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Transcript of Chapter 8
8-1 Relating Decimals, Fractions, and Percents
Course 3
Warm UpWarm Up
Problem of the DayProblem of the Day
Lesson PresentationLesson Presentation
Warm UpEvaluate.
1. 2.
3. 4.
13
1
3+
14
215
315
–712
312
4 5
7 2
123
1 4
Course 3
8-1 Relating Decimals, Fractions, and Percents
45
2145
or
Problem of the Day
A fast-growing flower grows to a height of 12 inches in 12 weeks by doubling its height every week. If you want your flower to be only 6 inches tall, after how many weeks should you pick it?
11 weeks
Course 3
8-1 Relating Decimals, Fractions, and Percents
Learn to relate decimals, fractions, and percents.
Course 3
8-1 Relating Decimals, Fractions, and Percents
Vocabulary
percent
Insert Lesson Title Here
Course 3
8-1 Relating Decimals, Fractions, and Percents
Percents are ratios that compare a number to 100.
RatioEquivalent Ratio with Denominator of 100 Percent
310
1234
3010050
10075
100
30%
50%
75%
Course 3
8-1 Relating Decimals, Fractions, and Percents
Think of the % symbol as meaning /100.
0.75 = 75% = 75/100
Reading Math
Course 3
8-1 Relating Decimals, Fractions, and Percents
To convert a fraction to a decimal, divide the numerator by the denominator.
18 = 1 ÷ 8 = 0.125
To convert a decimal to a percent, multiply by 100 and insert the percent symbol.
0.125 100 12.5%
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
Additional Example 1: Finding Equivalent Ratios and Percents
1
10a: 10% =
10100
=
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
Additional Example 1: Finding Equivalent Ratios and Percents
b: 0.25 =14
= 25%
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
Additional Example 1: Finding Equivalent Ratios and Percents
c: 40% =40100
=2
5
4
10=
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
Additional Example 1: Finding Equivalent Ratios and Percents
d: 0.60 =35
= 60%
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
Additional Example 1: Finding Equivalent Ratios and Percents
e: 23
% =66 0.666 = 23
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
Additional Example 1: Finding Equivalent Ratios and Percents
f: 12
% =87 0.875 = 78
8751000
=
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
Additional Example 1: Finding Equivalent Ratios and Percents
g: 125% =125 100
=5
4=
1
41
Course 3
8-1 Relating Decimals, Fractions, and Percents
Try This: Example 1
Course 3
8-1 Relating Decimals, Fractions, and Percents
Find the missing ratio or percent equivalent for each letter a–g on the number line.
c
a b
e
d
50%12 %
f
g
38
25%12
58
75%
1
a: 12
% =12 0.125 = 18
1251000
=
Try This: Example 1 Continued
Course 3
8-1 Relating Decimals, Fractions, and Percents
b: 25% =25100
=1
4
Find the missing ratio or percent equivalent for each letter a–g on the number line.
c
a b
e
d
50%12 %
f
g
38
25%12
58
75%
1
Try This: Example 1 Continued
Course 3
8-1 Relating Decimals, Fractions, and Percents
c: 0.375 =38
= 37 %1
2
Find the missing ratio or percent equivalent for each letter a–g on the number line.
c
a b
e
d
50%12 %
f
g
38
25%12
58
75%
1
Try This: Example 1 Continued
Course 3
8-1 Relating Decimals, Fractions, and Percents
d: 50% =50100
=1
2
Find the missing ratio or percent equivalent for each letter a–g on the number line.
c
a b
e
d
50%12 %
f
g
38
25%12
58
75%
1
Try This: Example 1 Continued
Course 3
8-1 Relating Decimals, Fractions, and Percents
e: 0.625 =58
= 62 %1
2
Find the missing ratio or percent equivalent for each letter a–g on the number line.
c
a b
e
d
50%12 %
f
g
38
25%12
58
75%
1
Try This: Example 1 Continued
Course 3
8-1 Relating Decimals, Fractions, and Percents
f: 75% =75100
=3
4
Find the missing ratio or percent equivalent for each letter a–g on the number line.
c
a b
e
d
50%12 %
f
g
38
25%12
58
75%
1
Try This: Example 1 Continued
Course 3
8-1 Relating Decimals, Fractions, and Percents
g: 1 =100 100
= 100%
Find the missing ratio or percent equivalent for each letter a–g on the number line.
c
a b
e
d
50%12 %
f
g
38
25%12
58
75%
1
Find the equivalent fraction, decimal, or percent for each value given on the circle graph.
Additional Example 2: Finding Equivalent Fractions, Decimals, and Percents
0.15(100) = 15%
720
= 0.35
Fraction Decimal Percent
0.15
35%
38%
320
15100
=
720
35100
=
1950
38100
= 1950 = 0.38
325 = 0.12 0.12(100) = 12%
325
Course 3
8-1 Relating Decimals, Fractions, and Percents
You can use information in each column to make three equivalent circle graphs. One shows the breakdown by fractions, one shows the breakdown by decimals, and one shows the breakdown by percents.
