Chapter 28 Atomic Physics The Hydrogen Atom The Bohr Model Electron Waves in the Atom.
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Transcript of Chapter 28 Atomic Physics The Hydrogen Atom The Bohr Model Electron Waves in the Atom.
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Chapter 28 Atomic PhysicsChapter 28 Atomic Physics
The Hydrogen AtomThe Hydrogen Atom
The Bohr Model The Bohr Model
Electron Waves in the Atom Electron Waves in the Atom
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Wave FunctionWave Function, ,
The value of 2 for a particular object at a certain place and time is proportional to the probability of finding the
object at that place at that time.
The Heisenberg Uncertainty The Heisenberg Uncertainty
PrinciplePrinciple Momentum and position xp ≥ h/4 Energy and time Et ≥ h/4
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Spectrum of White Light
Emission Spectrum of Hydrogen
Emission Spectrum of Helium
Emission Spectrum of Lithium
Emission Spectrum of Mercury
Absorption Spectrum of Hydrogen
Line Spectrum
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Rutherford Model Predicts:(1)A continuous range of frequencies of light emitted (2)Unstable atomsThese are inconsistent with experimental observations
Why ?Why ?
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Niels Henrik David Bohr1885-1962
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Quantized orbits Each orbit has a different energy
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Excited Electron
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Photon emitted: hf=Eu-El
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1/=R(1/22-1/n2), n=3,4,… for Balmer series where Rydberg constant R=1.097x107 m-1
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Spectrum of White Light
Emission Spectrum of Hydrogen
Emission Spectrum of Helium
Emission Spectrum of Lithium
Emission Spectrum of Mercury
Absorption Spectrum of Hydrogen
Line Spectrum: hf=Eu-El
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Equations Associated with The Bohr Equations Associated with The Bohr ModelModel
Electron’s angular momentum L=I=mvrn=nh/2n=1,2,3
n is called quantum number of the orbit
Radius of a circular orbit rn=n2h2/42mkZe2=(n2/Z)r1
where r1=h2/42mke2=5.29x10-11 m (n=1)r1 is called Bohr radius, the smallest orbit in H
Total energy for an electron in the nth orbit: En=(-22Z2e4mk2/h2)(1/n2)=(Z2/n2)E1
where E1=-22Z2e4mk2/h2 =-13.6 eV (n=1)E1 is called Ground State of the hydrogen
Both orbits and energies depend on n, the quantum number
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To break a hydrogen atom apart requires 13.6 eVTo break a hydrogen atom apart requires 13.6 eV
+ 13.6 eV =
Hydrogenatom
+
Proton electron
r=0.053 nm
v=2.2x106 m/s
Electron orbit
e
p
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Question: In the Bohr model of the hydrogen atom, the electron revolves around the nucleus in order to
(a) emit spectral lines(b) produce X rays(c) form energy levels that depend on its speed(d) keep from falling into the nucleus
Answer: d
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Question: A hydrogen atom is in its ground state when its orbital electron
(a) is within the nucleus (b) has escaped from the atom(c) is in its lowest energy level(d) is stationary
Answer: c
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Which one of the following statements is the assumption that Niels Bohr made about the angular momentum of the electron in the hydrogen atom?(a) The angular momentum of the electron is zero.(b) The angular momentum can assume only certain discrete values.(c) Angular momentum is not quantized.(d) The angular momentum can assume any value greater than zero because it’s proportional tothe radius of the orbit.(e) The angular momentum is independent of the mass of the electron.
X
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Example: Find the orbital radius and energy of an electron in a hydrogen atom characterized by principal quantum number n=2.
Solution: For n=2,
r2=r1n2=0.0529nm(2)2=0.212 nm
and
E2=E1/n2=-13.6/22 eV=-3.40 eV
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1.The kinetic energy of the ground state electron in hydrogen is +13.6 eV. What is its potential energy?(a) –13.6 eV (b) –27.2 eV (c) zero eV(d) +27.2 eV (e) +56.2 eV
2. An electron is in the ground state of a hydrogen atom. A photon is absorbed by the atom and the electron is excited to the n = 2 state. What is the energy in eV of the photon?(a) 13.6 eV (b) 3.40 eV (c) 0.54 eV(d) 10.2 eV (e) 1.51 eV
X
X
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Line and Absorption SpectraLine and Absorption Spectra
hf=Eu- El
hc/=Eu - El
1/=(1/hc)Eu- El
1/=(22Z2e4mk2/ch3)(1/nl2-1/nu
2)
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Each atom in the periodic table has a unique set of spectral lines. Which one of the followingstatements is the best explanation for this observation?(a) Each atom has a dense central nucleus.(b) The electrons in atoms orbit the nucleus.(c) Each atom has a unique set of energy levels.(d) The electrons in atoms are in constant motion.(e) Each atom is composed of positive and negative charges.
