DC Machines Week

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    KL3073

    DC Motors Starters and Breaking

    Methods

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    DC MOTOR STARTERS

    In order for a dc motor to functionproperly it must have some special

    control and protection equipment

    The purposes of this equipment are.

    To protect the motor against damage

    due to short circuits in the equipment

    from long-term overloads from excessive starting currents

    To provide a convenient manner in which

    to control the operating speed of the

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    DC Motor Problems on Starting

    It must be protected from physicaldamage during the starting period.

    At starting conditions, the motor is not

    turning, and so EA= 0 V.

    The full-load current of this motor is:

    Since the internal resistance of a normal

    dc motor is very low a very high currentflows.

    This current is over many times the

    motor's rated full-load current. This may

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    Solution to the problem of excess current

    Insert a starting resistor in series with thearmature to limit the current flow.

    Resistor must not be in the circuit

    permanently.because of: excessive losses

    torque speed characteristic to

    drop Resistor must be removed again as the

    speed of the motor builds up.

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    Solution to the problem of excess current

    Shunt motor with an extra starting resistor.

    In designing the starter it is important toproperly pick the size and number of

    resistor segments.

    Shuts the resistor bypass contacts at the

    ro er time

    shunt motor with astarting resistor

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    Selected Rstart so that the current flowequals say twice the rated current.

    the increasing EA decreases the IA in the

    motor. When the IA falls to rated current, a

    section of the starting resistor must betaken out to increase the starting current

    back up to 200 percent of rated current the increasing EA decreases the IA in the

    motor.

    Repeat until all segments are out

    Solution to the problem of excess current

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    How many steps are required to

    accomplish the current limiting?

    Rtotas the original resistance in the

    starting circuit

    The total resistance left in the starting

    circuit after stages 1

    Initial starting resistance must be

    resistance R, must be switched out at 1st

    stage

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    How many steps are required to

    accomplish the current limiting?

    After switching that part of the resistance

    out, the armature current must jump to

    Equating previous 2 equation

    By direct extension, the resistance left in

    the circuit after the nth stage is switched

    out is

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    How many steps are required to

    accomplish the current limiting?

    At the boundary where RA= Rtot,n

    Equating previous 2 equation

    Solving for n yields

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    Example

    Example 6-7. Figure 6-24 shows a 100-hp 250-V 350-A shunt de motor with an armature

    resistance of 0.05 ohms. It is desired to design

    a starter circuit for this motor which will limit the

    maximum starting current to twice its rated

    value and which will switch out sections of

    resistance as the armature current falls to its

    rated value. (a) How many stages of starting resistance will

    be required to limit the current to the range

    specified?

    (b) What must the value of each segment of the

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    DC Motor Starting Circuits

    Devices commonly used in motor-control

    circuits

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    DC Motor Starting Circuits

    One common motor-starting circuit

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    DC Motor Starting Circuits

    One common motor-starting circuit

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    THE WARD-LEONARD SPEED

    CONTROLLER

    The speed of a separately excited, shunt, orcompounded dc motor can be varied in one of

    three ways:

    by changing the field resistance, changing the armature voltage, or

    changing the armature resistance.

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    THE WARD-LEONARD SPEED

    CONTROLLER

    figure below shows an ac motor serving as a

    prime mover for a dc generator, which in turn is

    used to supply a dc voltage to a dc motor by

    changing the field resistance. This system is called Ward-Leonard system.

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    THE WARD-LEONARD SPEED

    CONTROLLER

    Controlling the field current of the dc generatorarmature voltage can be controlled

    This allows the motor's speed to be smoothly

    varied between a very small value and the basespeed.

    Higher speed can be achieved by reducing the

    motor's field current

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    THE WARD-LEONARD SPEED

    CONTROLLER

    if the field current of the generator is reversed,polarity of generated voltage also reversed.

    This reverse the motor's direction of rotation.

    If the torque or the speed alone of the motorreverses while the other quantity does not, then

    the machine serves as a generator.

    The operating range of a Ward-

    Leonard motor-control system

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    SOLID-STATE SPEED CONTROLLERS

    The average voltage applied to the armature ofthe motor can be controlled by fraction of the

    time the supply voltage is applied to the

    armature.

    fast on and off of the supply can be done by

    modern solid state devices such as SCR.

    A simple dc armature voltage controller circuit

    using SCR is shown below

    A two-quadrant solid-state dc motor controller

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    SOLID-STATE SPEED CONTROLLERS

    A more advanced circuit capable of supplyingan armature voltage with either polarity is

    shown below. This armature voltage control

    circuit can permit a current flow out of the

    positive terminals of the generator, so a motor

    with this type of controller can regenerate

    A 4-quadrant solid-state dc motor controller

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    DC MOTOR BREAKING METHODS

    There are three kinds of electric breaking, namely:

    Rheostatic or dynamic breaking

    Plugging and

    Regenerative breaking

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    Electr ic breaking for shun t motors

    The armature of the shunt motor is disconnectedfrom the supply and it is connected across avariable resistor R.

    The field winding is kept undisrupted and thisbreaking is controlled by varying the seriesresistor R.

    This method used generator action.

    Rheostatic or dynamic breaking

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    Electr ic breaking for shun t motors

    the armature terminals are reversed to rotate themotor in the reverse direction

    VT and the back Eb start acting in the samedirection.

    Plugging or Reverse Breaking

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    Electr ic breaking for shun t motors

    In regenerative breaking, Ebis greater than Vt.

    The direction of IA

    and the armature torque Tbare reversed

    Regenerative Breaking

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    Electr ic b reaking for ser ies moto rs

    it is similar to that of shunt motor.

    Plugging or Reverse Current Breaking