Additional Example 2 Continued
The sum of the fractions should be 1.
The sum of the decimals should be 1.
The sum of the percents should be 100%.
Course 3
8-1 Relating Decimals, Fractions, and Percents
Try This: Example 2
Fill in the missing pieces on the chart below.
Fraction Decimal Percent
0.1
45%
110 0.1(100) = 10%
0.2(100) = 20%
45100
=0.45
1 5
15
=0.2525100
Course 3
8-1 Relating Decimals, Fractions, and Percents
1 4
45100
920=
0.25(100) = 25%
= 0.2
Gold that is 24 karat is 100% pure gold. Gold that is 14 karat is 14 parts pure gold and 10 parts another metal, such as copper, zinc, silver, or nickel. What percent of 14 karat gold is pure gold?
Additional Example 3: Physical Science Application
Set up a ratio and reduce.parts pure goldtotal parts
1424
712
=
712
= 7 12 = Find the percent.0.583 = 58.3%
13So 14-karat gold is 58.3%, or 58 % pure
gold.
Course 3
8-1 Relating Decimals, Fractions, and Percents
A baker’s dozen is 13. When a shopper purchases a dozen items at the bakery they get 12. It is said that the baker eats 1 item from every batch. So, what percentage of the food the baker cooks is eaten without being sold?
Try This: Example 3
Set up a ratio and reduce. items eatentotal items
113
113
= 1 13 = Find the percent.0.077 = 7.7%
So the baker, eats 7.7% of the items they bake.
Course 3
8-1 Relating Decimals, Fractions, and Percents
Lesson Quiz
Find each equivalent value.
1. as a percent
2. 20% as a fraction
3. as a decimal
4. as a percent
5. About 342,000 km2 of Greenland’s total area (2,175,000 km2) is not covered with ice. To the nearest percent, what percent of Greenland’s total area is not covered with ice?
16%
37.5%
Insert Lesson Title Here
0.625
56%
38
1425
15
58
Course 3
8-1 Relating Decimals, Fractions, and Percents
8-2 Finding Percents
Course 3
Warm UpWarm Up
Problem of the DayProblem of the Day
Lesson PresentationLesson Presentation
Warm UpRewrite each value as indicated.
1. as a percent
2. 25% as a fraction
3. as a decimal
4. 0.16 as a fraction
48%
0.375
Course 3
8-2 Finding Percents
425
24 50
3 8
14
Problem of the Day
A number between 1 and 10 is halved, and the result is squared. This gives an answer that is double the original number. What is the starting number?8
Course 3
8-2 Finding Percents
Learn to find percents.
Course 3
8-2 Finding Percents
Course 3
8-2 Finding Percents
Relative humidity is a measure of the amount of water vapor in the air. When the relative humidity is 100%, the air has the maximum amount of water vapor. At this point, any additional water vapor would cause precipitation. To find the relative humidity on a given day, you would need to find a percent.
Additional Example 1A: Finding the Percent One Number Is of Another
Course 3
8-2 Finding Percents
A. What percent of 220 is 88?
Method 1: Set up an equation to find the percent.
p 220 = 88 Set up an equation.
88220
p = Solve for p.
p = 0.4 0.4 is 40%.
So 88 is 40% of 220.
B. Eddie weighs 160 lb, and his bones weigh 24 lb. Find the percent of his weight that his bones are.
Additional Example 1B: Finding the Percent One Number Is of Another
Course 3
8-2 Finding Percents
Think: What number is to 100 as 24 is to 160?
=number
100 partwhole
Set up a proportion.
Substitute. n
100 24160
=
n 160 = 100 24
160n = 2400
Find the cross products.
Method 2: Set up a proportion to find the percent.
Additional Example 1 Continued
Course 3
8-2 Finding Percents
n = 15
= 15
100 24160
The proportion is reasonable.
Solve for n.160 2400n =
So 15% of Eddie’s weight is bone.
Try This: Example 1A
A. What percent of 110 is 11?
Insert Lesson Title Here
Course 3
8-2 Finding Percents
Method 1: Set up an equation to find the percent.
p 110 = 11 Set up an equation.
11110
p = Solve for p.
p = 0.1 0.1 is 10%.
So 11 is 10% of 110.
B. Jamie weighs 140 lb, and his bones weigh 21 lb. Find the percent of his weight that his bones are.
Course 3
8-2 Finding Percents
Think: What number is to 100 as 21 is to 140?
=number
100 partwhole Set up a proportion.
Substitute. n
100 21140
=
n 140 = 100 21
140n = 2100
Find the cross products.
Try This: Example 1B
Method 2: Set up a proportion to find the percent.
Course 3
8-2 Finding Percents
n = 15
The proportion is reasonable.
Solve for n.140 2100n =
So 15% of Jamie’s weight is bone.