X
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Complete the following statement: An individual copper atom emits electromagnetic radiationwith wavelengths that are(a) evenly spaced across the spectrum.(b) unique to that particular copper atom.(c) the same as other elements in the same column of the periodic table.(d) unique to all copper atoms.(e) the same as those of all elements.
X
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Orbits and energies are quantized!
Why?
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Wave-Particle DualityWave-Particle Duality
= h/p= h/mv
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The quantized orbits and energy states in the Bohr model are due to the wave nature of the electron, and the electron wave functions can only occur in the form of standing waves.
Implication: The wave-particle duality is at the root of atomic structure
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Condition for orbit
An electron can circle an atomic nucleus only if its orbit is a whole number of electron wavelengths in circumference
Condition for orbit stability
n=2rn, n=1,2,3…
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Unless a whole number of wavelengths fits into the wire loop, destructive interference causes the vibrations to die out rapidly
n=4n=4
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de Broglie wavelength is =h/mv and the speed of the electron in a hydrogen is
v=2.2x106 m/s so =h/mv =6.63x10-34Js/(9.1x10-31kg)(2.2x106m/s) =3.3x10-10 m
2r1=2x5.29x10-11m=3.3x10-10 m The orbit of the electron in a hydrogen atom
corresponds to one complete electron wave joined on itself!
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Question: With increasing quantum number, the energy difference between adjacent energy levels
(a) decreases(b) remains the same(c) increases(d) sometimes decreases and sometimes
increases
Answer: a
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Question: An atom emits a photon when one of its electrons
(a) collides with another of its electrons(b) is removed from the atom(c) undergoes a transition to a quantum state of
lower energy(d) undergoes a transition to a quantum state of
higher energy
Answer: c
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Question: The bright-line spectrum produced by the excited atoms of an element contains wavelength that
(a) are the same for all elements(b) are characteristic of the particular element(c) are evenly distributed throughout the entire
visible spectrum(d) are different from the wavelength in its dark-
line spectrum
Answer: b
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Question: According to the Bohr model, an electron can revolve around the nucleus of a hydrogen indefinitely if its orbit is
(a) a perfect circle(b) sufficient far from the nucleus to avoid capture(c) less than one de Broglie wavelength in
circumference(d) exactly one de Broglie wavelength in
circumference
Answer: d
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Question: How can the spectrum of hydrogen contains so many lines when hydrogen contains only one electron?
Answer: The electron in the hydrogen atom can be in any of a nearly infinite number of quantized energy levels. A spectral line is emitted when the electron makes a transition from one discrete energy level to another discrete energy of lower energy. A collection of many hydrogen atoms with electrons in different energy levels will give a large number of spectral lines.
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Example: An electron collides with a hydrogen atom initially in its ground state and excites it to a state of n=3, How much energy was transferred to the hydrogen atom in this inelastic (KE not conserved) collision?
Solution: E=E1(1/n2f-1/n2
i)
Here ni=1, nf=3 and E1=13.6 eV
E=E1(1/n2f-1/n2
i)=E1(1/32-1/12)=-13.6(-8/9)eV =12.1 eV
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The presence of definite energy levels in an atom is true for all atoms. Quantization is characteristic of many quantities in nature
Bohr’s theory worked well for hydrogen and for one-electron ions. But it did not prove as successful for multielectrons.
It is quantum mechanics that finally solved the problems
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Early Quantum TheoryEarly Quantum Theory
Quantum energy: E=hf
Photoelectric effect: hf=KEmax+Wo
De Broglie wavelength: =h/mv
Bohr theory: L=mvr=nh/2 En=E1/n2 where E1=-13.6 eV
Wave-particle duality
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Limitations of the Bohr TheoryLimitations of the Bohr Theory
Unable to predict the line spectra for more complex atoms
Unable to predict the brightness of spectral lines of hydrogen
Unable to explain the fine structureUnable to explain bonding of atoms in
molecules, solids and liquidsUnable to really resolve the wave-particle
duality
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Quantum MechanicsQuantum Mechanics
It solves all these problems and has explained a wide range of physical phenomena.
It works on all scales of size. Classical physics is an approximation of quantum physics
It uses an abstract mathematical formulation dealing with probabilitiesprobabilities
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Bohr ModelBohr Model Quantum mechanicsQuantum mechanics
Definite circular orbits of electrons No precise orbits of electrons, only theprobability of finding a given electron at a given point
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Upon which one of the following parameters does the energy of a photon depend?
(a) mass (c) polarization (e) phase relationships
(b) amplitude (d) frequency
For which one of the following problems did Max Planck make contributions that eventually led
to the development of the “quantum” hypothesis?
