Cu 1: gi s mt gen c cu to t 4 loi nucleotit: A, T, G, X th c th c ti a bao nhiu loi m b ba?

thi trc nghim c ch di truyn v bin d - luyn thi i hc mn sinh hc

Bi 1. GEN, M DI TRUYN V QU TRNH NHN I ADNCu 1: gi s mt gen c cu to t 4 loi nucleotit: A, T, G, X th c th c ti a bao nhiu loi m b ba?A. 46 loi m b baB. 61 loi m b baC. 64 loi m b baD. 32 loi m b ba

n thi i hc online luyn thi i hc trc tuynCu 2: sinh vt nhn thc, trnh t nucleotit trong vng m ha ca gen nhng khng m ha axit amin c gi l:A. on intronB. on ixnonC. Gen phn mnhD. Vng vn hnh

Cu 3: trong 64 b ba m duy truyn, c 3 b ba khng m ha cho axit amin no. Cc b ba l:A. UGU, UAA, UAGB. UUG, UGA, UAGC. UAG, UAA, UGAD. UUG, UAA, UGACu 4: trong qu trnh nhn i ADN, v sao trn mi chc ti bn c mt mch c tng hp lin tc cn mch kia c tng hp gin on? A. V enzim ADN polimeraza ch tng hp mch mi theo chiu 53B. V enzim ADN polimeraza ch tc dng ln mt mchC. V enzim ADN polimeraza ch tc dng ln mch khun 35D. V enzim ADN polimeraza ch tc dng ln mch khun 53

Cu 5: M duy truyn c tnh c hiu, tc l:A. Tt c cc loi u dng chung mt b m di truynB. M m u l AUG, m kt thc l UAA, UGA, UAGC. Nhiu b ba cng xc nh mt axit aminD. mt b ba m ha ch m ha cho mt loi axit amin

Cu 6: Tt c cc loi sinh vt u c chung mt b m di truyn, tr mt vi ngoi l, iu ny biu hin c im g ca m di truyn?A. M di truyn c tnh c hiuB. M di truyn c tnh thoi haC. M di truyn c tnh ph binD. M di truyn lun l m b baCu 7: Gen khng phn mnh cA. c intrn v exnB. vng m ha khng lin tcC. vng m ha lin tcD. cc on intrn

Cu 8: Mt on ca phn t ADN mang thng tin m ha cho mt chui polipeptit hay mt phn t ARN gi l A. codon B. genC. anticodonD. m di truyn

Cu 9: Qu trnh nhn i ADN c thc hin theo nguyn tc g?A. Hai mch c tng hp theo nguyn tc b sung song song lin tcB. Mt mch c tng hp gin on, mt mch c tng hp song songC. Nguyn tc b sung v nguyn tc bn bo tonD. Mch lin tc hng vo nhau, mch gin on hng ra chc ba ti bn

n thi i hc online luyn thi i hc trc tuynCu 10: M di truyn lA. m b 3, c ba nucleotit lin k m ha cho mt axit aminB. cc axit amin c m ha trong genC. ba nucleotit lin k cng loi hay khc loi u m ha cho mt axit aminD. mt b ba m ha cho mt axit amin

Cu 11: vng kt thc ca gen l vngA. mang tn hiu khi ng v kim sot qu trnh phin mB. mang tn hiu kt thc phin mC. quy nh trnh t sp xp cc aa trong phn t proteinD. mang thng tin m ha cc aa

Cu 12: m di truyn mang tnh thoi ha, tc lA. nhiu b ba khc nhau cng m ha cho mt loi axit aminB. tt c cc loi u dng chung nhiu m b baC. tt c cc loi u dng chung mt m b baD. mt b ba m di truyn ch m ha cho mt axit amin

Cu 13: m di truyn c tnh ph bin, tc lA. tt c cc loi u dng chung nhiu m b baB. nhiu b ba cng xc nh mt axit aminC. mt b ba m di truyn ch m ha cho mt axit aminD. tt c cc loi u dng chung mt m b ba, tr mt vi loi ngoi l

Cu 14: Mi ADN con sau nhn i u c mt mch ca ADN m, mch cn li c hnh thnh t cc nucltit t do. y l c s ca nguyn tcA. b sung.B. bn bo ton. C. b sung v bo ton. D. b sung v bn bo ton.

Cu 15: Mi gen m ho prtin in hnh gm cc vng theo trnh t l:A. vng iu ho, vng vn hnh, vng m ho.B. vng iu ho, vng m ho, vng kt thc.C. vng iu ho, vng vn hnh, vng kt thc.D. vng vn hnh, vng m ho, vng kt thc.Cu 16: Gen l mt on ca phn t ADNA. mang thng tin m ho chui polipeptit hay phn t ARN. B. mang thng tin di truyn ca cc loi.C. mang thng tin cu trc ca phn t prtin. D. cha cc b 3 m ho cc axit amin.

Cu 17: Vng no ca gen quyt nh cu trc phn t protin do n quy nh tng hp?A. Vng kt thc.B. Vng iu ha.C. Vng m ha.D. C ba vng ca gen.

Cu 18: Trong qu trnh nhn i ADN, cc on Okazaki c ni li vi nhau thnh mch lin tc nh enzim ni, enzim ni lA. ADN girazaB. ADN plimerazaC. hlicazaD. ADN ligaza

Cu 19: Mt gen c 480 anin v 3120 lin kt hir. Gen c s lng nucltit lA. 1800B. 2400C. 3000D. 2040

Cu 20: Intron lA. on gen m ha axit amin.B. on gen khng m ha axit amin.C. gen phn mnh xen k vi cc xn.D. on gen mang tnh hiu kt thc phin m.

Cu 21: Vai tr ca enzim ADN plimeraza trong qu trnh nhn i ADN l:A. tho xon phn t ADN.B. lp rp cc nucltit t do theo nguyn tc b sung vi mi mch khun ca ADN.C. b gy cc lin kt hir gia hai mch ca ADN. D. ni cc on Okazaki vi nhau.

Cu 22: Vng m ho ca gen l vngA. mang tn hiu khi ng v kim sot phin mB. mang tn hiu kt thc phin mC. mang tn hiu m ho cc axit amin D. mang b ba m u v b ba kt thc

n thi i hc online luyn thi i hc trc tuynCu 23: Nhiu b ba khc nhau c th cng m ha mt axit amin tr AUG v UGG, iu ny biu hin c im g ca m di truyn?A. M di truyn c tnh ph bin.B. M di truyn c tnh c hiu.C. M di truyn lun l m b ba.D. M di truyn c tnh thoi ha.

Cu 24: n v mang thng tin di truyn trong ADN c gi lA. nucltit.B. b ba m ha.C. triplet.D. gen.

Cu 25: n v m ho thng tin di truyn trn ADN c gi lA. gen.B. codon.C. triplet.D. axit amin.

Cu 26: M di truyn l:A. m b mt, tc l c mt nucltit xc nh mt loi axit amin.B. m b bn, tc l c bn nucltit xc nh mt loi axit amin.C. m b ba, tc l c ba nucltit xc nh mt loi axit amin.D. m b hai, tc l c hai nucltit xc nh mt loi axit amin.Cu 27: Gen l mt on ADN A. Mang thng tin cu trc ca phn t prtin.B. Mang thng tin m ho cho mt sn phm xc nh l chui polipptt hay ARN.C. Mang thng tin di truyn.D. Cha cc b 3 m ho cc axitaminCu 28: Mi gen m ho prtin in hnh gm vng A. Khi u, m ho, kt thc.B. iu ho, m ho, kt thc.C. iu ho, vn hnh, kt thc.D. iu ho, vn hnh, m ho.

Cu 29: Gen khng phn mnh c A. vng m ho lin tc.B. on intrn. C. vng khng m ho lin tc.D. c exn v intrn.

Cu 30: Gen phn mnh c A. c vng m ho lin tc.B. ch c on intrn. C. vng m ho khng lin tc.D. ch c exn.

Cu 31: sinh vt nhn thcA. cc gen c vng m ho lin tc.B. mt s gen c vng m ho lin tc.C. phn ln cc gen c vng m ho khng lin tc.D. phn ln cc gen c vng m ho lin tc.

Cu 32: sinh vt nhn sA. cc gen c vng m ho lin tc.B. cc gen khng c vng m ho lin tc.C. phn ln cc gen c vng m ho khng lin tc.D. phn ln cc gen khng c vng m ho lin tc.

Cu 33: Bn cht ca m di truyn lA. mt b ba m ho cho mt axitamin.B. 3 nucltit lin k cng loi hay khc loi u m ho cho mt axitamin.C. trnh t sp xp cc nultit trong gen quy nh trnh t sp xp cc axit amin trong prtin.D. cc axitamin c m ho trong gen.