= 15
100 21140
Additional Example 2A: Finding a Percent of a Number
Course 3
8-2 Finding Percents
A. After a drought, a reservoir had only 66 % of the average amount of water. If the average amount of water is 57,000,000 gallons, how much water was in the reservoir after the drought?
23
Choose a method: Set up an equation.
Think: What number is 66 % of 57,000,000?23
w = 66 % 57,000,000 Set up an equation.23
w = 57,000,000 66 % is equivalent to . 23
23
23
Additional Example 2A Continued
Course 3
8-2 Finding Percents
The reservoir contained 38,000,000 gallons of water after the drought.
w = = 38,000,000 114,000,000
3
Additional Example 2B: Finding Percents
Course 3
8-2 Finding Percents
B. Ms. Chang deposited $550 in the bank. Four years later her account held 110% of the original amount. How much money did Ms. Chang have in the bank at the end of the four years?
Choose a method: Set up a proportion.
=110
100 a
550Set up a proportion.
110 550 = 100 a Find the cross products.
60,500 = 100a
Additional Example 2B Continued
Course 3
8-2 Finding Percents
605 = a Solve for a.
Ms. Chang had $605 in the bank at the end of the four years.
Try This: Example 2A
Course 3
8-2 Finding Percents
A. After a drought, a river had only 50 % of the average amount of water flow. If the average amount of water flow is 60,000,000 gallons per day, how much water was flowing in the river after the drought?
23
Choose a method: Set up an equation.
Think: What number is 50 % of 60,000,000?23
w = 50 % 60,000,000 Set up an equation.23
w = 0.506 60,000,000 50 % is equivalent to 0.506. 23
Try This: Example 2A
Course 3
8-2 Finding Percents
The water flow in the river was 30,400,000 gallons per day after the drought.
w = 30,400,000
Try This: Example 2B
Course 3
8-2 Finding Percents
B. Mr. Downing deposited $770 in the bank. Four years later her account held 120% of the original amount. How much money did Mr. Downing have in the bank at the end of the four years?
Choose a method: Set up a proportion.
=120
100 a
770 Set up a proportion.
120 770 = 100 a Find the cross products.
92,400 = 100a
Try This: Example 2B Continued
Course 3
8-2 Finding Percents
924 = a Solve for a.
Mr. Downing had $924 in the bank at the end of the four years.
Lesson Quiz
Find each percent to the nearest tenth.
1. What percent of 33 is 22?
2. What percent of 300 is 120?
3. 18 is what percent of 25?
4. The volume of Lake Superior is 2900 mi3 and
the volume of Lake Erie is 116 mi3. What percent
of the volume of Lake Superior is the volume of
Lake Erie?
40%
66.7%
Insert Lesson Title Here
72%
4%
Course 3
8-2 Finding Percents
8-3 Finding a Number When the Percent Is Known
Course 3
Warm UpWarm Up
Problem of the DayProblem of the Day
Lesson PresentationLesson Presentation
Warm Up
1. What percent of 20 is 18?
2. What percent of 400 is 50?
3. 9 is what percent of 27?
4. 25 is what percent of 4?
90%
12.5%
Course 3
8-3 Finding a Number When the Percent Is Known
625%
331
3 %
Problem of the Day
The original price of a sweater is $40. The sweater goes on sale for 75% of its original price. Later, the sweater goes on clearance for 50% of its sale price. What is the clearance price of the sweater?$15
Course 3
8-3 Finding a Number When the Percent Is Known
Learn to find a number when the percent is known.
Course 3
8-3 Finding a Number When the Percent Is Known
The Pacific giant squid can grow to a weight of 2000 pounds. This is 1250% of the maximum weight of the Pacific giant octopus. When one number is known, and is relationship to another number is given by a percent, the other number can be found.
Course 3
8-3 Finding a Number When the Percent Is Known
60 = 0.12n
60 is 12% of what number?
Additional Example 1: Finding a Number When the Percent Is Known
Set up an equation to find the number.
60 = 12% n
= n 60
0.12 0.12
0.12Divide both sides by 0.12.
500 = n
60 is 12% of 500.
Course 3
8-3 Finding a Number When the Percent Is Known
Set up an equation.
1210012% =
75 = 0.25n
75 is 25% of what number?
Try This: Example 1
Set up an equation to find the number.
75 = 25% n
= n 75
0.25 0.25
0.25 Divide both sides by 0.25.
300 = n
75 is 25% of 300.
Course 3
8-3 Finding a Number When the Percent Is Known
Set up an equation.
2510025% =
Anna earned 85% on a test by answering 17 questions correctly. If each question was worth the same amount, how many questions were on the test?
Additional Example 2: Application
Choose a method: Set up a proportion to find the number.
Think: 85 is to 100 as 17 is to what number?
= 85
10017
nSet up a proportion.
Course 3
8-3 Finding a Number When the Percent Is Known
Additional Example 2 Continued
There were 20 questions on the test.
85 n = 100 17 Find the cross products.
