Chapter 7- Acid Base Theories - Weebly · 2020. 10. 18. · 2. Acid and Base theories define...
Transcript of Chapter 7- Acid Base Theories - Weebly · 2020. 10. 18. · 2. Acid and Base theories define...
Chapter 7- Acid Base Theories
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Review of the Previous Lecture
1. We discussed different type of imperfections, both intrinsic and extrinsic, in solid-state lattices of ionic compounds and how they make an entropic contribution▪ These imperfections allow for conductivity
2. Band Theory was defined and used to distinguish between conductors (metals), insulators (nonmetals), and semiconductors.
3. An emphasis was placed on the Band gap of semiconductors▪ Intrinsic▪ Extrinsic
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Acid-Base theories are a unifiying theme for differenttypes of chemical species interactions.
1. Solubility
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A. “Like dissolves like”
I. Nonpolar solute dissolves in nonpolar solvent▪ Solvent interactions overcome weak London dispersion forces of the
nonpolar solute.
Instantaneous dipole
Induced dipole
E 1
r6
Extremely short range and weak
[A (s)]
1. Solubility
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Simple dissolution
A (s) A (soln)
Solubility constant:Ks =
[A (soln)]
Do not consider because the activityof a solid is unity.
Ks
Ks > 1, Thermodynamically favors dissolution
Δ G = -RT ln Keq = -RT ln Ks ; Δ G < 0
Therefore Ks is a measure of solubility.
1. Solubility
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II. Polar and ionic compound solutes dissolve in polar solvents. The solvents
▪ Overcome dipole-dipole interactions of polar solutes
▪ Overcome electrostatic interactions of ionic compounds
- Relatively insensitive to r and omnidirectional.- Bond strength (250-400 kJ/mol)
E 1
r3
E 1
r
H2O as the polar solvent
1. Solubility
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Can have:
a. Simple dissolution- With polar solutes
b. Dissolution with dissociation- With ionic compounds
PbI2 (s) Pb2+ (aq) + 2I- (aq)
Ksp = [Pb2+][I-]2 = 8.49 x 10-9 at 298 K
What is the maximum solubility of Pb2+?Consider: [I-] = 2 [Pb2+]
Ksp = [Pb2+](2 [Pb2+])2 = 4 [Pb2+]3 = 8.49 x 10-9
[Pb2+] = (2.12 x 10-9)1/3 = 1.28 mM
2. Acid and Base theories define affinity concepts in solution.
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A. Historical definition- Alchemists used taste to identify acids/bases
▪ Acids- Sour▪ Bases- Bitter
B. Arrhenius (1884)
▪ Acids: Yield H+ in aqueous solution▪ Bases: Yield OH- in aqueous solution
HCl (aq) + NaOH (aq) NaCl (aq) + H2O (l)
Definition limited to aqueous solutions.
Salt Water
2. Acid and Base theories define affinity concepts in solution.
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C. Brønsted-Lowry (1923)
▪ Acids: H+ donors▪ Bases: H+ acceptors
I. Reaction
HA + B- A- + HB
Conjugate Pair
Conjugate Pair
Conjugate Acid
Conjugate Base
Definition not limited to aqueous solutions.
C. Brønsted-Lowry (1923)
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II. Some solvents are amphoteric. They are both acids and bases.
Ex.) Water
NH3 (aq) + H2O (l) NH4+ (aq) + OH- (aq)
HF (aq) + H2O (l) H3O+ (aq) + F- (aq)
Acid
Base
C. Brønsted-Lowry (1923)
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III. Thermodynamics
a. Let’s consider the autoionization of water. What is the [H3O+] or [H+] at 25 ºC?
