Chemistry 2014 csir net question paper

download Chemistry 2014 csir net question paper

of 42

Transcript of Chemistry 2014 csir net question paper

  • 8/11/2019 Chemistry 2014 csir net question paper

    1/42

    i?h n:..1..?;-.1.?;.:

    ..............

    77

    y ..........................

    O R 5?%T:. .A.m.O

    .....

  • 8/11/2019 Chemistry 2014 csir net question paper

    2/42

  • 8/11/2019 Chemistry 2014 csir net question paper

    3/42

    9.11 x 10-~11cg

    6.63 x I@ J sec

    1.6

    x

    10-'9c

    1.38 x 10-= J/K

    3.0

    x

    lVm/Sec

    'eV

    amu

    G

    Y

    N

    A

    E O

    o

    6.023

    x

    l

    O

    mole-'

    USEFUL

    FUND MENT L

    CONSTANTS

    Mass of electron

    9.1 1

    x

    10-J'Kg

    ~ l a n c k ' s onstant 6 . 6 3 ~ 1 0 - ~ J s e c

    Charge of electron

    1.6

    x

    10-l9C

    Boltzmann constant

    Velocity of Light

    1.6 x 1 0 - 9 ~

    I,v

    mu

    ydberg constant

    1 . 0 9 7 ~07m-I

    6.023 x 100

    mole-'

    vogadro number

    8 854 x 10-'2Fm4

    7t x 1 0 - 7 ~ '

    Molar

    as

    const nts

  • 8/11/2019 Chemistry 2014 csir net question paper

    4/42

    LIST

    O

    THE TOMIC WEIGHTS

    O

    THE ELEMENTS

    Element Symbol Atomic Atomic Element

    Svmbol Atomic Atomic

    Number Weight Number Weight

    Actinium Ac -

    89 (227)

    Mercury Hg

    80 200.59

    Alum~nium A l

    13 26.98

    Molybdenum Mo

    42 95.94

    Americium A m

    95 (243)

    Neodymium Nd

    60 144.24

    Antimony Sb

    51 121.75

    Neon Ne

    10 20.183

    Argon A r

    18 39.948

    Neptunium

    NP

    93

    Arsenic

    (237)

    A s

    33 74.92

    Nickel Ni

    28 58.71

    Astatine At

    85 (210)

    Niobium Nb

    41 92.91

    Barium Ba

    56 137.34

    Nitrogen N

    7 14.007

    Berkelium Bk 97 (249) Nobelium

    No

    102 (253)

    Beryllium Be 4 9.012 O smi u m 0 s 76 190.2

    Bismuth Bi 83 208.98 Oxygen 0 8 15.9994

    Boron

    5 10.81

    Palladium Pd

    46 106.4

    Bromine Br 35 79.909 Phosphorus P 15 30.974

    Cadmium Cd

    48 112.40 ,

    Platinum Pt

    78 195.09

    Calcium C a

    20

    40.08

    Plutonium PU

    94

    Californium C 98 (251) ~ o l o n i u m

    (242)

    Po

    84

    Carbon C 6 12e011 potassium

    (210)

    K 19 39.102

    Cerium C e

    58 140.12

    Praseodymium pr

    59 140.91

    Cesium C s 55 132.91 Prometh ium

    Pm 61

    Chlorine CI

    17 35.453

    protactinium

    (147)

    Pa

    91

    Chromium C r

    24 (231)

    52 00

    Radium

    Cobalt

    a

    88

    Co 27

    (226)

    58.93 Radon Rn

    86

    Copper Cu 29

    (222)

    Curium

    63 54

    Rhenium Re

    75 186.23

    C m

    96

    (247)

    Rhodium Rh

    45 102.91

    Dysprosium DY 66

    162 50

    Rubidium Rb

    37 85.47

    Einstein~um Es 99

    Erbium

    (254)

    Ruthenium

    68

    Ru

    - 4 4 101.1

    Er

    167.26

    Samarium-

    63

    Sm

    Europium

    62 150.35

    Eu

    Fermium F m

    100

    151.96 Scandium Sc 21 44.96

    Fluorine

    F 9

    (253)

    selenium Se

    34 78.96

    Fra-ncium Fr 87

    19 00

    silicon Si 14 28.09

    Gadolinium Gd

    64

    (223)

    silver Ag

    47 107.870

    Gall~um Ga 31 69.72 Na .-

    57.25 Sodium

    11 22.9898

    Germanium

    G

    e

    32 72.59

    Stront ium

    S

    38 87.62

    Gold A u

    79 196.97

    Sulfur S

    7

    6 32.064

    Hafnium H

    72

    178.49

    Tantalum Ta

    73 180.95

    Helium

    He

    2 4.003

    Technetium

    Tc 43 (99)

    t jolmium Ho 67

    164.93

    Tellurium Te

    52 127.60

    Hydrogen H 1

    1,0080

    Terbium Tb

    65 158.92

    Ind ium In 49

    114.82

    Thallium TI 81 204.37

    Iodine I .