85 n = 1700
Course 3
8-3 Finding a Number When the Percent Is Known
n = Solve for n.1700
85
n = 20
Try This: Example 2
Course 3
8-3 Finding a Number When the Percent Is Known
Choose a method: Set up a proportion to find the number.
Think: 80 is to 100 as 20 is to what number?
= 80
10020
nSet up a proportion.
Tom earned 80% on a test by answering 20 questions correctly. If each question was worth the same amount, how many questions were on the test?
Try This: Example 2 Continued
Course 3
8-3 Finding a Number When the Percent Is Known
There were 25 questions on the test.
80 n = 100 20 Find the cross products.
80 n = 2000
n = Solve for n.2000
80
n = 25
A. A fisherman caught a lobster that weighed 11.5 lb. This was 70% of the weight of the largest lobster that fisherman had ever caught. What was the weight, to the nearest tenth of a pound, of the largest lobster the fisherman had ever caught?
Additional Example 3A: Life Science Application
Choose a method: Set up an equation.
Think: 11.5 is 70% of what number?
11.5 = 70% n Set up an equation.
Course 3
8-3 Finding a Number When the Percent Is Known
Additional Example 3A Continued
16.4 n
The largest lobster the fisherman had ever caught was about 16.4 lb.
11.5 = 0.70 n 70% = 0.70
Solve for n. 11.5 0.70
n=
Course 3
8-3 Finding a Number When the Percent Is Known
B. When a giraffe is born, is approximately 55% as tall as it will be as an adult. If a baby giraffe is 5.2 feet tall when it is born, how tall will it be when it is full grown, to the nearest tenth of a foot?
Additional Example 3B: Life Science Application
Choose a method: Set up a proportion.
Think: 55 is to 100 and 5.2 is to what number?
= h
5.2 55 100
Set up a proportion.
Course 3
8-3 Finding a Number When the Percent Is Known
Additional Example 3B Continued
55h = 520
This giraffe will be approximately 9.5 feet tall when full grown.
55 h = 100 5.2 Find the cross products.
52055
h = Solve for h.
h 9.5
Course 3
8-3 Finding a Number When the Percent Is Known
A. Amy caught a fish that weighed 15.5 lb. This was 85% of the weight of the largest fish that Amy had ever caught. What was the weight, to the nearest tenth of a pound, of the largest fish that Amy had ever caught?
Try This: Example 3
Choose a method: Set up an equation.
Think: 15.5 is 85% of what number?
15.5 = 85% n Set up an equation.
Course 3
8-3 Finding a Number When the Percent Is Known
Try This: Example 3 Continued
18.2 n
The largest fish that Amy had ever caught was about 18.2 lb.
15.5 = 0.85 n 85% = 0.85
Solve for n. 15.5 0.85
n=
Course 3
8-3 Finding a Number When the Percent Is Known
B. When Bart was 12, he was approximately 85% of the weight he is now. If Bart was 120 lb, how heavy is he now, to the nearest tenth of a pound?
Try This: Example 3
Choose a method: Set up a proportion.
Think: 85 is to 100 as 120 is to what number?
= w
120 85 100
Set up a proportion.
Course 3
8-3 Finding a Number When the Percent Is Known
85w = 12000
Bart weighs approximately 141.2 lbs.
85 w = 100 120 Find the cross products.
12000 85
w = Solve for h.
w 141.2
Course 3
8-3 Finding a Number When the Percent Is Known
Try This: Example 3 Continued
Course 3
8-3 Finding a Number When the Percent Is Known
Three Types of Percent Problems
1. Finding the percent of a number. 15% of 120 = n
2. Finding the percent one number is of another.p% of 120 = 18
3. Finding a number when the percent is known.15% of n = 18
You have now seen all three types of percent problems.
Lesson Quiz
1. 10 is 12 % of what number?
2. 326 is 25% of what number?
3. 44% of what number is 11?
4. 290% of what number is 145?
5. Larry has 9 novels about the American
Revolutionary War. This represents 15% of his
total book collection. How many books does Larry
have in all?
1304
80
Insert Lesson Title Here
25
50
12
60
Course 3
8-3 Finding a Number When the Percent Is Known
8-4 Percent Increase and Decrease
Course 3
Warm UpWarm Up
Problem of the DayProblem of the Day
Lesson PresentationLesson Presentation
Warm Up
1. 14,000 is 2 % of what number?
2. 39 is 13% of what number?
3. 37 % of what number is 12?
4. 150% of what number is 189?
560,000
300
32
Course 3
8-4 Percent Increase and Decrease
12
126
12
Problem of the Day
In a school survey, 45% of the students said orange juice was their favorite juice, 25% preferred apple, and 10% preferred grapefruit. The remaining 32 students preferred grape juice. How many students participated in the survey?
160 students
Course 3
8-4 Percent Increase and Decrease
Learn to find percent increase and decrease.
