Collision theory of bimolecular reactions • Arrhenius formula...

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物理化學() 應用化學系朱超原老師 1 • Collision theory of bimolecular reactions • Arrhenius formula (again) • Fraction number in bimolecular reactions • Unimolecular reactions VIII. The chemical reaction mechanisms VIII. The chemical reaction mechanisms

Transcript of Collision theory of bimolecular reactions • Arrhenius formula...

  • 物理化學(三) 應用化學系朱超原老師 1

    • Collision theory of bimolecular reactions• Arrhenius formula (again)• Fraction number in bimolecular reactions • Unimolecular reactions

    VIII. The chemical reaction mechanismsVIII. The chemical reaction mechanisms

  • 物理化學(三) 應用化學系朱超原老師 2

    VIIIVIII--1. Collision theory of bimolecular reactions1. Collision theory of bimolecular reactions

    bBaA products

    dt

    tBdbdt

    tAda

    tr 11

    Two reactants

    For simplicity (a=b=1)

    products

    products

    A A

  • 物理化學(三) 應用化學系朱超原老師 3

    Reaction mechanisms

    Kinetic energy

    Internal energy Rotational energyVibrational energyElectronic energy

    No kinetic energy change Elastic collision

    Internal energy change inelastic collision

    Bond forming or/and breaking Reactive collision

    collision scattering

  • 物理化學(三) 應用化學系朱超原老師 4

    Total collision rate

    22

    VN5.0

    21

    dv

    VNzZ rel

    mTk

    vv Brel 16

    2

    Number of collision per unit volume +per unit time

    scollisonsofnumber3m

    Fraction number of reactions = f fZReaction rate =

    fZN Av

    1Reaction rate in mole =

  • 物理化學(三) 應用化學系朱超原老師 5

    AAA 2 products

    22

    AvV

    N/NA

    22VN5.01

    21

    dv

    Nf

    dtAd

    relAv

    225.021 AdvfN

    dtAd

    relAv

    Rate constant

    AvB Nm

    Tkdfk

    42

    (second-order)

    Only dependent on temperature

    (Ideal case = elementary)

  • 物理化學(三) 應用化學系朱超原老師 6

    BA products

    dtBd

    dtAdfZ

    N Av12

    1Reaction rate in mole =

    212

    121212 dV

    NVN

    vZ 12

    128

    Tkv B

    BA

    V/NN

    V/NN Av2Av1

    BAdvfNdt

    AdAv

    21212

    AvB N

    Tkdfk

    12

    212

    8

    Rate constant

  • 物理化學(三) 應用化學系朱超原老師 7

    Example 2HIIH 22

    1115 smolL1074.8 fk

    At T = 373.15K

    Calculate fraction number f

    Rate constant

    AvB N

    Tkdfk

    12

    212

    8

    Table A15

    6.35397I2

    2.72294H2

    d×1010/mT/K

    mmd 101012 1054.41035.672.221

    kgkgmm

    mm 272721

    2112 103.31066.12542

    2542

  • 物理化學(三) 應用化學系朱超原老師 8

    smolL

    smolm

    NTk

    d AvB

    11

    38

    12

    212

    1077.7

    1077.7

    8

    -123 JK10380.1 Bk

    molN Av /10022.623

    At T = 373.15K

    md 1012 1054.4

    kg2712 103.3

    1115 smolL1074.8 fk2611

    15101.1

    1077.71074.8

    f

    If T = 473.15K 1110 smolL1053.9 fk

    smolL

    smolL

    NTkd AvB

    11

    11

    12

    212

    1075.8

    15.37315.4731077.7

    8

    2111

    10101.1

    1075.81053.9

    f

  • 物理化學(三) 應用化學系朱超原老師 9

    VIIIVIII--2. Arrhenius formula (again)2. Arrhenius formula (again)

    Kinetic energy

    212122

    1 vK

    Classical picture

    aEK

    No reaction aEK

    Reactions occur

    K

    aE

  • 物理化學(三) 應用化學系朱超原老師 10

    Arrhenius formula

    RTE

    Ak aexp

    Activation energy

    Arrhenius preexponential factor

    A and Ea are very slow change with respect to temperature

    dTkdRTEa

    ln2

    Activation energy is measured through experiment reaction rate cActivation energy is measured through experiment reaction rate constant onstant