    53 126.90

    Thorium Th

    90 232.04

    Ir idium

    Ir 77 192.2

    Thul ium Tm

    69 168.93

    I ron Fa

    26 55.85 Tin

    Sn

    50 118.69

    Krypton Kr 36 83.80 Titanium Ti 22 47.90

    Lanthanum La

    57 138.91

    Tungsten W

    74 183.85

    Lawrencium Lr 103 (257) Uranium U 92 238.03

    Lead Pb

    82 207.19

    Vanadium V

    23 9 , 9 4

    Lithium L i

    3 6.939

    Xe

    54 131.30

    Lutet ium L u 71 174.97 Ytterbium Yb 70 173.04

    Magnesium M 9

    12 24.312

    Yttrium Y

    39 88.91

    Manganese M n 25 54.94 Zinc

    Z

    n 30 65.37

    Mendelev~um Md

    101 (256)

    Zirconium Zr

    40 91.22

    Based on mass of Cqz at

    12.000

    ... The ratio of these weights of those on the order chemicalqcale (in which Oxygen of

    natural isotopic composition was assigned a mass of

    16.0000...

    is

    1.000050.

    (Values in parentheses represent the most

    stable known isotopes.)

  • 8/11/2019 Chemistry 2014 csir net question paper

    5/42

    f f

    2.

    4; /

    PART

    A

    1

    The following diagram shows

    2

    perpendiculply inter-grown prismatic crystals

    twins) of identical shape

    and

    size. What is the

    3

    volume of the object shown units are

    arbitrary)?

    Suppose in a

    box

    there are

    2

    red, 30 black, 40

    blue and 50 white balk What is the minimum

    number of balls to

    be

    dr~wn, witl~out

    replacement, so that you

    are

    certain about

    getting

    4

    red,

    5

    black,.

    5

    blus

    and , 7

    white

    balls?

    In the growing years of a child, the height

    increases as the square root of the age while

    the weight increases in direct proportion to tlze

    age. The ratio of the weight to

    the

    square of

    the height in this phase of growth

    1 is constant.

    2

    reduces with age.

    3 increases with age.

    4

    is constant only if the weight and height at

    birth are both zero.

    ~ A ~ ~ ~ 3 k W

    80,70,50,60,90,301

    B

    a

    40, 80, 35, 70, 85, 45, 50, 75, 60

    hi d l

    m*f

    -

    0 )= 3mm 3iF

    -

    3 k

    W k RD) =-

    *

    31

    1 w

    Am

    R D = T

    Bm RD

    2 . w Am RD> w Bm RD

    3 Am RD w Bm RD

    4 . w q r A m D c w BmD

  • 8/11/2019 Chemistry 2014 csir net question paper

    6/42

    4 Students

    in

    group A obtained the following

    marks: 40 80 70 50 60 90 30. Students in

    group B obtained 40 80 35 70 85 45 50

    75 60 marks.

    Defme

    dispersion @ =

    maximum

    marks

    minimum

    marks , and

    tspenton

    relative dispersion

    RD)

    = .

    Then,

    1. RDofgroupA=RDofgroupB.

    2.

    RD

    of group

    A >

    RD of group B.

    3. RD of group

    A

  • 8/11/2019 Chemistry 2014 csir net question paper

    7/42

    9

    If all horses are donkeys, some donkeys are

    monkeys, and some monkeys are men, then

    which statement mGst be true?

    1. All donkeys are men.

    2.

    Some donkeys may be men.

    3. Some horses are m en.

    4. All horses are also monkeys.

    i

    10.

    A rectangular area of sides 9 and

    6

    units is to

    be covered by square tiles of sides

    1, 2, and 5

    units. The minimum number of tiles needed

    for th is is

    1. 3 2. 11

    3. 12 4. 15

    ll

    Suppose n is a positive integer. Then

    n2

    n) 2n 1)

    1.

    may not be divisible by

    2.

    2.

    is always divisible by 2 but may not be

    divisible by 3.

    3

    is always divisible by

    3

    but may not be

    divisib le by 6

    4. is always divisible by

    6

    12. There is a train of Length 500 m, in which a

    man is standing at the rear end. At the instant

    the rear end crosses a stationary observer on a

    platform, the man starts walking from the rear

    to the front and the front to the rear of the train

    at a constant speed of

    3

    kmhr. The speed of

    the train is 80 km/hr. Th e distance of the man

    from the observer at the e nd of 3 0 minutes is

    1

    41.5

    km 2

    40.5

    krn

    3

    40.0

    km

    4. 41.Okm.

    Three identical flat equilateral-triangular

    plates of side cm each ar e placed together

    such that they form a trap ezium . The length of

    the longer of the two parallel sides of this

    trapezium s

  • 8/11/2019 Chemistry 2014 csir net question paper

    8/42

    14. An rcher climbs to the top of a 10 m high

    building and aims at a bird atop a

    tree

    17 m

    away. The line of sight from the archer to the

    bird makes an angle of 45 to the horizon tal.

    What is the height of the

    tree?

    1. 17m 2. 2 7 m

    3. 37m 4. 4 7 m

    J'i

    A B = A C = ~ . hT

    m

    i

    T iW

    APOQ kT

    d h iX

    8,

    r n r n p . o r 8 1 r n

    r r m a ; r r * q m ~ * m ~ m

    ~ ~ r r A ~ o . 2 i ~ ~ ~ m 8 1

    15 Consider ;right-angled triangle

    ABC

    where

    AB

    =

    AC

    =

    3. A

    rectangle APOQ is drawn

    inside it as shown, such that the height of the

    rectangle is twice its width. The rectangle is

    moved horizontally by a distance 0.2 as shown

    schematically in the diagram (not to scale).

    C

    Area o AABC

    What is the value of the ratio

    Area

    o AOST

    1 625 2 400

    3 225

    4.

    125

    16 80 srn paper is cut into sheets of 200 mm

    x

    300 mm size and assembled in packets of 500

    sheets. What will be the weight of a packet?

