Conics – curves that are created by the intersection of a plane and a right circular cone. Section...
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Transcript of Conics – curves that are created by the intersection of a plane and a right circular cone. Section...
Conics – curves that are created by the intersection of a plane and a right circular cone.
Section 11.6 – Conic Sections
Parabola – set of points in a plane that are equidistant from a fixed point (d(F, P)) and a fixed line (d (P, Q)).
Focus - the fixed point of a parabola.
Directrix - the fixed line of a parabola. Axis of Symmetry
Directrix
Axis of Symmetry – The line that goes through the focus and is perpendicular to the directrix.
Vertex – the point of intersection of the axis of symmetry and the parabola.
Section 11.6 – Conic Sections
Section 11.6 – Conic SectionsParabolas
𝑦 2=4𝑝𝑥 𝑥2=4𝑝𝑦
(𝑥−h)2=4𝑝 (𝑦−𝑘)(𝑦−𝑘)2=4𝑝 (𝑥−h)
Find the vertex, focus and the directrix
𝑥2=16 𝑦
𝑣 𝑒𝑟𝑡𝑒𝑥 :(0,0)
16=4𝑝𝑝=4
𝑓 𝑖𝑛𝑑𝑝
𝑝𝑎𝑟𝑎𝑏𝑜𝑙𝑎 ,𝑜𝑝𝑒𝑛𝑠𝑢𝑝
𝑓 𝑜𝑐𝑢𝑠(0,0+𝑝)(0,4 )
𝑦=0−𝑝
𝑑𝑖𝑟𝑒𝑐𝑡𝑟𝑖𝑥
𝑦=−4
𝑦=−4
Section 11.6 – Conic Sections
Find the vertex and the focus given:
1=4𝑝
𝑝=14
𝑓 𝑖𝑛𝑑𝑝
𝑜𝑝𝑒𝑛𝑠𝑙𝑒𝑓𝑡
𝑣 𝑒𝑟𝑡𝑒𝑥
𝑓 𝑜𝑐𝑢𝑠(5−
14,−5)
𝑦 2+10 𝑦+𝑥+20=0
𝑐 𝑜𝑚𝑝𝑙𝑒𝑡𝑒 h𝑡 𝑒𝑠𝑞𝑢𝑎𝑟𝑒𝑦 2+10 𝑦=−𝑥−20
102
=5 52=25
𝑦 2+10 𝑦+25=−𝑥−20+25(𝑦+5)2=−𝑥+5(𝑦+5)2=−(𝑥−5)
(5 ,−5)
(434,−5)
𝑑𝑖𝑟𝑒𝑐𝑡𝑟𝑖𝑥𝑥=5+
14
𝑥=514
𝑥=514
Section 11.6 – Conic Sections
Ellipse – a set of points in a plane whose sum of the distances from two fixed points is a constant.
Q
𝑑 (𝐹 1 ,𝑃 )+𝑑 (𝐹2 ,𝑃 )=𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡
𝑑 (𝐹 1 ,𝑄 )+𝑑 (𝐹 2 ,𝑄 )=¿𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡¿𝑑 (𝐹 1 ,𝑃 )+𝑑 (𝐹 2 ,𝑃 )
Section 11.6 – Conic Sections
Foci – the two fixed points, , whose distances from a single point on the ellipse is a constant.
Major axis – the line that contains the foci and goes through the center of the ellipse.
Vertices – the two points of intersection of the ellipse and the major axis, .
Minor axis – the line that is perpendicular to the major axis and goes through the center of the ellipse.