Cu 34: M di truyn c tnh thoi ho vA. c nhiu b ba khc nhau cng m ho cho mt axit amin.B. c nhiu axitamin c m ho bi mt b ba.C. c nhiu b ba m ho ng thi nhiu axitamin.D. mt b ba m ho mt axitamin.

n thi i hc online luyn thi i hc trc tuynCu 35: M di truyn phn nh tnh thng nht ca sinh gii vA. ph bin cho mi sinh vt B. c c mt chiu lin tc t 5 3 c m m u, m kt thc m c tnh c hiu.C. ph bin cho mi sinh vt, l m b 3, m c tnh c hiu, c tnh linh ng.D. c m m u, m kt thc, ph bin cho mi sinh vt, l m b 3.

Cu 36: M di truyn phn nh tnh a dng ca sinh gii vA. c 61 b ba, c th m ho cho 20 loi axit amin.B. s sp xp theo mt trnh t nghim ngt cc b ba to ra bn mt m TTDT c trng cho loiC. s sp xp theo nhiu cch khc nhau ca cc b ba to nhiu bn mt m TTDT khc nhau.D. vi 4 loi nucltit to 64 b m, c th m ho cho 20 loi axit amin.

Cu 37: Qu trnh t nhn i ca ADN din ra theo nguyn tcA. b sung; bn bo ton. B. trong phn t ADN con c mt mch ca m v mt mch mi c tng hp.C. mch mi c tng hp theo mch khun ca m.D. mt mch tng hp lin tc, mt mch tng hp gin on.

Cu 38: cp phn t nguyn tc b sung c th hin trong c chA. t sao, tng hp ARN. B. tng hp ADN, ARN, dch m.C. tng hp ADN, dch m. D. t sao, dch m.

Cu 39: cp phn t nguyn tc bn bo tn c th hin trong c ch A. t sao. B. tng hp ADN, ARN.C. Dch m. D. Tng hp ARN.

Cu 40: Qu trnh phin m c A. vi rt, vi khun.B. sinh vt nhn chun, vi rt. C. sinh vt nhn s, sinh vt nhn thcD. sinh vt nhn s, vi rt.

Cu 41: Qu trnh phin m to ra A. tARN.B. mARN.C. rARN.D. tARNm, mARN, rARN.

n thi i hc online luyn thi i hc trc tuynCu 42: Loi ARN c chc nng truyn t thng tin di truyn lA. ARN thng tin.B. ARN vn chuyn.C. ARN ribxm.D. nARN.

Cu 43: Trong phin m, mch ADN c dng lm khun l mchA. 3, - 5, .B. 5, - 3, .C. 3, - 3,.D. 5, - 5,

Cu 44: Qu trnh t nhn i ca ADN ch c mt mch c tng hp lin tc, mch cn li tng hp gin on vA. enzim ADN plimeraza ch tng hp mch mi theo chiu 5, - 3, .B. enzim ADN plimeraza ch tng hp mch mi theo chiu t 3, - 5, .C. enzim ADN plimeraza ch tng hp mch mi theo chiu t 5, - 5, .D. enzim ADN plimeraza ch tng hp mch mi theo chiu t 3, - 3, .Cu 45: Qu trnh t nhn i ca ADN, NST din ra trong phaA. G1 ca chu k t bo.B. G2 ca chu k t bo.C. S ca chu k t bo.D. M ca chu k t bo.

Cu 46: Qu trnh nhn i ADN din ra .A: T bo cht.B: Ribxm.C: Ti th.D: Nhn t bo.

Cu (4.7.11): Dng thng tin di truyn c trc tip s dng trong tng hp prtin l:A: ADN.B: mARN.C: rARN.D: tARN.

Cu 47: ARN l h gen ca:A: Vi khun.B: Virut.C: Mt s loi virut.D: tt c cc t bo nhn s.

Cu (6.7.11): Trong chu k t bo, s nhn i ADN din ra :A: K trung gian.B: K gia.C: K u.D: K sau v k cui.

Cu 48: Trn mt on mch khun ca phn t ADN c s nucltit cc loi nh sau: A = 60, G = 120, X= 80, T = 30. Sau mt ln nhn i i hi mi trng cung cp s nucltit mi loi l bao nhiu?A. A = T = 180; G = X = 110.C. A = T = 90; G = X = 200.B. A = T = 150; G = X = 140.D. A = T = 200; G = X = 90.

Cu 49: Phn t ADN c chiu di 1,02mm. Khi phn t ny nhn i mt ln, s nucltit t do mi trng ni bo cung cp l:A: 1,2.106.B: 6.105.C: 6.106.D: 3.106.

n thi i hc online luyn thi i hc trc tuynCu 50: Trong qu trnh nhn i ADN, enzim ADN plimeraza di chuyn.A: Theo chiu 5-3 v cng chiu vi mch khun.B: Theo chiu 3-5 v ngc chiu vi mch khun.C: Theo chiu 5 3 v ngc chiu vi chiu m mch khun.D: Ngu nhin.

Cu 51: Cc con no di y khng m ho axit amin (con v ngha)?A: AUA, UAA, UXG.B: AAU, GAU, UXA.C. UAA, UAG, UGA.D. XUG, AXG, GUA.

Bi 2. PHIN M V DCH MCu 1: Qu trnh phin m vi khun E.coli xy ra trongA. RibxmB. t bo cht.C. nhn t bo.D. ti th.

Cu 2: Lm khun mu cho qu trnh phin m l nhim v caA. mch m ho.B. mARN.C. mch m gc.D. tARN.

Cu 3: n v c s dng gii m cho thng tin di truyn nm trong chui polipeptit lA. anticodon.B. axit amin.B. codon.C. triplet.

Cu 4: c im no di y thuc v cu trc ca mARN?A. mARN c cu trc mch kp, dng vng, gm 4 loi n phn A, T, G, X.B. mARN c cu trc mch kp, gm 4 loi n phn A, T, G, X.C. mARN c cu trc mch n, gm 4 loi n phn A, U, G, X.D. mARN c cu trc mch n, dng thng, gm 4 loi n phn A, U, G, X.

Cu 6: Trong qu trnh dch m, mARN thng gn vi mt nhm ribxm gi l poliribxm gipA. tng hiu sut tng hp prtin.B. iu ho s tng hp prtin.C. tng hp cc prtin cng loi.D. tng hp c nhiu loi prtin.

Cu 7: i m c hiu trn phn t tARN c gi lA. codon.B. axit amin.C. anticodon.D. triplet.

Cu 8: ARN c tng hp t mch no ca gen?A. T mch c chiu 5 3.B. T c hai mch n.C. Khi th t mch 1, khi th t mch 2.D. T mch mang m gc.

Cu 9: Loi axit nuclic tham gia vo thnh phn cu to nn ribxm lA. rARN.B. mARN.C. tARN.D. ADN.

Cu 10: Dch m c th hin trong giai onA. tng hp prtein.B. tng hp ADN.C. t sao, tng hp ARN.D. tng hp ADN, ARN.

n thi i hc online luyn thi i hc trc tuynCu 11: Cc chui polipeptit c tng hp trong t bo nhn s uA. kt thc bng Met.B. bt u bng axit amin Met.C. bt u bng axit foocmin-Met.D. bt u t mt phc hp aa-tARN.

Cu 12: Qu trnh tng hp ca ARN, Prtin din ra trong phaA.G1 ca chu k t bo.B.G2 ca chu k t bo.C.S ca chu k t bo.D.M ca chu k t bo.

Cu 13: Cc chui polipeptit c tng hp trong t bo nhn thc uA. kt thc bng Met.B. bt u bng axit amin Met.C. bt u bng axit foocmin-Met.D. bt u t mt phc hp aa-tARN.

Cu 14: Dch m c thc hin bi:A. rARN.B. mARN.C. tARN.D. ARN.

Cu 15: Lm khun mu cho qu trnh dch m l nhim v caA. mch m ho.B. mARN.C. tARN.D. mch m gc.

Cu 16: Phin m l qu trnh tng hp nn phn tA. ADN v ARNB. prtinC. ARND. ADN

Cu 17: Trong qu trnh phin m, ARN-polimeraza s tng tc vi vng no lm gen tho xon?A. Vng khi ng.B. Vng m ho.C. Vng kt thc.D. Vng vn hnh.

Cu 18: Trong qu trnh phin m, chui polinucltit c tng hp theo chiu no?A. 3 3.B. 3 5.C. 5 3.D. 5 5.

Cu 19: Giai on hot ho axit amin ca qu trnh dch m din ra :A. nhn conB. t bo chtC. nhnD. mng nhn

Cu 20: Sn phm ca giai on hot ho axit amin lA. axit amin hot ho.B. axit amin t do.C. chui polipeptit.D. phc hp aa-tARN.

n thi i hc online luyn thi i hc trc tuynCu 21: Giai on hot ho axit amin ca qu trnh dch m nh nng lng t s phn giiA. lipitB. ADPC. ATPD. glucz

Cu 22: Thng tin di truyn trong ADN c biu hin thnh tnh trng trong i c th nh c chA. nhn i ADN v phin m.B. nhn i ADN v dch m.C. phin m v dch m.D. nhn i ADN, phin m v dch m.

