Chapter 7: Conservation of Energy - National MagLabshill/Teaching/2048 Spring11/Lecture12.pdf ·...
Transcript of Chapter 7: Conservation of Energy - National MagLabshill/Teaching/2048 Spring11/Lecture12.pdf ·...
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Chapter 7: Conservation of Energy Chapter 9: Center of Mass and Momentum
Tuesday February 17th
Reading: up to page 113 in Ch. 7, then start of Ch. 9
• Review: Potential Energy • Review: Conservation of Energy • Calculus method for determining work • Example problems, iclicker and demos • Chapter 9: center of mass (if time) • Chapter 9: momentum and impulse (if time)
Mini Exam III on Thursday • Will cover LONCAPA #7-10 (Newton’s laws and energy cons.)
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ΔU =U f −Ui
= −Wcons.
= −FgΔxΔUg = Mgh
= +Wn.c.
F
Mg
h
Work & Potential Energy One can define a ‘Potential Energy’, U, for ALL conservative forces as follows:
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ΔU =U f −Ui
= −Wcons.
= −FgΔxΔUg = Mgh
= +Wn.c.
F
Mg
h
Work & Potential Energy One can define a ‘Potential Energy’, U, for ALL conservative forces as follows:
The Potential Energy change, ΔU, does not care how the height change was achieved.
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Conservation of Energy
ΔK = K f − Ki =Wnet
=Wcons. +Wn.c.
Work-Kinetic Energy theorem
• We can now replace any work due to conservative forces by potential energy terms, i.e.,
ΔK = −ΔU +Wn.c.
ΔEmech = ΔK + ΔU =Wn.c.
Or
• Here, Emech is the total mechanical energy of a system, equal to the sum of the kinetic and potential energy of the system.
• If work is performed on the system by an external, non-conservative force, then Emech increases.
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Conservation of Energy Alternatively:
ΔEmech = ΔK + ΔU =Wn.c.
⇒ K f − Ki( ) + U f −Ui( ) =Wn.c.
Or K f +U f = Ki +Ui( ) +Wn.c.
i.e. Emech, f = Emech,i +Wn.c.
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Power • Power is defined as the "rate at which work is done." • If an amount of work W is done in a time interval Δt by a force, the average power due to the force during the time interval is defined as
Pavg =
WΔt
• Instantaneous power is defined as P = dW
dt• The SI unit for power is the Watt (W).
1 watt = 1 W = 1 J/s = 0.738 ft · lb/s 1 horsepower = 1 hp = 550 ft · lb/s = 746 W
1 kilowatt-hour = 1 kW · h = (103 W)(3600 s) = 3.60 MJ
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More on Power • Power is defined as the "rate at which work is done." • If an amount of work W is done in a time interval Δt by a force, the average power due to the force during the time interval is defined as
P = dW
dt=!F. d !r
dt=!F.!v
• Alternative definition of instantaneous power: Pavg =
WΔt
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General (calculus) method for calculating Work
ΔU = −Wc
= − Fc1Δx + Fc2Δx + ....FcjΔx + ...( )= − FcjΔx
j∑
ΔU = −Wc = − Fc (x)dx
xi
x f∫
Take the limit Δx → 0
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Gravitational Potential Energy
ΔU = − (−mg)dyyi
y f∫ = mg dyyi
y f∫= mg y f − yi( ) = mgΔy = mgh
ΔU = −Wc = − Fc (x)dx
xi
x f∫Fg
-mg
yi yf
y
Constant Force
Fg = -mg
yi
yf
h
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Gravitational Potential Energy
ΔU = + (+mg)dyyi
y f∫ = mg dyyi
y f∫= mg y f − yi( ) = mgΔy = mgh
Fg
-mg
yi yf
y
Constant Force
Fn.c. = mg
ΔU = +Wn.c. = + Fn.c.(x)dx
xi
x f∫
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Elastic/Spring Potential Energy
ΔU = − (−kx)dxxi
x f∫ = k x dxxi
x f∫= 1
2 k x2⎡⎣ ⎤⎦xi
x f = 12 kx f
2 − 12 kxi
2
ΔU = −Wc = − Fc (x)dx
xi
x f∫F
xi xf
Fc = -kx Δx
Fc = -kx
U = − (−kx)dx0
x
∫ = k x dx0
x
∫= 1
2 k x2⎡⎣ ⎤⎦0
x= 1
2 kx2
0
x
-kxf