CS b553 : A lgorithms for Optimization and Learning

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CS B553: ALGORITHMS FOR OPTIMIZATION AND LEARNING Bayesian Networks

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CS b553 : A lgorithms for Optimization and Learning. Bayesian Networks. agenda. B ayesian networks Chain rule for Bayes nets Naïve Bayes models Independence declarations D-separation Probabilistic inference queries. Purposes of bayesian Networks. - PowerPoint PPT Presentation

Transcript of CS b553 : A lgorithms for Optimization and Learning

Page 1: CS  b553 : A lgorithms  for Optimization and Learning

CS B553: ALGORITHMS FOR OPTIMIZATION AND LEARNINGBayesian Networks

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AGENDA Bayesian networks

Chain rule for Bayes nets Naïve Bayes models

Independence declarations D-separation

Probabilistic inference queries

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PURPOSES OF BAYESIAN NETWORKS Efficient and intuitive modeling of complex

causal interactions Compact representation of joint distributions

O(n) rather than O(2n) Algorithms for efficient inference with given

evidence (more on this next time)

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INDEPENDENCE OF RANDOM VARIABLES Two random variables a and b are

independent if P(A,B) = P(A) P(B)

hence P(A|B) = P(A) Knowing b doesn’t give you any information

about a

[This equality has to hold for all combinations of values that A and B can take on, i.e., all events A=a and B=b are independent]

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SIGNIFICANCE OF INDEPENDENCE If A and B are independent, then

P(A,B) = P(A) P(B)

=> The joint distribution over A and B can be defined as a product over the distribution of A and the distribution of B

=> Store two much smaller probability tables rather than a large probability table over all combinations of A and B

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CONDITIONAL INDEPENDENCE Two random variables a and b are

conditionally independent given C, if P(A, B|C) = P(A|C) P(B|C)

hence P(A|B,C) = P(A|C) Once you know C, learning B doesn’t give

you any information about A

[again, this has to hold for all combinations of values that A,B,C can take on]

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SIGNIFICANCE OF CONDITIONAL INDEPENDENCE Consider Grade(CS101), Intelligence, and SAT Ostensibly, the grade in a course doesn’t

have a direct relationship with SAT scores but good students are more likely to get good

SAT scores, so they are not independent… It is reasonable to believe that Grade(CS101)

and SAT are conditionally independent given Intelligence

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BAYESIAN NETWORK Explicitly represent independence among

propositions Notice that Intelligence is the “cause” of both Grade

and SAT, and the causality is represented explicitly

Intel.

Grade

P(I=x)high 0.3low 0.7

SAT

6 probabilities, instead of 11

P(I,G,S) = P(G,S|I) P(I) = P(G|I) P(S|I) P(I)

P(G=x|I) I=low I=high

‘a’ 0.2 0.74‘b’ 0.34 0.17‘C’ 0.46 0.09

P(S=x|I) I=low I=highlow 0.95 0.05high 0.2 0.8

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DEFINITION: BAYESIAN NETWORK Set of random variables X={X1,…,Xn} with

domains Val(X1),…,Val(Xn) Each node has a set of parents PaX

Graph must be a DAG Each node also maintains a conditional

probability distribution (often, a table) P(X|PaX) 2k-1 entries for binary valued variables

Overall: O(n2k) storage for binary variables

Encodes the joint probability over X1,…,Xn

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CALCULATION OF JOINT PROBABILITY

B E P(a|…)TTFF

TFTF

0.950.940.290.001

Burglary Earthquake

Alarm

MaryCallsJohnCalls

P(b)0.001

P(e)0.002

A P(j|…)TF

0.900.05

A P(m|…)

TF

0.700.01

P(jmabe) = ??

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P(jmabe)= P(jm|a,b,e) P(abe)= P(j|a,b,e) P(m|a,b,e) P(abe)(J and M are independent given A)

P(j|a,b,e) = P(j|a)(J and B and J and E are independent given A)

P(m|a,b,e) = P(m|a) P(abe) = P(a|b,e) P(b|e) P(e)

= P(a|b,e) P(b) P(e)(B and E are independent)

P(jmabe) = P(j|a)P(m|a)P(a|b,e)P(b)P(e)

Burglary Earthquake

Alarm

MaryCallsJohnCalls

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CALCULATION OF JOINT PROBABILITY

B E P(a|…)TTFF

TFTF

0.950.940.290.001

Burglary Earthquake

alarm

MaryCallsJohnCalls

P(b)0.001

P(e)0.002

A P(j|…)TF

0.900.05

A P(m|…)

TF

0.700.01

P(jmabe)= P(j|a)P(m|a)P(a|b,e)P(b)P(e)= 0.9 x 0.7 x 0.001 x 0.999 x 0.998= 0.00062

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CALCULATION OF JOINT PROBABILITY

b e P(a|…)TTFF

TFTF

0.950.940.290.001

Burglary Earthquake

alarm

maryCallsjohnCalls

P(b)0.001

P(e)0.002

a P(j|…)TF

0.900.05

a P(m|…)

TF

0.700.01

P(jmabe)= P(j|a)P(m|a)P(a|b,e)P(b)P(e)= 0.9 x 0.7 x 0.001 x 0.999 x 0.998= 0.00062

