Chapter 18 Solubility. Equilibria of Slightly Soluble Ionic Compounds Explore the aqueous equilibria...

25
Chapter 18 Solubility

Transcript of Chapter 18 Solubility. Equilibria of Slightly Soluble Ionic Compounds Explore the aqueous equilibria...

Chapter 18 Solubility

Equilibria of Slightly Soluble Ionic Compounds

• Explore the aqueous equilibria of slightly soluble ionic compounds.

• Chapter 5. Precipitation Reactions:

AgNO3(aq) + NaCl(aq) ??

• Want to consider quantitative predictions

The Formation & Dissolution of Precipitates

• Solubility: maximum amount of solute that will dissolve in a given amount of solvent (depends on solvent, temperature and pressure)

No compound is infinitely soluble andno compound is perfectly insoluble.

Solute Solubility

(g solute/100 g solvent)

Qualitative Solubility

Description

Less than 0.1 Insoluble

0.1 – 1 Slightly soluble

1 – 10 Soluble

Greater than 10 Very soluble

The Formation & Dissolution of Precipitates

• Saturated solution: contains maximum concentration of solute– Equilibrium between undissolved and dissolved solute.

• Solutes (even those called “soluble”) have a limited solubility in a particular solvent.

• Slightly soluble (often called “insoluble”) ionic compounds have a relatively low solubility – Reach equilibrium with little solute dissolved– Heterogeneous equilibrium

Why is this important?

Dissolving and Precipitation occurs around us:– Tooth enamel dissolves in acidic soln (tooth decay)

– Ppt of certain salts in kidneys causes kidney stones

– Waters of Earth contains dissolved salts as water passes over and through the ground

– Ppt of CaCO3 from groundwater is responsible for cave formation.

Let’s look at the factors that affect solubility!

Solubility-Product Constant (Ksp)

• Solubility-product constant (Ksp): equilibrium constant for equilibrium between slightly soluble ionic solid and a solution of its ions– Indicates how soluble the solid is in water

• Solubility: quantity that dissolves to form a saturated solution (g/L)

• Molar solubility: number of moles of solute that dissolves in forming a liter of saturated solution of solute (mol/L)

• Solubility depends on concentrations of other ions and pH but Ksp is a constant.

Solubility-Product Constant (Ksp)

Practice: Write an ionic equation for the dissolution, and the equation for the solubility product for:

(a) Calcium carbonate

(b) Magnesium hydroxide

(c) Ag3PO4

• Magnitude of Ksp is measure of how far to the right dissolution proceeds at equilibrium (saturation).

– Used to compare solubilities if same total number of ions

Ksp of Selected Ionic Compounds (25 °C)

Name, Formula Ksp

Aluminum hydroxide, Al(OH)3 3 x 10-34

Cobalt(II) carbonate, CoCO3 1.0 x 10-10

Iron(II) hydroxide, Fe(OH)2 4.1 x 10-15

Lead(II) fluoride, PbF2 3.6 x 10-8

Lead(II) sulfate, PbSO4 1.6 x 10-8

Mercury(I) iodide, Hg2I2 4.7 x 10-29

Silver sulfide, Ag2S 8 x 10-48

Zinc iodate, Zn(IO3)2 3.9 x 10-6

See Appendix D in your book for a much more extensive list.

Example

Predict which of the following compounds will

have the greatest molar solubility in water

A) AgCl Ksp = 1.8 x 10-10

B) AgBr Ksp = 5.0 x 10-13

C) AgI Ksp = 8.3 x 10-17

D) all have the same molar solubility

Solubilities and Solubility Products

• Ksp for a slightly soluble solid can be determined from its solubility – as long as there is no other reaction

• Example 1: Lead(II) sulfate (PbSO4) is a key component in lead-acid car batteries. Its solubility in water at 25 °C is 4.25 x 10-3 g/100 mL solution. What is the Ksp of PbSO4?

• Example 2: Determine the molar solubility of MgF2 from its solubility product (Ksp = 6.4 x 10-9).

Example

Calculate the molar solubility of calcium

fluoride, CaF2

Ksp = 3.7 x 10-11

Factors that Affect Solubility: Common Ion Effect

•The presence of a common ion decreases the solubility of a slightly soluble ionic compound.

•The shift in equilibrium that occurs because of the addition of an ion already involved in the equilibrium reaction.

AgCl(s) ⇌ Ag+(aq) + Cl(aq)

adding NaCl( ) shifts equilibrium positionaq

The effect of a common ion on solubility

PbCrO4(s) Pb2+(aq) + CrO42-(aq) PbCrO4(s) Pb2+(aq) + CrO4

2-(aq)

CrO42- added

Example

The solubility of Ca(OH)2 in water is 0.012 M.

What is its solubility in 0.10 M Ca(NO3)2?

Ksp of Ca(OH)2 is 6.5 x 10-6

Le Châtelier’s Principle

Determine the effects of solubility when each of

the following is added to a mixture of the

slightly soluble solid NiCO3 and water at

equilibrium:

(a)Ni(NO3)2 (c) K2CO3

(b)KClO4 (d) HNO3

Effect of pH on solubility

• [H3O+] can have a profound effect on the solubility of an ionic compound.

• Solubility of slightly soluble salts containing basic anions increases as [H+] increases– More basic anion…more solubility is influenced by pH

• Predict the effect on solubility of adding a strong acid

CaCO3(s) ⇌ Ca2+(aq) + CO3

2-(aq)

AgCl(s) ⇌ Ag+(aq) + Cl-

(aq)

Ca(OH)2(s) ⇌ Ca2+(aq) + 2OH-

(aq)

If limestone (CaCO3) deposit is near surface…sinkhole

If limestone (CaCO3) deposit is well below the surface….caves

A view inside Carlsbad Caverns, New Mexico

Copyright © Houghton Mifflin Company.All rights reserved. 1–19

Cango Caves

Copyright © Houghton Mifflin Company.All rights reserved. 1–20

Sudwala Caves

Example

Calculate the molar solubility of MgF2 in 0.10 M

MgCl2 at 25 C.

Ksp of MgF2 = 7.4 x 10-11

Predicting the Formation of a Precipitate

Compare Qsp to Ksp to predict if a precipitate will form

and, if not, what concentrations of ions will cause it to

do so.

Qsp = Ksp soln is saturated & no changes occur

Qsp > Ksp ppt forms until soln is saturated

Qsp < Ksp soln is unsaturated & no ppt forms

Practice

• Example 1: Determine whether CaHPO4 will precipitate from a solution with [Ca2+] = 0.0001 M and [HPO4

2-] = 0.001 M.

• Example 2: Does silver chloride precipitate when equal volumes of a 2 x 10-4 M solution of AgNO3 and a 2 x 10-4 M solution of NaCl are mixed.

AgNO3(aq) + NaCl(aq) AgCl(s) + NaNO3(aq)

Practice

Will a precipitate form when 0.10 L of

8.0 x 10-3 M Pb(NO3)2 is added to 0.40 L of

5.0 x 10-3 M Na2SO4?

Ksp for PbSO4 = 6.3 x 10-7

Concentration Necessary to Form a Ppt

• We can also determine the concentration of an ion necessary for precipitation to begin.

• Assume that precipitation begins when Qsp = Ksp

• Example: If a solution contains 0.0020 mol CrO42-

per liter, what concentration of Ag+ ion must be added as AgNO3 before Ag2CrO4 begins to precipitate. (Neglect any increase in volume upon adding the solid silver nitrate.)