Chapter 2 - Graphs of Functions II
Transcript of Chapter 2 - Graphs of Functions II
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10
10
1
2
3
3
2
1
x2 4
4
5
y = 2x 3
3
y
1. Draw the graphs of the following linear functions.
1
2
0
4
6
x
2 4
8
y =x + 4
3
y
x
y = 3x 6
10
2
4
6
4
22 3
6
y
x
y = 5 2x
22 0
2
4
4
24
6
8
10
y
Draw the graph ofy = 2x 3 for 0x 4.
Step 1: Construct a table displaying the values ofx andy.
y = 2x 3
Step 2: Plot the points. Using a ruler, join the points to form a straight line.
Note:
For a straight line, only
2 points are needed.
(b) y =3x 6
x 0 3
y3 3
(a) y = x + 4 x 0 4
y 4 8
(c) y =5 2x x 2 4
y 9 3
x
y = 2x x2
10
1
3
2
12 3
y
Draw the graph of the following functions.
(a) y = 2x x2
(a) Step 1: Construct a table displaying the values
ofx andy.
Step 2: Plot the points. Join the points by a
smooth curve.
x 0 1 2 3y 0 1 0 3
(b) y = 3x x 3
(b) Step 1: Construct a table displaying the valuesofx andy.
Step 2: Plot the points. Join the points by a
smooth curve.
x 2 1 0 1 2y 2 2 0 2 2
x
y = 3x x3
112 0
1
2
2
12
y
x 0 3
y 6 3
Graphs of Functions II2CHAPTER
Understand and use the concept of graph of functions2.1
Example
Example
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2. Draw the graphs of the following functions.
(a) y = 3x2 + 3x + 1 (b) y = x2 5x
(c) y =1
x3 2
(d) y =2x3 + 1
(e) y =2
x(f) y =
4
3x
x 1 01
1 2
2y 5 1 1.75 1 5
x 2 1 0 1 2y 4 0.5 0 0.5 4
x 1 2 3 4 5
y 2 1 0.67 0.5 0.4
x 1 0 1 11
22
y 3 1 1 5.75 15
x 0 1 2 21
3 4 5 6
2y 0 4 6 6.25 6 4 0 6
x
y = 3x2 + 3x + 1
11 0
1
3
2
5
6
4
12
y
x
y =x2 5x
210
2
4
6
6
4
24 5 63
y
x
112 0
4
1
2
3
4
1
2
3
2
y = x31
2y
x
21 0
2
4
6
8
2
10
12
14
16
1
y = 2x3 + 1
y
x
10
0.5
1
1.5
2
2 3 4 5
y =2
x
y
x
1
2
3
1234 0
y = 4
3x
y
x 4 3 2 1 1
2
y
0.33 0.4 4 0.67 1.33 2.67
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(b) (i) the value ofy whenx = 5.
(ii) the value ofx wheny = 2.6.
(c) (i) the value ofy whenx = 3.5.
(ii) the value ofx wheny = 4.
(d) (i) the value ofy whenx = 1.
(ii) the value ofx wheny = 2.
3. From the following graphs, find
(a) (i) the value ofy whenx = 1.
(ii) the value ofx wheny = 2.
Find the values of (a) y whenx = 2 and (b) x wheny = 2 for the following graphs.
From the graph,
(a) whenx = 2,y = 3.5.
(b) wheny = 2,x = 2.4.
From the graph,
(a) whenx = 2,y = 3.5.
(b) wheny = 2,x = 0.23 or 4.23.
x
y
12 0
4
2
2
4
6
8
6
10
12
2 31
y = x3 21
2
x
y
y= 2x + 5
112 0
4
2
2
4
8
6
10
2 3 4
x
y
14 0
4
2
2
4
8
6
10
12
14
16
42 13 2 3
y = x2 + 2x 11
2
x
y
10
2
1
4
5
6
3
4 5 62 3
y= + 22
x
x
4y =5x + 4
224 0
2
2
4
4
6
4
y
x212 145 3 0
4
2
4
2
8
10
6
12
14
43
y
y = (x + 5)(x 1)1
2
(a) (b)
(ii) x = 1.5 (i) y = 2.4 (ii) x = 3.4
(i) y = 12.1 (ii) x = 1.7 (i) y = 2.5 (ii) x = 2
(i) y = 7
Example
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x
y
0
5
5
y = x + 5
x
y
0
y = 3x 2
2
32 x
y
0
2y x = 31
21
3
4. Identify the type of function for the following graphs.
x x x
y y y
0
x
y
0
00
Identify the type of function for the following graphs.
