis example interpolates at the point x=0.28 from the function values

xi- 1.00 0.50 0.00 0.50 1.00 1.50 yi - 0.00 0.53 1.00 0.46 2.00 11.09 .

Find f (x) from the table below also find f (7)X : 0 1 2 3 4 5 6

F (x) : -1 3 19 53 111 199 323

Page 2: Derive Formulae Involving Backward Differences

For the given table of values0.1 0.2 0.3 0.4 0.5 0.6

0.425 0.475 0.400 0.452 0.525 0.575

 

, using two-point equation will be calculated as.............

 

 

 

        -0.5

        0.5

        0.75

        -0.75

Read more: MTH603 Numerical Analysis Solved Final Term MCQs Mega File - Virtual University of Pakistan http://vustudents.ning.com/group/mth603numericalanalysis/forum/topics/mth603-numerical-analysis-solved-final-term-mcqs-mega-file#ixzz2ToSWfNOk

Interpolate the value of 0.25 using Newton’s forward difference formula.

x 0.2 0.3 0.4 0.5 0.6

F(x) 0.2304 0.2788 0.3222 0.3617 0.3979

Construct a forward difference table for the following values

x 0.1 0.3 0.5 0.7 0.9 1.1 1.3

y 0.003 0.067 0.148 0.248 0.37 0.518 0.697