Cu 23: Cp baz nit no sau y khng c lin kt hidr b sung?A. U v TB. T v AC. A v UD. G v X

Cu 24: Nhn nh no sau y l ng v phn t ARN?A. Tt c cc loi ARN u c cu to mch thng.B. tARN c chc nng vn chuyn axit amin ti ribxm.C. mARN khng c sao y khun t mch gc ca ADN.D. Trn cc tARN c cc anticodon ging nhau.

Cu 25: Dch m l qu trnh tng hp nn phn tA. mARNB. ADNC. prtinD. mARN v prtin

Cu 26: Enzim chnh tham gia vo qu trnh phin m lA. ADN-polimeraza. B. restrictaza.C. ADN-ligaza.D. ARN-polimeraza.

Cu 27: Trong qu trnh dch m, lin kt peptit u tin c hnh thnh giaA. hai axit amin k nhau.B. axit amin th nht vi axit amin th hai.C. axit amin m u vi axit amin th nht.D. hai axit amin cng loi hay khc loi.

Cu 28: n v m ho cho thng tin di truyn trn mARN c gi lA. anticodon.B. codon.C. triplet.D. axit amin.

Cu 29: Loi ARN no sau y c b ba i m?A: rARN.B: tARN.C: mARN.D: c 3 loi.

n thi i hc online luyn thi i hc trc tuynCu 30: Cc con no di y khng m ho axit amin (con v ngha)?A: AUA, UAA, UXG.B: AAU, GAU, UXA.C. UAA, UAG, UGA.D. XUG, AXG, GUA.

Cu 31: Qu trnh dch m kt thc khi:A: Ribxm tip xc vi con AUG trn mARN.B: Ribxm ri khi mARN v tr v trng thi t do.C: Ribxm tip xc vi 1 trong 3 b ba UAA, UAG, UGA.D: Ribxm gn axitamin Met vo v tr cui cng ca chui plipeptit.

Bi 3. IU HA HOT NG GENCu 1: iu ha hot ng gen chnh l:A. iu ha qu trnh dch m.B. iu ha lng sn phm ca gen.C. iu ha qu trnh phin m.D. iu ho hot ng nhn i ADN.

Cu 2: Trong c ch iu ha hot ng ca opron Lac E.coli, khi mi trng c lactz thA. prtin c ch khng gn vo vng vn hnh.B. prtin c ch khng c tng hp.C. sn phm ca gen cu trc khng c to ra.D. ARN-polimeraza khng gn vo vng khi ng.

Cu 3: Operon Lac ca vi khun E.coli gm c cc thnh phn theo trt t:A. vng khi ng vng vn hnh nhm gen cu trc (Z,Y,A)B. gen iu ha vng vn hnh vng khi ng nhm gen cu trc (Z, Y, A)C. gen iu ha vng khi ng vng vn hnh nhm gen cu trc (Z, Y, A)D. vng khi ng gen iu ha vng vn hnh nhm gen cu trc (Z, Y, A)

Cu 4: Enzim ARN polimeraza ch khi ng c qu trnh phin m khi tng tc c vi vngA. vn hnh.B. iu ha.C. khi ng.D. m ha.

Cu 5: Operon lA. mt on trn phn t ADN bao gm mt s gen cu trc v mt gen vn hnh chi phi.B. cm gm mt s gen iu ha nm trn phn t ADN.C. mt on gm nhiu gen cu trc trn phn t ADN.D. cm gen cu trc c chung mt c ch iu

Cu 6: Gen iu ha R khi hot ng s tng hp nn:A. Enzim phn hy lactz.B. prtin c ch.C. lactz.D. Enzim iu khin Operon.

Cu 7: iu ha hot ng gen ca sinh vt nhn s ch yu xy ra giai onA. phin m.B. dch m.C. sau dch m.D. sau phin m.

n thi i hc online luyn thi i hc trc tuynCu 8: Trong c ch iu ha hot ng ca opron Lac E.coli, khi mi trng khng c lactz th prtin c ch s c ch qu trnh phin m bng cchA. lin kt vo vng khi ng.B. lin kt vo gen iu ha.C. lin kt vo vng vn hnh.D. lin kt vo vng m ha.

Cu 9: Trong c ch iu ha hot ng ca opron Lac E.coli, lactz ng vai tr ca chtA. xc tcB. c ch.C. cm ng.D. trung gian.Cu 10: Ni m ADN plimraza bm vo v khi u cho phin m l:A. vng iu ha.B. vng khi ng.C. gen iu ha.D. vng vn hnh

Cu 11: Theo c ch iu ha hot ng ca opron Lac E.coli, khi c mt ca lactz trong t bo, lactz s lin kt vi:A. vng khi ng.B. enzim phin mC. prtin c ch.D. vng vn hnh.

Cu 12: Khng thuc thnh phn ca mt opron nhng c vai tr quyt nh hot ng ca opron lA. vng vn hnh.B. vng m ha.C. gen iu ha.D. gen cu trc.

Cu 13: Hot ng ca gen chu s kim sot biA. gen iu ho.B. c ch iu ho c ch.C. c ch iu ho cm ng.D. c ch iu ho.

Cu 14: Hai nh khoa hc ngi Php pht hin ra c ch iu ho hot ng gen :A. vi khun lactic.B. vi khun E. coli.C. vi khun Rhizobium.D. vi khun lam.

Cu 15: Trong opron Lac, vai tr ca cm gen cu trc Z, Y, A l:A. tng hp prtein c ch bm vo vng khi ng khi u phin m.B. tng hp enzim ARN polimeraza bm vo vng khi ng khi u phin m.C. tng hp prtein c ch bm vo vng vn hnh ngn cn qu trnh phin m.D. tng hp cc loi enzim tham gia vo phn ng phn gii ng lactz.

Cu 16: Trong mt opron, vng c trnh t nucltit c bit prtin c ch c th lin kt ngn cn qu trnh phin m, l vng:A. khi ng.B. vn hnh.C. iu ho.D. kt thc.

n thi i hc online luyn thi i hc trc tuynCu 17: Khi no th cm gen cu trc Z, Y, A trong opron Lac E. coli hot ng?A. Khi mi trng c hoc khng c lactz. B. Khi trong t bo c lactz.C. Khi trong t bo khng c lactz.D. Khi prtein c ch bm vo vng vn hnh.

Cu 18: Hai nh khoa hc no pht hin ra c ch iu ho opron?A. Menen v Morgan.B. Jacp v Mn.C. Lamac v acuyn.D. Haci v Vanbec.

Bi 4. T BIN GENCu 1: t bin gen l nhng bin i trong cu trc ca:A. Gen.B. NST.C. Nucltit.D. A.amin.

Cu 2: Loi t bin khng di truyn qua sinh sn hu tnh l t bin xy ra :A. gen.B. NST.C. T bo xma.D. giao t.

Cu 3: Th t bin l nhng c th mang gen t binA. biu hin ra kiu hnh. B. nhim sc th.C. gen hay t bin nhim sc th. D. mang t bin gen.

Cu 4: S pht sinh t bin gen ph thuc voA. cng , liu lng, loi tc nhn gy t bin v cu trc ca gen.B. mi quan h gia kiu gen, mi trng v kiu hnh.C. sc khng ca tng c th.D. iu kin sng ca sinh vt.

Cu 5: t bin im c cc dngA.mt, thm, thay th 1 cp nultit. B.mt, thm, o v tr 1 cp nultit.C.mt, thay th, o v tr vi cp nultitD.thm, thay th, o v tr vi cp nultit.

Cu 6: t bin mt cp nucltit gy hu qu ln nht trong cu trc ca gen v trA.u gen.B.gia gen.C.2/3 gen.D.cui gen.

Cu 7: Guanin dng him kt cp vi timin trong nhn i ADN to nnA. 2 phn t timin trn cng 1 mch ADN gn ni vi nhau. B. t bin A-TG-X.C. t bin G-X A-T. D. s sai hng ngu nhin.Cu 8: Tc nhn ho hc nh 5- brm uraxin l cht ng ng ca timin gyA. t bin thm A. B. t bin mt A.C. 2 phn t timin trn cng 1 mch AND gn ni vi nhau.D. t bin A-TG-X

Cu 9: Tc ng ca tc nhn vt l nh tia t ngoi (UV) gy ra: A.t bin thm A.B.t bin mt A.C. 2 phn t timin trn cng 1 mch AND gn ni vi nhau.D.t bin A-TG-X.

Cu 11: Trng hp gen cu trc b t bin thay th 1 cp G-X bng 1 cp A-T th s lin kt hyr s A. tng 1.B. tng 2.C. gim 1.D. gim 2.