(a) photoelectric effect (d) the motion of the earth in the ether
(b) uncertainty principle (e) the invariance of the speed of light through vacuum
(c) blackbody radiation curves
X
X
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Wave Function, Wave Function,
The Heisenberg Uncertainty PrincipleThe Heisenberg Uncertainty Principle
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Description of wavesDescription of waves
Type of waves Variable physical quantityType of waves Variable physical quantity
Water waves Height of the water surface
Sound waves Pressure in the medium
Light waves Electric and magnetic fields
Matter waves Wave function, Matter waves Wave function, the amplitude of a matter wave, is a
function of time and position
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Probability Density Probability Density 22
The value of 2 for a particular object at a certain place and time is proportional to the probability of finding the object at that place at that time.
For example: 2 =1: the object is definitely there 2 =0: the object is definitely not there 2 =0.4: there is 40% chance of finding the object there
at that time.
2 starts from Schrodinger’s equation, a differential equation that is central to quantum mechanics
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Why Why 22? Why not ? Why not ??
Amplitude of every wave varies from –A to +A to –A to +A and so on (A is the maximum absolute value whatever the wave variable is).
A negative probability is meaningless. 2 2 gives a positive quantity that can be
compared with experiments.
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The key point to the wave function is that the position of a particle is only expressed as a likelihood or probability until a measurement is made.
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The probability the electron will be found at the particular position is determined by the wave function illustrated to the right of the aperture. When the electron is detected at A, the wave function instantaneously collapses so that it is zero at B.
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The Heisenberg Uncertainty PrincipleThe Heisenberg Uncertainty Principle
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Example: Compare the de Broglie wavelength of 54-eV electrons with that of a 1500-kg car whose speed is 30 m/s.
Solution: For the 54-eV electronFor the 54-eV electron:KE=(54eV)(1.6x10-19J/eV)=8.6x10-18 JKE=1/2 mv2, mv=(2mKE)1/2
=h/mv=h/(2mKE)1/2= 1.7x10-10 m
The wavelength of the electron is comparable to atomic scales (e.g., Bohr radius=5.29x10-11 m). The wave aspects of matter are very significant.
For the car: For the car: =h/mv=6.63x10-34 J•s/(1.5x103)(30m/s)= 1.5x10-38 m
The wavelength is so small compared to the car’s dimension that no wave behavior is to be expected.
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The Heisenberg Uncertainty PrincipleThe Heisenberg Uncertainty Principle
In the microscopic world where the wave aspects of matter are very significant, these wave aspects set a fundamental limit to the accuracy of measurements of position and momentum regardless of how good instruments used are.
The uncertainty principle is the physical law which follows from the wave nature of matter
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p=h/precisex unknown
x better defined(narrower wave packet) p less defined(greater spread of )
Uncertainty principlexp≥h/2
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1. If an object has a well-defined position at a certain time, its momentum must have a large uncertainty.
2. If an object has a well-defined momentum at a certain time, its position must have a large uncertainty.
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Uncertainty Principle
Momentum and position xp ≥ h/2
Energy and time Et ≥ h/2
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Question: The quantum theory of the atom
(a) is based on the Bohr theory
(b) is more comprehensive but less accurate than Bohr theory
(c) cannot be reconciled with Newton’s laws of motion
(d) is not based on a mechanical model and considers only observable quantities
Answer: d
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Question: A large value of the probability density of an atomic electron at a certain place and time signifies that the electron
(a) is likely to be found there
(b) is certain to be found there
(c) has a great deal of energy there
(d) has a great deal of charge there
Answer: a
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Question: A moving body is described by the wave function at a certain time and place. The value of 2 is proportional to the body’s
a. electric field.
b. speed
c. energy
d. probability of being found
Answer: d
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Question: The narrower the wave packet of a particle is
a. the shorter its wavelengthb. the more precisely its position can be
established c. the more precisely its momentum can be
establishedd. the more precisely its energy can be
established
Answer: b
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Question: Modern physical theories indicate that
a. all particle exhibit wave behaviorb. only moving particles exhibit wave
behaviorc. only charged particles exhibit wave
behavior d. only uncharged particles exhibit wave
behaviorAnswer: b
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Question:The description of a moving body in terms of matter wave is legitimate because
a. it is based on common sense
b. matter waves have been actually seen
c. the analogy with EM waves is plausible
d. theory and experiment agree
Answer: d
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Question: The wave packet that corresponds to a moving particle
a. has the same size as the particle
b. has the same speed as the particle
c. has the speed of light
d. consists of x-ray
Answer: b
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Question: If Planck’s constant were larger than it is,
a. moving bodies would have shorter wavelength
b. moving bodies would have higher energies
c. moving bodies would have higher momenta
d. The uncertainty principle would be significant on a larger scale of size
Answer: d
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Wave Function, Wave Function,
The Heisenberg Uncertainty PrincipleThe Heisenberg Uncertainty Principle