2 H2O (l) H3O+ (aq) + OH- (aq)
1.0 0 0-x +x +x
1.0 – x x x
Initial
Change
Equilibrium
[H2O]2Kw =
[H3O+][OH-]
=(1-x)2
(x) (x)
Kw
C. III. Thermodynamics
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[H2O]2Kw =
[H3O+][OH-]
=(1-x)2
(x) (x)
~1 because water is the solvent and will be virtually unchanged
= x2 = 10-14.0
[H2O]Kw =
[H+][OH-]
Kw is very low, which indicates that the autoionization is very low.
pKw = - log10 Kw = 14.0
C. III. Thermodynamics
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Determine the value of x:
= x2 = 10-14= [H+][OH-]
(x2)1/2 = (10-14)1/2
x = (10-7.0) = [H3O+] = [H+]
p [H+] = pH = -log10 (10-7.0) = 7.0
Kw = [H3O+][OH-]
C. III. Thermodynamics
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b. Measuring the strength of an acid and a base in water
i) Acid:
HA (aq) A- (aq) + H+ (aq)
[HA]i 0 0-x +x +x
[HA]i – x x x
Initial
Change
Equilibrium
[HA]Ka =
[H+][A-]=
[HA]i – x
x2
Ka
C. III. Thermodynamics
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[HA]Ka =
[H+][A-]=
[HA]i – x
x2pKa = -log10 Ka
Ka is a measure of the strength to donate a H+
Ka , pKa , the stronger the acid
▪ Very big Ka indicates that an acid will undergo full dissociation
C. III. Thermodynamics
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b. Measuring the strength of an acid and a base in water
ii) Base:
OCl- (aq) + H2O (l) HOCl (aq) + OH- (aq)
[OCl-]Kb =
[HOCl][OH-]
Kb
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ii) Base:
OCl- (aq) + H2O (l) HOCl (aq) + OH- (aq)
[OCl-]Kb =
[HOCl][OH-]
If given Ka = 3.5 x 10-8, determine Kb :
[HOCl]Ka =
[H+][OCl-]
Ka x Kb = [H+][OH-] = Kw = 1.0 x 10-14
Kb = Kw
Ka
=1.0 x 10-14
3.5 x 10-8= 2.86 x 10-7
[OCl-]
[HOCl][OH-]
[HOCl]
[H+][OCl-]x =
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ii) Base:
Given 0.028 M NaOCl, determine the %OH- that forms. Recall that Kb = 2.86 x 10-7
OCl- (aq) + H2O (l) HOCl (aq) + OH- (aq)
0.028 M 0 0-x +x +x
0.028 M – x x x
Assume full dissociation of NaOCl.
Initial
Change
Equilibrium
[OCl-]Kb =
[HOCl][OH-]
0.028 M - x
x2
= = 2.86 x 10-7
Assume ~0.028 given the very low value of Kb
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ii) Base:
Given 0.028 M NaOCl, determine the %OH- that forms. Recall that Kb = 2.86 x 10-7
[OCl-]Kb =
[HOCl][OH-]
0.028 - x
x2
= = 2.86 x 10-7
Assume ~0.028 given the very low value of Kb
0.028
x2
= 2.86 x 10-7
x2 = 2.86 x 10-7 x 0.028
(x2)1/2 = 8.01 x 10-9
x = 8.9 x 10-5 M
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ii) Base:
Given 0.028 M NaOCl, determine the %OH- that forms. Recall that Kb = 2.86 x 10-7
x = 8.9 x 10-5 M = [OH-]
OCl- (aq) + H2O (l) HOCl (aq) + OH- (aq)
0.028 M 0 0-x +x +x
0.028 M – x x x
Initial
Change
Equilibrium
[NaOCl]ini
[OH-]= X 100%
0.028 M
8.9 x 10-5 MX 100% = 0.32%
An expected low % dissociation given the very low Kb = 2.86 x 10-7
The assumption that 0.028 M – x ~ 0.028 M is valid given the % dissociation is less than 5%.
IV. Le Chatlier’s Principle
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If a chemical system @ equilibrium experiences a change in concentration, theequilibrium shifts to counteract the imposed change and a new equilibrium isestablished.
▪ [reactants] or [products]; equilibrium shifts to the left
▪ [reactants] or [products]; equilibrium shifts to the right
HA + B- A- + HB
IV. Le Chatlier’s Principle
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Let’s consider the dissociation of acetic acid.