(b) (c)(a) (d)
5. Sketch the graphs of the following linear functions.
x = 0,y = 0 + 5 = 5
y = 0,x = 5
x = 0,y = 3(0) 2 = 2
y = 0, 3x = 2
x =23
x
y
0
8
4
y = 2x 8
x
y
0
5
5
y = x + 5
Sketch the graphs of the following linear functions.
x
y
0
x
y
0
x
y
0
x
y
0
x
y
0
x
y
0x
y
0
y
0
(a) (b) (c) (d)
(e) (f) (g) (h)
Reciprocal function Cubic function Cubic functionQuadratic function
Linear function Quadratic function Reciprocal function Cubic function
(b) Linear function (c) Quadratic function(a) Reciprocal function (d) Cubic function
(c) 2y x = 3
x = 0, 2y = 3
y = 1
1
2
y = 0, x = 3
x = 3
(b) y = 3x 2
Example
Example
(a) y = 2x 8 m 0
The gradient is positive and they-intercept is 8.
x = 0,y = 2(0) 8
= 8
y = 0, 2x = 8
x = 4
(b) y = x + 5 m 0
The gradient is negative and they-intercept is 5.
x = 0,y = 0 + 5
= 5
y = 0,x = 5
(a) y = x + 5
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x
y
6
2 30
y = (x + 2)(x 3)
y = x2 + 4
x
y
0 22
4
Sketch the graphs of the following quadratic functions.
x
y
27
30
x
y
x
y
9
300
4y = 9 x3
1
3
1
2
y = 32x3 + 4
y =x3 27
7. Sketch the graphs of the following cubic functions.
(a) y =x3 27 (b) y = 9 1 x3 3(c) y = 32x3 + 4
x = 0,y = 32(0) + 4 = 4
y = 0, 32x3 = 4
x3 =
18
x =
12
x
y
20
y = 2x2 4x
x
y
1
2
20
y = (x + 1)(x 2)
x
y
2
10
0
y = (5 x )(x + 2)
5
6. Sketch the graphs of the following quadratic functions.
x = 0,y = (1)(2) = 2
y = 0, (x + 1)(x 2) = 0x = 1, 2
(c) y = (5 x)(x + 2)
x = 0,y = (5)(2) = 10
y = 0, (5 x)(x + 2) = 0 x = 5, 2
x = 0,y = 2(0) 4(0) = 0
y = 0, 0 = 2x(x 2) x = 0 orx = 2
(a) y = 2x2 4x (b) y = (x + 1)(x 2)
y = 3x3
x
y
0 x
y
2
4
0
y = x3 + 41
2
Sketch the graphs of the following cubic functions.
(b) y = 1
x 3 + 4 a 02
The function has a shape and the y-intercept is 4.
x = 0,y = 1
(0) + 42
= 4
y = 0,
1x3 = 4
2
x3 = 8
x = 2
(a) y = 3x3 a 0
The function has a shape and the
y-intercept is 0.
x = 0,y = 0
x = 0,y = 0 27 = 27
y = 0,x3 = 27
x = 3
13
x = 0,y = 9 (0) = 9
y = 0,1
x3 = 9
3x3 = 27
x = 3
Example
(a) y = (x + 2)(x 3)
y =x2
x 6 a
0The function has a shape and the y-intercept
is 6.
x = 0,y = 0 0 6 = 6
y = 0, (x + 2)(x 3) = 0
x = 2 or 3
(b) y = x2 + 4 a 0
The function has a shape and the y-interceptis 4.
x = 0,y = 4
y = 0,x2 = 4
x = 2 or 2
Example
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x
y
0x
y
0x
y
0
y = 5
x
y =6
x
y = 4
x
x
y
0
y =2
x
x
y
0
y = 2
x
Sketch the graphs of the following reciprocal functions.
