Continuum Plasticity - ERNETmaterials.iisc.ernet.in/~ramu/Continuum Plasticity.pdf · Continuum...

44
Continuum Plasticity Largely from “ Mechanical Metallurgy,by G. E. Dieter, McGraw Hill, SI Metric Edition Chapters 3 and 8

Transcript of Continuum Plasticity - ERNETmaterials.iisc.ernet.in/~ramu/Continuum Plasticity.pdf · Continuum...

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Continuum Plasticity

Largely from “Mechanical Metallurgy,” by G. E. Dieter, McGraw Hill, SI Metric Editionby G. E. Dieter, McGraw Hill, SI Metric Edition

Chapters 3 and 8

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Stress-strain response

• Stress, s = P/A0

• Strain, e =d/L0

• The s-e response will depend on Temp., depend on Temp., composition, strain rate, heat treatment, state of stress, history, etc.

• E, sy, UTS, eu, RA

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Total Strain, e = eelalstic +eplastic

= s/E + eplastic

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True Stress-True Strain Curve

s = s(1+e)e=ln(1+e)

Also known as the flow curve.

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Strain Hardening Exponent, n

s=Ken

K is known as strengthening coefficient

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Work Hardening Data

Stainless Steel 0.45-0.55

70/30 Brass 0.49

Copper (annealed) 0.3-0.54Copper (annealed) 0.3-0.54

Aluminum 0.15-0.25

Iron 0.05-0.15

0.05% C steel 0.26

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Necking

• Volume of the specimen is constant during plastic deformation: AL =A0L0

• Initial strain hardening more than compensates for reduction in area. Engineering stress continues to raisewith engineering strain.with engineering strain.

• A point is reached where decrease in area > increase in strength due to strain hardening. Deformation gets localized. A decreases more rapidly than the load due strain hardening. Further elongation occurs with decreasing load.

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Considère’s Criterion

• “Necking begins when the increase in stress due to decrease in the cross-sectional area is greater than the increase in load bearing capacity of the specimen due to work hardening.”

• dP =0=sdA+Ads ds/s =-dA/A• dP =0=sdA+Ads ds/s =-dA/A• Volume preservation -dA/A = dL/L =de• Combining, ds/de = s. Necking begins at a point

where rate of strain hardening is equal to the stress. • In terms of engineering values, ds/de = 0, at max. s!!

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Plasticity

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Yield Criteria

In uniaxial loading, plastic flow begins when s= s0, the tensile yield stress

When does yielding begin when a material is

subjected to an arbitrary state stress?

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Yield Criteria for Metals• Pure hydrostatic pressure or mean stress tensor, sm,

doesn’t cause yielding in metals.

• Only the deviatoric stress, s´ij, which represents the shear stresses causes plastic flow.

• For an isotropic solid, the yield criterion must be • For an isotropic solid, the yield criterion must be independent of the choice of the axes, i.e., it must be an invariant function.

Yield criterion must be some function of the J’s.

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Von Mises’ Yield Criterion• “Yielding would occur when J2 exceeds some

critical value” J2=k2

• Yielding in uniaxial tension: s1=s0, s2=s3=0

213

232

2212 6

1 J6

s0/3 = k

2/1213

232

2210 2

1

2/12222220 )(6)()()(

2

1xzyzxyxzzyyx

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12 1

2 412 6k2

• Pure shear (torsion test): s1=-s3=t, s2=0

• At yielding:

t=k

• Yield stress in pure tension is higher!

s / t =3s0/ t =3

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Energy Equivalence• Hencky (1924) showed that Von Mises

yield criterion is equivalent to assuming “yielding occurs when the distortion energy reaches a critical value.”

• Elastic strain energy per unit volume, U0• Elastic strain energy per unit volume, U0

U0 1

2E( x

2 y2 z

2)E

( x y y z z x )

1

2G( xy

2 yz2 zx

2 )

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In terms of principal stresses:

)(221

31232123

22

210

EU

In terms of invariants of the stress tensors:

)1(21

2210 IIU )1(2

2 210 IIE

U

Expressing in terms of bulk modulus (K) representing vol.change and shear modulus (G) representing distortion

GKGK

E

39

GKGK

2623

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• The first term on the RHS is dependent on change in volume and the second on distortion.

)3(61

18 22

1

21

0 IIGK

IU

1

• For a uniaxial state of stress,

213

232

221,0 )()()(

121 G

U dist

20,0 2

121 G

U dist

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Tresca (Max. Shear Stress) Criterion

“Yielding occurs when the max. shear stress reaches the value of shear yield stress in the uniaxial tension test.”

• Max shear stress, • In uniaxial tension, t0 = s0 /2

2/)( 31max

• In uniaxial tension, t0 = s0 /2• Tresca criterion: (s1-s3) = s0

• Pure shear: s1 =-s3 = k; s2 = 0 (s1-s3) = 2k = s0 k = s0 /2

• Predicts the same stress for yielding in uniaxial tension and in pure shear

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• Less complicated mathematically than von Mises criterion

• Often used in engineering design• Doesn’t consider s2

• Need to know apriori the max. and min. principal stresses

• General form:

0649636274 62

422

223

32 kJkJkJJ

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Yield Locus 2/12

132

322

210 2

1

For a biaxial plane-stress condition (s2 =0);the von Mises criterion can be expressed as

Equation of an ellipse whose major semi-axis is 2s0 and minor semi-axis is (2/3)s0

2031

23

21

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3/2/0

Von Mises and Tresca predict the same yield stressfor uniaxial and balanced biaxial stress loading. Max. difference (15.5%) for pure shear case.