    (gsm = dm2)

    1. 1.2k g 2. 2.4 kg

    3. 3.6 kg 4. 4.8 kg

    17

    Find the missing letter

    A

    B

    C

    F

    I

    L

    K

    P U Z

    P

    W

    18.

    A

    merchant buys equal numbers of shirts and

    trousers and pays

    Rs.

    38000. If the cost of

    3

    shirts is Rs 800 and that of a trouser is Rs

    1000, then how many shirts were bought?

  • 8/11/2019 Chemistry 2014 csir net question paper

    9/42

    19 3M {1711 7 ~ ~, 1 7 ~ ~ .

    1

    The correct order of basicity for the following

    f h l ? l ~ ~ T b ~ ~ 3 k 3

    nions is

    1. 60

    2.

    75

    3. 100

    4. 150

    19 Consider the set of numbers

    {1711 72,.- 7 ~ ~ ~ .

    OW many of these

    numbers. 60 end with the digit

    3?.

    75

    N02

    O2 O2

    3. 100 4 150

    1. 16 2. 96

    3. 50 4 80

    -

    20 Find the missing number in the triangle

    PART 'B'

  • 8/11/2019 Chemistry 2014 csir net question paper

    10/42

    22 The major product formed in the reaction of

    2,s-hexanedione with

    P p 5

    s

    23. The absolute configuration of the two

    stereogenk (chiral) centres in the following

    malcc- le-i-s - -

    ---

    I

    24

    The correct statement about the following

    molecule is

    A e c u l e s chiral and possesses a chiral

    plane

    2 Molecule is chimi and possesses a chjral

    /

    axis-.

    3.

    Molecule is achiral as it possesses a plane

    of symmetry

    4

    Moiecule is achiral as it possesses a centre

    of symmetry

    -

    A.

    cis- KT

    fW trans

    I

    B

    tram

    t l ~ ~ fEW f? T

    cis

    I

    c . t r a m m

    7 r m I

    D cs ZW srPdaiS r

    m

    I

  • 8/11/2019 Chemistry 2014 csir net question paper

    11/42

    25 Consider the follow ing statementsabout

    -

    is-

    and tr&dccalins-

    A. c5-isomer is mo re stable

    than

    trdns-isomer

    B: tr--isomer is m ir e stable than ck iso m gr

    C. trans-isom erund ergoes ring-flip -

    D. cis-isomer undergoes ring-flip

    The orrect statem ents among theabove are

    d a n d 2 A a n d C

    3.

    A a n d D

    4.

    . B a n d C

    26 I3is@I $%X ~ M I ~ ~ T T J ~ )

    ~ ( I I )

    m

    In bis dimethylglyoximato)nickel IQ, the

    number of Ni-N

    ,

    N& and i nt ra m ol ec ul ~

    respectively, are

    2. 2 ,2 and 2

    3. 2 ,2 a n d 0 4. 4,O and 1

    27 f 7

    FhPh,

    (A) Ni(I1);

    +T$m-

    GRx (B) AI(II1);

    If

    an enzyme @s

    N2

    n plants

    by

    evolving

    H2 he ? u ~ b e r f electrons and protons

    i ed S it h that, respectively,

    ? ? f a n d

    6

    3.

    6

    and 8

    2 . 3 d

    4. 8and6

    29 Th e particles postulated to always accompany

    the positron emission among

    (A) neutrina,-'(B) anti-neutrino, (C) electron,

    8 z r P P , % 8

    30.

    1. A,B?lW C

    2.

    A?TUTB

    3

    A?iW C 47 B?TUT C

    27

    hLong the following species,

    (A)

    NKII)

    s

    dihe@lglyo@nate, (8)

    Al(IIQ.

    ox';iate, (C) Ag(1)

    s

    chloride, those

    th j

    31.

    precipita'te with the urea hydrolysis .

    method are

    1. A , B a n d C 2. A a n d B

    3. A a n d C

    4.

    B a n d C

    are

    1.

    A , B a n d C 2. A a n d B

    3. A and C 4. Ba nd C

    Toxicity o f cadmium and mercury in the body

    is being re?&i'Sed% proteins, mainly using

    the am ino acid residue,

    1.

    Gly cine 2. Leucine

    3. Lysine 4 Cysteine

  • 8/11/2019 Chemistry 2014 csir net question paper

    12/42

    31.

    NiBr2 reacts

    with

    (EtXphhP

    at,

    78

    OC in CS2

    tii--@ie

    ki

    compound;

    A ,

    which upon

    standing at room temperature turn green to

    give compound, 'B', of the

    same

    formula.

    Th e meam red magnetic moments of

    ' A ' '

    5re 0.0 and 3.2 BM, re~~ect ive ly .~The-

    g e o m et r i i of ' ~ ' z de ~

    1. -Square

    war

    and Tetrahedral

    -

    2. ~ d e d r a lnd Square planar

    3. Square planar and Octahedral

    4.

    Tetrahedral and Octahedral

    U.+&&netic, paramagnet ic and d ia m a p ti c

    2 paramagnetic,diamagnetic

    m

    ~arml agne t i c

    3. diank-gnetic, paramagnetic and diamagnetic

    4.

    p&magnetic, diamagnetic and diamagnetic

    -

    - -

    35. - m f i - e

    vmrnif

    1.

    Na2Cr04?iWF%03

    2.

    Na2Cr207

    iW

    03

    3. Crz(C03), IT Fe(OH)3

    I .SC12 1,- .2. SClz

    am

    I

    35.

    Chromite

    ore

    on h i o n with sodium

    3.SC12 V4T ClF;

    4.

