Copyright © 2011 Pearson, Inc. 2.8 Solving Inequalities in One Variable.
Copyright © 2013, 2009, 2005 Pearson Education, Inc. Section 3.2 Introduction to Problem Solving.
-
Upload
evan-larsen -
Category
Documents
-
view
216 -
download
1
Transcript of Copyright © 2013, 2009, 2005 Pearson Education, Inc. Section 3.2 Introduction to Problem Solving.
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Section 3.2
Introduction to Problem Solving
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Objectives
• Solving a Formula for a Variable
• Steps for Solving a Problem
• Percentages
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
A parallelogram has an area of 35 cm2 and a base of 7 cm.a. Write a formula to find the height h of the parallelogram with known area A and base b.b. Use the formula to find h.Solutiona. We must solve A = bh for h.
b. Substitute 35 for A and 7 for b into this formula.
A bhA
hb
35
7h 5 cm
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
The formula is used to convert degrees Fahrenheit to degrees Celsius.Use this formula to convert 23°F to an equivalent Celsius temperature.Solution
532
9C F
= −5°C
532
9C F
25
329
3C
59
9C
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
Solve the equation for y and write a formula for a function f defined by y = f(x).
−5(x – 2y) = −8xSolution
−5x +10y = −8x
−5(x – 2y) = −8x
−5x + 5x 10y = −8x + 5x
10y = −3x3
10y x
Thus 3.
10f x x
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Step 1: Read the problem carefully to be sure that you understand it. (You may need to read the problem more than once.) Assign a variable to what you are being asked to find. If necessary, write other quantities in terms of this variable.
Step 2: Write an equation that relates the quantities described in the problem. You may need to sketch a diagram, make a table, or refer to known formulas.
STEPS FOR SOLVING A PROBLEM
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Step 3: Solve the equation and determine the solution.
Step 4: Look back and check your answer. Does it seem reasonable? Did you find the required information?
STEPS FOR SOLVING A PROBLEM
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
The sum of three consecutive integers is 126. Find the three numbers.SolutionStep 1: Assign a variable to an unknown quantity.
n: smallest of the three integersn + 1: next integern + 2: largest integer
Step 2: Write an equation that relates these unknown quantities.
n + (n + 1) + (n + 2) = 126
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example (cont)
Step 3: Solve the equation in Step 2.n + (n + 1) + (n + 2) = 126(n + n + n) + (1 + 2) = 126
3n + 3 = 1263n = 123
n = 41So the numbers are 41, 42, and 43.
Step 4: Check your answer. The sum of these integers is 41 + 42 + 43 = 126. The answer checks.
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
The perimeter of a basketball court is 288 ft. The width is 44 ft less than the length. Find the dimensions of the court. SolutionStep 1: Assign a variable to an unknown quantity.
x: width of the courtx + 44: length of the court
Step 2: Write an equation that relates these unknown quantities. x + (x + 44) + x + (x + 44) = 288
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example (cont)
The perimeter of a basketball court is 288 ft. The width is 44 ft less than the length. Find the dimensions of the court. Step 3: Solve
x + (x + 44) + x + (x + 44) = 288 4x + 88 = 288
4x = 200 x = 50
The width is 50 ft and the length is 50 + 44 = 94 ft. Step 4: Check your answer. The perimeter is 50 + 94 + 50 + 94 = 288 feet. It checks.
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
Two trucks leave Perrysburg at the same time and travel in opposite directions. After 4 hours, they are 320 miles apart. If one truck is traveling 20 miles per hour faster than the other truck, find the speeds of the two trucks. Solutionx: speed of the slower truckx + 20: speed of the faster truck
Rate Time Distance
Slower Truck x 4 4x
Faster Truck x + 20 4 4 (x + 20)
Total 320
4x + 4(x + 20) = 320
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example (cont)
Solve.
The speed of the slower truck is 30 mph and the speed of the faster truck is 20 miles per hour faster, or 50 mph.
4x + 4(x + 20) = 3204x + 4x + 80 = 320
8x + 80 = 3208x = 240x = 30
Check: Distance traveled by the slower truck 30 × 4 = 120Distance traveled by the faster truck 50 × 4 = 200 120 + 200 = 320 miles
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
Convert each percentage to fraction and decimal notation.a.47% b. 9.8% c. 0.9%Solution
Fraction Notation Decimal Notationa.
b.
c.
4747%
100 47% 0.47
9.8 98 49 2 499.8%
100 1000 500 2 500
9.8% 0.098
0.9 90.9%
100 1000 0.9% 0.009
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
A car salesman sells a total of 85 cars in the first and second quarter of the year. In the second quarter, he had an increase of 240% over the previous quarter. How many cars did the salesman sell in the first quarter? SolutionStep 1: Assign a variable.
x: the amount sold in the first quarter.
Step 2: Write an equation. x + 2.4x = 85
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example (cont)
Step 3: Solve the equation in Step 2. x + 2.4x = 85
3.4x = 85 x = 25
In the first quarter the salesman sold 25 cars.
Step 4: Check your answer. An increase of 240% of 25 is 2.4 × 25 = 60.
Thus the amount of cars sold in the second quarter would be 25 + 60 = 85.
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example
A chemist mixes 100 mL of a 28% solution of alcohol with another sample of 40% alcohol solution to obtain a sample containing 36% alcohol. How much of the 40% alcohol was used?SolutionLet x = milliliters of 40%Let x + 100 = milliliters of 36%
Concentration Solution Amount (milliliters)
Pure alcohol
0.28 100 28
0.40 x 0.4x
0.36 x + 100 0.36x + 36
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example (cont)
A chemist mixes 100 mL of a 28% solution of alcohol with another sample of 40% alcohol solution to obtain a sample containing 36% alcohol. How much of the 40% alcohol was used?
Step 2: Write an equation. 0.28(100) + 0.4x = 0.36(x + 100)
Concentration Solution Amount (milliliters)
Pure alcohol
0.28 100 28
0.40 x 0.4x
0.36 x + 100 0.36x + 36
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example (cont)
Step 3: Solve the equation in Step 2.0.28(100) + 0.4x = 0.36(x + 100) 28(100) + 40x = 36(x + 100)
2800 + 40x = 36x + 3600 2800 + 4x = 3600
4x = 800x = 200
200 mL of 40% alcohol solution was added to the 100 mL of the 28% solution.
Copyright © 2013, 2009, 2005 Pearson Education, Inc.
Example (cont)
Step 4: Check your answer. If 200 mL of 40% solution are added to the 100 mL of 28% solution, there will be 300 mL of solution.
200(0.4) + 100(0.28) = 80 + 28 = 108 of pure alcohol.
The concentration is or 36%.
1080.36,
300