Course 3
8-4 Percent Increase and Decrease
Vocabulary
percent changepercent increasepercent decrease
Insert Lesson Title Here
Course 3
8-4 Percent Increase and Decrease
Course 3
8-4 Percent Increase and Decrease
Percents can be used to describe a change. Percent change is the ratio of the amount of change to the original amount.
Percent increase describes how much the original amount increases.
Percent decrease describes how much the original amount decreases.
amount of changeoriginal amountpercent change =
Find the percent increase or decrease from 16 to 12.
Additional Example 1: Percent Increase and Decrease
Course 3
8-4 Percent Increase and Decrease
This is percent decrease.
16 – 12 = 4 First find the amount of change.
Think: What percent is 4 of 16?
amount of decreaseoriginal amount
416
Set up the ratio.
Additional Example 1 Continued
Course 3
8-4 Percent Increase and Decrease
= 25% Write as a percent.
= 0.25 Find the decimal form.416
From 16 to 12 is a 25% decrease.
Find the percent increase or decrease from 15 to 20.
Try This: Example 1
Course 3
8-4 Percent Increase and Decrease
This is percent increase.
20 – 15 = 5 First find the amount of change.
Think: What percent is 5 of 20?
amount of increaseoriginal amount
520
Set up the ratio.
Try This: Example 1 Continued
Course 3
8-4 Percent Increase and Decrease
= 25% Write as a percent.
= 0.25 Find the decimal form.520
From 15 to 20 is a 25% increase.
A. When Jim was exercising, his heart rate went from 70 beats per minute to 98 beats per minute. What was the percent increase?
Additional Example 2: Life Science Application
Course 3
8-4 Percent Increase and Decrease
Think: What percent is 28 of 70?
28 70
Set up the ratio.
98 – 70 = 28 First find the amount of change.
amount of increaseoriginal amount
Additional Example 2 Continued
Course 3
8-4 Percent Increase and Decrease
= 40% Write as a percent.
= 0.4 Find the decimal form. 70
28
Jim’s heart rate increased by 40% when he exercised.
B. In 1999, a certain stock was worth $1.25 a share. In 2002, the same stock was worth $0.85 a share. What was the percent decrease?
Additional Example 2B: Application
Course 3
8-4 Percent Increase and Decrease
1.25 – 0.85 = 0.40 First find the amount of change.
Think: What percent is 0.40 of 1.25?
amount of decreaseoriginal amount 1.25
0.40Set up the ratio.
Additional Example 2B Continued
Course 3
8-4 Percent Increase and Decrease
= 32% Write as a percent.
= 0.32 Find the decimal form. 1.25
0.40
The value of the stock decreased by 32%.
A. When Jeff was watching TV, the number of times his eyelids blinked went from 50 blinks per minute to 75 blinks per minute. What was the percent increase?
Try This: Example 2A
Course 3
8-4 Percent Increase and Decrease
Think: What percent is 25 of 50?
25 50
Set up the ratio.
75 – 50 = 25 First find the amount of change.
amount of increaseoriginal amount
Course 3
8-4 Percent Increase and Decrease
= 50% Write as a percent.
= 0.5 Find the decimal form. 50
25
The blinking of Jeff’s eyelids increased by 50% when he watched TV.
Try This: Example 2A Continued
B. In 2000, a certain stock was worth $9.00 a share. In 2003, the same stock was worth $3.80 a share. What was the percent decrease?
Try This: Example 2B
Course 3
8-4 Percent Increase and Decrease
9.00 – 3.80 = 5.20 First find the amount of change.
Think: What percent is 5.20 of 9.00?
amount of decreaseoriginal amount 9.00
5.20Set up the ratio.
Course 3
8-4 Percent Increase and Decrease
The value of the stock decreased by about 57.8%.
9.005.20 = 0.57 Find the decimal form.
= 57.7% Write as a percent.
Try This: Example 2B Continued
A. Sarah bought a DVD player originally priced at $450 that was on sale for 20% off. What was the sale price?
Additional Example 3A: Percent Increase and Decrease
Course 3
8-4 Percent Increase and Decrease
$450 20% First find 20% of $450.
$450 0.20 = $90 20% = 0.20
The amount of decrease is $90.
Think: The reduced price is $90 less than $450.
$450 – $90 = $360 Subtract the amount of decrease.The sale price of the DVD player was $360.
B. Mr. Olsen has a computer business in which he sells everything at 40% above the wholesale price. If he purchased a printer for $85 wholesale, what will be the retail price?
Additional Example 3B: Percent Increase and Decrease
Course 3
8-4 Percent Increase and Decrease
$85 40% First find 40% of $85.
$85 0.40 = $34 40% = 0.40
The amount of increase is $34.
Think: The retail price is $34 more than $85.
$85 + $34 = $119 Add the amount of increase.
The retail price of this printer will be $119.
A. Lily bought a dog house originally priced at $750 that was on sale for 10% off. What was the sale price?
Try This: Example 3A
Course 3
8-4 Percent Increase and Decrease
$750 10% First find 10% of $750.