(b) y = 2 a 0
x(a) y =
2
a
0 x
8. Sketch the graphs of the following reciprocal functions.
(b) y = 6
x
(a) y = 5
x(c) y =
4
x
1. Find the points of intersection of the given graphs.
(b)(a)
x
21123 0
1
1
2
2
3
4
5
6
4 53
y
y = x2 +x + 41
2
y =2
x
x
211234 0
1
2
3
4
4
3
1
2
5
6
43
y
y = x3 4x1
2
y = x + 13
2
From the graph, the points of intersection are
(3.4, 6.1), ( 0.2, 0.8) and (3.2, 3.8).
From the graph, the points of intersection are
(3.8, 0.5), (0.4, 4.4) and (2.3, 0.8).
Find thex-coordinates of the points of intersection of these two graphs:y = 2x2 3x 5 andy = 2x + 1.
x
2112 0
2
2
4
6
4
6
8
10
4 53
y
y = 2x + 1
y = 2x2 3x 5
From the graph,x = 3.4 andx = 0.8.
Example
Example
Understand and use the concept of the solution of an equation bygraphical method
2.2
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Solve the equationx2 +x + 1 = 1
x + 5 graphically.2
Step 1: Draw the graphs ofy =x2
+x + 1 and
y = 1
x + 5.2
From the graph,
x = 1.4 and 2.9.
Step 2: The solution will be the x-coordinates of thepoints of intersection.
x
21123 0
1
2
3
4
5
6
7
3
y
y = x + 5
y =x2+x +1
1
2
2. Solve the following equations by graphical method.
(c) 2x2 5x 3 = 2
x
(d) x3 6x 2 = 4 2x
x
2 3112345 0
1
2
3
4
5
3
1
2
y
y = x2 2x + 5
1
2y = x + 3
x
2 3 411234 0
1
2
3
4
4
3
1
2
y
y =x 2
4
xy =
x
2 3 4112 0
1
2
3
4
5
6
7
3
1
2
y
y = 2x2 5x 3
2
xy =
x
2 3112 0
1
2
3
4
5
4
5
6
7
8
3
1
2
y
y = 4 2x
y =x3 6x 2
From the graph,
x = 3.1 and 0.7.
From the graph,
x = 3.2 and 1.2.
From the graph,
x = 2.9, 0.4 and 0.8.
From the graph,
x = 2.5.
(a)1
x + 3 = x2 2x + 52
(b) 4
=x 2 x
Example
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x
211234 0
2
24
6
8
4
6
8
y
y = 4 + 2x
y = 2x2+ 5x 4
(c) x2 4x = 0.5x 1
x2 4x + 2 = 0.5x 1 + 2
x2 4x + 2 = 0.5x + 1
From the graph,x = 0.27 and 3.7
(c) x3 4x + 1 = 0
x3 + 4x 1 = 0
x3 + 3x = 1 x
From the graph,x = 1.8, 0.25 and 2.1.
x
y
2145 123 0
1
1
2
3
2
3
4
5
6
y = x+ 1
y = x2 4x + 2
1
2
x
y
y = 1 x
y = x3 + 3x
1 2123 0
2
2
4
6
8
(a) Complete the table below for the equationy = 2x2 + 5x 4.
(b) By using a scale of 1 cm to 1 unit on the x-axis and 1 cm to 2 units on the y-axis, draw the graph of
y = 2x2 + 5x 4 for 3.5x 1.5.
(c) Draw a suitable straight line on your graph to find all the values ofx which satisfy the equation
2x2 + 3x = 8 for 3.5 x 1.5.
(a) (b)
(c) 2x2 + 3x = 8
2x2 + 3x + 2x = 8 + 2x
2x2 + 5x = 8 + 2x
2x2+ 5x 4 = 8 + 2x 42x2 + 5x 4 = 4 + 2x
From the graph,x = 1.4 and 2.9.
x 3.5 3 2 1.5 1 0 1 1.5
y 3 1 6 7 3 8
x 3.5 3 2 1.5 1 0 1 1.5
y 3 1 6 7 7 4 3 8
Tip:
Draw the graph
ofy = 4 + 2x.
Tip:
Change the left-hand
side of the equation to
2x2 + 5x 4.
3. (a) Complete the table below for the equation
y = x2 4x + 2.