Foci
Major axis
Vertices
Minor axis
Section 11.6 – Conic Sections
Equation of an Ellipse Centered at the Origin
Section 11.6 – Conic Sections
𝑥2
𝑎2 +𝑦2
𝑏2 =1 h𝑤 𝑒𝑟𝑒𝑎>𝑏 𝑥2
𝑏2 +𝑦2
𝑎2 =1 h𝑤 𝑒𝑟𝑒𝑎>𝑏
Section 11.6 – Conic SectionsEquation of an Ellipse Centered at a Point
𝑥2
25+ 𝑦
2
9=1
Vertices of major axis:
𝑎2=25
Major axis is along the x-axis
Vertices of the minor axis
Foci𝑏2=9
𝑐2=𝑎2−𝑏2
𝑎=±5 (−5,0 )𝑎𝑛𝑑(5,0)
𝑏=±3 (0,3 )𝑎𝑛𝑑(0 ,−3)
𝑐2=25−9𝑐2=16𝑐=±4
(−4,0 )𝑎𝑛𝑑 (4,0)
Find the vertices for the major and minor axes, and the foci using the following equation of an ellipse.
Section 11.6 – Conic Sections
4 𝑥2
36+ 9 𝑦2
36=1
Vertices of major axis:
𝑎2=9
Major axis is along the x-axis
Vertices of the minor axis
Foci𝑏2=4
𝑐2=𝑎2−𝑏2
𝑎=±3(−3,0 )𝑎𝑛𝑑(3,0)
𝑏=±2 (0,2 )𝑎𝑛𝑑 (0 ,−2)
𝑐2=9−4𝑐2=5𝑐=±√5
(−√5 ,0 )𝑎𝑛𝑑 (√5 ,0)
Find the vertices for the major and minor axes, and the foci using the following equation of an ellipse.
4 𝑥2+9 𝑦2=36𝑥2
9+ 𝑦2
4=1
Section 11.6 – Conic Sections
Find the center, the vertices of the major and minor axes, and the foci using the following equation of an ellipse.
16 𝑥2+4 𝑦2+96 𝑥−8 𝑦+84=016 𝑥2+96 𝑥+4 𝑦2−8 𝑦=−8416 (𝑥¿¿ 2+6 𝑥)+4 (𝑦2−2 𝑦 )=−84 ¿
62=332=9
−22
=−1(−1)2=1
16 (𝑥¿¿ 2+6 𝑥+9)+4 (𝑦 2−2 𝑦+1 )=−84+144+4¿16 (𝑥+3)2+4 (𝑦−1)2=64
16(𝑥+3)2
64+
4 (𝑦−1)2
64=1
(𝑥+3)2
4+
(𝑦−1)2
16=1
Section 11.6 – Conic Sections
Center:
(−3,1)
(𝑥+3)2
4+
(𝑦−1)2
16=1
Major axis: Vertices:𝑎2=16
Vertices of the minor axis
𝑏2=4
𝑎=±4(−3,1−4 )𝑎𝑛𝑑(−3,1+4 )
𝑏=±2(−3−2,1 )𝑎𝑛𝑑(−3+2,1)
(−3 ,−3 )𝑎𝑛𝑑 (−3,5)
(−5,1 )𝑎𝑛𝑑 (−1,1)
Foci
𝑐2=𝑎2−𝑏2
𝑐2=16−4𝑐2=12𝑐=±2√3
(−3,1−2√3 )𝑎𝑛𝑑 (−3,1+2√3)(−3 ,−2.464 )𝑎𝑛𝑑 (−3 ,4.464)
Minor axis:
Section 11.6 – Conic Sections
Center:
(−3,1)
(𝑥+3)2
4+
(𝑦−1)2
16=1
Major axis vertices:
Minor axis vertices:(−5,1 )𝑎𝑛𝑑 (−1,1)
(−3 ,−3 )𝑎𝑛𝑑 (−3,5)
Foci
(−3 ,−2.464 )𝑎𝑛𝑑 (−3,4.464 )
Section 11.6 – Conic Sections
Q
𝑑 (𝐹 1 ,𝑄 )−𝑑 (𝐹 2,𝑄 )=¿𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡¿±2𝑎
Hyperbola – a set of points in a plane whose difference of the distances from two fixed points is a constant.