$750 0.10 = $75 10% = 0.10
The amount of decrease is $75.
Think: The reduced price is $75 less than $750.
$750 – $75 = $675 Subtract the amount of decrease.
The sale price of the dog house was $675.
B. Barb has a grocery store in which she sells everything at 50% above the wholesale price. If she purchased a prime rib for $30 wholesale, what will be the retail price?
Course 3
8-4 Percent Increase and Decrease
$30 50% First find 50% of $30.
$30 0.50 = $15 50% = 0.50
The amount of increase is $15.
Think: The retail price is $15 more than $30.
$30 + $15 = $45 Add the amount of increase.
The retail price of the prime rib will be $45.
Try This: Example 3B
Lesson QuizFind each percent increase or decrease to the nearest percent.
1. from 12 to 15
2. from 1625 to 1400
3. from 37 to 125
4. from 1.25 to 0.85
5. A computer game originally sold for $40 but is
now on sale for 30% off. What is the sale price of
the computer game?
14% decrease
25% increase
Insert Lesson Title Here
238% increase
32% decrease
Course 3
8-4 Percent Increase and Decrease
$28
8-6 Applications of Percents
Course 3
Warm UpWarm Up
Problem of the DayProblem of the Day
Lesson PresentationLesson Presentation
Warm UpEstimate.
1. 20% of 602
2. 133 out of 264
3. 151% of 78
4. 0.28 out of 0.95
120
50%
120
Course 3
8-6 Applications of Percents
30%
Possible answers:
Problem of the Day
What is the percent discount on a purchase of three shirts if you take advantage of the shirt sale?
All Shirts on Sale!Buy 2—Get the Third for Half Price!
Course 3
8-6 Applications of Percents
16 %2
3
Learn to find commission, sales tax, and withholding tax.
Course 3
8-6 Applications of Percents
Vocabulary
commissioncommission ratesales taxwithholding tax
Insert Lesson Title Here
Course 3
8-6 Applications of Percents
Course 3
8-6 Applications of Percents
Real estate agents often work for commission. A commission is a fee paid to a person who makes a sale. It is usually a percent of the selling price. This percent is called the commission rate.
Often agents are paid a commission plus a regular salary. The total pay is a percent of the sales they make plus a salary.
commission ratecommission rate salessales = commissioncommission
A real-estate agent is paid a monthly salary of $900 plus commission. Last month he sold one condominium for $65,000, earning a 4% commission on the sale. How much was his commission? What was his total pay last month?
Additional Example 1: Multiplying by Percents to Find Commission Amounts
Course 3
8-6 Applications of Percents
First find his commission.
4% $65,000 = c commission rate sales = commission
0.04 65,000 = c Change the percent to a decimal.
Additional Example 1 Continued
Course 3
8-6 Applications of Percents
2600 = c Solve for c.
He earned a commission of $2600 on the sale.
Now find his total pay for last month.
$2600 + $900 = $3500 commission + salary = total pay
His total pay for last month was $3500.
A car sales agent is paid a monthly salary of $700 plus commission. Last month she sold one sports car for $50,000, earning a 5% commission on the sale. How much was her commission? What was her total pay last month?
Try This: Example 1
Course 3
8-6 Applications of Percents
First find her commission.
5% $50,000 = c commission rate sales = commission
0.05 50,000 = c Change the percent to a decimal.
Try This: Example 1 Continued
Course 3
8-6 Applications of Percents
2500 = c Solve for c.
The agent earned a commission of $2500 on the sale.
Now find her total pay for last month.
$2500 + $700 = $3200 commission + salary = total pay
Her total pay for last month was $3200.
Course 3
8-6 Applications of Percents
Sales tax is the tax on the sale of an item or service. It is a percent of the purchase price and is collected by the seller.
If the sales tax rate is 6.75%, how much tax would Adrian pay if he bought two CDs at $16.99 each and one DVD for $36.29?
Additional Example 2: Multiplying by Percents to Find Sales Tax Amounts
Course 3
8-6 Applications of Percents
CD: 2 at $16.99 $33.98
DVD: 1 at $36.29 $36.29
$70.27 Total Price
0.0675 70.27 = 4.743225 Convert tax rate to a decimal and multiply by the total price.
Adrian would pay $4.74 in sales tax.
Try This: Example 2
Amy rents a hotel for $45 per night. She rents for two nights and pays a sales tax of 13%. How much tax did she pay?
Insert Lesson Title Here
Course 3
8-6 Applications of Percents
$45 2 = $90 Find the total price for the hotel stay.
$90 0.13 = $11.70 Convert tax rate to a decimal and multiply by the total price.
Amy spent $11.70 on sales tax.
Course 3
8-6 Applications of Percents
A tax deducted from a person’s earnings as an advance payment of income tax is called withholding tax.
Anna earns $1500 monthly. Of that, $114.75 is withheld for Social Security and Medicare. What percent of Anna’s earnings are withheld for Social Security and Medicare?