(b) By using a scale of 1 cm to 1 unit on bothaxes, draw the graph ofy = x2 4x + 2 for
5x 1.
(c) Draw a suitable straight line on your graph
to solve the equation x2 4x = 0.5x 1.
(b)
4. (a) Complete the table below for the equation
y = x3 + 3x.
(b) By using a scale of 2 cm to 1 unit on thex-axis and 2 cm to 2 units on they-axis, draw
the graph ofy = x3 + 3x for 2.5x 2.
(c) By drawing a suitable straight line, solve the
equationx3 4x + 1 = 0.
(b)
x 5 4 3 2 1 0 1
y 3 2 5 6 5 2 3
x 2.5 2 1.5 1 0.5 0 0.5 1 1.5 2
y 8.1 2 1.1 2 1.4 0 1.4 2 1.1 2
Example
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x
y
y = 5
212 13467 5 0
2
3
1
2
1
3
54
6
7y = x2 + x1
2
5
2
5. (a) Show that the volume of the cuboid is (5x2 5x) cm3.
(b) Given thaty = 5x2 5x, complete the table below.
(c) By using a scale of 2 cm to 1 unit on thex-axis and
2 cm to 2 units on they-axis, draw the graph of
y = 5x2 5x for 0x 2.0.
(d) Given that the volume of the cuboid is 8 cm3.
Find the value ofx.
(a) Volume of cuboid = 5x (x 1)
= (5x2 5x) cm3
(d) If the volume of the cuboid is 8 cm3, theny = 8.
From the graph,x = 1.85.
x cm5 cm
(x 1) cm
(c)
x
y
y = 8
y = 5x2 5x
1 2 30
1
1
2
3
4
5
6
78
9
10
x 7 6 5 4 3 2 1 0 1 2
y 7 3 0 3 2 0 3 7
x 0 0.3 0.5 0.8 1.2 1.5 1.8 2.0
y 0 1.1 1.3 0.8 1.2 3.8 7.2 10
x 7 6 5 4 3 2 1 0 1 2y 7 3 0 2 3 3 2 0 3 7
Example
(a) Show that the area of the trapezium is ( 1 x2 + 5 x) cm2. 2 2(b) Given that y =
1x2
+
5x, complete the table below. 2 2
(c) By using a scale of 1 cm to 1 unit on both axes, draw the graph ofy =1
x2 +5
x for 7x 2. 2 2
(d) If the area of the trapezium is 5 cm2, find the values ofx.
(a) Area of trapezium =1
(x + 5)x (c)2
= ( 1 x2 + 5 x ) cm2 2 2
(b)
(d) If the area of the trapezium is 5 cm2, theny = 5.
From the graph,x = 1.5 and 6.5.
5 cm
x cm
x cm
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1. Determine whether the following points satisfyy = 3x + 7,y 3x + 7 ory 3x + 7.
y = 2
3x + 7 = 3(1) + 7= 10
Since 2 10, therefore
(1, 2) satisfiesy 3x + 7.
2. Determine whether the following points satisfyy =
1x 5,y
1x 5 ory
1x 5.
2 2 2
Identify the inequality representing the following region.
x
y y = x + 6
6
6 0
Step 1: Choose a convenient point, say (0, 0), from the shaded region.
Step 2:y = 0
x + 6 = 0 + 6 = 6
Since 0 6, therefore (0, 0) satisfiesyx + 6.Step 3: Hence, the inequality representing the region isy x + 6.
x
y
y =3x
0
3. Identify the inequality representing the following regions.
(a) (b) (c)
y 3x y 2 5y 8x + 40
x
y
0
8
5y = 8x + 40
5
x
y
0
2
(a) (20, 5) (b) (1, 2) (c) (2, 1)
(a) (2, 0) (b) ( 6, 8) (c) (6, 5)
y = 5
1x 5 =
1(6) 5
2 2= 2
Since 5 2,
(6, 5) satisfiesy1x 5.
2
y = 5
3x + 7 = 3(20) + 7= 53
Since 5 53, therefore
(20, 5) satisfiesy 3x + 7.
y = 8
1x 5 =
1( 6) 5
2 2= 8
Since 8 = 8,
( 6, 8) satisfiesy =1x 5.
