Chemistry Notes- Metals.docx

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    Metals

    Outline and examine some uses of different metals through history, including

    contemporary uses, as uncombined metals or as alloys An alloy is a mixture of two or more metal elements or non-metal and metal elements

    fused together through dissolving each other in molten state

    Metal Historic Uses Contemporary uses

    Copper metal (around 6000years ago)

    Ornaments, tools, weaponsand cooking

    Electrical cables and wiring,radiators, refrigeration

    systems, water pipes

    Iron metal (3000 BC) Tools and weapons found at3000BC

    Usually converted into steeldue to its corrosion to makebuildings, bridges,automobiles

    Gold uncombined metal Oldest native metal.Egyptians used gold in theirornaments

    Jewellery, dentistry, electricalconnections

    Bronze alloy

    3000-1000BC

    Used for cutting tools andarmour

    Church bells, statues

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    Metal Properties Common Uses How it relates to its propertiesSteel Usually is

    susceptible tocorrosion butwhen alloyed withother metals, it willbecome corrosionresistant. Steel isalso strong

    Sinks, cutlery,buildings

    Steel is a ferrous metal, meaning it containsiron. The iron in the metallic matrix willcombine with oxygen creation iron oxide(rust). Therefore, to counter rust, othermetals are alloyed with steel to createdifferent types of alloy steels. For example,stainless steel, which is used in cutlery andutensils that handle food, must be resistantto corrosion to ensure that foodcontamination does not occur. This ismainly due to the 10% chromium that isadded to the steel, by mass.

    Brass Resists corrosionand ductile

    Doorknobs,screws

    Solder Low melting point Joining wires

    Explain why energy input is necessary to extract a metal from its ore Process of extraction

    1. Mining To extract the ore, energy for heavy machinery is needed to break and obtainthe desired ores from the earth (Physical separation method/process)

    2. Milling Processes such as froth floatation are needed which requires a lot of waterand energy to agitate the bubbles to separate the gangue. Also transportation of theores/minerals is needed in this process. (Physical separation method/process)

    3. Smeltin g Ores are blasted at high temperature to extract the metal. Energy isrequired to maintain the high temperatures in a furnace. (Chemical separationmethod/process)

    4. Refining High amounts of heat and electricity is needed and is to be maintainedthroughout the process to purify the metal, depending on the type of refining process.In electrolytic refining (electrolysis), electricity/energy is needed to separate thechemical bonds. (Chemical separation method/process)

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    Identify why there are more metals available for people to use now than there were 200 yearsago

    More advanced technology and extraction processes to extract ores that were unable tobe used 200 years ago. In previous centuries, there was limited knowledge on theextraction processes that offered pure extracts. As the rate of technology and knowledgeincreased, mankind began to apply more advanced machinery and derive better extractionmethods and thus extract and use more metals. Some technology/extraction methods weuse today to obtain metals were unavailable centuries ago due to the slow rate oftechnology advance.

    More discoveries of metal and locations allows more extraction

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    Identify the reaction of metals with acids as requiring the transfer of electrons Oxidation is losing electrons O.I.L (Electrons on the right) [Reductant] Reduction is gaining electrons R.I.G (Electrons on the left) [Oxidant]

    Reactions with dilute acid Most metals react with dilute hydrochloric acid and sulphuric acid to form hydrogen. We can write these

    equation as:

    Describe observable changes when metals react with dilute acid, water and oxygen.

    When a very reactive metal reacts with water, a metal hydroxide and hydrogen gas isproduced.

    o metal + water metal hydroxide + hydrogen gasEg.2Na (s) + 2H O(l) 2NaOH (aq) + H (g)

    When a less reactive metal reacts with water, a metal oxide is produced.o metal + oxygen metal oxide

    Eg. 2Mg (s) + O (g) 2MgO (s)

    When a metal reacts with an acid, a metal salt and hydrogen gas is formedo metal + acid metal salt + hydrogen gas

    Eg.Zn (s) + 2HCL (aq) ZnCl (aq) + H (g)

    describe and justify the criteria used to place metals into an order of activity based on their ease of reaction with oxygen, waterand dilute acids

    the most active metals are at the top , the least reactive areat the bottom

    the more reactive, the harder it is to extract It can be established by observation of the reaction of the

    metals with water, oxygen or acids. The lower the metal, the earlier it was found/discovered.,

    The order of reactivity with oxygen is {Li, Na, K, Ca, Ba} > {Mg, Al, Fe,Zn} > {Sn, Pb, Cu}, {Ag, Au, Pt}

    The order of reactivity with water is { Na, K } > {Li, Ca, Ba} > {Mg, AL,Fe, Zn}, {Sn, Pb, Cu, Ag, Au, Pt}

    construct half-equations to represent the electron transfer reactions occurring when metals react with dilute hydrochloric anddilute sulfuric acids.