Cu 10: Trng hp gen cu trc b t bin thay th 1 cp A-T bng 1 cp G-X th s lin kt hyr s A. tng 1.B. tng 2.C. gim 1.D. gim 2.

Cu 12: Trng hp t bin lin quan ti 1 cp nucltit lm cho gen cu trc c s lin kt hidro khng thay i so vi gen ban u l t binA. o v tr 1 cp nucltit.B. o v tr hoc thay th cp nucltit cng loi.C. o v tr hoc thm 1 cp nucltit.D. thay th cp nucltit.

Cu 13: Tc nhn sinh hc c th gy t bin gen lA. vi khunB. ng vt nguyn sinhC. 5BUD. virut hecpet

n thi i hc online luyn thi i hc trc tuynCu 14: Xt t bin gen do 5BU, th t dng tin t bin n khi xut hin gen t bin phi quaA. 1 ln nhn i.B. 2 ln nhn i.C. 3 ln nhn i.D. 4 ln nhn i.

Cu 15: Guanin dng him (G*) kt cp khng ng trong ti bn s gyA. bin i cp G-X thnh cp A-TB. bin i cp G-X thnh cp X-GC. bin i cp G-X thnh cp T-AD. bin i cp G-X thnh cp A-UCu 16: Trong cc dng t bin gen, dng no thng gy bin i nhiu nht trong cu trc ca prtin tng ng, nu t bin khng lm xut hin b ba kt thc?A. Mt mt cp nucltit.B. Thm mt cp nucltit.C. Mt hoc thm mt cp nucltit.D. Thay th mt cp nucltit

Cu 17: Phn nhiu t bin im thng:A. C hi.B. Trung tnh.C. C li.D. Xy ra u gen.

Cu 18: t bin thay th mt cp nucltit v tr s 9 tnh t m m u nhng khng lm xut hin m kt thc. Chui polipeptit tng ng do gen ny tng hpA. mt mt axit amin v tr th 3 trong chui polipeptit.B. thay i mt axit amin v tr th 3 trong chui polipeptit.C. c th thay i mt axit amin v tr th 2 trong chui polipeptit.D. c th thay i cc axit amin t v tr th 2 v sau trong chui polipeptit.Cu 19: Dng t bin im lm dch khung c m di truyn lA. thay th cp A-T thnh cp T-AB. thay th cp G-X thnh cp T-AC. mt cp nucltit A-T hay G-XD. thay th cp A-T thnh cp G-X

Cu 20: t bin gen ln s biu hin trn kiu hnhA. khi trng thi d hp t v ng hp tB. thnh kiu hnh ngay th h sau.C. ngay c th mang t bin.D. khi trng thi ng hp t.

Cu 21: Bin i trn gen lin quan n mt cp nucltit c gi lA. t bin NSTB. t bin gen.C. th t bin.D. t bin im.

Cu 22: t bin gen thng gy hi cho c th mang t bin vA. lm ngng tr qu trnh phin m, khng tng hp c prtin.B. lm bin i cu trc gen dn ti c th s/vt khng kim sot c qu trnh ti bn ca gen.C. lm gen b bin i dn ti khng k tc vt cht di truyn qua cc th h.D. lm sai lch thng tin di truyn dn ti lm ri lon qu trnh sinh tng hp prtin.

n thi i hc online luyn thi i hc trc tuynCu 23: Chui plipeptit do gen t bin tng hp so vi chui plipeptit do gen bnh thng tng hp c s axit amin bng nhau nhng khc nhau axit amin th 80. t bin im trn gen cu trc ny thuc dng:A. thay th mt cp nucltit b ba th 80.B. mt mt cp nucltit v tr th 80.C. thay th mt cp nucltit b ba th 81.D. thm mt cp nucltit vo v tr 80.

Bi 5. NHIM SC TH V T BIN CU TRC NHIM SC THCu 1: Nhm sinh vt cha c cu trc NST l:A. to lc.B. vi khun.C. rui gim.D. sinh vt nhn thc.

Cu 2: Dng t bin cu trc NST chc chn dn n lm tng s lng gen trn nhim sc th lA. mt on. B. o on.C. lp on.D. chuyn on.

Cu 3: Mc xon 3 trong cu trc siu hin vi ca nhim sc th sinh vt nhn thc gi lA. nuclxm.B. si nhim sc.C. si siu xon.D. si c bn.

Cu 4: loi b nhng gen xu khi nhim sc th, ngi ta vn dng hin tngA. mt on nh. B. mt on ln.C. chuyn on nh.D. chuyn on ln.

Cu 5: Trnh t nucltit trong ADN c tc dng bo v v lm cc NST khng dnh vo nhau nm A. tm ng.B. hai u mt NST.C. eo th cp.D. im khi s nhn i.

Cu 6: Trao i on gia 2 nhim sc th khng tng ng gy hin tngA. chuyn on.B. lp on.C. o on.D. hon v gen.n thi i hc online luyn thi i hc trc tuynCu 7: Trong chu k t bo, nhim sc th n co xon cc i quan st c di knh hin vi voA. k trung gian.B. k gia.C. k sau.D. k cui.

Cu 8: n v nh nht trong cu trc nhim sc th gm 2 thnh phn ADN v prtin histon lA. nuclxm.B. polixm.C. nucltit.D. si c bn.

Cu 9: Dng t bin cu trc nhim sc th thng gy mt cn bng gen nghim trng nht l:A. o on.B. chuyn on.C. mt on.D. lp on.Cu 10: iu khng ng khi cho rng: cc loi n tnh giao phi, nhim sc th gii tnhA. ch tn ti trong t bo sinh dc ca c th.B. ch gm mt cp, tng ng gii ny th khng tng ng gii kia.C. khng ch mang gen quy nh gii tnh m cn mang gen quy nh tnh trng thng.D. ca cc loi th, rui gim con c l XY con ci l XX.

Cu 11: S co xon cc mc khc nhau ca nhim sc th to iu kin thun li choA. s phn li nhim sc th trong phn bo. B. s t hp nhim sc th trong phn bo.C. s biu hin hnh thi NST k gia.D. s phn li v t hp NST trong phn bo.

Cu 12: Phn t ADN lin kt vi prtin m ch yu l histon to nn cu trc c hiu, cu trc ny ch pht hin t boA. thc khun.B. vi khun.C. x khun.D. sinh vt nhn thc.Cu 13: Trnh t nucltit c bit trong ADN ca NST, l v tr lin kt vi thoi phn bo c gi lA. tm ng.B. hai u mt NST.C. eo th cp. D. im khi u nhn i.

Cu 14: Dng t bin cu trc nhim sc th c vai tr quan trng trong qu trnh hnh thnh loi mi lA. lp on.B. mt on.C. o on.D. chuyn on.

n thi i hc online luyn thi i hc trc tuynCu 15: Dng t bin no c ng dng loi khi nhim sc th nhng gen khng mong mun mt s ging cy trng?A. t bin gen.B. Mt on nh.C. Chuyn on nh.D. t bin lch bi.

Cu 16: Mi loi sinh vt c b nhim sc th c trng biA.s lng, hnh dng, cu trc nhim sc th. B.s lng , hnh thi nhim sc th.C.s lng, cu trc nhim sc th.D.s lng khng i.

Cu 17: n v cu trc gm mt on ADN cha 146 cp nu qun quanh 8 phn t histon 1 vng ca nhim sc th sinh vt nhn thc c gi lA. ADN.B. nuclxm.C. si c bn.D. si nhim sc.

Cu 18: Mc cu trc xon ca nhim sc th c chiu ngang 30nm lA. si ADN.B. si c bn.C. si nhim sc.D. cu trc siu xon.

Cu 20: S lin kt gia ADN vi histn trong cu trc ca nhim sc th m bo chc nngA. lu gi, bo qun, truyn t thng tin di truyn. B. phn li NST trong phn bo thun li.C. t hp NST trong phn bo thun li. D. iu ha hot ng cc gen trong AND trn NST.

Cu 21: Nhim sc th di gp nhiu ln so vi ng knh t bo, nhng vn c xp gn trong nhn vA. ng knh ca n rt nh.B. n c ct thnh nhiu on.C. n c ng xon nhiu cp . D. n c dn nn lai thnh nhn con.

Cu 22: t bin lm tng cng hm lng Amylaza i mch thuc dngA. mt on nhim sc th.B. lp on nhim sc th.C. o on nhim sc th.D. chuyn on nhim sc th.

Cu 23: Phn t ADN lin kt vi prtin m ch yu l histon to nn cu trc c hiu gi lA. nhim sc th.B. axit nuclic.C. gen.D. nhn con.n thi i hc online luyn thi i hc trc tuynCu 24: Loi t bin cu trc nhim sc th khng lm thay i hm lng ADN trn nhim sc th lA. lp on, chuyn on.B. o on, chuyn on trn cng mt NST.C. mt on, chuyn on.D. chuyn on trn cng mt NST.