P(x1x2…xn) = Pi=1,…,nP(xi|paXi) full joint distribution

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CHAIN RULE FOR BAYES NETS Joint distribution is a product of all CPTs

P(X1,X2,…,Xn) = Pi=1,…,nP(Xi|PaXi)

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EXAMPLE: NAÏVE BAYES MODELS P(Cause,Effect1,…,Effectn)

= P(Cause) Pi P(Effecti | Cause)

Cause

Effect1 Effect2 Effectn

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ADVANTAGES OF BAYES NETS (AND OTHER GRAPHICAL MODELS) More manageable # of parameters to set and

store Incremental modeling Explicit encoding of independence

assumptions Efficient inference techniques

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ARCS DO NOT NECESSARILY ENCODE CAUSALITY

A

B

C

C

B

A

2 BN’s with the same expressive power, and a 3rd with greater power (exercise)

C

B

A

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READING OFF INDEPENDENCE RELATIONSHIPS

Given B, does the value of A affect the probability of C? P(C|B,A) = P(C|B)?

No! C parent’s (B) are

given, and so it is independent of its non-descendents (A)

Independence is symmetric:C A | B => A C | B

A

B

C

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BASIC RULE A node is independent of its non-descendants

given its parents (and given nothing else)

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WHAT DOES THE BN ENCODE?

Burglary EarthquakeJohnCalls MaryCalls | AlarmJohnCalls Burglary | AlarmJohnCalls Earthquake | AlarmMaryCalls Burglary | AlarmMaryCalls Earthquake | Alarm

Burglary Earthquake

Alarm

MaryCallsJohnCalls

A node is independent of its non-descendents, given its parents

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READING OFF INDEPENDENCE RELATIONSHIPS

How about Burglary Earthquake | Alarm ? No! Why?

Burglary Earthquake

Alarm

MaryCallsJohnCalls

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READING OFF INDEPENDENCE RELATIONSHIPS

How about Burglary Earthquake | Alarm ? No! Why? P(BE|A) = P(A|B,E)P(BE)/P(A) = 0.00075 P(B|A)P(E|A) = 0.086

Burglary Earthquake

Alarm

MaryCallsJohnCalls

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READING OFF INDEPENDENCE RELATIONSHIPS

How about Burglary Earthquake | JohnCalls? No! Why? Knowing JohnCalls affects the probability of Alarm,

which makes Burglary and Earthquake dependent

Burglary Earthquake

Alarm

MaryCallsJohnCalls

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INDEPENDENCE RELATIONSHIPS For polytrees, there exists a unique

undirected path between A and B. For each node on the path: Evidence on the directed road XEY or XEY

makes X and Y independent Evidence on an XEY makes descendants

independent Evidence on a “V” node, or below the V:

XEY, or XWY with W… Emakes the X and Y dependent (otherwise they are independent)

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GENERAL CASE Formal property in general case:

D-separation : the above properties hold for all (acyclic) paths between A and B

D-separation independence

That is, we can’t read off any more independence relationships from the graph than those that are encoded in D-separation The CPTs may indeed encode additional

independences

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PROBABILITY QUERIES Given: some probabilistic model over

variables X Find: distribution over YX given evidence

E=e for some subset E X / Y P(Y|E=e)

Inference problem

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ANSWERING INFERENCE PROBLEMS WITH THE JOINT DISTRIBUTION Easiest case: Y=X/E

P(Y|E=e) = P(Y,e)/P(e) Denominator makes the probabilities sum to 1 Determine P(e) by marginalizing: P(e) = Sy P(Y=y,e)

Otherwise, let Z=X/(EY) P(Y|E=e) = Sz P(Y,Z=z,e) /P(e) P(e) = Sy Sz P(Y=y,Z=z,e)

Inference with joint distribution: O(2|X/E|) for binary variables

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NAÏVE BAYES CLASSIFIER P(Class,Feature1,…,Featuren)

= P(Class) Pi P(Featurei | Class)

Class

Feature1 Feature2 Featuren

P(C|F1,….,Fn) = P(C,F1,….,Fn)/P(F1,….,Fn)

= 1/Z P(C) Pi P(Fi|C)

Given features, what class?

Spam / Not SpamEnglish / French / Latin

Word occurrences

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NAÏVE BAYES CLASSIFIER P(Class,Feature1,…,Featuren)

= P(Class) Pi P(Featurei | Class)

P(C|F1,….,Fk) = 1/Z P(C,F1,….,Fk)

= 1/Z Sfk+1…fn P(C,F1,….,Fk,fk+1,…fn)

= 1/Z P(C) Sfk+1…fn Pi=1…k P(Fi|C)Pj=k+1…n P(fj|C)

= 1/Z P(C) Pi=1…k P(Fi|C)Pj=k+1…n Sfj P(fj|C)

= 1/Z P(C) Pi=1…k P(Fi|C)

Given some features, what is the distribution over class?

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FOR GENERAL QUERIES For BNs and queries in general, it’s not that

simple… more in later lectures.

Next class: skim 5.1-3, begin reading 9.1-4