    Half-equations help us understand the electron transfer process between metals and non-metals. Generally: metals lose electrons to form metal ions (cations)

    non -metals gain electrons to form non-metal ions (anions) hydrogen ions gain electrons to form hydrogen gas.Using these generalisations, we can write half-equations for the reactions between metals and dilute acids. Half-equations must bebalanced in terms of atoms and charges.

    Example: Reaction of aluminium with hot sulfuric acidAluminium atoms will lose three electrons and the hydrogen ions will gain two electrons.Electron loss: Al(s) > Al 3+(aq) + 3e Electron gain: 2H+(aq) + 2e > H2(g)

    To balance the electrons, multiply half-equation (1) by 2 and halfequation (2) by 3, and then add the two half-equations. Check thatthe atoms and charges balance.Electron loss: 2Al(s) > 2Al3+(aq) + 6e

    Electron gain: 6H +(aq) + 6e > 3H2(g)Ionic equation: 2Al(s) + 6H+(aq) > 2Al3+(aq) + 3H2(g)

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    o Balanced formulae equations- shows the whole balanced equationo Net ionic equations- shows only the ionic species that undergo changeo Complete ionic equations- shows all the ions involved in the solutions used for the reaction.

    For example when aluminium reacts with Hydrochloric acid we get: o 2AI2+ + 6HCI > 2AlCI3+ + 3H2 o 2AI + 6H + 6CI- > 2AI3+ + 6CI- + 3H2 o 2AI + 6H+ > 2AI 3++ 3H2

    Outline examples of the selection of metals for different purposes based on their reactivity,with a particular emphasis on current developments in the use of metals

    1. Magnesium: Used as a sacrificial layer. The magnesium is galvanised, over the layerof steel on the underside of ships. Because of the reactivity, magnesium will corrodebefore the steel.

    2. Calcium: In vacuum tubes, calcium is used, where air must not be present. Thecalcium will react the oxygen forming calcium oxygen which will no longer affectthe vacuum tubes application.

    3. Tin and chromium: Both metals are used to coat another metal to create a shinyappearance.

    Identif ytheimportanceoffirstionisationenergyindeterminingtherelativereac

    Outline the relationship between the relative activities of metals and their positions on thePeriodic Table

    For alkali and alkaline earth metals:1. Left is more reactive than right2. Down is more reactive than up3. Left-right is more dominant than down-up4. Therefore, potassium is the most reactive most down and most left) and

    magnesium is the least reactive most top and most right)

    5.

    Trends are non-existent for transitional metals

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    tivity ofmetals

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    Outline the history of the developments of the Periodic Table including its origins, the original data used to construct it andthe predictions made after its construction

    In 1789, Antoine La voisier published a table of 33 elements.1. Contained some compounds which at that time could not be broken down into simpler substances2. Divided his table into metals and non-metals

    In 1817 and 1829, Johann Dobereiner observed the chemical similarities between certain groups of 3 elementscalled triads.

    In 1864, Meyer arranged that elements in order of increasing atomic mass and placed them in groups based ontheir valency.

    In 1869, Dmitri Mendeleev arranged the elements in horizontal rows in order of increasing atomic mass.Elements with similar properties were arranged in vertical columns in the table. Mendeleev was also able tomake accurate predictions about elements that bad not been discovered by leaving gaps.

    In 1913, Henry Moseley proposed the concept of atomic number to fix the irregularities in Mendeleevs table. Itwas eventually determined that atomic number determines the chemical properties rather thanatomic mass.

    Explain the relationship between the position of elements in the Periodic Table, and their properties.

    - electrical conductivity

    Trend

    Identify an appropriate model that has been developed todescribe the atomic structure

    The modern atomic model At the centre of the atom is a positively charged

    nucleus consisting of neutral charged neutrons andpositively charged protons

    Around the nucleus are negatively charged electrons

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    Physical Property Definition Across a Period Down A group

    Electrical Conductivity A materials ability toconduct electriccurrents

    Generally decreases aselements become lessmetallic. Non-metals haveno free mobile electrons

    Generally increases as elements becomemore metallic (except group III)

    Ionisation Energy The energy requiredto remove an electronfrom an gaseousatom. Inner electron

    shells also reducesthe energy neededfor ionisation.

