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    Chapter 5

    Solids & Fluid

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    Solids, Liquids and Gases

    Pressure

    Characteristics of Solid, Liquid and Gas

    Density and relative density

    Contents

    Pascal Principle

    Archimedes Principle

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    Three states of matter

    solid liquid gas

    At room temperature most substances exist in one of three

    physical states.

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    The particle model

    The difference between solids, liquids and gases can be

    explained by the

    All substances are made up of particles.

    The particles are attracted to each other. Some particles

    are attracted strongly to each other and others weakly.

    The particles move around. They are described ashaving kinetic energy.

    The kinetic energy of the particles increases withtemperature.

    http://h/power%20point%20azah/States%20of%20Matter.rvhttp://h/power%20point%20azah/States%20of%20Matter.rv
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    Particles in a solid

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    Particles in a liquid

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    Particles in a gas

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    click

    http://h/power%20point%20azah/States%20of%20Matter.rv
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    Properties of solids, liquids and gases

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    How do smells spread out?

    Where is the smell coming from and how does it spread out?

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    Diffusion occurs in liquids and gases but hardly at all in

    solids.

    What is diffusion?

    Diffusion is themovement of

    particles that allows them to spread

    out and mix with other particles.

    For example, the smell of aftershave

    or perfume diffuses and is detected by

    people on the other side of the room.

    Use the particle model to explain these facts about diffusion:

    Diffusion happens more quickly for gases than for liquids.

    Diffusion happens more quickly at warm temperatures

    than at cooler temperatures.

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    Across:

    2. Change from liquid to solid

    5. Force caused by collisions ofparticles

    6. Arranged in a 3-dimensional

    pattern

    9. Spacing of particles in solidsand liquids

    10. All substances are this state

    at very low temperatures

    11.Only liquids and gases do this

    1

    2 3

    45

    6

    7 8

    9

    10

    11

    Down:1. Closely packed particles 6. Particles are close but disorganised

    3. Change from gas to liquid 7. Particles widely spread out

    4. Change from solid to liquid 8. Change from liquid to gas

    Crossword

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    DEFINE DENSITY,

    Density is defined as ratio of the mass of substance to its

    volume. It is a measure of how tightly packed and how heavy the

    molecules are in an object. Density is the amount of matter within a

    certain volume.

    Proof that water and ice have

    different densities

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    To find the density

    Find the mass of theobject

    Find the volume of

    the object

    DEFINE DENSITY

    Units for density usually express

    in kg/m3

    = m (kg)

    V (m3)

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    Example 1:

    A big box has mass of 20N and size 30cmx30cmx30cm,

    Using all the information, calculate the density of the box.

    Solution:

    W = mg

    20 N = m (9.81)

    m = 20 / 9.81

    = 2.04 kg

    Volume = 30cm x 30cm x 30cm

    = 0.3m x 0.3m x 0.3m

    = 0.027m3

    30cm

    30cm

    30cm

    = m = 2.04 kg = 75.57 kg/m3

    V 0.027m3

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    Also known as Specific Gravity Specific gravity is ratio of the density of a sunstance to the

    density t of water.

    DEFINE RELATIVE DENSITY, b

    b= substance (kg/m3)

    water (kg/m3)No unit

    1000 kg/m3

    E l 2

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    Example 2:

    If the density of an object is 4000 kg/m3 ,calculate the

    specific gravity of the object. ( Density of water = 1000 kg/m3)

    b= subs tance (kg/m3)

    water (kg/m3)

    b= 4000(kg/m3)1000(kg/m3)

    = 4

    PRESSURE P

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    PRESSURE, P

    Pressure is defined as Force per unit Area acting on a surface.

    Factors that affect the pressure acting on a surfaceContact area ( Smaller contact area greater pressure)

    Force acting on the surface ( Large force greater pressure)

    P = F (N)

    A (m2)

    Unit in N/m2 or Pascal (Pa)

    A

    F

    A

    F

    APPLICATION OF PRESSURE

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    APPLICATION OF PRESSURE

    High Pressure Low Pressure

    E l 3

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    Example 3:

    How many Pascals are exerted by an elephant of weight

    50 000 N standing on his feet of total area 0.8m

    2 ?

    Solution:

    F = 50000 N

    Area = 0.8m2

    P = F / A

    = 50000 / 0.8

    = 62 500 Pa

    E l 4

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    Example 4:

    What Pressure is exerted by an apple of weight 1 N sitting

    on area 20mm

    2

    ?Solution:

    F = 1 N

    Area =20 mm2 = 0.00002m2

    P = F / A

    = 1 / 0.00002

    = 50 000 Pa

    PRESSURE IN LIQUID

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    PRESSURE IN LIQUID

    A liquid in a container exerts pressure because of it weight (Force).

    P = gh Unit in N/m2 or Pascal (Pa)

    A

    h

    Volume, V = Ah

    Density, = mV

    Mass, m = V

    Weight,w = Force,F = mg= Vg

    = Ahg

    Pressure = F = Ahg = hgA A

    CHARACTERISTICS OF PRESSURE IN A LIQUID

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    CHARACTERISTICS OF PRESSURE IN A LIQUID

    Depth to pressure in liquid

    Liquid pressure increase

    with depth

    The pressure of water isthe lowest at the highest

    point of the cylinder and

    the pressure of water is

    highest at the lowestpoint of the cylinder.