2
y = 0
1x 5 =
1(2) 5
2 2= 6
Since 0 6,
(2, 0) satisfiesy1x 5.
2
Understand and use the concept of the region representing inequalities intwo variables
2.3
Example
Determine whether the following points satisfyy = 2x + 3, y 2x + 3 ory 2x + 3.
(a) (1, 5) (b) (2, 3) (c) (1, 6)
(a) y = 5
2x + 3 = 2(1) + 3 = 5
Since 5 = 5, therefore
(1, 5) satisfiesy = 2x + 3.
(b) y = 3
2x + 3 = 2(2) + 3 = 7
Since 3 7, therefore
(2, 3) satisfiesy 2x + 3.
(c) y = 6
2x + 3 = 2(1) + 3 = 1
Since 6 1, therefore
(1, 6) satisfiesy 2x + 3.
Example
y = 1
3x + 7 = 3(2) + 7= 1
Since 1 = 1, therefore
(2, 1) satisfiesy = 3x + 7.
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x
yy = 2x 5
2
5
0 1
2
y = 2x 5
2
5
12
x
y
y = x + 3
3
3
0
x
y
y = x + 33
3
0
4. Shade the region satisfying the following inequalities.
Shade the region satisfyingy 3x 3.
Step 1: Choose a convenient point, say (0, 0).
Step 2: y = 03x 3 = 3(0) 3 = 3
(0, 0) satisfiesy 3x 3.
Step 3: (0, 0) lies above the line. So any point above
the line satisfiesy 3x 3.
x
y y =3x 3
3
0 1Note:
Ify 3x 3, then the line
will be a solid line.
x
y y =x + 3
3
3
0
x
y
y = 5x 5
1
5
0
x
y y = 2x + 1
1
01
2
x
y
y = 5 3x
5
0
12
3
5. Shade the region representing the following inequalities.
(b) y 6x 1,y 1
x + 2 (c) y1 + 4x,y x + 52
x
y
43
1
2
0
1
4y = x 1
2
3y = x + 2
x
y
y = 6x 1
41
61
2
0
y = x + 212
x
y y = 1 + 4x
5
5
1
0
y = x + 5
1
4
(d) y 1
x + 3,y 3x 4 (e) y4x 2,y 2x + 2 (f) y 3x 7,y 5 x
2
Step 4:y 3x 3 is the region below the line.
Shade the region representingy 2x 5 andyx + 3.
Step 1: Identify the regions y 2x 5 and y x + 3
separately.
Step 2: Combine the two graphs and obtain
the common region between them.
x
yy = 3x 4
6
1
24
3
0
y = x + 3
1
31
x
yy = 4x 2
1
2
2
0
y = 2x + 2
1
2
x
y
y = 5 x
5
7
5
0
y = 3x 7
21
3
(a) y x + 3 (b) y5x 5 (c) y 2x + 1 (d) y 5 3x
(a) y 2
x + 2,y 1
x 1
3 4
Example
Example
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Shade the region which satisfies the following inequalities: y 2,y 2x + 1,y 3x 3.
6. Shade the region which satisfies the following inequalities.
(a) x0,y 2,y 2x + 4 (b) x 2,y 0,y x 5
y = 3x 3
32
1
2
x
y
y = 2x + 1
y = 2
1
1
0
x
yy = 2x + 4
y = 2
4
2
02
x
y
y =x 5
2
x = 2
50
5
x
y
x = 2y = 2x 3
y = 3x + 4
2
4
3
0 11
21
1
3x
y
y = 3x + 3
y = 33
3
61 0
y = x + 31
2
x
y
y =xy = x
8 y = 8
0
x
y y = 2x
y = 6
x = 1
6
01
(c) x 2,y 3x + 4,y 2x 3 (d) y 3,y 1
x + 3,y 3x + 32
(e) y8,y x,y x (f) x 1,y 6,y2x
Example
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x
y
0
2
x
y
0
x
y
0
55
2
x
y
0
x
y
0
x
y
0
x
y
0
x
y
0
x
y
0
33
3
3 x
y
0
x
y
0
x
y
0
1. Which of the following represents the graph of
y = 2x3 5?
A C
B D
2. Which of the following represents the graph of
y =x2 + 3?