    Increases because theatomic radius decreasesacross the period so thevalence electrons are closer

    to the nucleus

    Decreases because the atomic radiusincreases hence meaning there are moreelectron shells. The outer shell electronsare weaker attracted to the nucleus.

    Atomic Radius The radius of anatom. It depends onthe number ofelectron shells andthe size of the nucleuscharge

    Decreases as the valenceshell moves closer towardsthe increasingly positivenucleus

    Increases as the number of electron shellincreases

    Meting Point andBoiling Point

    Melting point is whenthe element turns

    into an liquid. Boilingpoint is when anelement turns into anliquid. The metallicbond is strongest inthe transition metals.

    increases in groups I to IV

    decreases as the latticechanges from metallic tocovalent network and thencovalent molecular

    decreases in groups I to IV increases in groups V to VIII

    generally increases for transition metals

    Combining Power(Valency)

    the combining powerof an element that itwill combine with

    Maximum valency increasesfrom groups I to VII, inwhich group number equalsmaximum valency.

    Maximum valency is constant and equal tthe group number (except for group VIIIwith a valency of 0).

    Electronegativity A measure of theelectron-attractingability of an element.

    increases as the metalliccharacter decreases

    decreases as the metallic characterdecreases

    Reactivity The rate at which achemical substancetends to undergo achemical reaction intime.

    Each period starts with areactive metal and endswith an unreactive noblegas.

    increases down groups I and II. decreases down the group of transition

    metals. decreases down groups III and IV for soft

    metals. generally decreases down groups V to VII

    for non-metals. increases down the group of noble gases.

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    Hence, most reactive elements at bottom left and least reactive elements at top right

    Moles The unit of measurement for the amount of substance or chemical amount.

    12g of the carbon-12 isotope contains 6.0221023

    atoms which is 1 mole The moles of an substance = mass/molar mass

    isotopeso Each of 2 or more forms of the same element contain equal numbers of protons but different amount of

    neutrons.Molar mass

    o The mass of an element per mole of its atom. E.g. the molar mass of water, (H 20 ) is 1.008+1.008 +16) =18.061g/mol

    compare mass changes in samples of metals when they combine with oxygen Law of conservation of mass: matter can neither be created nor destroyed in a

    chemical reaction 2Mg s) + O 2 g) 2MgO s) using the periodic table to find the elements masses)

    1. 224.305 + 2x15.999 2 24.305 + 15.999)2. 80.608 80.6083. LHS = RHS, therefore it obeys the law of conservation

    Describe the contribution of Gay-Lussac to the understanding of gaseous reactions andapply this to an understanding of the mole concept

    Gases combine in simple whole number ratios; Stoichiometric Ratio

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    Derives chemical equations and finds moles

    Recount Avogadros law and describe its importance in developing the mole concept Avogadros law states that equal volumes of gases, at the same temperature and pressure,

    contain equal number of molecules1. The number of molecules in equal volume of gases is independent of size or mass.2. If each gas has the same volume and under the same conditions, they will contain the

    same amount of molecules

    3. E.g. hydrogen + chlorine > hydrogen chloride. 1 litre + 1 litre > 2 litres 4. 1 mole of any gas is 24.79L at SLC or 25 degrees5. 1 mole of any gas is 22.71L at 0 degrees

    Distinguish between empirical formulae and molecular formulae An empirical formula shows the ratio in which atoms are present in a compound A molecular formula shows how many of each type of atom are present To change between molecular and empirical,

    Determine the molecular formula

    If it is written structurally, convert it to standard Write the new equation

    E.g. hydrogen peroxide1. Molecular formula = H 2O2 2. All subscripts divided by 2 or lowest common factor3. Empirical = HO

    How to create an empirical formula from mass or percentage composition1. Create a chart with six columns, and the number of rows should be equal to the number of element in the compound.2. In the first column write the elements.3. In the second column write the percent composition of each element.4. Using the percent composition as the mass, divide each by the molecular mass of the respective element.5. Divide each of those numbers by the smallest of the numbers in that column to reduce the ratio.

