ConcepTest 9.4Using a Wrench You are using a wrench to loosen a rusty nut. Which arrangement will be...
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Transcript of ConcepTest 9.4Using a Wrench You are using a wrench to loosen a rusty nut. Which arrangement will be...
ConcepTest 9.4ConcepTest 9.4 Using a WrenchUsing a Wrench
You are using a wrench to
loosen a rusty nut. Which
arrangement will be the
most effective in loosening
the nut?
1
34
2
5) all are equally effective
ConcepTest 9.4ConcepTest 9.4 Using a WrenchUsing a Wrench
You are using a wrench to
loosen a rusty nut. Which
arrangement will be the
most effective in loosening
the nut?
1
34
2
Since the forces are all the same, the only difference is the lever arm. The arrangement with the largest largest
lever armlever arm (case #2case #2) will
provide the largest torquelargest torque.
5) all are equally effective
Follow-up:Follow-up: What is the difference between arrangement 1 and 4? What is the difference between arrangement 1 and 4?
ConcepTest 9.6ConcepTest 9.6 Closing a DoorClosing a Door
In which of the cases shown below
is the torque provided by the
applied force about the rotation
axis biggest? For all cases the
magnitude of the applied force is
the same.
1) F1
2) F3
3) F4
4) all of them
5) none of them
ConcepTest 9.6ConcepTest 9.6 Closing a DoorClosing a Door
1) F1
2) F3
3) F4
4) all of them
5) none of them
In which of the cases shown below
is the torque provided by the
applied force about the rotation
axis biggest? For all cases the
magnitude of the applied force is
the same.
The torque is: == F d sin F d sin
and so the force that is at 90°90°
to the lever arm is the one that
will have the largest torquelargest torque.
Clearly, to close the door, you
want to push perpendicularperpendicular!!
Follow-up:Follow-up: How large would the force have to be for How large would the force have to be for FF44??
ConcepTest 9.8aConcepTest 9.8a Dumbbell IDumbbell I
1) case (a)1) case (a)
2) case (b)2) case (b)
3) no difference3) no difference
4) It depends on the rotational 4) It depends on the rotational inertia of the dumbbell.inertia of the dumbbell.
A force is applied to a dumbbell for a certain period of time, first as in (a) and then as in (b). In which case does the dumbbell acquire the greater center-of-mass speed ?
ConcepTest 9.8aConcepTest 9.8a Dumbbell IDumbbell I
1) case (a)1) case (a)
2) case (b)2) case (b)
3) no difference3) no difference
4) It depends on the rotational 4) It depends on the rotational inertia of the dumbbell.inertia of the dumbbell.
A force is applied to a dumbbell for a certain period of time, first as in (a) and then as in (b). In which case does the dumbbell acquire the greater center-of-mass speed ?
Because the same force acts for the
same time interval in both cases, the
change in momentum must be the
same, thus the CM velocity must be
the same.
1) case (a)1) case (a)
2) case (b)2) case (b)
3) no difference3) no difference
4) It depends on the rotational 4) It depends on the rotational inertia of the dumbbell.inertia of the dumbbell.
A force is applied to a dumbbell for a certain period of time, first as in (a) and then as in (b). In which case does the dumbbell acquire the greater energy ?
ConcepTest 9.8bConcepTest 9.8b Dumbbell IIDumbbell II
1) case (a)1) case (a)
2) case (b)2) case (b)
3) no difference3) no difference
4) It depends on the rotational 4) It depends on the rotational inertia of the dumbbell.inertia of the dumbbell.
A force is applied to a dumbbell for a certain period of time, first as in (a) and then as in (b). In which case does the dumbbell acquire the greater energy ?
If the CM velocities are the same,
the translational kinetic energies
must be the same. Because
dumbbell (b) is also rotating, it has
rotational kinetic energy in addition.
ConcepTest 9.8bConcepTest 9.8b Dumbbell IIDumbbell II
ConcepTest 9.9ConcepTest 9.9 Moment of InertiaMoment of Inertia
1) 1) solid aluminum
2) hollow gold2) hollow gold
3) same3) same
same mass & radius
solid hollow
Two spheres have the same radius and equal masses. One is made of solid aluminum, and the other is made from a hollow shell of gold.
Which one has the bigger moment of inertia about an axis through its center?
ConcepTest 9.9ConcepTest 9.9 Moment of InertiaMoment of Inertia
1) 1) solid aluminum
2) hollow gold2) hollow gold
3) same3) same
same mass & radius
solid hollow
Two spheres have the same radius and equal masses. One is made of solid aluminum, and the other is made from a hollow shell of gold.
Which one has the bigger moment of inertia about an axis through its center?
Moment of inertia depends on mass and distance from axis squared. It is bigger for the shell since its mass is located
farther from the center.
ConcepTest 9.10ConcepTest 9.10 Figure SkaterFigure Skater
1) the same1) the same
2) larger because she’s rotating 2) larger because she’s rotating fasterfaster
3) smaller because her rotational 3) smaller because her rotational
inertia is smallerinertia is smaller
A figure skater spins with her arms extended. When she pulls in her arms, she reduces her rotational inertia and spins faster so that her angular momentum is conserved. Compared to her initial rotational kinetic energy, her rotational kinetic energy after she pulls in her arms must be
ConcepTest 9.10ConcepTest 9.10 Figure SkaterFigure Skater
1) the same1) the same
2) larger because she’s rotating 2) larger because she’s rotating fasterfaster
3) smaller because her rotational 3) smaller because her rotational
inertia is smallerinertia is smaller
A figure skater spins with her arms extended. When she pulls in her arms, she reduces her rotational inertia and spins faster so that her angular momentum is conserved. Compared to her initial rotational kinetic energy, her rotational kinetic energy after she pulls in her arms must be
KErot=1/2 I 2 = 1/2 L (used L= I ).