    1,'SX ClF; carbonate gives

    1. Na2CrC?4 ~ i i d e203

    32. The correct non-cinear and iso-structural pair is

    2. Na2Cr207and Fez03

    ,;/ I2 and

    b

    .

    SClz and'I3-

    4 -

    3. Cr2(C03)3 nd Fe(OH)3

    -\ 3.

    .?(&and

    CjFf : 4.

    J; and . IF;

    4.

    Na2C r04 nd Fe~(C03)3

    t3 5 . I . A f s 7 y .,

    i .

    33.

    mpFT

    36.

    221

    -

    298

    K

    WT

    ?7

    [(r15-c5H5)

    33.

    Ozone present in upper atmosphere protects

    a --__----

    people on the earth

    1. due to its diam agnetic nature,

    2. due to its blue colour

    3. due to abso rption of radiation of

    wavelength at 255 nm

    ' 4. by destroying chlorofluoro carbons

    36. Th e ligand(s) that is (are) fluxional in [(l15-c5H5)

    -

    ( q 1 , ; ~ s ~ 5 ) ~ e ( ~ ~ ) 2 ]n the temperature range

    I 221

    -

    298

    K,

    is'iare)

    1. q 5 - ~ 5 ~ 3

    G4 Trc5~5

    3. q 5 - ~ 5 ~ 5nd CO

    4. ' q ' - ~ 5 ~ 5nd CO .

    /-\-.

    2. NH 33W 1,10--

    34.

    9R L

    Vii

    ?zmf w*

    mz if

    m

    3 H20

    m

    ,lO- lwiah a,

    mfbfAgL412', [AgLa]" ?iW [ A ~ L ~ I ~ '

    T?J:

    ?

    --

    4. HzO P I T NH3

    -

    J k FG l Q

    2. qy- ~,

    m

    qg6al6cl

    37. [ C O L ~ ] ~ 's red in colour whereas [co L '~ ]' ~s

    3.

    -

    32YcslCh?~

    T

    green . L and L' respectively corresponds to,

    1. NH3 and H 20

    4 . ~ , m y a 7 4 h 3 W - 2. NH3 and 1,lO-phenanthroline

    3 . H 20and 1,lO-phenanthroline

    34.

    If L is a n eugal monodentate ligand, the species,

    f4ii

    4. H 2 0and NH3

    [ A ~ L ~ ] ~ ' ,A ~ L ~ ] ~ 'nd [ A ~ L ~ ] ~ 'respectively, are

    ,

    4 ;

    V

    : --b

    H

    \

    1 p -.

    ,

    4

    < \

    cd

    1

    ' 4 4 ,./

    n

    , Y

    Ca

    ..,

    f -

    --

    --

    1 .r

  • 8/11/2019 Chemistry 2014 csir net question paper

    13/42

    'r

    38 [N~~(co)~]'-*

    18

    $ f h Ni*

    ic

    3 m m f V J T ~ ~ ~ - ~ ~ *

    *i

    1.

    Ni(-II), 1 2 N i 2 =

    3

    Ni(-I), 3 ll3XT 4

    N i i 3TiTZT

    L

    li

    38 The oxidation state af-Ni nd the number of

    r

    metal - metal bonds in ~ i ~ ~ 1 2 -hat are

    f

    consistent w ith the

    18

    electron

    rule are

    J

    2 Ni(lV), 2 bonds

    -I), 1 bond 4. N i o , 3 bonds

    I

    1

    t

    ...

    39 Structures pf SbPh5and P P ~ ~espectively are

    1. trigonal bipyramidal, squarqpyramidal

    . 3

    2 squa re pyramidal, trigona l gipyramidal

    3 trigo nal bipyramidal, trigonal bipyrarnidal

    l

    4.

    squa re pyramidal, square pyramidal

    The typical electronic configurations of the

    transition metal centrid , .ar oxidy&vzaddit,ion

    ar A l > C a > S

    2

    S > A s > A I > C a

    3.

    A l > C a > S > A s

    4.

    S > C a > A s > A I

    88.

    M ~ ~ N ~ H ~ C H ~ C H ~ P P ~ ~

    TW KSCN

    1:2

    m91n~

    K2[PdC14] Wi

    d i IT

    F @ i T A f l i f ; I ~ A ~ ~ G l ? l l

    ~ 8 ~ ~ ~ ~ @ ~ t r a n s ~ , ~

    famfaZmm -

    (A) P, N (B) N, S (C) P, S (D) N, N

    1.

    A m

    B

    2 A m

    D

    3 BPTT

    C

    4.

    CPJT D

    -

    88.

    A

    :2

    mixture of Me2NCH2CH2CH2PPh2nd

    KSCN with K2[Pd CI4] gives a square planar

    complex

    A.

    ldentify the correct pairs of

    donor atoms trans to each other in complex A

    from the follow ing combinations.

    P, N

    B)

    N,

    S

    (C) P, S

    Dl

    N,

    N

    (B)

    m m - ~

    mt

    (C) af3Vm f

    Q r n s f ; l r l f t r l l o r

    89.

    For a low energy nuclear reaction,

    24

    Mg(d, a) ~a, the correct statements from

    the follow ing are

    (A ) kineti c energy of d particle is not hl ly

    available for exciting M ~

    (B ) total nu mber of protons and neutrons is

    conseried

    (C)

    Q

    value of nuclear reaction is much

    higher in magnitude relative to heat of

    chem ical reaction

    (D ) th resho ld energy is value

    1.

    A , B a n d C 2. A , B a nd D

    3.

