Chemical Equilibrium Equations, balancing and equilibrium.

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Chemical Equilibrium Equations, balancing and equilibrium

Transcript of Chemical Equilibrium Equations, balancing and equilibrium.

Page 1: Chemical Equilibrium Equations, balancing and equilibrium.

Chemical Equilibrium

Equations, balancing and equilibrium

Page 2: Chemical Equilibrium Equations, balancing and equilibrium.

Equations:

• A chemical equation uses the chemical symbols and formulas of the chemicals that are used and made by the reaction and other symbolic terms to represent states of matter and reaction conditions.

Page 3: Chemical Equilibrium Equations, balancing and equilibrium.

Equations

• The reactants the chemicals that are put into the reaction. They are placed on the left of the arrow to signify that.

• The products are the chemicals that are made by the reaction. They are placed on the right of the arrow

Reactants Products

Page 4: Chemical Equilibrium Equations, balancing and equilibrium.

Examples

• A B

• PbO + CaS PbS + CaO

• NaCl + KNO3 NaNO3 + KCl

Page 5: Chemical Equilibrium Equations, balancing and equilibrium.

Examples

• A B

• PbO + CaS PbS + CaO

• NaCl + KNO3 NaNO3 + KCl

Reactant

Reactant Reactant

Reactant Reactant

Product

Product Product

Product Product

Page 6: Chemical Equilibrium Equations, balancing and equilibrium.

Equations

• Conditions required to carry out the reaction may be placed over the arrow.

These can include:HeatAcid (H+)Time for reactionCatalysts

Page 7: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing the equations

Coefficients are placed in front of formulas to balance the equation and to indicate the number of formula units (atoms, molecules, moles, ions) of each substance reacting or being produced. When no number is shown it is understood that one formula unit of the substance is indicated.This is known as Stoichiometry

Page 8: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• The total number of each atom on the left and the right of the periodic table must be the same

• Therefore when we do reactions the two sides must be balanced

• We do this by using Stoichiometry (Fancy word for number-in-front-of-chemical)

Page 9: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• The easiest way to do these is to balance each atom in the order of ‘least occurring’ and finishing with the atoms that occur in the most chemicals

• The overall rules can be summarised:

Page 10: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations• 1. Count and compare atoms on either side to determine which

atoms need to be balanced. • 2. Select the most complicated formula (the one with the most

atoms other than O or H). • 3. Treat polyatomic ions as individual units if they occur on either

side of the equation. • 4. Balance each atom or polyatomic ion by placing coefficients in

front of the formula including the unbalanced atom or ion. • 5. Check that balancing a formula with a coefficient, has not

unbalanced other atoms. Make adjustments as necessary. • 6. ALWAYS do a final check making sure each atom or polyatomic ion

is balanced and the smallest set of whole numbers has been used.

Page 11: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• Examples:

S + O2 SO

H2 + O2 H2O

Ca + H2O Ca (OH)2 + H2

Page 12: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• Examples:

2 S + O2 2 SO

2 H2 + O2 2 H2O

Ca + 2 H2O Ca (OH)2 + H2

Page 13: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• Examples:

LiCl + Ca(OH)2 LiOH + CaCl2

FeBr3 + H3PO4 FePO4 + HBr

PbCl2 + H2SO4 PbSO4 + HCl

Page 14: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• Examples:

2 LiCl + Ca(OH)2 2 LiOH + CaCl2

FeBr3 + H3PO4 FePO4 + 3 HBr

PbCl2 + H2SO4 PbSO4 + 2 HCl

Page 15: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• Examples:

C6H12O6 + O2 CO2 + H2O

C7H14O + O2 CO2 + H2O

NaHCO3 + H2SO4 CO2 + H2O + Na2SO4

Page 16: Chemical Equilibrium Equations, balancing and equilibrium.

Balancing Equations

• Examples:

C6H12O6 + 6 O2 6 CO2 + 6 H2O

C7H14O + 10 O2 7 CO2 + 7 H2O

2NaHCO3 + H2SO4 2CO2 + 2H2O + Na2SO4

Page 17: Chemical Equilibrium Equations, balancing and equilibrium.

States of matter

• Often you will see letters in brackets after the chemical. It denotes what state the element is in:

• (s) = solid• (l) = liquid• (aq) = aqueous i.e. dissolved in water• (g) = gas

Page 18: Chemical Equilibrium Equations, balancing and equilibrium.

