Core Focus on Introductory Algebra

11
Using The Distributive Property With Variables Core Focus on Introductory Algebra Lesson 2.7

description

Warm-Up Find the product of each expression using the Distributive Property. 1. 3(799) 2. 6(12.2) 3. 805(4) 2,397 73.2 3,220

Transcript of Core Focus on Introductory Algebra

Page 1: Core Focus on Introductory Algebra

Using The Distributive Property With Variables

Core Focus on Introductory Algebra

Lesson 2.7

Page 2: Core Focus on Introductory Algebra

Find the product of each expression using the Distributive Property.

1. 3(799)

2. 6(12.2)

3. 805(4)

Warm-Up

2,397

73.2

3,220

Page 3: Core Focus on Introductory Algebra

Using the Distributive Property with Variables

Simplify expressions with variables.

Lesson 2.7

Page 4: Core Focus on Introductory Algebra

Equivalent ExpressionsTwo algebraic expressions which represent the same simplified algebraic expression.

Vocabulary

Page 5: Core Focus on Introductory Algebra

Good to Know!Many algebraic expressions have parentheses. In order to simplify algebraic expressions with parentheses, the Distributive Property must be used. Multiply the front factor by each term in the parentheses.

3(x + 4) = 3(x) + 3(4) = 3x + 12

Algebraic expressions or equations often have like terms that can be combined. If there are parentheses involved in the expression, the Distributive Property must be used FIRST before combining like terms.

2y + 4(y + 5) − 1 = 2y + 4y + 20 − 1 = 6y + 19

Page 6: Core Focus on Introductory Algebra

Use the Distributive Property to simplify each expression.

a. 2(x + 6)

b. 5(y − 8)

c. 4(3x − 2)

Example 1

= 2(x) + 2(6) = 2x + 12

= 5(y) − 5(8) = 5y − 40

= 4(3x) − 4(2) = 12x − 8

Only multiply the two coefficients together. Think of it as 4 groups of 3x.

Page 7: Core Focus on Introductory Algebra

Simplify by distributing and combining like terms.

5(x + 4) + 3x + 3

Distribute first. 5(x + 4) + 3x + 3 = 5x + 20 + 3x + 3

Use the Commutative Property 5x + 3x + 20 + 3to group like terms.

Combine like terms. 8x + 23

5(x + 4) + 3x + 3 = 8x + 23

Example 2

Page 8: Core Focus on Introductory Algebra

Explore! Equivalent Expressions

Step 1 Simplify each LETTER Expression Card.

Two algebraic expressions are equivalent expressions if they represent the same simplified algebraic expression.

In this matching game, each card in the deck has an algebraic expression on it. The goal of the game is to match the six LETTER Expression Cards (A, B, C...) to their equivalent NUMBER Expression Cards (1, 2, 3...).

For the cards on the next slide:

Step 2 Match each LETTER Expression Card to its equivalent NUMBER Expression Card.

Step 3 Create two more LETTER Expression Cards and corresponding NUMBER Expression Cards to be used in a future matching game.

Page 9: Core Focus on Introductory Algebra

Explore! Equivalent Expressions

Page 10: Core Focus on Introductory Algebra

What is the process for simplifying an expression that contains parentheses and like terms?

Communication Prompt

Page 11: Core Focus on Introductory Algebra

Simplify each expression.

1. 7(x + 3)

2. 2(5y − 8)

3. 3(x + 4) + 2x − 1

4. 6 + 2(7x − 1)

Exit Problems

7x + 21

10y − 16

5x + 11

4 + 14x