    Reactants aE

    Products

    Activated Complex

    aE

    Path of a reaction

    ΔH

  • 物理化學(三) 應用化學系朱超原老師 11

    Example 2HIIH 22

    1115 smolL1074.8 fkAt T = 373.15K

    Rate constant

    At T = 473.15K 1110 smolL1053.9 fk

    Calculate activation energy and pre-exponential factor

    11 exp RT

    EAk a

    22 exp RT

    EAk a

    15

    2

    1

    21

    21 molJ10703.1ln

    kk

    RTT

    TTEa

    11mol8.314JK R

    3.432

    RTEa 1192 smolL1008.63.43exp kA

  • 物理化學(三) 應用化學系朱超原老師 12

    PCIIIweek16-1作業

    Problems 12.712.8

    Page 539

  • 物理化學(三) 應用化學系朱超原老師 13

    VIIIVIII--3. Fraction number in bimolecular reactions3. Fraction number in bimolecular reactions

    Total collision rate

    VN

    VNdvZ 122121212 12

    128

    Tkv B

    vgMaxwell–Boltzmann distribution 1311 vdvgN number of A particles in 111 vdvv

    1311 vdvgN number of B particles in 222 vdvv

    Differential collision rate

    V

    vdvgNV

    vdvgNddZ 1

    3112

    3222

    121212 vv

    13 vdvg

  • 物理化學(三) 應用化學系朱超原老師 14

    Maxwell–Boltzmann distribution

    Tkmv

    Tkmvg

    BB 2exp

    2

    23

    222

    211 2

    121 vmvmH

    Center-of –mass coordinate

    12 vvv

    21

    1122M

    vvV

    mmmm

    2221

    21 vMVH M

    vdvgVdVgM

    mmV

    NNddZ MM

    33212

    1221212 v

    1

  • 物理化學(三) 應用化學系朱超原老師 15

    Integral d3VM vdvg

    VNN

    ddZ 32122

    1212 v

    If we integral d3v 2122

    121212 vV

    NNdZ (no new)

    Total reaction rate

    cv

    Classical pict ure

    v ( relative speed)

    Reaction probability

    0

    1

    cvv All reactions

    cvv no reaction

  • 物理化學(三) 應用化學系朱超原老師 16

    Total reaction rate vdvvgVNN

    dreactionZ 32122

    1212

    cv BBdvv

    Tkv

    TkVNNdreactionZ 3

    212

    312

    2122

    1212 2exp4

    2

    2121

    2exp 23

    212 c

    c

    avc

    v Be

    av

    advv

    Tkv

    Tka

    B212

    F ract ion number in bimolecul ar re actionsF ract ion number in bimolecul ar re actions

    RTE

    cTk

    B

    cTkv

    B

    cc

    B

    c

    B

    c

    eRTE

    eTk

    eTk

    vf

    11

    21 2

    212

    212

  • 物理化學(三) 應用化學系朱超原老師 17

    Example 2HIIH 22 At T = 373.15K

    26101.1 fFraction number of reaction

    Tk

    B

    cTkv

    B

    c Bc

    B

    c

    eTk

    eTk

    vf

    1

    21 2

    212

    212

    26101.11 xex 10ln261.1ln)1ln( xxx = 63.9454499236402

    Txk Bc

    eVmolkJmolJxRTEc 2/198/1098.15

    11mol8.314JK R

  • 物理化學(三) 應用化學系朱超原老師 18

    new4

    BA products

    Elementary bimolecular reaction (two reactants)

    BAkdt

    Ad

    RTE

    cAv

    BC

    eRTE

    NTkdk

    18

    12

    212

    RTE

    Ak aexp ac EE

    Compare with Arrhenius formula

    Rate constant

  • 物理化學(三) 應用化學系朱超原老師 19

    Example 2HIIH 22

    molJEc /1098.15

    T1 = 293.15K T2 = 303.15K

    11mol8.314JK R

    KREc 41038.2

    14exp

    exp

    1

    2

    RTERTE

    C

    C

    983.0

    1

    1

    2

    1

    11

    22

    1

    2

    TT

    RTE

    T

    RTE

    T

    TATA

    c

    c

    Change fast

    Change slow

  • 物理化學(三) 應用化學系朱超原老師 20

    v (relative speed)