Equilibrium

All reactions have a bias towards being products or reactants.• Equilibrium is reached when:1. The rates of opposing reactions are equal.2. Equilibrium concentrations of reactants and products remain constant.3. Attainment of equilibrium is not instantaneous and may require an extended period of time.

Page 19: Chemical Equilibrium Equations, balancing and equilibrium.

Equilibrium

• For a reaction to reach equilibrium two criteria must be met:

1. The temperature must be kept constant2. The system must be closed. This means

that once the reaction has started no substances can be added or removed.

Page 20: Chemical Equilibrium Equations, balancing and equilibrium.

Equilibrium Constant (K)

• The equilibrium constant is a mathematical ratio between the concentration of the reactants and products.

• It is given as the formulaaA + bB cC + dD would give K = [C]c x [D]d

[A]a x [B]b

(Products / Reactants)

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Equilibrium Constant

• There are things that must be left out of the K-expression as they do not have concentrations

• These are SOLIDS and LIQUIDS• They are simply considered to be ‘1’ and

therefore can be left out

Page 22: Chemical Equilibrium Equations, balancing and equilibrium.

Examples• C6H12O6 (s) + 6 O2 (g) 6 CO2 (g) + 6 H2O (l)

• PbCl2 (s) Pb (s) + Cl2 (g)

• H2O (l) H2O (g)

• 2 H2 (g) + O2 (g) 2 H2O (g)

• 2 Al (s) + 6 HCl (aq) 2 AlCl3 (s) + 3 H2 (g)

• 4 Al (s) + 3 O2 (g) 2 Al2O3 (s)

• Ca3(PO4)2 (s) + 2 H2SO4 (aq) 2 CaSO4 (s) + Ca(H2PO4)2 (s)

Page 23: Chemical Equilibrium Equations, balancing and equilibrium.

Value of K

• Because K is a ratio, the value of it can indicate if a reaction is likely to lie with the products or the reactants.

• If K is a large value (greater than 1000) then it means: Products

Reactants

Which means the reaction must be working, the products are more favoured than the reactants

This must be bigger

This must be smaller

Page 24: Chemical Equilibrium Equations, balancing and equilibrium.

Value of K

• If K is a small value (less than 0.001) then it means: Products

Reactants

Which means the reaction does not favour the products, i.e. It doesn’t go…

This must be bigger

This must be smaller

Page 25: Chemical Equilibrium Equations, balancing and equilibrium.

Le Chatelier

• An equilibrium can be shifted with different changes to a system – – Change in concentration– Change in pressure– Change in volume– Change in temperature

Page 26: Chemical Equilibrium Equations, balancing and equilibrium.

Change in concentration

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

Changing the concentration of the various compounds means the equilibrium will shift to try to re-correct back to the correct ratio

Page 27: Chemical Equilibrium Equations, balancing and equilibrium.

Change in concentration

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

e.g. Increasing the concentration of H2

Page 28: Chemical Equilibrium Equations, balancing and equilibrium.

Change in concentration

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

e.g. Increasing the concentration of H2

This will cause too much to be on the left-hand side of the equilibrium, meaning that the reaction will move to the right, using up the H2 and making more H2O

Page 29: Chemical Equilibrium Equations, balancing and equilibrium.

Change in concentration

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

e.g. Decreasing the concentration of O2

Page 30: Chemical Equilibrium Equations, balancing and equilibrium.

Change in concentration

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

e.g. Decreasing the concentration of O2

This would mean there was now too little on the left hand side, therefore the equilibrium will move to the right, H2O would decrease to make more O2

Page 31: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Pressure (by volume change)

• Volume and pressure are related. • Increasing the volume will result in a

decreased pressure and decreasing the volume will result in an increased pressure.

• This ONLY CONCERNS GAS MOLECULES• Let’s use the equilibrium

2H2 (g) + O2 (g) 2 H2O (g)

Page 32: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Pressure (by volume change)

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

• E.g. increasing the volume (decreasing the pressure)

Page 33: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Pressure (by volume change)

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

• E.g. increasing the volume (decreasing the pressure) On the left of this equilibrium there are THREE gas molecules, and on the right there are TWO. Having more volume means that more molecules can be present, therefore the reaction will move to the LEFT

Page 34: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Pressure (by volume change)

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

• E.g. decreasing the volume (increasing the pressure)

Page 35: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Pressure (by volume change)

• Let’s use the equilibrium 2H2 (g) + O2 (g) 2 H2O (g)