    Example: Determine the empirical formula for a compound containing 74.0% carbon (C), 8.65% hydrogen (H), and 17.3%nitrogen (N) by mass.

    element percentage % / molar mass Divide by largestdenominator

    Round up

    C= 74% 74/12 6.16/1.24 4.96 5H= 8.65% 8.65/1.01 8.56/1.24 6.9 7N= 17.3% 17.3/14.01 1.24/1.24 1 1

    Therefore the formula is C 5H7N

    Examples:A 9.2 gram sample of a compound is 2.8 grams nitrogen and 6.4 grams oxygen. Find the empirical formula of the compound.

    Therefore the empirical formula is NO 2

    element Mass over total percentage Percentage/mmN= 2.8/9.2 30% 30/14.0 2.143/2.143 1 1O= 6.4/9.2 70% 70/16 4.375/2.143 2.04 2

    Define the terms mineral and ore with reference to economic and non-economic deposits of

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    natural resources An ore is a deposit of minerals that contains metal s) that are considered

    valuableenough to be mined Minerals are naturally occurring solid homogeneous inorganic that contain a

    metal s) that are deemed valuable

    Describe the relationship between the commercial prices of common metals, their actualabundances and relative costs of production

    Abundance:1. A mineral must be sufficiently concentrated in the ore body to make it

    economically viable to extract. If the concentration is low, it is usually noteconomical, as the costs of extraction and production are greater thanthe value of the mineral obtained.

    Cost of production:1. Companies need to determine the cost of mining, milling and extracting

    a metal from its ore. This would impact upon the final price;transportation costs may also vary due to the remoteness of some orebodies. The location can also affect the price as there may be a lot of

    energy/water or the site may be environmentally protected. Common metals:

    Some metals are more expensive to extract than others due to higher energy costs involved.For example, aluminium is more expensive to extract than copper due to the high cost of theelectrolytic process used to make aluminium.

    Explain why ores are non-renewable resources Ores are non-renewable resources as they were formed when the earth was

    formed and there is no way of forming more ores. Also, the rates at which humans are using these ores are much faster than the

    rate that these ores are formed in the earth. Therefore our consumption ofthese ores is much greater than their production, resulting in the classification ofores as non-renewable resources.

    Describe the separation processes, chemical reactions and energy considerations involved in the extractionof copper from one of its ores

    Extraction of copper from copper sulphide ores Mining and Milling: Ores are mined from the earth and crushed, which are both physical

    methods of separation. The ores are merely reduced in particle size.

    Froth Floatation: With the ore in smaller particle size, froth floatation can be used to removeimpurities called gangue. In this physical separation technique, bubble are agitated in asolution of water and detergent. The copper particles cling onto these bubbles and areskimmed off.

    Roasting: The copper is then roasted with sand and air. It is subjected to high temperatures. Achemical separation technique involves the chemical reaction of sand (SiO 2) combining withiron oxide (FeO) impurities to form a compound called a silicate (SiO 3).

    o 2CuFeS 2(s) + 4O2(g) > Cu 2S(l) + 2FeO(s) + 3SO 2(g) Smelting: Like roasting, smelting is a chemical separation technique that subjects the copper to

    high temperatures with carbon and air. The copper concentrate reacts with oxygen in the hotair to remove the sulphur as sulphur dioxide (SO 2). This leaves copper of 98% purity which iscalled blister copper.

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    o FeO(s) + SiO2(s) FeSiO3(l) Electrolytic Refining: The copper is transported to a facility that refines copper using

    electricity, which is a chemical separation technique. The blister copper anode graduallydissolves and pure copper deposits on the cathode. Impurities that give up electrons lessreadily than copper fall to the bottom. This leaves the copper 99.99% pure.

    o Anode: Cu(s) Cu 2+ > (aq) + 2e o Cathode: Cu2+(aq) + 2e > Cu(s)

    Energy considerations:1. Froth floatation requires very little energy2. Roasting requires little fuel since the reaction is strongly exothermic (gives out heat).

    It releases energy that can be useful in returning some energy.3. Electrolysis process requires a high amount of energy since it is using electricity4. Since copper is so reactive with other elements, it requires more energy to separate

    them. Elements such as gold require very little energy since no other elements arecombined with gold.

    Recounts the steps taken to recycle aluminium1. Aluminium is collected from recycling bins2. The aluminium is transported to a recycling plant/facility3. Differ the aluminium from its alloys and aluminium metal4. Aluminium products are deposited in a furnace where they are subjected to very high

    temperatures. This process purifies the metal, as it removes the impurities based onmelting points.

    5. Analyse the purity of the aluminium and adjust it composition before casting it intoingots.

    6. The solution, pure aluminium, is remoulded into the desired product and sold tocompanies that need it.