Cu 25: C ch pht sinh t bin cu trc nhim sc th l do tc nhn gy t bin:A. lm t gy NST, ri lon nhn i NST, trao i cho khng u gia cc crmatt.B. lm t gy nhim sc th, lm nh hng ti qu trnh t nhn i ADN.C. tip hp hoc trao i cho khng u gia cc crmatt.D. lm t gy nhim sc th dn n ri lon trao i cho.

Cu 26: S thu gn cu trc khng gian ca nhim sc th A. thun li cho s phn ly cc nhim sc th trong qu trnh phn bo.B. thun li cho s t hp cc nhim sc th trong qu trnh phn bo.C. thun li cho s phn ly, s t hp cc nhim sc th trong qu trnh phn bo.D. gip t bo cha c nhiu nhim sc th.

Cu 27: Mt nuclxm gmA.mt on phn t ADN qun 11/4 vng quanh khi cu gm 8 phn t histn.B.phn t ADN qun 7/4 vng quanh khi cu gm 8 phn t histn.C.phn t histn c qun quanh bi mt on ADN di 146 cp nucltit.D. 8 phn t histn c qun quanh bi 7/4 vng xon ADN di 146 cp nucltit.

Cu 28: Mc xon 1 ca nhim sc th lA. si c bn, ng knh 11 nm.B. si cht nhim sc, ng knh 30 nm.C. siu xon, ng knh 300 nm. D. crmatt, ng knh 700 nm.

Cu 29: Mc xon 2 ca nhim sc th lA. si c bn, ng knh 11 nm.B. si cht nhim sc, ng knh 30 nm.C. siu xon, ng knh 300 nm. D. crmatt, ng knh 700 nm.

Cu 30: Mc xon 3 ca nhim sc th lA. si c bn, ng knh 11 nm. B. si cht nhim sc, ng knh 30 nm.C. siu xon, ng knh 300 nm.D. crmatt, ng knh 700 nm.

Cu 31: Cu trc ca NST sinh vt nhn thc c cc mc xon theo trt t:A. Phn t ADN n v c bn nuclxm si c bn si nhim sc crmatitB. Phn t ADN si c bn n v c bn nuclxm si nhim sc crmatitC. Phn t ADN n v c bn nuclxm si nhim sc si c bn crmatitD. Phn t ADN si c bn si nhim sc n v c bn nuclxm crmatit

Cu 32: ngi, mt on nhim sc th s 21 s gy nn bnhA. ung th mu.B. bnh ao.C. mu kh ng.D. hng cu hnh li lim.

Cu 33: ngi, mt phn vai di nhim sc th s 22 s gy nn bnhA. ung th mu c tnh.B. bnh ao.C. mu kh ng.D. hng cu hnh li lim.

Cu 34: ngi, mt phn vai ngn nhim sc th s 5 s gy nn hi chngA. ting mo ku.B. bnh ao.C. mu kh ng.D. hng cu hnh li lim.

n thi i hc online luyn thi i hc trc tuynCu 35: NST thng c trnh t sau: A B C D E F G H * Hy xc nh dng t bin NST c minh ho trong cc trng hp sau :a. A B C F E D G H *b. A B C D E F E F G H *c. A B D E F G H *

Cu 36: Nu t bo lng bi c bnh thng c 2n NST. S NST c trong t bo ca nhng trng hp sau l bao nhiu?a. Th khng.b. Th mt.c.Th ba.d. Th ba kp.e. T bi.f. Lc bi.

Cu 37: Nhng sp xp gen sau y trn 1 NST thy rui gim D.meanogaster ti cc vng a l khc nhau.a.ABCDEFGHI.b. HEFBAGCDI.c.ABFEHGCDI.d.ABFCGHEDI.e.ABFEHGCDI.Cho rng sp xp a l sp xp ban u, cc o on khc c th xut hin theo trnh t no?

Cu 37: t bin NST gm:A. t bin cu trc v t bin s lng NST.B. Thm on v o on NST.C. Lch bi v a bi.D. a bi chn v a bi l.

Cu 38: Dng t bin no sau y thng gy cht hoc lm gim sc sng?A: Chuyn on nh.B: Mt on.C: Lp on.D: o on.

Bi 6. T BIN S LNG NHIM SC THCu 1: ngi, mt s bnh di truyn do t bin lch bi (D bi) c pht hin lA. ung th mu, Tcn, Claiphent.B. Claiphent, ao, Tcn.C. Claiphent, mu kh ng, ao.D. siu n, Tcn, ung th mu.

Cu 2: Ri lon phn li ca nhim sc th k sau trong phn bo l c ch lm pht sinh t binA. lch bi.B. a bi.C. cu trc NST.D. s lng NST.

Cu 3: S khng phn ly ca mt cp nhim sc th tng ng t bo sinh dng sA. dn ti trong c th c dng t bo bnh thng v dng mang t bin.B. dn ti tt c cc t bo ca c th u mang t bin.C. ch c c quan sinh dc mang t bin. D. ch cc t bo sinh dng mang t bin.

Cu 4: c chua 2n = 24. Khi quan st tiu bn ca 1 t bo sinh dng loi ny ngi ta m c 22 NST trng thi cha nhn i. B nhim sc th trong t bo ny c k hiu lA. 2n 2B. 2n 1 1C. 2n 2 + 4D. A, B ng.

n thi i hc online luyn thi i hc trc tuynCu 5: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cy thn cao 2n + 1 c kiu gen AAa t th phn th kt qu phn tnh F1 s lA. 35 cao: 1 thp.B. 5 cao: 1 thp.C. 3 cao: 1 thp.D. 11 cao: 1 thp.

Cu 6: C th m t bo sinh dng u tha 2 nhim sc th trn 2 cp tng ng c gi lA. th ba.B. th ba kp.C. th bn.D. th t bi

Cu 7: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 4n c kiu gen AAaa s sinh ra cc loi giao t:A. 1AA : 4Aa : 1aaB. 2AA : 4Aa : 2aaC. AA : aaD. Aa : aa

Cu 8: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 4n c kiu gen Aaaa s sinh ra cc loi giao t:A. 1AA : 4Aa : 1aaB. 2AA : 4Aa : 2aaC. AA : aaD. Aa : aa

Cu 9: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 4n c kiu gen AAAa s sinh ra cc loi giao t:A. 1AA : 4Aa : 1aaB. 2AA : 4Aa : 2aaC. AA : AaD. Aa : aa

Cu 10: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 4n c kiu gen AAAA s sinh ra cc loi giao t:A. 1AA : 4Aa : 1aaB. 2AA : 4Aa : 2aaC. AA : aaD. 100% AA

Cu 11: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 4n c kiu gen AAAA s sinh ra cc loi giao t:A. 1AA : 4Aa : 1aaB. 2AA : 4Aa : 2aaC. AA : aaD. 100% AA

Cu 12: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 3n c kiu gen AAA s sinh ra cc loi giao t:A. 1A : 2a : 1AA : 2aaB. A : AAC. 2A : 1a : 1AA : 2AaD. 100% AA

Cu 13: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 3n c kiu gen AAa s sinh ra cc loi giao t:A. 1A : 2a : 1AA : 2aaB. A : AAC. 2A : 1a : 1AA : 2AaD. 100% AA

n thi i hc online luyn thi i hc trc tuynCu 14: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 3n c kiu gen Aaa s sinh ra cc loi giao t:A. 1A : 2a : 2Aa : 1aaB. A : AAC. 2A : 1a : 1AA : 2AaD. 100% AA

Cu 15: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 2n + 1 c kiu gen Aaa giao phn vi cy thn cao 2n + 1 c kiu gen Aaa th kt qu phn tnh F1 s lA. 35 cao: 1 thp.B. 5 cao: 1 thp.C. 3 cao: 1 thp.D. 11 cao: 1 thp.Cu 16: mt loi thc vt, gen A qui nh thn cao l tri hon ton so vi thn thp do gen a qui nh. Cho cy thn cao 4n c kiu gen AAaa giao phn vi cy thn cao 4n c kiu gen Aaaa th kt qu phn tnh F1 s lA. 35 cao: 1 thp.B. 11 cao: 1 thp.C. 3 cao: 1 thp.D. 5 cao: 1 thp.Cu 17: mt loi thc vt, gen A qui nh qu tri hon ton so vi gen a qui nh qu vng. Cho cy 4n c kiu gen aaaa giao phn vi cy 4n c kiu gen AAaa, kt qu phn tnh i lai lA. 11 : 1 vng.B. 5 : 1 vng.C. 1 : 1 vng.D. 3 : 1 vng.

Cu 18: c c dc 2n = 24. S dng t bin th ba c pht hin loi ny lA. 12.B. 24.C. 25.D. 23.

