DC Machines
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Transcript of DC Machines
dcmotor 1
Basics of a Electric Motor
DC Machines
http://www.wisc-online.com/objects/ViewObject.aspx?ID=IAU9508
http://www.youtube.com/watch?v=RAc1RYilugI&feature=player_embedded
dcmotor 5
A Two Pole DC Motor
dcmotor 6
A Four Pole DC Motor
dcmotor 7
Armature of a DC Motor
DC Machines
Significant Features of DC Machines • Conventional DC generators are being replaced by the
solid state rectifiers where ac supply is available.
• The same is not true for dc motors because of– Constant mechanical power output or constant torque
– Rapid acceleration or deceleration
– Responsiveness to feedback signals
• 1W to 10,000 hp
• Applications – in electric vehicles to extend their range and reduce vehicle weight, in steel and aluminum rolling mills, traction motors, electric trains, overhead cranes, control devices, etc.
Introduction
Electromagnetic Energy Conversion:
1. When armature conductors move in a magnetic field produced by the current in stator field winding, voltage is induced in the armature conductors.
2. When current carrying armature conductors are placed in a magnetic field produced by the current in stator field winding, the armature conductors experience a mechanical force.
These two effects occur simultaneously in a DC machine whenever energy conversion takes place from electrical to mechanical or vice versa.
Constructional Features of DC Machines
• Commutator along with the armature on the rotor
• Salient-pole on the stator and, except for a few smaller machines, commutating poles between the main poles.
• Field windings (as many as 4):– Two fields that act in a corrective
capacity to combact the detrimental effects of armature reaction, called the commutating (compole or interpole) and compensating windings, which are connected in series with the armature.
– Two normal exciting field windings, the shunt and series windings
Schematic Connection Diagram of a DC Machine
Armature Reaction
If a load is connected to the terminals of the dc machine, a current will flow in its armature windings. This current flow will produce a magnetic field of its own, which will distort the original magnetic field from the machine’s field poles. This distortion of the magnetic flux in a machine as the load is increased is called the armature reaction.
16
Armature Reaction(AR)
• AR is the magnetic field produced by the armature current
•AR aids the main flux in one half of the pole and opposes the main flux in the other half of the pole
The net effect is the reduction of the field current
17
Minimizing Armature Reaction
•Since AR reduces main flux, voltage in generators and torque in motors reduces with it. This is particularly objectionable in steel rolling mills that require sudden torque increase.
•Compensating windings put on polefaces can effectively negate the effectof AR. These windings are connectedin series with armature winding.
18
Minimizing commutation problems•Smooth transfer of current during commutation is hampered by a) coil inductance and b) voltage due to AR flux in the interpolar axis. This voltage is called reactance voltage.
•Can be minimized using interpoles. Theyproduce an opposing field that cancels out the AR in the interpolar region. Thus this winding is also connected in series with the armature winding.
Note: The UVic lab motors have interpoles in them. This should be connected in series with the armature winding for experiments.
Equivalent Circuit of a DC Machine
aaat
fff
RIEV
RIV
Ia_gen
If
Vf VtRf
+
- Ea
+
-
Ia_mot
Ra
+
Ia
If
VtRf
Ea
-
IL
Ra
+
+
-
Generated emf and Electromagnetic Torque
aaat
fff
RIEV
RIV
mdaa KE
adae IKT
meaaem TIEP
Voltage generated in the armature circuit due the flux of the stator field current
Electromagnetic torque
Ka: design constant
Motor: Vt > Ea
Generator: Vt > Ea
21
Magnetization Curve
maa KE
•Flux is a non-linear function of field current and
hence Ea is a non-linear function of field current
•For a given value of flux Ea
is directly proportional to m
Types of DC Machines
Both the armature and field circuits carry direct current in the case of a DC machine.
Types:
Self-excited DC machine: when a machine supplies its own excitation of the field windings. In this machine, residual magnetism must be present in the ferromagnetic circuit of the machine in order to start the self-excitation process.
Separately-excited DC machine: The field windings may be separately excited from an eternal DC source.
Shunt Machine: armature and field circuits are connected in parallel. Shunt generator can be separately-excited or self-excited.
Series Machine: armature and field circuits are connected in series.