Additional Example 3: Using Proportions to Find the Percent of Tax Withheld
Course 3
8-6 Applications of Percents
Think: What percent of $1500 is $114.75?
Solve by proportion:
114.75 1500
n100
=
n 1500 = 100 114.75Find the cross products.
Additional Example 3 Continued
Course 3
8-6 Applications of Percents
n = 7.65
7.65% of Anna’s earnings is withheld for Social Security and Medicare.
11,475 1500
n =
1500n = 11,475 Divide both sides by 1500.
BJ earns $2500 monthly. Of that, $500 is withheld for income tax. What percent of BJ’s earnings are withheld for income tax?
Try This: Example 3
Course 3
8-6 Applications of Percents
Think: What percent of $2500 is $500?
Solve by proportion:
500 2500
n100
=
n 2500 = 100 500 Find the cross products.
Try This: Example 3 Continued
Course 3
8-6 Applications of Percents
n = 20
20% of BJ’s earnings are withheld for income tax.
50000 2500
n =
2500n = 50,000 Divide both sides by 2500.
A furniture sales associate earned $960 in commission in May. If his commission is 12% of sales, how much were his sales in May?
Additional Example 4: Dividing by Percents to Find Total Sales
Course 3
8-6 Applications of Percents
Think: $960 is 12% of what number?
Solve by equation:
960 = 0.12 s Let s = total sales.
9600.12
= s Divide each side by 0.12.
The associate’s sales in May were $8000.
A sales associate earned $770 in commission in May. If his commission is 7% of sales, how much were his sales in May?
Try This: Example 4
Course 3
8-6 Applications of Percents
Think: $770 is 7% of what number?
Solve by equation:
770 = 0.07 s Let s represent total sales.
7700.07
= s Divide each side by 0.07.
The associate’s sales in May were $11,000.
Lesson Quiz: Part 1
1. The lunch bill was $8, and you want to leave a 15% tip. How much should you tip?
2. The sales tax is 5.75%, and the shirt costs $20. What is the total cost of the shirt?
3. As of 2001, the minimum hourly wage was $5.15. Congress proposed to increase it to $6.15 per hour. To the nearest percent, what is the proposed percent increase in the minimum wage?
$21.15
$1.20
Insert Lesson Title Here
Course 3
8-6 Applications of Percents
19%
Lesson Quiz: Part 2
4. It costs a business $13.30 to make its product. To satisfy investors, the company needs to make $4 profit per unit. To the nearest percent, what should be the company’s markup?
Insert Lesson Title Here
30%
Course 3
8-6 Applications of Percents
8-7 More Applications of Percents
Course 3
Warm UpWarm Up
Problem of the DayProblem of the Day
Lesson PresentationLesson Presentation
Warm Up
1. What is 35 increased by 8%?
2. What is the percent of decrease from 144 to 120?
3. What is 1500 decreased by 75%?
4. What is the percent of increase from 0.32 to 0.64?
37.8
375
Course 3
8-7 More Applications of Percents
100%
16 %2
3
Problem of the Day
Maggie is running for class president. A poll revealed that 40% of her classmates have decided to vote for her, 32% have decided to vote for her opponent, and 7 voters are undecided. If she needs 50% of the vote to win, how many of the undecided voters must vote for Maggie for her to win the election? 3
Course 3
8-7 More Applications of Percents
Learn to compute simple interest.
Course 3
8-7 More Applications of Percents
Vocabulary
interestsimple interestprincipalrate of interest
Insert Lesson Title Here
Course 3
8-7 More Applications of Percents
Course 3
8-7 More Applications of Percents
When you borrow money from a bank, you pay interest for the use of the bank’s money. When you deposit money into a savings account, you are paid interest. Simple interest is one type of fee paid for the use of money.
I = P r t
Simple Interest
Principal is the amount of money borrowed or invested
Rate of interest is the percent charged or earned
Time that the money is borrowed or invested (in years)
To buy a car, Jessica borrowed $15,000 for 3 years at an annual simple interest rate of 9%. How much interest will she pay if she pays the entire loan off at the end of the third year? What is the total amount that she will repay?
Additional Example 1: Finding Interest and Total Payment on a Loan
Course 3
8-7 More Applications of Percents
First, find the interest she will pay.
I = P r t Use the formula.
I = 15,000 0.09 3 Substitute. Use 0.09 for 9%.
I = 4050 Solve for I.
Additional Example 1 Continued
Course 3
8-7 More Applications of Percents
Jessica will pay $4050 in interest.
P + I = A principal + interest = amount
15,000 + 4050 = A Substitute.
19,050 = A Solve for A.
You can find the total amount A to be repaid on a loan by adding the principal P to the interest I.
Jessica will repay a total of $19,050 on her loan.
To buy a laptop computer, Elaine borrowed $2,000 for 3 years at an annual simple interest rate of 5%. How much interest will she pay if she pays the entire loan off at the end of the third year? What is the total amount that she will repay?