Cu 19: C th m t bo sinh dng u tha 2 nhim sc th trn mi cp tng ng c gi lA. th ba.B. th ba kp.C. th bn.D. th t bi

Cu 20: C th m t bo sinh dng u tha 2 nhim sc th trn 1 cp tng ng c gi lA. th ba.B. th ba kp.C. th bn.D. th t bi

Cu 21: t bin lch bi l s bin i s lng nhim sc th lin quan tiA. mt s cp nhim sc th.B. mt s hoc ton b cc cp nhim sc th.C. mt, mt s hoc ton b cc cp NST.D. mt hoc mt s cp nhim sc th.

Cu 22: Mt loi sinh vt c b NST 2n = 14 v tt c cc cp NST tng ng u cha nhiu cp gen d hp. Nu khng xy ra t bin gen, t bin cu trc NST v khng xy ra hon v gen, th loi ny c th hnh thnh bao nhiu loi th ba khc nhau v b NST?A. 7.B. 14.C. 35.D. 21.

Cu 23: mt loi thc vt, gen A qui nh tnh trng ht tri hon ton so vi gen a qui nh tnh trng ln ht trng. Cho cy d hp 4n t th phn, F1 ng tnh cy ht . Kiu gen ca cy b m lA. AAaa x AAaaB. AAAa x AAAaC. AAaa x AaaaD. Aaaa x Aaaa

n thi i hc online luyn thi i hc trc tuynCu 24: Khi x l cc dng lng bi c kiu gen AA, Aa, aa bng tc nhn cnsixin, c th to ra c cc dng t bi no sau y? 1/ AAAA ; 2/ AAAa ; 3/ AAaa ; 4/ Aaaa ; 5/ aaaaA. 2, 4, 5.B. 1, 2, 3.C. 1, 3, 5.D. 1, 2, 4.

Cu 25: Php lai AAaa x AAaa to kiu gen AAaa th h sau vi t lA. 2/9B. 1/4C. 1/8D. 1/2.

Cu 26: t bin s lng nhim sc th l s bin i s lng nhim sc th c lin quan ti mtA. hoc mt s cp NST.B. s cp NST.C. s hoc ton b cc cp NST.D. mt s hoc ton b cc cp NST.

Cu 27: t bin lch bi l s bin i s lng nhim sc th lin quan ti mtA. mt hoc mt s cp NST.B. mt s cp NST.C. mt s hoc ton b cc cp NST.D. mt s hoc ton b cc cp NST.

Cu 28: S thay i s lng nhim sc th ch lin quan n mt hay mt s cp nhim sc th gi lA.th lch bi.B.a bi th l.C.th tam bi. D.th t bi.

Cu 29: Trng hp c th sinh vt trong b nhim sc th gm c hai b nhim ca loi khc nhau l A.th lch bi.B.a bi th chn.C.th d a bi. D.th lng bi.

Cu 30: S khng phn ly ca mt cp nhim sc th tng ng t bo sinh dng s A. dn ti tt c cc t bo ca c th u mang t bin.B. ch cc t bo sinh dng mang t bin.C. dn ti trong c th c hai dng t bo bnh thng v dng mang t bin.D. ch c c quan sinh dc mang t bin.

Cu 31: a bi th l trong t bo cha s nhim sc thA. n bi ln hn 2n.B. gp i s nhim sc th.C. 2n + 2.D. 4n + 2.

Cu 32: Cht cnsixin thng c dng gy t bin th a bi, bi v n c kh nngA. kch thch c quan sinh dng pht trin nn cc b phn ny thng c kch thc ln.B. tng cng s trao i cht t bo, tng sc chu ng sinh vt.C. tng cng qu trnh sinh tng hp cht hu c.D. cn tr s hnh thnh thoi v sc lm cho nhim sc th khng phn ly.Cu 33: C ch pht sinh t bin s lng nhim sc th lA. qu trnh tip hp v trao i cho ca nhim sc th b ri lon.B. qu trnh t nhn i ca nhim sc th b ri lon.C. s phn ly bt thng ca mt hay nhiu cp nhim sc th ti k sau ca qu trnh phn bo.D. thoi v sc khng hnh thnh trong qu trnh phn bo.

n thi i hc online luyn thi i hc trc tuynCu 34: Mt loi c b nhim sc th 2n = 14. Mt c th ca loi trong t bo c 21 nhim sc th c th thuc thA. d bi.B. tam nhim.C. tam bi.D. a bi lch.

Cu 35: Mt loi c b nhim sc th 2n = 24. Mt cc th ca loi trong t bo c 48 nhim sc th c th thuc thA. t bi.B. bn nhim.C. d bi.D. a bi lch.

Cu 36: Th a bi c hnh thnh do trong phn boA. mt s cp NST khng phn ly.B. tt c cc cp NST khng phn ly.C. mt cp NST khng phn ly.D. mt na s cp NST khng phn ly.

Cu 37: D a bi l hin tng trong t bo cha b nhim sc thA. lng bi ca loi.B. lng bi ca 2 loi. C. ln hn 2n.D. n bi ca 2 loi.

Cu 38: Nu k hiu b nhim sc th ca loi th nht l AA, loi th 2 l BB th song nh bi lA. AABB.B. AAAA.C. BBBB.D. AB.

Cu 39: Nu k hiu b nhim sc th lng bi ca loi th nht l AA, loi th 2 l BB, t a bi gmA.AABB v AAAA.B.AAAA v BBBB.C.BBBB v AABB.D.AB v AABB.

Cu 40: Nu k hiu b nhim sc th lng bi ca loi th nht l AA, loi th 2 l BB, th d t bi l

A. AABB.B. AAAA.C. BBBB.D. AB.

Cu 41: S kt hp gia giao t 2n ca loi A vi giao t 2n ca loi B to thA. t bi.B. song nh bi.C. bn nhim.D. bn nhim kp.

Cu 42: Trong t nhin a bi th thng gp ph bin A. vi khun.B. cc loi sinh sn hu tnh.C. thc vt.D. nm.

Cu 43: Hin tng a bi ng vt rt him xy ra vA. chng mn cm vi cc yu t gy t bin.B. c quan sinh sn thng nm su trong c th nn rt t chu nh hng ca cc tc nhn gy a bi.C. c quan sinh sn thng nm su trong c th, h thn kinh rt nhy cm d cht khi b x l.D. chng thng chu tc ng ca ha cht.

Chng II. TNH QUY LUT CA HIN TNG DI TRUYNBi 8. QUY LUT MENEN: QUY LUT PHN LYCu 1: Cc bc trong phng php lai v phn tch c th lai ca Menen gm:1. a gi thuyt gii thch kt qu v chng minh gi thuyt2. Lai cc dng thun khc nhau v 1 hoc vi tnh trng ri phn tch kt qu F1,F2,F3.3. To cc dng thun chng.4. S dng ton xc sut phn tch kt qu laiTrnh t cc bc Menen tin hnh nghin cu rt ra c quy lut di truyn l:A. 1, 2, 3, 4B. 2, 3, 4, 1C. 3, 2, 4, 1D. 2, 1, 3, 4

Cu 2: c im no sau y trong phn bo c s dng gii thch cc quy lut di truyn Menen?A. S phn chia ca nhim sc th.B. S nhn i v phn li ca nhim sc th.C. S tip hp v bt cho nhim sc th.D. S phn chia tm ng k sau.

Cu 3: Theo Menen, php lai gia 1 c th mang tnh trng tri vi 1 c th ln tng ng c gi lA. lai phn tch.B. lai khc dng.C. lai thun-nghchD. lai ci tin.Cu 4: Ging thun chng l ging cA. kiu hnh th h con hon ton ging b m.B. c tnh di truyn ng nht nhng khng n nh qua cc th h.C. c tnh di truyn ng nht v n nh qua cc th h.D. kiu hnh th h sau hon ton ging b hoc ging m.n thi i hc online luyn thi i hc trc tuynCu 5: Alen l g?A. L nhng trng thi khc nhau ca cng mt gen.B. L trng thi biu hin ca gen.C. L cc gen khc bit trong trnh t cc nucltit.D. L cc gen c pht sinh do t bin.

Cu 6: Theo quan nim v giao t thun khit ca Menen, c th lai F1 khi to giao t th:A. mi giao t u cha mt nhn t di truyn ca b v m.B. mi giao t ch cha mt nhn t di truyn ca b hoc m.C. mi giao t cha cp nhn t di truyn ca b v m, nhng khng c s pha trn.D. mi giao t u cha cp nhn t di truyn hoc ca b hoc ca m.

Cu 7: Theo Menen, trong php lai v mt cp tnh trng tng phn, ch mt tnh trng biu hin F1. Tnh trng biu hin F1 gi lA. tnh trng u vit.B. tnh trng trung gian.C. tnh trng tri.D. tnh trng lnCu 8: Quy lut phn ly ca Menen khng nghim ng trong trng hp:A. b m thun chng v cp tnh trng em lai.B. s lng c th thu c ca php lai phi ln.C. tnh trng do mt gen qui nh trong gen tri t hon ton gen ln.D. tnh trng do mt gen qui nh v chu nh hng ca mi trng.