A C
B D
3. Which of the following represents the graph of
y = 3 ?__
x
A C
B D
4. The equationx3 5x =x2 3 can be solved
by drawing 2 graphs. Which of the following
equations represent the 2 suitable graphs?
A y =x3 5x andy = 3 x2
B y =x3 5x andy =x2 3
C y = 5xx3 andy =x2 3
D y =x3 5x andy =x2 + 3
5. Which of the following statements is true?
A A linear function has an equation in the form
ofy = ax2 + b.
B They-intercept of a linear equation is 5 if the
equation isy = 8x 5.
C A linear function is a straight line graph.
D A linear function has a maximum point.
6. Table 1 shows the values ofx andy for the
equation 2x =y + 6.
TABLE 1
Find the value ofa.
A 4 C 0
B 2 D 2
7. Diagram 1 shows a graph.
DIAGRAM 1
Which region satisfies the inequalitiesx 10
andy 10?
A I C III
B II D IV
8. Diagram 2 shows the graph ofy = 8 x3.
DIAGRAM 2
State the value ofk.
A 8 C 2
B 2 D 8
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2004
x
y
I IV
II
10 0
10
III
x
y
(0, k)y = 8 x3
0
SPM
2002
SPM
2006
x 3 4 5 6
y a 2 4 6
Paper 1
SPM Practice2
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x
y
0 1
3
x
y
0 1
3
x
y
0
3
x
y
01
3
1
y
0
9
y
0 9
y
0 9
9
y
0
x
y = 2 xy =x + 4y
IIII
IV
II
4
4
0 2
2
x
y
0x
y
0
x
y
0x
y
0
9. Which of the following graphs represents the
inequalityy 3x 3?
A
B
C
D
10. Which of the following graphs represents
y = 9 x2
?A
B
C
D
11. Which of the following statements is false?
A A quadratic function is of the form
y = ax2 + bx + c.
B A quadratic function has a parabolic shape.
C A quadratic function has 2 lines of symmetry.
D A quadratic function has a maximum or
minimum point.
12. Diagram 3 shows a graph.
DIAGRAM 3
Which region satisfies the inequalitiesyx + 4
andy 2 x?
A I C III
B II D IV
13. Which of the following graphs represents
y = ax n + b, when n = 2?
A C
B D
14. Diagram 4 shows the graph ofy = (x + 3)(x 1).
DIAGRAM 4
Find the coordinates ofP.
A (3 , 0)
B (1 , 0)
C (0 , 3)
D (0 , 1)
x
y
P0
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15. Which of the following graphs satisfies the
inequalitiesy 4 andyx 4?
A
B
C
D
16. Diagram 5 shows the graph ofy =xn
4.
DIAGRAM 5
Find the values ofn and k.
A n = 3 , k= 4 C n = 1 , k= 4
B n = 2 , k= 4 D n = 3 , k= 4
Questions 17 and 18 are based on Diagram 6.
Diagram 6 shows the graph ofy =x3
+ 4.__2
DIAGRAM 6
17. Find the coordinates ofP.
A (4 , 0)
B (2 , 3)
C (2 , 0)
D (0 , 4)
18. Find the coordinates ofQ.
A (2 , 0)
B (0 , 8)
C (2 , 8)
D ( 4 , 0)
19. Diagram 7 shows the graph ofy = 5x 2.
DIAGRAM 7
From the graph, find the value ofy when
x = 0.6.
A 0.5 C 3 B 1 D 6
20. Diagram 8 shows the graph ofy =x2 4.
DIAGRAM 8
From the graph, find the values ofx wheny = 1.
A 3, 3 C 1.7, 1.7
B 2.3, 2.3 D 1.5, 1.5
x
y
y = xn 4
0
(0, k)
x
y
P
Q
0 2
y = + 4x3
2
x
2 31123 0
2
4
2
4
6
y
y =x2 4
x
2112 0
2
3
1
2
1
3
4
y
y = 5x 2
x
y
y = 4
y =x 4
0 4
4
4
x
y
y = 4
y =x 4
0 4
4
4
x
y
y = 4
y =x 4
0 4
4
4
x
y
y = 4
y =x 4
0 4
4
4
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Paper 2
4. Shade the region defined by the following
inequalities:y 3
x + 3 andy3
x + 3. 4 2
(a)
(b)
y = (x 1)(x + 4)
x
y
4
4
10
y = x3+ 1
x
y
0
1
1
y = 2x + 12
y = 12
x = 6
x
y
6
12
0
y = x + 3
x
y
4
3
02
3
4
y = x + 33
2
SPM
2005SPM
2007
2. Sketch the graph of(a) y = (x 1)(x + 4)
(b) y = x3 + 1
3. On the graph in the answer space, shade the
region which satisfies the three inequalitiesy 2x + 12,x 6 andy 12.