    CHARACTERISTICS OF PRESSURE IN A LIQUID

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    CHARACTERISTICS OF PRESSURE IN A LIQUID

    Density to pressure in liquid

    Pressure of liquid is increases with density.

    Water Oil

    x1 x2

    x1 > x2 Density of cooking oil is less than water

    CHARACTERISTICS OF PRESSURE IN A LIQUID

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    Fluid exerts forces in many directions. Try to submerse a

    rubber ball in water to see that an upward force acts on thefloat.

    Fluids exert pressure in

    all directions.F

    CHARACTERISTICS OF PRESSURE IN A LIQUID

    CHARACTERISTICS OF PRESSURE IN A LIQUID

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    CHARACTERISTICS OF PRESSURE IN A LIQUID

    Water seeks its own

    level, indicating that

    fluid pressure is

    independent of area

    and shape of itscontainer.

    At any depth h below

    the surface of the

    water in any column,the pressure P is the

    same. The shape and

    area are not factors.

    h

    Water

    level

    Independence of Shape and Area

    Example 5:

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    Example 5:

    The figure shows a cross section of a dam. Calculate;

    a.The pressure exerted by the water at X, if the density of

    water is 1000kg/m2

    b.Explain why the bottom of the dam is built with thick

    wall?

    c.If there is air exerted and given that Patmis 101.3Kpa.

    What is absolute pressure at point x?

    6.5mx0.5m

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    Solution:

    a) Px= watergh

    = (1000)(9.81)(6.5-0.5)

    = 580860 Pa

    b) This is because the water pressure increase as the

    depth of water increases. So, a grater pressure is

    exerted at the bottom of the dam.

    c) Pabsolute = Patm + Px

    = 101.3 kPa + 580860 Pa

    = 682.16 kPa

    APPLICATION OF PRESSURE IN LIQUIDS

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    APPLICATION OF PRESSURE IN LIQUIDS

    Public water supply

    systems ( Water Tank)

    The wall of a dam

    PASCAL PRINCIPLE

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    PASCAL PRINCIPLE

    Pascals principle states that pressure exerted on an

    enclosed fluid is transmitted equally to every part of the

    fluid.

    P1 = P2

    F1= F2

    A1 A2

    Pressure in Pascal can be

    expressed:

    A1d1= A2d2

    Transmitting force

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    Transmitting force

    An applied force F1can beamplified:

    Hydraulic press

    P F1

    A1

    F2

    A2

    F2

    F1

    A2

    A1

    A common application of this is a hydraulic lift used to raise

    a car off the ground so it can be repaired at a garage.

    Example

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    Example

    The cylindrical piston of a hydraulic jack has a cross-sectional

    area of 0.06 m2 and the plunger has a cross-sectional area of

    0.002m2.a.The upward force for lifting a load placed on top of the large

    piston is 9 000 N. calculate the downward force on the

    plunger required

    b.If the distance moved by the plunger is 75cm, what is the

    distance moved by the large piston?

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    Solution:

    a) F1 = F2

    A1 A2

    F1 = F2A1

    A2

    = 0.002 x 9 000

    0.06

    = 300 N

    b) A1d1 = A2d2

    d2 = A1d1

    A2

    = 0.002 x 75

    0.06

    = 2.5cm

    APPLICATION OF PASCAL PRINCIPLE

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    APPLICATION OF PASCAL PRINCIPLE

    Hydraulic Brake Hydraulic Jack

    ARCHIMEDES PRINCIPLE

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    ARCHIMEDES PRINCIPLE

    Archimedes' principle is the law of buoyancy.

    It states that "Any object partially or completelysubmerged in a fluid is buoyed up by a force equal to the

    weight of the fluid displaced by the body."

    ARCHIMEDES PRINCIPLE

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    Buoyant force = Weight of fluid displaced

    Buoyant force = Weight object in airweight in water

    Buoyant force = Vg

    ARCHIMEDES PRINCIPLE

    Volume of the submerged = Volume of the liquid

    object displaced

    ARCHIMEDES PRINCIPLE

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    Related buoyant force with the actual weight and

    apparent weight

    ARCHIMEDES PRINCIPLE

    Buoyant force makes things

    seem to be lighter.

    The weight of an object is its

    actual weight.

    The weight measured whenthe object is immersed in fluid is

    its apparent weight.

    The apparent weight loss of

    the object is due to buoyantforce

    Buoyant force = Apparent

    weight Loss

    Law of Floatation

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    Law of Floatation

    A floating object displaces its own weight of fluid in

    which it floats.

    Buoyancy explains why some objects sink and othersfloat.

    Objects that are less density than water will float.

    Objects that are more density than water will sink.

    Objects that are the same density as water will neither

    sink nor float.

    Law of Floatation

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    Law of Floatation

    Which ball will sink in water?Which ball will float in water?

    APPLICATION OF ARCHIMEDES PRINCIPLE

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    APPLICATION OF ARCHIMEDES PRINCIPLE