Cu 9: iu khng thuc v bn cht ca quy lut phn ly Menen l g?A. Mi tnh trng ca c th do mt cp nhn t di truyn quy nh.B. Mi tnh trng ca c th do nhiu cp gen qui nh.C. Do s phn ly ng u ca cp nhn t di truyn nn mi giao t ch cha mt nhn t ca cp.D. F1 tuy l c th lai nhng khi to giao t th giao t l thun khit.

Cu 10: C s t bo hc ca quy lut phn li lA. s phn li v t hp ca cp nhn t di truyn trong gim phn v th tinh.B. s phn li ca cp nhim sc th tng ng trong gim phnC. s phn li v t hp ca cp nhim sc th tng ng trong gim phn v th tinh.D. s t hp ca cp nhim sc th tng ng trong th tinh.Cu 11: Locut l:A. V tr xc nh ca nhiu gen trn nhim sc th.B. v tr xc nh ca mi gen trn nhim sc th.C. V tr xc nh ca mi tnh trng trn nhim sc th.D. v tr xc nh ca nhiu tnh trng trn nhim sc th.Cu 12:. Menen kim tra gi thuyt v qui lut phn li ca mnh bng cch no?A. Cho F1 lai phn tch.B. Cho F2 t th phn.C. Cho F1 giao phn vi nhau.D. Cho F1 t th phn.

n thi i hc online luyn thi i hc trc tuynCu 13: Cp alen lA. hai alen ging nhau thuc cng mt gen trn cp nhim sc th tng ng sinh vt lng bi.B. hai alen ging nhau hay khc nhau thuc cng mt gen trn cp NST tng ng sinh vt lng bi.C. hai gen khc nhau cng nm trn cp nhim sc th tng ng sinh vt lng bi.D. hai alen khc nhau thuc cng mt gen trn cp nhim sc th tng ng sinh vt lng bi.

Cu 14: Kiu gen l t hp gm ton b:A. cc tnh trng trong t bo ca c th sinh vt.B. cc alen trong t bo ca c th sinh vt.C. cc NST trong t bo ca c th sinh vtD. cc gen trong t bo ca c th sinh vt.Cu 15: C s t bo hc ca quy lut phn li ca Menen l:A. Cc thnh vin ca cp Alen & mi NST trong cp NST tng ng phn li ng u v cc giao t.B. s t hp ca cp nhim sc th tng ng trong th tinh.C. s phn li v t hp ca cp nhim sc th tng ng trong gim phn v th tinh.D. s phn li ca cp nhn t di truyn trong gim phn.Cu 16: Trong cc th nghim ca Menen, khi lai b m thun chng khc nhau v mt cp tnh trng tng phn, ng nhn thy th h th haiA. c s phn ly theo t l 3 tri: 1 ln.B. c s phn ly theo t l 1 tri: 1 ln.C. u c kiu hnh khc b m.D. u c kiu hnh ging b m.

Cu 17: V khi nim, kiu hnh lA. do kiu gen qui nh, khng chu nh hng ca cc yu t khc.B. s biu hin ra bn ngoi ca kiu gen.C. t hp ton b cc tnh trng v c tnh ca c th.D. kt qu ca s tc ng qua li gia kiu gen v mi trng.Cu 18: Theo Menen, php lai gia 1 c th mang tnh trng tri vi 1 c th ln tng ng c gi lA. lai phn tch.B. lai khc dng.C. lai thun-nghchD. lai ci tin.Cu 19: Ging thun chng l ging cA. kiu hnh th h con hon ton ging b m.B. c tnh di truyn ng nht nhng khng n nh qua cc th h.C. c tnh di truyn ng nht v n nh qua cc th h.D. kiu hnh th h sau hon ton ging b hoc ging m.Cu 20: Alen l g?A. Hai trng thi khc nhau ca cng mt gen.B. Mi trng thi khc nhau ca cng mt gen.C. Mi trng thi khc nhau ca cng mt tnh trng.D. Nhiu trng thi khc nhau ca cng mt tnh trng.

Cu 21: Theo quan nim v giao t thun khit ca Menen, c th lai F1 khi to giao t th:A. mi giao t u cha mt nhn t di truyn ca b v m.B. mi giao t ch cha mt nhn t di truyn ca b hoc m.C. mi giao t cha cp nhn t di truyn ca b v m, nhng khng c s pha trn.D. mi giao t u cha cp nhn t di truyn hoc ca b hoc ca m.Cu 22: xc nh kiu gen ca c th mang tnh trng tri, ta thc hin:A. lai phn tch.B. lai khc dng.C. lai thun-nghchD. lai ci tin.Cu 23: no sau y khng phi l iu kin nghim ng ca quy lut Menen:A. b m thun chng v cp tnh trng em lai.B. s lng c th thu c ca php lai phi ln.C. tnh trng do mt gen qui nh trong gen tri t hon ton gen ln.D. tnh trng do mt gen qui nh v chu nh hng ca mi trng.

n thi i hc online luyn thi i hc trc tuynCu 24: Cp tnh trng tng phn l:A. Hai trng thi khc nhau ca cng mt gen.B. Hai trng thi khc nhau ca cng mt tnh trng.C. Mi trng thi khc nhau ca cc tnh trng.D. Nhiu trng thi khc nhau ca cng mt tnh trng.

Cu 26: Xt mt gen gm 2 alen tri-ln hon ton. S loi kiu gen c to ra l: A. 2. B. 3. C. 4.D. 6.

Cu 25: C th thun chng c cc gen:A. u trng thi d hpB. Mt s trng thi d hpC. u trng thi ng hpD. Mt s trng thi ng hpCu 27: Xt mt gen gm 2 alen tri-ln hon ton. S loi php lai khc nhau v kiu gen m cho th h sau ng tnh lA. 4. B. 3. C. 2.D. 6.Cu 28: ngi, gen quy nh nhm mu A, B, O v AB c 3 alen: IA, IB, IO trn NST thng. Mt cp v chng c nhm mu A v B sinh c 1 trai u lng c nhm mu O. Kiu gen v nhm mu ca cp v chng ny l:A. chng IAIO v IBIO.B. chng IBIO v IAIO.C. chng IAIO v IAIO.D. mt ngi IAIO ngi cn li IBIO.

Cu 29: ngi, kiu tc do 1 gen gm 2 alen (A, a) nm trn NST thng. Mt ngi n ng tc xon ly v cng tc xon, h sinh ln th nht c 1 trai tc xon v ln th hai c 1 gi tc thng. Cp v chng ny c kiu gen l:A. AA x Aa.B. AA x AA.C. Aa x Aa.D. AA x aa.Cu 30: la, ht trn tri hon ton so vi ht di .Cho la ht trn lai vi la ht di, F1 thu c 50% la ht trn & 50% la ht di. Cho bit kiu gen la ht trn P ? A. AAaa.B. AA.C. aaD. Aa.

Cu 31: la, ht trn tri hon ton so vi ht di .Cho la ht trn lai vi la ht di, F1 thu c 100% la ht trn. Cho bit kiu gen la ht trn P? A. AAaa.B. AA.C. aaD. Aa.Cu 32: ngi, kiu tc do 1 gen gm 2 alen (A, a) nm trn NST thng. Mt ngi n ng tc xon ly v cng tc xon, sinh c 1 gi tc thng. Kiu gen ca c 2 v chng u l:A. AAaa.B. AA.C. aaD. Aa.

Cu 33: c chua, A quy nh qu tri hon ton so vi a quy nh qu vng. Khi cho c chua qu d hp F1 t th phn F2 c t l phn li kiu gen l:A. 1:1B. 1:2:1C. 3:1D. 1:3Cu 34: Trong lai mt cp tnh trng ca Menen, nu cc tnh trng di truyn theo hin tng tri khng hon ton, th t l kiu gen F2 l:A. 1:1B. 1:2:1C. 3:1D. 1:3n thi i hc online luyn thi i hc trc tuynCu 35: Gen qui nh nhm mu ngi c 3 alen, s to ra c:A. 4 kiu hnh & 4 kiu gen.B. 6 kiu hnh & 4 kiu gen.C. 4 kiu hnh & 6 kiu gen.D. 2 kiu hnh & 3 kiu gen.Cu 36: c chua, A quy nh qu tri hon ton so vi a quy nh qu vng. Khi cho c chua qu d hp F1 t th phn F2 c t l phn li kiu hnh l:A. 1:1B. 1:2:1C. 3:1D. 1:3Cu 37: Trong lai mt cp tnh trng ca Menen, nu cc tnh trng di truyn theo hin tng tri khng hon ton, th c s xut hin:A. Tnh trng miB. Tnh trng trung gianC. Bin d t hpD. Kiu gen miBi 9. QUY LUT MENDEN: QUY LUT PHN LY C LPCu 1: iu kin c bn m bo cho s di truyn c lp cc cp tnh trng lA. nhiu cp gen phi nm trn mt cp NST tng ngB. mi cp gen phi nm trn mi cp NST tng ng khc nhauC. nhiu cp gen phi nm trn hai cp NST tng ng khc nhauD. mi cp gen phi nm trn mt NST ca cp tng ng Cu 2: u H Lan, gen A: thn cao, alen a: thn thp; gen B: hoa , alen b: hoa trng nm trn 2 cp NST tng ng. Cho u thn cao, hoa d hp v 2 cp gen t th phn c F1. F1 c t l phn li kiu hnh:A. 1:1:1:1.B. 3:1.C. 9:3:3:1.D. 1:1.