1.
On the graph, shade the region which satisfies
the three inequalities yx + 4,y 1
x 1
2
andx 1.
y =x + 4
x
y
224 4
2
4
0
2y = x 11
2
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5. Shade the region defined by the following
inequalities:x 0,y 0,y 1
x + 4 and2
y
1
x 3.__2
6. Diagram 1 shows the graph ofy =x3 4x.
DIAGRAM 1
Find the coordinates ofA andB.
x3
4x = 0 x(x2 4) = 0
x(x + 2)(x 2) = 0
x = 0, 2, 2
Coordinates ofA = (2 , 0)
Coordinates ofB = (2 , 0)
7. (a) Complete the table below for the equation
y =x3 + 5 by writing down the values ofy
whenx = 1 andx = 2.
(b) By using the scale of 2 cm to 1 unit on
the x-axis and 2 cm to 5 units on the
y-axis, draw the graph of y = x3 + 5 for
3x 2.5.
(c) From your graph, find
(i) the valueofy whenx = 1.5,
(ii) the value ofx wheny = 10.
(d) Draw a suitable straight line on your graph
to find the values ofx which satisfy the
equationx3
8x 4 = 0 for 3
x
2.5.State these values ofx.
x
y
86
4
0
3
y = x + 41
2
y = x 31
2
x
y
y =x3 4x
BA 0
(a)
(b)
x 3 2.5 2 1 0 1 2 2.5
y 22 10.625 3 5 6 20.625
x = 1,y = 4;x = 2,y = 13
(c) (i) 1.5
(ii) 2.45
(d) 0.5, 2.6
x
y
y = 8x + 9
y =x3 + 5
1123 2 30
5
10
15
20
25
5
15
10
20
25
SPM
2007
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x 2 1 0 1 2 3 4 5
y 31 14 3 2 1 6 19 38
SPM
2006
SPM
2005
(c) (i) y = 22(ii) x = 4.9
(d) 3x2 8x + 3 = x + 1
Draw the graph ofy = x + 1.
From the graph,x = 0.4 and 2.
x
y
y = x + 1
y = 3x2 8x + 3
2112 43 5 60
10
10
20
30
40
(b)
x
y
y =x + 6
2112345 43 50
5
10
15
5
10
15
y =16
x
(b)
9. (a) Complete Table 2 for the equation y = 16__
x
by writing down the values ofy when
x = 3 andx = 1.5.
TABLE 2
(b) By using a scale of 2 cm to 2 units on the
x-axis and 2 cm to 5 units on the y-axis,
draw the graph ofy = 16for 4x 4.__
x
(c) From your graph, find
(i) the value ofy whenx = 2.5,
(ii) the value ofx wheny = 8.
(d) Draw a suitable straight line on your graph
to find a value ofx which satisfies theequationx2 + 6x = 16 for 4x 4.
x 4 3 2 1 1.5 2 3 4
y 4 5.3 8 16 10.7 8 5.3 4
(c) (i) y = 6.4(ii) x = 2
(d) x2 + 6x = 16
x(x + 6) = 16
x + 6 =
16
x
Draw the graph ofy =x + 6.
From the graph,x = 2.
8. (a) Complete Table 1 for the equation
y = 3x2 8x + 3.
TABLE 1
(b) By using a scale of 2 cm to 2 units on the
x-axis and 2 cm to 10 units on they-axis,
draw the graph ofy = 3x2 8x + 3 for
2x 5.
(c) From the graph, find
(i) the value ofy whenx = 4.2,
(ii) the value ofx wheny = 35.
(d) Draw a suitable line on your graph to
find all the values of x which satisfy
the equation 3x2 8x + 3 = x + 1 for
2x 5.
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