Try This: Example 1
Course 3
8-7 More Applications of Percents
First, find the interest she will pay.
I = P r t Use the formula.
I = 2,000 0.05 3 Substitute. Use 0.05 for 5%.
I = 300 Solve for I.
Try This: Example 1 Continued
Course 3
8-7 More Applications of Percents
Elaine will pay $300 in interest.
P + I = A principal + interest = amount
2000 + 300 = A Substitute.
2300 = A Solve for A.
You can find the total amount A to be repaid on a loan by adding the principal P to the interest I.
Elaine will repay a total of $2300 on her loan.
Additional Example 2: Determining the Amount of Investment Time
Course 3
8-7 More Applications of Percents
I = P r t Use the formula.
450 = 6,000 0.03 t Substitute values into the equation.
2.5 = t Solve for t.
Nancy invested $6000 in a bond at a yearly rate of 3%. She earned $450 in interest. How long was the money invested?
450 = 180t
The money was invested for 2.5 years, or 2 years and 6 months.
Try This: Example 2
Course 3
8-7 More Applications of Percents
I = P r t Use the formula.
200 = 4,000 0.02 t Substitute values into the equation.
2.5 = t Solve for t.
TJ invested $4000 in a bond at a yearly rate of 2%. He earned $200 in interest. How long was the money invested?
200 = 80t
The money was invested for 2.5 years, or 2 years and 6 months.
Course 3
8-7 More Applications of Percents
I = P r t Use the formula.
I = 1000 0.0325 18 Substitute. Use 0.0325 for 3.25%.
I = 585 Solve for I.
Now you can find the total.
Additional Example 3: Computing Total Savings
John’s parents deposited $1000 into a savings account as a college fund when he was born. How much will John have in this account after 18 years at a yearly simple interest rate of 3.25%?
Course 3
8-7 More Applications of Percents
P + I = A Use the formula.
1000 + 585 = A
1585 = A
John will have $1585 in the account after 18 years.
Additional Example 3 Continued
Course 3
8-7 More Applications of Percents
I = P r t Use the formula.
I = 1000 0.075 50 Substitute. Use 0.075 for 7.5%.
I = 3750 Solve for I.
Now you can find the total.
Try This: Example 3
Bertha deposited $1000 into a retirement account when she was 18. How much will Bertha have in this account after 50 years at a yearly simple interest rate of 7.5%?
Course 3
8-7 More Applications of Percents
P + I = A Use the formula.
1000 + 3750 = A
4750 = A
Bertha will have $4750 in the account after 50 years.
Try This: Example 3 Continued
Mr. Johnson borrowed $8000 for 4 years to make home improvements. If he repaid a total of $10,320, at what interest rate did he borrow the money?
Additional Example 4: Finding the Rate of Interest
Course 3
8-7 More Applications of Percents
P + I = A Use the formula.
8000 + I = 10,320
I = 10,320 – 8000 = 2320 Find the amount of interest.
He paid $2320 in interest. Use the amount of interest to find the interest rate.
Additional Example 4 Continued
Course 3
8-7 More Applications of Percents
2320 = 32,000 r Multiply.
I = P r t Use the formula.
2320 = 8000 r 4 Substitute.
232032,000
= r Divide both sides by 32,000.
0.0725 = r
Mr. Johnson borrowed the money at an annual rate
of 7.25%, or 7 %.14
Mr. Mogi borrowed $9000 for 10 years to make home improvements. If he repaid a total of $20,000 at what interest rate did he borrow the money?
Try This: Example 4
Course 3
8-7 More Applications of Percents
P + I = A Use the formula.
9000 + I = 20,000
I = 20,000 – 9000 = 11,000 Find the amount of interest.
He paid $11,000 in interest. Use the amount of interest to find the interest rate.
Try This: Example 4 Continued
Course 3
8-7 More Applications of Percents
11,000 = 90,000 r Multiply.
I = P r t Use the formula.
11,000 = 9000 r 10 Substitute.
11,000 90,000
= r Divide both sides by 90,000.
0.12 = r
Mr. Mogi borrowed the money at an annual rate of about 12.2%.
Lesson Quiz: Part 1
1. A bank is offering 2.5% simple interest on a savings account. If you deposit $5000, how much interest will you earn in one year?
2. Joshua borrowed $1000 from his friend and paid him back $1050 in six months. What simple annual interest did Joshua pay his friend? 10%
$125
Insert Lesson Title Here
Course 3
8-7 More Applications of Percents
Lesson Quiz: Part 2
3. The Hemmings borrowed $3000 for home improvements. They repaid the loan and $600 in simple interest four years later. What simple annual interest rate did they pay?
4. Mr. Berry had $120,000 in a retirement account. The account paid 4.25% simple interest. How much money was in the account at the end of 10 years?
Insert Lesson Title Here
5%
$171,000
Course 3
8-7 More Applications of Percents