Cu 3: C th c kiu gen AaBbDD khi gim phn sinh ra bao nhiu loi giao t ?A. 2.B. 3.C. 4.D. 8.Cu 4: C th c kiu gen AaBbDd khi gim phn sinh ra bao nhiu loi giao t ?A. 2.B. 3.C. 4.D. 8.Cu 5: C th c kiu gen AaBBDD khi gim phn sinh ra bao nhiu loi giao t ?A. 2.B. 3.C. 4.D. 8.Cu 6: Php lai P: AaBbDd x AaBbDd, th h sau to c th c kiu hnh tri v 3 gen trn vi t l :A. 100%B. 27/64C. 9/64D. 1/64Cu 7: Php lai P: AaBbDd x AaBbDd, th h sau to c th c kiu hnh ln v 3 gen trn vi t l :A. 100%B. 27/64C. 9/64D. 1/64Cu 8: Php lai P: AaBbDd x AaBbDd, th h sau to bao nhiu t hp kiu hnh:A. 2B. 8C. 6D. 4Cu 9: Php lai P: AaBbDd x AaBbDd, th h sau to bao nhiu t hp kiu gen:A. 22B. 33C. 23D. 44

Cu 10: Php lai P: AaBbDd x AaBbDd, th h sau to bao nhiu c s phn li t l kiu hnh:A. (3+1)1B. (3+1)2C. (3+1)3D. (9+3+3+1)Cu 11: Php lai P: AaBbDd x AaBBDD, th h sau to bao nhiu t hp c th:A. 2B. 4C. 8D. 16

Cu 12: u H Lan, gen A: thn cao, alen a: thn thp; gen B: hoa , alen b: hoa trng nm trn 2 cp nhim sc th tng ng. Cho u thn cao, hoa d hp lai phn tch. F1 c s phn li t l kiu hnh theo t l:A. 1:1:1:1.B. ng tnh.C. 9:3:3:1.D. 1:1.

n thi i hc online luyn thi i hc trc tuynCu 13: u H Lan, gen A: thn cao, alen a: thn thp; gen B: hoa , alen b: hoa trng nm trn 2 cp nhim sc th tng ng. Cho u thn cao, hoa ng hp lai phn tch. F1 c s phn li t l kiu hnh theo t l:A. 1:1:1:1.B. ng tnh.C. 9:3:3:1.D. 1:1.Cu 14: D on kt qu v kiu hnh ca php lai P: AaBb (vng, trn) x aabb (xanh, nhn)A. 9 vng, trn: 3 vng, nhn: 3 xanh, trn: 1 xanh, nhn.B. 1 vng, trn: 1 vng, nhn: 1 xanh, trn: 1 xanh, nhn.C. 3 vng, trn: 3 xanh, trn: 1 vng, nhn: 1 xanh, nhn.D. 3 vng, trn: 3 vng, nhn: 1 xanh, trn: 1 xanh, nhn.

Cu 15: D on kt qu v kiu hnh F2 ca php lai P: AABB (vng, trn) x aabb (xanh, nhn)A. 9 vng, trn: 3 vng, nhn: 3 xanh, trn: 1 xanh, nhn.B. 1 vng, trn: 1 vng, nhn: 1 xanh, trn: 1 xanh, nhn.C. 3 vng, trn: 3 xanh, trn: 1 vng, nhn: 1 xanh, nhn.D. 3 vng, trn: 3 vng, nhn: 1 xanh, trn: 1 xanh, nhn.

Cu 16: Xt php lai P: AaBbDd x AaBbDd. Th h F1 thu c kiu gen aaBbdd vi t l:A. 1/32B. 1/2C. 1/64D. Cu 17: mt u H Lan, xt 2 cp alen trn 2 cp nhim sc th tng ng; gen A: vng, alen a: xanh; gen B: ht trn, alen b: ht nhn. D on kt qu v kiu hnh ca php lai P: AaBB x AaBb.A. 3 vng, trn: 1 vng, nhn.B. 3 vng, trn: 1 xanh, trn.C. 1 vng, trn: 1 xanh, trn.D. 3 vng, nhn: 1 xanh, trn.

Cu 18: Php lai P: AabbDdEe x AabbDdEe c th hnh thnh th h F1 bao nhiu loi kiu gen?A. 4 loi kiu gen.B. 9 loi kiu gen.C. 54 loi kiu gen.D. 27 loi kiu gen.

Cu 19: c chua, A: qu , a: qu vng; B: qu trn, b: qu dt; bit cc cp gen phn li c lp. F1 c t l: 3 dt: 1 vng dt th phi chn cp P c kiu gen v kiu hnh nh th no?A. Aabb ( dt) x aaBb (vng trn).B. aaBb (vng trn) x aabb (vng dt).C. Aabb ( dt) x Aabb ( dt).D. AaBb ( trn) x Aabb ( dt).Cu 20: Cho php lai P: AaBbDd x AabbDD. T l kiu gen AaBbDd c hnh thnh F1 lA. 3/16.B. 1/8.C. 1/16.D. 1/4.

Cu 21: u H Lan, gen A quy nh ht vng, a quy nh ht xanh, B quy nh ht trn, b quy nh ht nhn. Hai cp gen ny di truyn phn ly c lp vi nhau. Cho P: ht vng, nhn x ht xanh, trn c F1 1ht vng, trn: 1ht xanh, trn. Kiu gen ca 2 cy P lA. AAbb x aaBbB. Aabb x aaBbC. AAbb x aaBBD. Aabb x aaBBCu 22: u H Lan, gen A quy nh ht vng, a quy nh ht xanh, B quy nh ht trn, b quy nh ht nhn. Hai cp gen ny di truyn phn ly c lp vi nhau. Php lai no di y khng lm xut hin kiu hnh ht xanh, nhn th h sau?A. AaBb x AaBbB. aabb x AaBBC. AaBb x AabbD. Aabb x aaBb

n thi i hc online luyn thi i hc trc tuynCu 23: Quy lut phn li c lp gp phn gii thch hin tngA. cc gen nm trn cng mt nhim sc th.B. cc gen phn li v t hp trong gim phn.C. s di truyn cc gen tn ti trong nhn t bo.D. bin d t hp phong ph loi giao phi.

Cu 24: C th c kiu gen AaBbddEe to giao t abde vi t lA. 1/4B. 1/6C. 1/8D. 1/16

Cu 25: c chua, gen A quy nh thn cao, gen a quy nh thn thp; gen B quy nh qu , gen a quy nh qu vng. Hai cp gen nm trn hai cp nhim sc th tng ng. Cho P: AaBb x AaBb. T l kiu gen Aabb c d on F1 l A. 3/8 B. 1/16C. D. 1/8

Cu 26: Vi n cp gen d hp t di truyn c lp th s loi giao t F1 lA. 2n .B. 3n .C. 4n .D. (1/2 )n.

Cu 27: Vi n cp gen d hp t di truyn c lp th s lng cc loi kiu gen i lai lA. 2n .B. 3n .C. 4n .D. (1/2 )n.

Cu 28: Vi n cp gen d hp t di truyn c lp th s lng cc loi kiu hnh i lai lA. 2n .B. 3n .C. 4n .D. ( 1/2)n.

Cu 29: Khi c th mang gen BbDdEEff gim phn bnh thng, sinh ra cc kiu giao t l:A: B, b, D, d, E, e, F, f.C: BbEE, Ddff, BbDd, Eeff.B: BDEf, bdEf, BdEf, bDEf.D: BbDd, EEff, Bbff, DdEE.

Cu 30: Cho c th mang kiu gen AabbDDEeff t th phn th s t hp giao t ti a l:A: 32.B: 64.C: 128.D: 256.

Cu 31: Trong php lai aaBbDdeeFf AABbDdeeff th t l kiu hnh con lai A-bbD-eeff l:A: 1/4.B: 1/8.C: 1/16.D: 1/32.n thi i hc online luyn thi i hc trc tuyn