• E.g. decreasing the volume (increasing the pressure) On the left of this equilibrium there are THREE gas molecules, and on the right there are TWO. Having less volume means that less molecules can be present, therefore the reaction will move to the RIGHT

Page 36: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Pressure (by volume change)

• Let’s use the equilibrium C6H12O6 (s) + 6 O2 (g) 6 CO2 (g) + 6 H2O (l)

• E.g. decreasing the volume (increasing the pressure)

Page 37: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Pressure (by volume change)

• Let’s use the equilibrium C6H12O6 (s) + 6 O2 (g) 6 CO2 (g) + 6 H2O (l)

• E.g. decreasing the volume (increasing the pressure). On the left there are SIX gas molecules, and on right there are SIX gas molecules. Because they are the same, changing the volume will not affect the equilibrium

Page 38: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in pressure (Using inert gases)

• By adding another gas into the same volume, the pressure can also be altered.

• This has NO EFFECT on the equilibrium.• Only if the gas is involved in the equilibrium or

the volume is changed will pressure be an issue.

Page 39: Chemical Equilibrium Equations, balancing and equilibrium.

Change in Temperature

• Endothermic means the reaction requires heat• Exothermic means the reaction releases heat

Page 40: Chemical Equilibrium Equations, balancing and equilibrium.

Change in Temperature

• Endothermic means the reaction requires heat A + heat B• Exothermic means the reaction releases heat

A B + heat

• Therefore heat can be though of as a product or a reactant when considering the equilibrium

Page 41: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Temperature

• What happens to an exothermic reaction if the temperature is increased?

• What happens to an endothermic reaction if the temperature is increased?

• What happens to an exothermic reaction if the temperature is decreased?

• What happens to an endothermic reaction if the temperature is decreased?

Page 42: Chemical Equilibrium Equations, balancing and equilibrium.

Changes in Temperature

• What happens to an exothermic reaction if the temperature is increased? LEFT

• What happens to an endothermic reaction if the temperature is increased? RIGHT

• What happens to an exothermic reaction if the temperature is decreased? RIGHT

• What happens to an endothermic reaction if the temperature is decreased? LEFT

Page 43: Chemical Equilibrium Equations, balancing and equilibrium.

Use of a CatalystA catalyst is a substance which increases the rate of a chemical reaction without being used up in the reaction. A reaction at equilibrium is occurring at equal rates in opposite directions. A catalyst increases the rates of the opposing reactions equally and has no effect on the position of equilibrium, but it allows the reaction to reach equilibrium faster.

Page 44: Chemical Equilibrium Equations, balancing and equilibrium.

Rates of reaction

• This is how long it takes to get to equilibrium, not which way the equilibrium will shift.

• Some reactions are naturally very quick, other reactions are known to take millennia!

• Rates are affected by two main factors:– Kinetic energy of particles– The number of collisions taking place

Page 45: Chemical Equilibrium Equations, balancing and equilibrium.

• Rate can be affected by:– Concentrations– Surface area– Temperature– Catalysts / Inhibitors

Rates of reaction

Page 46: Chemical Equilibrium Equations, balancing and equilibrium.

Rate measurement• Rates are measured by the change in the

concentration of a product or reactant, over a known amount of time.

Rate = Change in concentrationChange in time

For products they are reported as positive rates (being made)For reactants they are reported as negative rates (being used up)

Page 47: Chemical Equilibrium Equations, balancing and equilibrium.

Rates: Concentration• Concentration affects rates by changing the

number of collisions taking place.

• More particles = more collisions = faster reactions

• Therefore higher concentrations make for faster reactions. Lower concentrations have slower reactions

Page 48: Chemical Equilibrium Equations, balancing and equilibrium.

Rates: Surface Area

• Surface area affects rates by changing the number of collisions taking place.

• More surface area = more collisions = faster reactions

• Therefore higher surface areas make for faster reactions. Less surface areas have slower reactions

Page 49: Chemical Equilibrium Equations, balancing and equilibrium.

Rates: Temperature

• Temperature affects rates by changing the kinetic energy in the reaction

• Higher temperature = more kinetic energy = faster reactions

• Therefore higher temperature make for faster reactions. Colder reactions are slower

Page 50: Chemical Equilibrium Equations, balancing and equilibrium.

Rates: Catalysts / Inhibitors

• Catalysts increase the rate of a reaction without being used up

• They alter the mechanism of the reaction to make it faster

• Inhibitors have the opposite action to catalysts. They slow the reaction down without being used up