CH3COOH (aq) CH3COO- (aq) + H+ (aq)
[Acetic Acid]initial (M) [H+] (M) pH %H+ dissociated
1.00 4.23 x 10-3 2.37 0.423
0.05 9.49 x 10-4 3.02 1.90
0.005 2.91 x 10-4 3.54 5.82
5.0 x 10-6 4.87 x 10-7 6.31 9.74
%H
+d
isso
ciat
ion
[Acetic Acid]ini (M)
V. The Brønsted-Lowry concept is applicable to different solvents.
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Reconceptualize acid and base strength:
▪ The H3O+/H2O/OH- reference for quantifying relative acid and base strengths is only
useful when the examined acid is inherently weaker than H3O+ or the examined base is
weaker than OH-
▪ In H2O, H3O+ is the strongest acid
OH- is the strongest base
V. The Brønsted-Lowry concept is applicable to different solvents.
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▪ Acids inherently stronger than H3O+ cannot be differentiated by their aqueous ionization;
this is called the Leveling Effect
▪ The strength of a strong acid is limited (“leveled”) by the basicity of the solvent
A key perspective on leveling is that the classification of a substance as “weak” or “strong”and “acid” or “base” is tied to the solvent identity.
HA + H2O H3O+ + A-
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The Leveling Effect
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In H2SO4
HClO4 + H2SO4 (l)
HCl + H2SO4 (l)
HOCl + H2SO4 (l)
Weak Base
Weak Acid
Cl-
- H+
HOCl OCl-
Strong Acid
Strong Base
HCl
The Leveling Effect
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In H2SO4
HClO4 + H2SO4 (l) ClO4- + H3SO4
+
HCl + H2SO4 (l) H2Cl+ + HSO4-
HOCl + H2SO4 (l) H2OCl+ + HSO4-
HClO4 is a weak acid in H2SO4
HCl is a weak base in H2SO4
HOCl is a strong base in H2SO4
HCl Cl-
- H+
HOCl OCl-
The Leveling Effect
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In Acetic Acid (CH3COOH)
HClO4 + HAc (l)
HCl + HAc (l)
HOCl + HAc (l)
HCl Cl-
- H+
HOCl OCl-
Weak Base
Weak Acid
Strong Acid
Strong Base
The Leveling Effect
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In Acetic Acid (CH3COOH)
HClO4 + HAc (l) ClO4- + H2Ac+
HCl + HAc (l) Cl- + H2Ac+
HOCl + HAc (l) H2OCl+ + Ac-
HClO4 is a strong acid in HAc
HCl is a weak acid in HAc
HOCl is a weak base in HAc
HCl Cl-
- H+
HOCl OCl-
The Leveling Effect
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In water
HClO4 + H2O (l)
HCl + H2O (l)
HOCl + H2O (l)
HCl Cl-
HOCl OCl-
Weak Base
Weak Acid
Strong Acid
Strong Base
The Leveling Effect
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In water
HClO4 + H2O (l) ClO4- + H3O
+
HCl + H2O (l) Cl- + H3O+
HOCl + H2O (l) OCl- + H3O+
HClO4 is a strong acid in H2O
HCl is a strong acid in H2O
HOCl is a weak acid in H2O
Both HClO4 and HCl are leveled in water and have the same strength.
HCl Cl-
HOCl OCl-
The Leveling Effect
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In NH3
HClO4 + NH3 (l)
HCl + NH3 (l)
HOCl + NH3 (l)
HCl Cl-
HOCl OCl-
Strong Acid
Weak Acid
The Leveling Effect
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In NH3
HClO4 + NH3 (l) ClO4- + NH4
+
HCl + NH3 (l) Cl- + NH4+
HOCl + NH3 (l) OCl- + NH4+
HClO4 is a strong acid in NH3
HCl is a strong acid in NH3
HOCl is a strong acid in NH3
All are leveled in NH3 and have the same strength.
HCl Cl-
HOCl OCl-