Concrete Beam Design Concrete

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1 S2009abn Concrete Beams 1 Lecture 21 Elements of Architectural Structures ARCH 614 ELEMENTS OF ARCHITECTURAL STRUCTURES: FORM, BEHAVIOR, AND DESIGN ARCH 614 DR. ANNE NICHOLS SPRING 2014 lecture twenty one concrete construction: materials & beams http:// nisee.berkeley.edu/godden Concrete Beams 2 Lecture 21 Elements of Architectural Structures ARCH 614 S2007abn Concrete Beam Design composite of concrete and steel American Concrete Institute (ACI) design for maximum stresses limit state design service loads x load factors concrete holds no tension failure criteria is yield of reinforcement failure capacity x reduction factor factored loads < reduced capacity concrete strength = fc S2007abn Concrete Beams 3 Lecture 21 Elements of Architectural Structures ARCH 614 Concrete Construction cast-in-place tilt-up prestressing post-tensioning http://nisee.berkeley.edu/godden Concrete Beams 4 Lecture 21 Elements of Architectural Structures ARCH 614 S2007abn Concrete low strength to weight ratio relatively inexpensive Portland cement aggregate water hydration fire resistant creep & shrink

Transcript of Concrete Beam Design Concrete

Page 1: Concrete Beam Design Concrete

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S2009abnConcrete Beams 1

Lecture 21

Elements of Architectural Structures

ARCH 614

ELEMENTS OF ARCHITECTURAL STRUCTURES:

FORM, BEHAVIOR, AND DESIGN

ARCH 614

DR. ANNE NICHOLS

SPRING 2014

lecture

twenty one

concrete construction:

materials & beams

http:// nisee.berkeley.edu/godden

Concrete Beams 2

Lecture 21

Elements of Architectural Structures

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Concrete Beam Design

• composite of concrete and steel

• American Concrete Institute (ACI)

– design for maximum stresses

– limit state design• service loads x load factors

• concrete holds no tension

• failure criteria is yield of reinforcement

• failure capacity x reduction factor

• factored loads < reduced capacity

– concrete strength = f’c

S2007abnConcrete Beams 3

Lecture 21

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Concrete Construction

• cast-in-place

• tilt-up

• prestressing

• post-tensioning

http://nisee.berkeley.edu/godden

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Concrete

• low strength to weight ratio

• relatively inexpensive

– Portland cement

– aggregate

– water

• hydration

• fire resistant

• creep & shrink

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Concrete Beams 5

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Reinforcement

• deformed steel bars (rebar)

– Grade 40, Fy = 40 ksi

– Grade 60, Fy = 60 ksi - most common

– Grade 75, Fy = 75 ksi

– US customary in # of 1/8”

• longitudinally placed

– bottom

– top for compression reinforcement

– spliced, hooked, terminated...

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Behavior of Composite Members

• plane sections remain plane

• stress distribution changes

yEEf 1

11

yE

Ef 222

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Transformation of Material

• n is the ratio of E’s

• effectively widens a material to get

same stress distribution

1

2

E

En

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Stresses in Composite Section

• with a section

transformed to one

material, new I

– stresses in that

material are

determined as usual

– stresses in the other

material need to be

adjusted by n

concrete

steel

E

E

E

En

1

2

dtransforme

cI

Myf

dtransforme

sI

Mynf

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Reinforced Concrete - stress/strain

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Reinforced Concrete Analysis

• for stress calculations

– steel is transformed to concrete

– concrete is in compression above n.a. and

represented by an equivalent stress block

– concrete takes no tension

– steel takes tension

– force ductile failure

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Location of n.a.

• ignore concrete below n.a.

• transform steel

• same area moments, solve for x

0)(2

xdnAx

bx s

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T sections

• n.a. equation is different if n.a. below

flangef f

bw

bw

hf hf

0)(22

xdnAhx

bhxh

xhb sf

wff

ff

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S2007abnConcrete Beams 13

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Elements of Architectural Structures

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ACI Load Combinations*

*can also use old

ACI factors

• 1.4D

• 1.2D + 1.6L + 0.5(Lr or S or R)

• 1.2D + 1.6(Lr or S or R) + (1.0L or 0.5W)

• 1.2D + 1.0W + 1.0L + 0.5(Lr or S or R)

• 1.2D + 1.0E + 1.0L + 0.2S

• 0.9D + 1.0W

• 0.9D + 1.0E

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Reinforced Concrete Design

• stress distribution in bending

Wang & Salmon, Chapter 3

b

As

a/2

TTNA

CCx a=

1x

0.85f’c

actual stress Whitney stressblock

dh

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Force Equations

• C = 0.85 f cba

• T = Asfy

• where

– f c = concrete compressive

strength

– a = height of stress block

– 1 = factor based on f c

– x = location to the n.a.

– b = width of stress block

– fy = steel yield strength

– As = area of steel reinforcement

a/2

T

0.85f’c

Ca=1x

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• T = C

• Mn = T(d-a/2)

– d = depth to the steel n.a.

• with As

– a =

– Mu Mn = 0.9 for flexure

– Mu = T(d-a/2) = Asfy (d-a/2)

Equilibrium

a/2

T

C

0.85f’c

d

bf

fA

c

ys

85.0

a=1x

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S2009abnConcrete Beams 17

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• over-reinforced

– steel won’t yield

• under-reinforced

– steel will yield

• reinforcement ratio

– use as a design estimate to find As,b,d

– max is found with steel 0.004 (not bal)

Over and Under-reinforcement

bd

Aρ s

http://people.bath.ac.uk/abstji/concrete_video/virtual_lab.htm

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As for a Given Section

• several methods

– guess a and iterate

1. guess a (less than n.a.)

2.

3. solve for a from Mu = Asfy (d-a/2)

4. repeat from 2. until a from 3. matches a in 2.

y

cs

f

baf.A

850

ys

u

fA

Mda

2

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As for a Given Section (cont)

• chart method

– Wang & Salmon Fig. 3.8.1 Rn vs.

1. calculate

2. find curve for f’c and fy to get

3. calculate As and a

• simplify by setting h = 1.1d

2bd

MR n

n

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Reinforcement

• min for crack control

• required

• not less than

• As-max :

• typical cover

– 1.5 in, 3 in with soil

• bar spacing

)(3

bdf

fA

y

c

s

)(200

bdf

Ay

s

cover

spacing

)375.0(1 da

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Approximate Depths