    B , C a n d D

    4.

    A , C a n d D

  • 8/11/2019 Chemistry 2014 csir net question paper

    26/42

    99 At

    p 7 the

    zindIl

    ion in

    c rbonic

    anhydmw

    reacts with

    C 2

    give

    91

    Molybdoenzymes can both oxidize

    as

    well

    as

    reduce the substrates, because

    I

    Mow0 is more stable than M o w )

    2

    Mo(lV)can transfer oxygen atom to the

    substrate and Mo(VJ.) can abstract oxygen

    atom from the substrate

    3. conversion of M q I ) o Mo(IV) is not

    favoured

    4

    M o o an transfer oxygen atom to the

    substrate and Mo(1V) can abstract oxygen

    atom from the substrate

    a comparison of the valence electron

    'configuration of the elements, Sm and Eu

    suggests that

    1 Sm is a better one electron reductant than

    Eu

    2 Sm is a better one electron oxidant than Eu

    3. facile oxidation state is 2 for both the

    elements

    4 both of these display similar redox

    behaviour

    93 The cooperative binding of Oz in hemoglobin

    is due to

    1 a decrease in size of iron followed by

    changes

    iq

    the protein conformation

    2 an increase in

    size

    of iron f~llowedy

    chimges in the protein confoxmatior

    3 a decrease in s@ of iron that is NOT

    accompanied by the protein conformational

    changes

    4

    an increase in size of iron that is NOT

    accompanied'6y the protein conformational

    changes

  • 8/11/2019 Chemistry 2014 csir net question paper

    27/42

    94. Amongst the following which is not isolobal

    pairs

    1 M ~( CO )S , H3 2. Fe(C0)4,

    3

    Co(CO),, R2Si 4. Mn(C0)5,

    S

    q

    2 gp

    ti ti H

    95.

    Th e correct order of the size of

    S, s2-,2+

    and s4+pecies is,

    1.

    s>s2+>s4+>s2-

    2 s2+ s4+ s2-

    S

    3.

    sZ- s

    >

    s z + >

    s4+

    4. s4+ sZ- s>

    s2+

    dm J p

    KB~I H

    l N

    benzene

    reflux

    1. i. Ph3P+CH20MeCI-, uLi; ii. ~ ~ 0 ;ii.

    Jones

    36 d

    2. i. H2N-NHTs; ii. BuL i 2 equiv.); iii. DM F

    3.

    i. H2N-NHTs; ii. BuLi (2 equiv.); iii. C 0 2

    4. i. CICHZCO2Et,LDA; ii. B F3-OEtz; ii.

    DMSO, (COC1)2, Et3N,-78 OC to rt

    97.

    The correct combination of reagents to effe ct

    the following conversion is

    \-

    t

    1 i. P ~ ~P cH ~ oM ~ c I- , uLi; ii. ~ ~ 0 ;ii. Jones

    .

    ...

    reagent

    2. i. H2N-NHTs; ii. BuL i (2 equiv.); iii. DMF

    m z N - N H T s ; i. B uLi (2 equiv.); iii. C 0 2

    ----

    96.

    Th e major product formed in the following

    4.

    i

    ClCH2C02Et,LDA; ii. BF3.0E t2; iii.

    reaction is

    DMSO, (COC1)2, Et3N,

    -78

    OC to rt

  • 8/11/2019 Chemistry 2014 csir net question paper

    28/42

    E3u4N r'

    anhyd. CF3COOH

    CH CI

    2

    Br

    F 8 7 ~ h e ajor product formed in the following

    eaction is

    99 Consider the fol lowing reaction.

    The appropriate intermediate involved in this

    reaction is

    100. ~t a e t IW T

    l R

    c~hp t t 6)

    f mZt:

    ,

    100

    The correct

    13cN R

    chemical 6) shifi

    values of carbons labeled a e in the following

    ester are

  • 8/11/2019 Chemistry 2014 csir net question paper

    29/42

    B.

    ATP 43

    C NADPH*

    a

    iq

    ~ . m m a q

    m -iF

    1

    1. A , B a S r

    D 2.

    A m

    A : dO Bie:dN

    3.

    B r n

    C

    4.

    A C?Rll

    D

    2. 102

    The biosynthesis of isopentenyl

    A :

    s% .

    B:

    pyrophosphate fiom ace tyl Co A involves:

    H

    A. Four molecules of acetyl CoA

    B. Three molecules o f AT P

    3.

    C. Two molecules ofNADPH

    A : 6 a,n D. Two molecules of lipoic acid

    Me

    H

    The c o m t options among these are:

    A 1. A , B a n d D 2. A a n d B

    .

    3. B a n d C

    4

    A, C and D

    103

    - R M d 5

    - .e

    m ~ ~ , * w A * g

    '

    ?

    .

    The-prod.u.ctsA md .B.~ n..th e~f ollo win g

    -

    reaction sequence are

    hv

    A

    -

    B

    .

    1

    A

    t .---* C D

    1 A?fW C

    H

    Y ~

    2.

    3.