3/02/0

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Anisotropy in Yielding

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Yield SurfaceThe yield criteria can be represented geometrically by a cylinder oriented at equal angles to the s1, s2, & s3 axes.

•A state of stress which givesa point inside the cylinder a point inside the cylinder represents elastic behavior.•Yielding begins when the state of stress reaches the surface of the cylinder.•MN, the cylinder radius isthe deviatoric stress.

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• The cylinder axis, OM, which makes equal angles with the principal axes represents the hydrostatic component of the stress tensor.

• The generator of the yield surface is the line parallel to OM. If stress state characterized by (s1, s2, s3) lies on the yield surface, so by (s1, s2, s3) lies on the yield surface, so does (s1+H, s2 +H, s3 +H)

• Von Mises criterion is represented by a right circular cylinder whereas the Tresca criterion is represented by a regular hexagonal prism.

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Normality• Drucker (1951): “The total plastic strain vector,

must be normal to the yield surface.”

• Net work has to be expended during the plastic deformation of a body. So the rate of energy dissipation is nonnegative:

0pddissipation is nonnegative:

• The is the incremental plastic strain vector and must be normal to the yield surface.

• Because of the normality rule, the yield locus is always convex.

0pijijd

Pijd

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Hardening Models• How does the yield surface change during plastic

deformation?• Isotropic Hardening: The yield surface expands

uniformly, but with a fixed shape (e.g. ellipse in the case of von Mises solid) and fixed center.

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Bauschinger Effect

The lowering of yield stress when deformation in one direction is followed by deformation in by deformation in opposite direction.

Bauschinger 1881

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Kinematic HardeningThe yield surface does not change its shape and size,but simply translates in the stress space in the directionof its normal.

Accounts for the Bauschinger effect.Bauschinger effect.

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Invariants of Stress and Strain• Useful to simplify the representation of a

complex state of stress or strain by means of respective invariant functions in such a way that the flow curve is unaltered.

• Most frequently used invariant functions:• Most frequently used invariant functions:

Effective stress, , and effective strain,

2/1213

232

221

2/1213

232

221

)()()(32

)()()(2

1

ddddddd

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Pij

Pij

ijij

ddd

SSJ

3

2

2

33 2

1

Sij = sij

Numerical constants are chosen such that, in

Elasticij

Totalij

Plasticij

321 22 dddd

nK

chosen such that, inUniaxial tension,

Power law hardening:

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Plastic Stress-Strain Relations

• In elastic regime, the stress-strain relations are uniquely determined by the Hooke’s law

• In plastic deformation, the strains also depend on the history of loading.

It is necessary to determine the differentials or It is necessary to determine the differentials or increments of plastic strains throughout the loading path and then obtain the total strain by integration.

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Example

• A rod, 50 mm long, is extended to 60 mm and then compressed back to 50 mm.

• On the basis of total deformation:

05060

6050

dLdL 06050 LL

365.02.1ln25060

6050

LdL

LdL

On an incremental basis:

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Proportional Loading

A particular case in which all the stresses increase in the same ratio, i.e.,

321

ddd

321

Plastic strains are independent of the loading path

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Two general categories of plastic stress-strain relationships.

• Incremental or flow theories relate stresses to plastic strain increments.

• Deformation or total strain theories relate • Deformation or total strain theories relate the stresses to total plastic strains. Simpler mathematically.

• Both are the same for proportional loading!

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Levy-Mises Equations• Ideal plastic solids where elastic strains are

negligible.

• Consider yielding under uniaxial tension:

• Since only deviatoric stresses cause yielding

3/and,0,0 1321 m

• Since only deviatoric stresses cause yielding

• Constant vol. condition:

3;

32 1

321

11

m

2

1

2

1

321

2

22

dd

ddd

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• Generalization:

• At any instant of deformation, the ratio of the plastic strain increments to the current deviatoric stresses is constant.

• In terms of actual stresses,

dddd

3

3

2

2

1

1

• In terms of actual stresses,

etc.

Recall,

)(

21

32

3211 dd

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• Using the effective strain concept to evaluate l, which yields

dd3

2

1

)(2

13211

d

dd

ijijd

d 3

1

321 22 dddd

)(2

1

)(2

1

1233

3122

dd

ddijij

dd

2

3

)(1

zyxx E

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Drawback: Only plastic strains are considered.

Evaluation

)(2

1

)(2

1

)(2

1

1233

3122

3211

dd

dd

dd

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Prandtl-Reuss Equations• Proposed by Prandtl (1925) and Ruess

(1930) for Elastic-Plastic Solid

• Considers elastic strains as well

• Recall,

Pij

Eij

Tij ddd

ijkkijEij EE

1

ijkkijij EE

ijkkijEij E

dE

d

1

ijkk

ij

dE

dE

3

211

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• Combining with the plastic strain increments (given by Levy -Mises Equation)

• Use these with a yield criterion and the equation that characterizes the flow behavior of the

ijijkk

ijTij

dd

Ed

Ed

2

3

3

211

that characterizes the flow behavior of the material (e.g. power-law hardening) to calculate the strain increment for an increment in load.

• The complete solution must also satisfy equilibrium, e-d relations, and the BCs.

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SummaryGeneral Theory of Plasticity requires the following1) A yield criterion, which specifies the onset of plastic

deformation for different combinations of applied load.e.g. von Mises and Tresca

2) A hardening rule, which prescribes the work hardening of the material and the change in yield condition with of the material and the change in yield condition with the progression of plastic deformation.Isotropic or kinematic: power-law hardening

3) A flow rule which relates increments of plastic deformation to the stress components.e.g. Levy-Mises or Prandtal-Reuss