• There are 11 people entering a contest, how many ways can the contestants place 3rd,2nd, ands 1st.

• Select 3 contestants from the group of 11, so n = 11. the order of order is important making this a permutation.

• nPr= 11P3 = 11!/(11-3)!• =11!/8!• =11*10*9• =990

• There are 990 different orders in which the contestants can place in the contest.