    A m

    . =

    103 Amongst the following, the major products

    formed in the following photochemical

    3.

    reaction are

    d n i m u r ~ ~ - ~ : 1 A a n d C

    2. B and C .

    4. A a n d B

  • 8/11/2019 Chemistry 2014 csir net question paper

    30/42

    A : A

    B

    105. Anthranilic acid, on treatment with i so - a m a tr if e

    H N

    MeO

    furnishes a produet which displays a strong peak at

    76

    d e )

    in its

    mass spectrum. The structure of the

    product is

    The products and B in the following

    sequenc e are

  • 8/11/2019 Chemistry 2014 csir net question paper

    31/42

    1 0 7 . - f f T J r ~ * - = ~ *

    rn c9h?dl

    n=0, t?rrrr2)*

    1. ~ ; R * i f f 5 t l f m m d h m f T ~ p , , =

    0.633, pi = 0.233

    ?lW ~

    .086 8 h

    Shw

    n 2 3

    A @ ~ ~ F w * * . .

    mBm8 I

    2. 1. 0.032

    2. 0.048

    3. 0.952 4. 1.000

    107;

    Usmg Boltimarirl d ib u t io n , the probability of

    3.

    ~

    o ill or

    g the irst

    thr evels

    n =

    0, 1 ti 2)b

    f a d o be

    po=

    0.633,

    p, =

    0.233

    and

    p2= 0.0 6.

    The

    probability

    of

    findiig

    aii

    oscillator

    in n gy

    levelsn-23 is

    H Zn

    ;

    0,032

    2.

    0.048

    4.

    3. 0.952

    4. 1.000

    ..

    106. The, organoborane. X, when reacted with

    108. f b d & i 3 ~ f W m r s m r A ~ - m 1 q

    Et2Zn falowed bE-iodotoluene

    in

    the

    .

    atrr ~g

    pyi - J ~

    pr i5ni-of catalyti a m o x of pd(P~h,),

    i.

    P ~ N C O

    fumikhes a tris;b&tuted

    a

    The

    Et3N

    Hz

    RaneyNi

    intermediate and .&S iZGUC

  • 8/11/2019 Chemistry 2014 csir net question paper

    32/42

    -

    -

    :.-.> .

    .

    .-

  • 8/11/2019 Chemistry 2014 csir net question paper

    33/42

    1

    A

    odo2;

    B K 00~-N=N-COOX+,

    AcOH

    2. A 02,m M, h ~ K+-OOC-N=N-

    COOX+,ACOH

    3.

    A= 02,

    mm v; B

    =Hz,Pd/C

    4.

    A = O ~ , ~, B=H2,Pd/C

    112.The correct combination of reagents for

    effecting the foflowing-sequence of reactions

    is

    1

    A 03/02;B

    K+

    00~-N=N -COO X ,

    AcOH

    2.

    A 02,Rose Bengal, hv; B K+-OOC-

    N=N-cOOX', AcOH

    3.

    A

    0 2

    Rose Bengal, v; B

    Hz, PdC

    U1 Rose Bengal, A; B H2, PdC

    113.The correct combination of reagentsrequired

    to

    df the

    following conversion

    is

    4.

    s BuLi

    78 'C followe by ICH2C I

    r

    114 Consider a particle confined in a cubic

    box

    The degeneracy of the level, that has

    an

    energytwice.that of the lowest level, is

    1. 3

    2.

    1

    I

    ii

    BrCH2CH2Br

    115. Only two products are obtained in the

    following reaction sequence. The structures

    of the products from the list

    I-IV

    are

  • 8/11/2019 Chemistry 2014 csir net question paper

    34/42

    NaNHp

    ii

    BrC&CH r

    Mac '-: QCDP*

    o

    \ / ~ o o ~ e

    3

    H 4 OH

    ( -p

    117.

    ~ ~ I @ Z ~ T ~ ~ ~

    I u a

    rt

    ,L,J.---A

    oq NaCN

    Mn4

    dbxme

    6

    i . andII

    2.

    a n d N

    refha

    Wr0 1.

    Mef i

    3. I and

    4.

    n1 and IV

    1.

    116 ~ 3 l f h T f f ~ ~ A $

    A:

    )-Jy B:a

    c0

    eOOC COOMe

    A 2.

    >

    Heat

    < A :

    e:

    u (

    OOMe

    117. The products

    A

    and

    B

    in the following

    .. reaction sequence are

    3 4.

    OH

    so2

    aq. NaCN. M n 4

    A

    dioxane

    B

    IPrOH.Mc2NH

    r flux

    116. The

    major product A formed in the following

    reaction is 1.

    co

    eOOC COOMe

    A : 6 :

    A

    2.

    Heat

    -

    A :

    0 : 0J f

    COOMe

    COOMe

    3.

    2

  • 8/11/2019 Chemistry 2014 csir net question paper

    35/42

    The spatial part of the w ayefU ~ctio nof-th e

    atom in its ground state is ls(1 ) 14 2) . The

    spitrpaiGould be

    1. a l)a 2)

    2. P lIP 2)

    3. [a l)P 2) + P l)a 2)1

    NO, 2

    NO2

    i FGJ=4

    f 3 r o r ; 4 ~ r ~ ~ w ~ ~ ~

    The number of phases, eornponents and

    deg ree s of freedom, wnen ~r is added to

    n

    eqGZbrium mixture of NO, O2 and NO2 in

    gas phase are, respectively,

    1 . 1 ,3 ,5

    2

    1 , 4 , 5

    3

    1 , 3 , 4 4 . 1 , 4 , 4

    pyridine

    -

    O

    120 The major product formed in the following

    reaction is

    sCI

    pyridine

    121

    particle in a one dimensional harmonic

    oscillator in x-direction is perturbed by a

    potential

    x

    Is

    a

    number). The fi~st-orde r

    correc tioxo the energy of the ground state

    1. is o

    2

    is negaiive

    3. is positive

    4. may be negative or positive but NO T

    zero

  • 8/11/2019 Chemistry 2014 csir net question paper

    36/42

    Ph

    HO*OM~ B. LO

    A = HO.