Separately-Excited and Self-Excited DC Generators
If
IL
If
DC Supply VtRf
+
- Ea
+
-
Ra
+
Ia
VtRf
Ea
-
IL
Ra
+
Separately-Excited Self-Excited
24
Shunt Field Coil Armature
RA
Shunt Excited DC Machine
25
Series Field Coil
Armature
RA
Series Excited DC Machine
26
Shunt Field Coil Armature
RA
Compound Excited DC MachineSeries Field Coil
•If the shunt and series field aid each other it is called a cumulativelyexcited machine•If the shunt and series field oppose each other it is called a differentiallyexcited machine
27
Field CoilArmature
Ra
Vf
Separately Excited DC Generator
+
-
Rf
Vt
+
-
Field equation: Vf=RfIf
If
Ia
+
-
Ea
Armature equation: Vt=Ea-IaRa
Vt=IaRL, Ea=Kam
RL
28
Shunt Generators
Field equation: Vt=Rf If
Rf=Rfw+Rfc
Armature equation: Vt=Ea-Ia Ra
Vt=(Ia – If) RL, Ea=Kam
Shunt Field Coil Armature
Ra
RL
If IaIa – If
Vt
+
-
Rfc
Ea
+
-Field coil has Rfw : Implicit field resistance
Example 1
A 100-kW, 250-V DC shunt generator has an armature resistance of 0.05 and field circuit resistance of 60 . With the generator operating at rated voltage, determine the induced voltage at (a) full load, and (b) half-full load.
Solution to Example 1(a) At full load,Vt=Ea-IaRa
If=250/60=4.17 AIL_FL=100,000/250=400 AIa=IL_FL+If=400+4.17=404.17 AEa=Vt+IaRa=250+404.17*0.05=270.
2 V
(b) At half load, If=250/60=4.17 A IL_HL=50,000/250=200
A
Ia=IL_HL+If=200+4.17=204.17 A
Ea=Vt+IaRa=250+204.17*0.05=260.2 V
Armature
Ra
RL
If IaIa – If
+
-
Rfc
Ea
+
-
Example 2
Example 2-solution
Field CoilArmature
Ra
Vf+
-
Rf
Vt
+
-
If
Ia
+
-
Ea
RL
DC Generator Characteristics
In general, three characteristics specify the steady-state performance of a DC generators:
1. Open-circuit characteristics: generated voltage versus field current at constant speed.
2. External characteristic: terminal voltage versus load current at constant speed.
3. Load characteristic: terminal voltage versus field current at constant armature current and speed.
DC Generator Characteristics
Open-circuit and load characteristics
The terminal voltage of a dc generator is given by
aa
mf
aaat
RI
dropreactionArmatureIf
RIEV
,
DC Generator Characteristics
It can be seen from the external characteristics that the terminal voltage falls slightly as the load current increases. Voltage regulation is defined as the percentage change in terminal voltage when full load is removed, so that from the external characteristics,
External characteristics100
V
VEregulationVoltage
t
ta
Self-Excited DC Shunt Generator
Schematic diagram of connection
Open-circuit characteristic
Maximum permissible value of the field resistance if the terminal voltage has to build up.
Comparison between the Shunt and Series Connected DC Motor
Power Division in DC Machines
Input from
prime-mover
Elec-magnetic
Power =EaIa
Arm. terminal
power = Vta Ia
Output power
= Vt IL
No-load rotational loss (friction+windage+core)+stray load loss
Arm. copper loss Ia
2Ra+brush contact loss
Series field loss IL2Rs
+shunt field loss If2Rf
Input power from
mains =Vt IL
Elec-magnetic
Power =EaIa
Arm. terminal
power = Vta Ia
Output available
at the shaft
No-load rotational loss (friction+windage+core)+stray load loss
Arm. copper loss Ia
2Ra+brush contact loss
Series field loss IL2Rs
+shunt field loss If2Rf
DC Motor
DC Generator
Efficiency
InputPowerLosses
InputPowerLossesInputPower
InputPowerOutputPower
1
The losses are made up of rotational losses (3-15%), armature circuit copper losses (3-6%), and shunt field copper loss (1-5%). The voltage drop between the brush and commutator is 2V and the brush contact loss is therefore calculated as 2Ia.
DC Machines Formulas
Example 3
Example 3-solution
Problem 9-1 to 9-5
Solution to Problem 9-1 (Page 621)
Solution to Problem 9-2 (Page 621)
Solution to Problem 9-5 (Page 621)
Problem 9-13 (Page 623)
Solution to Problem 9-13 (Page 623)
Solution to Problem 9-13 (Page 623)
The End