Since L is conserved, larger
means larger KErot. The “extra”
energy comes from the work she
does on her arms.
Follow-up:Follow-up: Where does the extra energy come from? Where does the extra energy come from?
ConcepTest 9.12 ConcepTest 9.12 Spinning Bicycle WheelSpinning Bicycle Wheel
You are holding a spinning bicycle wheel while standing on a stationary turntable. If you suddenly flip the wheel over so that it is spinning in the opposite direction, the turntable will
1) remain stationary1) remain stationary
2) spin in the same direction as the 2) spin in the same direction as the wheel before flippingwheel before flipping
3) spin in the same direction as the 3) spin in the same direction as the wheel after flippingwheel after flipping
ConcepTest 9.12 ConcepTest 9.12 Spinning Bicycle WheelSpinning Bicycle Wheel
You are holding a spinning bicycle wheel while standing on a stationary turntable. If you suddenly flip the wheel over so that it is spinning in the opposite direction, the turntable will
The total angular momentum of the system is L upward, and it is conserved. So if the wheel has -L downward, you and the table must have +2L upward.
1) remain stationary1) remain stationary
2) spin in the same direction as 2) spin in the same direction as the wheel before flippingthe wheel before flipping
3) spin in the same direction as 3) spin in the same direction as the wheel after flippingthe wheel after flipping
ConcepTest 11.1ConcepTest 11.1 Balancing RodBalancing Rod
1kg
1m
A 1 kg ball is hung at the end of a rod 1
m long. If the system balances at a
point on the rod 0.25 m from the end
holding the mass, what is the mass of
the rod ?
1) 1/4 kg
2) 1/2 kg
3) 1 kg
4) 2 kg
5) 4 kg
1 kg
X
CM of rod
same distance mROD = 1 kg
A 1 kg ball is hung at the end of a rod 1
m long. If the system balances at a
point on the rod 0.25 m from the end
holding the mass, what is the mass of
the rod ?
The total torque about the The total torque about the
pivot must be zero !!pivot must be zero !! The CM
of the rod is at its center, 0.25 0.25
m to the right of the pivotm to the right of the pivot.
Since this must balance the
ball, which is the same distance same distance
to the left of the pivotto the left of the pivot, the
masses must be the same !!
1) 1/4 kg
2) 1/2 kg
3) 1 kg
4) 2 kg
5) 4 kg
ConcepTest 11.1ConcepTest 11.1 Balancing RodBalancing Rod
ConcepTest 11.2ConcepTest 11.2 MobileMobile
1 kg
1 m 3 m
1 m 2 m
?
?
A (static) mobile hangs as shown
below. The rods are massless and
have lengths as indicated. The mass
of the ball at the bottom right is 1 kg.
What is the total mass of the mobile ?
1) 5 kg
2) 6 kg
3) 7 kg
4) 8 kg
5) 9 kg
1 kg
1 m 3 m
1 m 2 m
?
?
A (static) mobile hangs as shown
below. The rods are massless and
have lengths as indicated. The mass
of the ball at the bottom right is 1 kg.
What is the total mass of the mobile ?
1) 5 kg
2) 6 kg
3) 7 kg
4) 8 kg
5) 9 kg
Use torques in two steps: (1)
find the big mass on the bottom
left (lower rod only). (2) use the
entire lower rod assembly (with
two masses) to find the mass on
top right. Finally, add up all the Finally, add up all the
masses.masses.
ConcepTest 11.2ConcepTest 11.2 MobileMobile
ConcepTest 11.3aConcepTest 11.3a Tipping Over ITipping Over I
1 2 3
1) all
2) 1 only
3) 2 only
4) 3 only
5) 2 and 3
A box is placed on a ramp in the
configurations shown below. Friction
prevents it from sliding. The center of
mass of the box is indicated by a blue
dot in each case. In which case(s) does
the box tip over ?
ConcepTest 11.3aConcepTest 11.3a Tipping Over ITipping Over I
1 2 3
1) all
2) 1 only
3) 2 only
4) 3 only
5) 2 and 3
A box is placed on a ramp in the
configurations shown below. Friction
prevents it from sliding. The center of
mass of the box is indicated by a blue
dot in each case. In which case(s) does
the box tip over ?
The torque due to gravity acts like all
the mass of an object is concentrated
at the CM. Consider the bottom right
corner of the box to be a pivot point.
If the box can rotate such that the CM If the box can rotate such that the CM
is lowered, it will !!is lowered, it will !!
ConcepTest 11.3bConcepTest 11.3b Tipping Over IITipping Over II
1) case 1 will tip
2) case 2 will tip
3) both will tip
4) neither will tip
Consider the two configurations of
books shown below. Which of the
following is true?
1/2
1/4 1/2
1/4
1 2
ConcepTest 11.3bConcepTest 11.3b Tipping Over IITipping Over II
The CM of the system is
midway between the CM of
each book. Therefore, the
CM of case #1 is not over the CM of case #1 is not over the
table, so it will tiptable, so it will tip.
1) case 1 will tip
2) case 2 will tip
3) both will tip
4) neither will tip
Consider the two configurations of
books shown below. Which of the
following is true?
1/2
1/4 1/2
1/4
1 2