    3 OH OH

    122. Th e pioducts A and B in the followkg

    sequence of reactions are

    1. HX= HF an dA = Br

    2. HX = HCl and A = Br

    3.

    H X = H B r a n d A = B r

    4. HX = HBr and A = Br

    H

    OH

    HoL Ho

    eOH

    I H

    . .

    - .

    refbx,

    4 h

    A

    O i ~

    H+

    The mass spectrum of the product A, formed

    in the following reaction, exhibits M, M 2,

    '

    M 4

    in the ratio of abo ut 1 2:1. The

    OH

    Ph

    reagent

    HX;and

    the pr0duct.A are

    -. -

    A = H&+OM 6 = OM

    . -

    -- '.

    7 . .Hx )

    1 OH .

    OH c

    c ,

    .

    . .

    A

    Br

    Hoq

    .

    A = HO B=

    3

    'O'

    L

    1. HX = HF and A = Br

    A =

    HO

    3. OH

    A = HHOO&~d B =

    2.

    HX

    =

    HCI and

    A

    =

    Br

    4

    OH

    8

  • 8/11/2019 Chemistry 2014 csir net question paper

    37/42

    125 A

    ..particle in a onedimensional box

    potential

    zero between o

    a

    and infinite

    outside) has the ground state energy

    above i l t o n i i n with +(x) = x(x )

    yields energy

    . . .

    l .

    .

    Using a linear

    c o m b i o n -two even func tlon ~x(x ~a1

    - +

    and xZ x ) , we obtain. yr ia tibnk

    m i n i o the ground state energy as E2.

    Which

  • 8/11/2019 Chemistry 2014 csir net question paper

    38/42

    128. If = 0.8

    P

    0.4 ~ is a normalized

    molecular orbital of a diatomic molecule

    . . .

    , .

    ..

    . ~ - - - . -

    A constructed from P

    and

    which ax

    . ., _^

    I .i_.._,..___ 0 ii

    - .

    .,,.

    < .:**,

    .-.. ; .

    also normallzed, the over1.y.2. etween-.A.v...L. P and

    is . .

    ,.

    1. 0.11 2 0.31

    3. 0.51 4 0.71.

    129. At a given temperature consider

    Fe203(s) +3CO(g) Fe(s) 3C02(g);

    K1= 0.05

    2C02(g) CO(g) Ol(g); K2

    =

    2x

    10-l2

    The equilibrium constant for the reaction

    mol- )

    increased

    he tempemlure by

    4

    K

    If

    the heat capacity of the calorimeter along

    with

    that

    of the rgaterial is 2.4 kJ K- , he

    molar internal energy of combmion,

    in

    kJ

    is

    1. 1000

    2.

    -1000

    3.

    20

    4

    -20

    131.

    The translational, rotational and vibrational

    pa dti on functions for a molecule are

    f-lation 10 m- 7 fmt tion 10, fv~~r tion

    1

    ksTh) 1O

    at room temperature,

    Using the appro xim ate data given above, the

    frequency factor (A) for a reaction of the

    type:

    atom diatomic molecult?

    -t

    nonlinear

    '

    ransition state product

    accordinp to the conventional transition state

    theory is

    1. 2 x lo3 2.

    6 x

    lo7

    3. 2 x 1012 4. 6 x l0l3

    1. 1000 2. 1000

    .

    132. The interplanar spacing of G O ) planes in a

    3

    20 4 20

    cubic unit cell with lattice

    130.

    In

    a bomb calorimeter, the combustion of

    0.5 g of compound A (molar mass = 50 g

  • 8/11/2019 Chemistry 2014 csir net question paper

    39/42

    39

    -

    . .

    133. A P B

    f t

    * 1- f*

    e fluorescence llfetlme of a molecule in a

    7 8 h q h m * r n m -

    solution is 5@

    s.

    The sum of all the

    nonradiative rate-constants

    Zk,,,)

    or the

    A ' a m m r f i t g ~ ~ m ~

    .

    decay of excited st e i s 1 . 2 ~08 s -'. n e

    d t ~ ~ w

    X

    l x P I T y i f ; flu ore sc en ce $ u a n t u m s d % f t h e.- - molecule

    , m r

    is

    1. 0.1

    1. 4,4 2. 4,8

    2. 0.2

    3. 8,4

    4.

    4 , 2

    3.

    0.4 w . 6

    133. A

    compound

    A B

    has a cu bic structure with 137.

    W - W

    3K&f

    A atoms ~ c c ~ ~ ~ ~ ~ a l l t h eorners of the cub e

    as

    well a s all the face cen i i sZ I ' o% . Th e3

    r m r r m % s t h * r n ~

    I .

    I

    atoms occupy four tetrahedral voids. The

    4 , 2 5 m 81 8

    p H - a l R m a f * ~

    v a l d s - o ~ ~ e l y ,re

    .=

    ~ f ; s r f F e @ w

    g 4 , 4 * - 2. 4,8,

    3 8 ,4 4J4,2

    8

    1. 4, 25 3W 81. 2. 2,5 r(PTT 9.

    134. CD3

    D*

    -1 a ESR -* 3. i l i , 115 isTT 119 4. i , I m 1

    - -it;

    137.

    Solutions of three elecl~olyteshave the same

    1. 1 2. 3

    3.