    Reaction probability

    cc

    c

    vvv

    vvv

    p1

    0

    Total reaction rate

    cv

    c

    BBdv

    vv

    vTk

    vTkV

    NNdreactionZ 12

    exp42

    32

    123

    122

    1221212

    RTE

    TkTkv c

    B

    c

    B

    c

    eeef

    2

    212

    Rate constant

    fraction number

    RTE

    AvB

    C

    eNTkdk

    12

    212

    8

    0

    1

    cv

  • 物理化學(三) 應用化學系朱超原老師 21

    Example 2HIIH 22 At T = 373.15K

    26101.1 fFraction number of reaction

    262 101.1

    212

    TkTkv

    B

    c

    B

    c

    eef

    1.1ln10ln26 x x = 59.77Txk Bc

    eVmolkJmolJxRTEc 93.1/186/1086.15

    11mol8.314JK R

    Better than …

    15 molJ10703.1(exp) aE

  • 物理化學(三) 應用化學系朱超原老師 22

    Example 2HIIH 22 At T = 373.15K1115 smolL1074.8 fkRate constant

    15 molJ10703.1(exp) aEActivation energy

    Calculate effective collision diameter

    RTE

    AvB

    C

    eNTkdk

    12

    212

    8

    904.54RTEa

    smolmN

    TkAv

    B

    2612

    10128

    242721218 1043.1102.11074.8 dCross section 221212 10093.5 md

    A4.0104 1112 md

  • 物理化學(三) 應用化學系朱超原老師 23

    Steric factor in bimolecular reactions

    If two molecules are not in right orientation in collision, thereis no reaction no matter how large kinetic energy.

    Simple way to consider this:

    RTEc

    ef

    Rate constant

    fraction number

    RTE

    AvB

    C

    eNTkdk

    12

    212

    8

    Steric factor

  • 物理化學(三) 應用化學系朱超原老師 24

    Example 2HIIH 22

    At T = 373.15K

    11mol8.314JK R

    RTE

    Ak aexp

    1115 smolL1074.8 k 15 molJ10703.1 aE 119 smolL100.6 A

    experiment

    Calculate steric factor RTE

    AvB

    C

    eNTkdk

    12

    212

    8

    smolL

    NTkd AvB

    11

    12

    212

    1077.7

    8

    Av

    B NTk

    dA12

    212

    8

    0077.0

  • 物理化學(三) 應用化學系朱超原老師 25

    PCIIIweek16-2作業

    Problems 12.1512.16

    Page 540

  • 物理化學(三) 應用化學系朱超原老師 26

    BA products BAkdt

    Ad

    Rate constant

    RTE

    Ak aexpExperiment

    RTEc

    ef

    Theory

    fraction number

    RTE

    AvB

    C

    eNTkdk

    12

    212

    8

    2

    1221

    cAvC vNE

    If A=B, kk 21

    2

    21 Ak

    dtAd

  • 物理化學(三) 應用化學系朱超原老師 27

    VIIIVIII--4. 4. UnimolecularUnimolecular reactionsreactions

    A CB

    Akdt

    Ad

    2Akdt

    Ad

    Experiment found this reaction

    neither nor

    Lindemann mechanism (2 steps)

    AA AA *

    *A CB

    (1)

    (2)

  • 物理化學(三) 應用化學系朱超原老師 28

    (1) *A as a product AAkAk

    dtAd

    dtAd **

    21

    12

    1

    (2) *A as a reactant ** 2 Akdt

    BddtAd

    forward reverse

    Compare two steps *** 2121 AkAAkAkdtAd

    *2 AkdtBd

    At equilibrium *A 0* dtAd Akk

    AkA12

    21*

    Akk

    Akkdt

    Bd

    12

    212

  • 物理化學(三) 應用化學系朱超原老師 29

    rate =

    AkkAkk

    dtBd

    dtAdtv

    12

    212

    A CB

    (a) 21 kAk

    Ak

    kkdt

    Bddt

    Adtv1

    12

    unik(b) 21 kAk

    21 AkdtBd

    dtAdtv

    First-order

    Second-order