Coordinate Geometry - Weebly...Coordinate Geometry Distance & midpoint Gradient Gradient of Parallel...
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Coordinate Geometry Distance & midpoint Gradient Gradient of Parallel & Perpendicular Lines
Transcript of Coordinate Geometry - Weebly...Coordinate Geometry Distance & midpoint Gradient Gradient of Parallel...
Coordinate Geometry
Distance & midpoint
Gradient
Gradient of Parallel & Perpendicular Lines
Area of Rectilinear Figures (Given vertices)
Example
Solution
Circles & Curves
Circles
An equation given in the form of 02222 =++++ cfygxyx is known as the general form.
To find its centre C and radius r, 2 methods:
Method 1 Method 2
1. Find g and f Use “completing the square” to express
2. Use the formula: 02222 =++++ cfygxyx as
cfgr
fgCbaC
−+=
−−=
22
),(),(
cfgfygx
cfgfygx
−+=+++
=+−−+++2222
2222
)()(
0)()(
Hence, cfgr
fgCbaC
−+=
−−=
22
),(),(
To summarize,
Standard Form
In general, the equation of a circle with centre (a, b) and radius r is given as
222 )()( rbyax =−+−
General Form
In general, the equation of a circle with centre (a, b) and radius r is given as
02222 =++++ cfygxyx
Example
Curves
Example
Practice (Past Year Questions)
Linear Law
Example
Practice
Example