𝑑 (𝐹 1 ,𝑃 )−𝑑 (𝐹2 ,𝑃 )=𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡=±2𝑎
Section 11.6 – Conic Sections
Foci – the two fixed points, , whose difference of the distances from a single point on the hyperbola is a constant.
Transverse axis – the line that contains the foci and goes through the center of the hyperbola.
Vertices – the two points of intersection of the hyperbola and the transverse axis, .
Conjugate axis – the line that is perpendicular to the transverse axis and goes through the center of the hyperbola.
Conjugate axis
Center – the midpoint of the line segment between the two foci.
Center
Section 11.6 – Conic Sections
Equation of an Ellipse Centered at the Origin
Section 11.6 – Conic Sections
Equation of a Hyperbola Centered at the Origin
Section 11.6 – Conic Sections
Equation of a Hyperbola Centered at a Point
Section 11.6 – Conic Sections
𝑦2
4−𝑥2
16=1
Vertices of transverse axis:
𝑎2=4
Center:
Equations of the AsymptotesFoci
𝑏2=16𝑏2=𝑐2−𝑎2
𝑎=±2(0 ,−2 )𝑎𝑛𝑑(0,2)
𝑏=±4 (−4,0 )𝑎𝑛𝑑 (4,0)16=𝑐2−4
𝑐2=20 𝑐=±2√5( 0 ,−2√5 )𝑎𝑛𝑑(0,2√5)
𝑦− 𝑦1=±𝑎𝑏
(𝑥−𝑥1)
𝑦−0=±24(𝑥−0)
𝑦=±12𝑥
Identify the direction of opening, the coordinates of the center, the vertices, and the foci. Find the equations of the asymptotes and sketch the graph.
Section 11.6 – Conic Sections
Find the center, the vertices of the transverse axis, the foci and the equations of the asymptotes using the following equation of a hyperbola.
𝑦 2−4 𝑥2−72𝑥+10 𝑦−399=0
( 𝑦2+10 𝑦 )−4 (𝑥¿¿2+18 𝑥)=399¿102
=552=25182
=992=81
( 𝑦2+10 𝑦+25 )−4 (𝑥¿¿2+18 𝑥+81)=399+25−324¿(𝑦+5)2−4 (𝑥+9)2=100
(𝑦+5)2
100−
4(𝑥+9)2
100=1
(𝑦+5)2
100−
(𝑥+9)2
25=1
𝑦 2+10 𝑦−4 𝑥2−72 𝑥=399
Opening up/down
Section 11.6 – Conic Sections
Find the center, the vertices of the transverse axis, the foci and the equations of the asymptotes using the following equation of a hyperbola.
𝑦 2−4 𝑥2−72𝑥+10 𝑦−399=0(𝑦+5)2
100−
(𝑥+9)2
25=1
Center:
Vertices:
𝑎2=100 𝑎=10(−9 ,−5−10 )𝑎𝑛𝑑 (−9 ,−5+10)
(−9 ,−15 )𝑎𝑛𝑑(−9,5)
Foci:
25=𝑐2−100𝑏2=𝑐2−𝑎2
(−9 ,−5−5√5 )𝑎𝑛𝑑(−9 ,−5+5√5)𝑐=√125=5√5
(−9 ,−16.18 )𝑎𝑛𝑑(−9,6.18)
𝑐2=125
Section 11.6 – Conic Sections
Find the center, the vertices of the transverse axis, the foci and the equations of the asymptotes using the following equation of a hyperbola.
𝑦 2−4 𝑥2−72𝑥+10 𝑦−399=0(𝑦+5)2
100−
(𝑥+9)2
25=1
Center:
𝑎=10
Equations of the Asymptotes
𝑦− 𝑦1=±𝑎𝑏
(𝑥−𝑥1)
𝑏=5
𝑦−(−5)=±105
(𝑥−(−9))
𝑦+5=±2(𝑥+9)
Section 11.6 – Conic Sections
Section 11.6 – Conic Sections