Corbel
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Transcript of Corbel
![Page 1: Corbel](https://reader036.fdocuments.net/reader036/viewer/2022081815/577cce091a28ab9e788d2373/html5/thumbnails/1.jpg)
Corbel Design
fcu = 40 N/mm2 hcs R = 6 m
Cover, C = 25 mm hcs L = 6 m
fy = 460 N/mm2 Self Weight =
fyv = 250 N/mm2 hcs & top = 4.5 kN/m2
= 0.7 m 700 x 700 Service DL = 2.9 kN/m2
reaction,V = 675 kN beam =av = 75 mm sect1 = 5.772 kN/m
bend, r = 4 Ø sect2 = 2.688 kN/m= 64 mm DL = 52.86 kN/m
1) Corbel geometry LL = 3 kN/m2
LL = 18 kN/m= 16 mm thus, W = 102.8 kN/m= 12 mm beam , L = 9 m
= 400 mm
= 0.6fcu
= 24 N/mm2
= V/(0.6fculb)
= 70 mm
c) length of corbel. Lc
Lc = av + 0.5w + 2x cover + Ømain + Ølink + r
= 252 mm
says 250 mm l1 l2
d) depth of corbel 1/2w
av
= 450 mm
h1 = 351 mm > h/2 w= 70h1 225
b1 = 110.2 mm 450ok b2 139.8 mmnot ok
225
d = 417 mm > av
oknot ok
b) bearing width
length, lb
CORBEL DESIGN
Max/ bearing
stress
width of
bearing, w
column width
250Lc=
a) tension barlink size
assume depth of
corbel, h
![Page 2: Corbel](https://reader036.fdocuments.net/reader036/viewer/2022081815/577cce091a28ab9e788d2373/html5/thumbnails/2.jpg)
e) check shear stress
v = V/ bd
= 2.31 N/mm2 < 0.8 √fcu
= 5.06 N/mm2
oknot ok
2) Corbel reinforcement
a) Main tie steel
Check if Fs > V/2
v/fcu = 0.36 (1-2av /d)
= 0.231
but v/fcu = 0.058 < 0.231
Thus, design for minimun tension
Fs = 0.5V
= 338 kN
Total tension = (Fs + T) T = 0 kN
= 338
v =
fcu
v/fcu = 0.058
av/d = 0.180
from chart z/d = 0.72
fs = 700 (z/d-0.55) / (1- z/d)
= 425 N/mm2
Hence As = 794.1 mm2
As min = 0.004 bd
= 417 mm2
3nos. of T 20 = 943 mm2
oknot ok
(0.4%bd min steel)
b) Check steel stress
(av/d)2 + (z/d)2
0.9 (z/d)(av/d)(1-z/d)
![Page 3: Corbel](https://reader036.fdocuments.net/reader036/viewer/2022081815/577cce091a28ab9e788d2373/html5/thumbnails/3.jpg)
c) check bearing stress within bend
Fs' = (Fs + T) As req
nos. of bar As prov
= 49.76 kN
minimun bend radius
r = (Fs / Ø) x (1 + 2Ø / ab)
ab = 76.8 mm says 75 mm
r = 55 mm
aasumer = 4 Ø= 64
oknot ok
d) shear links
v = 2.31 N/mm2
100 As prov /bd= 0.50
400 / d = 0.96
fcu / 25 = 1.6
λm = 1.25
vc = 0.80 N/mm2
enhancedvc' = 2d vc / av
= 8.85 N/mm2> 0.8√fcu = 5.06
hence vc' = vc = 5.06
use calculated vc'
use 0.8√fcu
since v < vc ; no shear links required but provide
25% 0f main bar for confinemnet
Link = 236 mm2
2 nos. of T 16 = 402.3 mm2 oknot ok
2fcu
x
![Page 4: Corbel](https://reader036.fdocuments.net/reader036/viewer/2022081815/577cce091a28ab9e788d2373/html5/thumbnails/4.jpg)
![Page 5: Corbel](https://reader036.fdocuments.net/reader036/viewer/2022081815/577cce091a28ab9e788d2373/html5/thumbnails/5.jpg)
AS PROVIDED SHOULD GREATER
THAN AS MIN OR AS REQUIRED??
- to check shear stress formula, v=v/bd, b
equal width of column or depth of corbel
![Page 6: Corbel](https://reader036.fdocuments.net/reader036/viewer/2022081815/577cce091a28ab9e788d2373/html5/thumbnails/6.jpg)
Projek :ILAJ
Loading Data
1. Dead load
Slab self weight
Ρconc = 24 kN/m3
205 H Core Slab = 2.7 kN/m2
Topping 75 = 1.8 kN/m2
mm 4.5 kN/m2
SDL
M & E = 0.25 kN/m2
Ceiling = 0.25 kN/m2
Screed = 1.2 kN/m2
Blockwall= 1.2 kN/m2
2.9 kN/m2
2. Live load
Imposed Load = 3 kN/m2
3. Calculate
Simply supported
Moment= wl2 / 8
Reaction= wl/2