    4 v 7 ioniestrengtli m d - d i R & e ~ ~ ~ cC O n i

    I

    as

    27?25

    ifid

    x

    134. The number of lines

    in

    the ESR spectrum of

    magnitude

    bf Debye-HUckc-l creening engths 2

    CD3 is (the spin of D is 1)

    of the three so lut6 ns are

    1. 1 2.

    3

    1.

    4 , 2 5 a n d 8 1 .

    2 2,5

    and 9.

    3. 4 4.

    7 3.

    112, 115 and 119 4. 1 , l a n d l

    0

    =

    135. COz C=O 3TlTXT ZWT 120 pm 8 C02

    1 .

    @

    3lT ZT fhl3

    *t - --r;--- - fA-&c;I;IY

    &-%

    r\

    I ~ ~ ~ ~

    ( C m Fh ?T

    8

    ? i i X ? T 1 . 9x10- ~~ g ~

    e m

    - 2 . 5 ~0"~ kg) 2. cis- --* m

    tram---

    ~

    1.

    1 . 8 x 1 0 ~ ~ k ~ m ~ 2. 3 .6 x1 0- ~ ~k gm ~

    3. 5 . 4 ~o4' kg m2 4 . 7 . 2 ~ 1 0 ~ ' k g m ~

    * m a

    3.

    cis- --& 7 w ~11s+cli'=m3 -

    \

    135.

    The C=O bond length is 120 pm in C0 2.The

    & f i av?T& T$

    moment of inertia of C 0 2would be close ta

    ( m ak es o f C an d a re 1 . 9 ~0-27kg and

    4. f i m * * r n h v

    -

    2.5X kg, respectively)

    mT%Fr

    @ ,8

    1. 1 . 8 ~ 1 0 ~ 'g m 2

    3. 5 . 4 ~ 1 0 ~ 'g m2

    2' 3.6x lo4' kg m2

    138.

    Simple H i i c e molgcular orbital

    theory

    4. 7 . 2 ~ 1 0 ~ ' k g r n ~

    1.

    con side rs electron-electron repulsion

    136. f%FbT *

    V

    iqS

    ?T m S f I 5 W F f

    explicitly

    2. distin gu ishes cis-butadiene and trans-

    5 ~ 1 0 - ~ s $3 d f % 3 ~ % t ; * f ? R butadiene

    mfr

    363f m

    T mEib3

    a h EL)r

    3. distinguishes cis-butadiene and

    1.2x108 s

    -

    it; 1 i m nf;TAf4T

    cyclobutadiene

    4. has dif fer ent coulomb integrals for non-

    mlXm*'f equivalent carbons

    1. 0.1 2. 0.2

    t

  • 8/11/2019 Chemistry 2014 csir net question paper

    40/42

    40

    .< 27

    \ A

    .

    ' i~w. '

    ul.

    In

    thii tiii eaver-~urk

    of

    ( i~jaliite]-'

    -7(--T&& o n ~ o n ) 1

    for

    &,

    enzyme .. c t lyzed

    reaction followiiig

    .

    MichaeliiMenten mechanism, the ...i :

    139. iW

    ?RE

    30

    bar

    W

    El RTF

    intercept is- s If the

    initial enzymnzyme

    mcenEratiun

    is 1x104 M, the turnover

    -

    umber

    is

    1. 2.5~10~

    .

    .

    2. 1.ox1o4

    3.

    2 . 5 ~ 1 0 ~

    4.

    2 . 0 ~ 1 0 ~

    139. For the nondissociative Langmuir type

    adsorption of a

    gas

    on

    a

    solid s;;face-

    at

    a

    particular temperature t h e h t i o n of surf ce

    coveme- is-35 at- 30 bar. ~ h i p T u

    isotherm constant (in bar-' units)

    at

    this

    temperature is

    1. 0.05 2. 0.20 I

    3. 2.0 4. 5.0

    142. The E 6i1E direct product in Dj point group

    contains the irrkduGble representations

    140. For a set of 10 observed data points, the mean

    is 8 and the variance is 0.04. The 'standard

    deviation' and the 'coefficient of variation' of

    the

    data

    set are, respectively,

    1.

    0.005,O.l 2. 0.02, 0.2

    3. 0.20,2.5 4. 0.32, 1.0

    3 4 4 ~ FmTr - 7 a x-&

    3d73 W y- k

    Ek 5000

    M-' s

    8

    143. The result of the product Cz x)Cz (y) is

  • 8/11/2019 Chemistry 2014 csir net question paper

    41/42

    144. Given;

    I

    r ~

    I

    A. F O Q (s),+ 2e- Fe(s)+2 0 H aq);

    E0=

    -0 877

    V

    B. A13+(aq)+ 3e-+.Al(s); EO=

    -1

    66V

    C. AgBr(aq) e- +Ads)

    +

    Br- (aq);

    EO=

    0 07

    V

    The overall r e e m or

    the

    cells in the

    directi6.a.ofw faii-eo S.G.ge-wOU-i be

    ....- --

    . .

    -

    . .

    1. Cell with A&B

    :

    Fe

    reduced

    cehvith'A&c

    :

    Fereduced

    2. ce ll wi& A&B . : Fe reduced

    Cellwith A&C

    :

    Fe oxidized

    3.

    Cell with

    A B

    :

    Fe oxidized

    Cell with A&C : Ee oxidized

    4. Cell with A&B : -Fe oxidized

    Cell with A&C :. Fe reduced

    S18 CSMH4 1 CH 4

    i 7

    145. The reagent

    A

    used and the major productB

    formed in the following reaction sequence are

  • 8/11/2019 Chemistry 2014 csir net question paper

    42/42