Chapter 7 : Interference of light

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Chapter 7: Interference of light Chapter 7: Interference of light

description

Chapter 7 : Interference of light. Chapter 7 : Interference of light. in·ter·fer·ence. 1. Life. Hindrance or imposition in the concerns of others. http://www.youtube.com/watch?v=qbQ3o0MkK38. 2. Sports . Obstruction of an opponent, resulting in penalty. - PowerPoint PPT Presentation

Transcript of Chapter 7 : Interference of light

Page 1: Chapter  7 :  Interference of light

Chapter 7: Interference of lightChapter 7: Interference of light

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2. Sports. Obstruction of an opponent, resulting in penalty.

in·ter·fer·ence

constructive destructive

3. Physics. Superposition of two or more waves, resulting in a new wave pattern.

1. Life. Hindrance or imposition in the concerns of others.http://www.youtube.com/watch?v=qbQ3o0MkK38

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HeNe laser

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Radio City Rockettes, New York, NY

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J.R. Stroop "Studies of interference in serial verbal reactions" Journal of Experimental Psychology 18:643-662 (1935).

rood blauw oranje paars oranje blauw groen rood blauw paars groen rood oranje blauw rood groen paars oranje rood blauw groen rood blauw paars oranje blauw rood groen paars oranje rood blauw

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Peacock

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Kauai, Hawaii

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2-beam interference

propagation distance from source of disturbance

initial phase (at t=0)

from superposition principle:

)cos(

)cos(

22022

11101

tks

tks

EE

EE

21 EEE

P

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EE

cI 0

- Electric fields are rapidly varying (~ 1014 Hz)

- Quickly averages to 0

- Instead of measuring E directly, measure radiant power density

= irradiance, Ee (W/m2)

= time average of the square of the electric field amplitude

- Note: to avoid confusion, Pedotti3 uses the symbol I instead of Ee

Measuring interference

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Irradiance at point P

20 PcI E

PPc EE

0

21210 EEEE

c

2122110 2 EEEEEE

cI

I1 I2 I12I = + +

- when E1 and E2 are parallel, maximum interference

- when orthogonal, dot product = 0; no interference

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The interference term I12

21012 2 EE

cI

)cos()cos( 2211021021 tkstksEEEE

dot product of electric fields:

simplify by introducing constant phases:

2211 ksks

)cos()cos(22 021021 tt EEEE

use trigonometry: 2cosAcosB = cos(A+B) + cos(B-A) and consider again the time average:

)cos()2cos(2 021021 tEEEE

kills it

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The interference term I12

)cos(0210 EE

)cos()2cos(2 021021 tEEEE

))(cos( 12120210 sskEE

simplify by introducing : 1212 )( ssk

cos0210012 EE

cI

to yield the interference term of the irradiance:

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Irradiance formula

1221 IIII

1101 EE

cI

)(cos22010 tcE

20101 2

1cEI

2202 EE

cI

)(cos22020 tcE

20202 2

1cEI

cos0210012 EE

cI

02100210 EEEE

if E1║ E2,

then

cos2 2112 III

cos2 2121 IIIII

-where is the phase difference -for parallel electric fields

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Interferencemutually incoherent beams (very short coherence time)

21 III

mutually coherent beams (long coherence time)

cos2 2121 IIIII

constructive interference

destructive interference

maximum when cos = 1

2121 2 IIIII

minimum when cos = -1

2121 2 IIIII

= (2m)

= (2m+1)

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Interference fringes

cos2 2121 IIIII

maximum when I1 = I2 = I0

1 + 1 = 4 !?!What about conservation of energy?

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Interference in time and space

Young’s experimentwavefront division

Michelson interferometeramplitude division

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The double slit experiment (first performed in early 1800s)

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http://www.youtube.com/watch?v=ZJ-0PBRuthc

Double slit experiment with electrons

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Criteria for light and dark bands

conditions for interference:

sinam

- approximate arc S1Q to be a straight line - optical path difference = a sin

sin2

1 am

constructive

destructive

m = 0, 1, 2, 3, …

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2-beam interference from 1 source: reflection

Fresnel’s mirrors

Lloyd’s mirror

part of the wavefront is reflected off each mirror

part of the wavefront is reflected; part goes direct to the screen

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Fresnel’s mirrors as solar collectors

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part of the incident light is refracted downward and part upward

2-beam interference from 1 source: refraction

Fresnel’s biprism

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Fresnel’s biprism for broadband pulse characterization

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Interference intermezzoInterference intermezzo

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Anatomy of a soap bubble

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optical path difference: = nf(AB + BC) = nf (2t)

Thin film interference: normal incidence

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= m: constructive interference = (m + ½): destructive interference where m = 0,1,2,…

Thin film interference: non-normal incidence

optical path difference: = nf(AB + BC) – n0(AD) = 2nf t cost

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Keep in mind the phase

Simple version: phase of reflected beam shifted by if n2 > n1

0 if n1 > n2

Correct version: use Fresnel equations!

“hard”reflection

“soft”reflection

analogous to wave on a rope

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Summary of phase shifts on reflection

TE mode TM mode

airglass

external reflectionn1 < n2

TE mode TM mode

airglass

internal reflectionn1 > n2

n1

n2

n1

n2

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Colors indicate bubble thickness

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How thick here (yellow band)?

tn>1

180o phase change

0o phase change

Constructive interference for 2t ~ (m + ½)

At first red band m = 0 t ~ ¼ (700 nm)

Consider a tapered soap film

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Bright: Colored “monochromatic” stripes occur at (1/4) for visible colors

White: Multiple, overlapping interferences (higher order)

Dark: Super thin; destructive interference for all wavelengths (no reflected light)

pop!

Dark, white, and bright bands

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Constructive reflection2d = (m+1/2)λ m=0, 1, 2, 3...

Destructive reflection 2d = mλ m=0, 1, 2, 3...

Fringes of equal thickness

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Newton’s rings

pattern depends on contact point: goal is concentric rings

m

mm

t

trR

2

22

white-light illumination

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Constructive reflection2d = mλ m=0, 1, 2, 3...

Destructive reflection 2d = (m+1/2)λ m=0, 1, 2, 3...

Oil slick on pavement

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Glass: n = 1.5MgF2 coating: n = 1.38

To make an AR coating for = 550 nm, how thick should the MgF2 layer be?

Thin film coatings: anti-reflective

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Broadband anti-reflective films

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• thin layers with a high refractive index n1,interleaved with thicker layers

with a lower refractive index n2

• path lengths lA and lB differ by exactly one wavelength

• each film has optical path length /4: all reflected beams in phase

• ultra-high reflectivity: 99.999% or better over a narrow wavelength range

Multilayer mirrors

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Anodized titanium

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Natural multi-layer reflectors

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Exercises

You are encouraged to solve all problems in the textbook (Pedrotti3).

The following may be covered in the werkcollege on 29 September 2010:

Chapter 7:1, 2, 7, 9, 15, 16, 24

Next week’s lecture given by Herman Offerhaus