Chapter 13 Unsaturated Hydrocarbonsdfard.weebly.com/uploads/1/0/5/3/10533150/ch13_cas.pdf · Two...
Transcript of Chapter 13 Unsaturated Hydrocarbonsdfard.weebly.com/uploads/1/0/5/3/10533150/ch13_cas.pdf · Two...
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Alkenes and AlkynesNaming Alkenes and AlkynesCis-Trans Isomers
Chapter 13 Unsaturated Hydrocarbons
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Saturated hydrocarbons: Have the maximum number of hydrogen atoms attached to each carbon atom.Are alkanes and cycloalkanes with single C-C bonds.
CH3—CH2—CH3
Saturated Hydrocarbons
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Unsaturated hydrocarbons: Have fewer hydrogen atoms attached to the carbon chain than alkanes.Are alkenes with double bonds or alkynes with triple bonds.
13.1Unsaturated Hydrocarbons
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Alkenes Have Double BondsIn a double bond:
One pair of electrons form a strong sigma (σ) bond.One pair of electrons in adjacent p orbitalsoverlap to form a pi (π) bond.
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Alkynes have Triple Bonds
In a triple bond: One pair of electrons form a strong sigma (σ) bond.Two pairs of electrons in adjacent p orbitals overlap to form two pi (π) bonds.
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Bond Angles in Alkenes and Alkynes
According to VSEPR theory: The three groups bonded to carbon atoms in a double bond are at angles of 120°.The two groups bonded to each carbon in a triple bond are at angles of 180°.
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In the IUPAC system, the –ane ending of the corresponding alkane is changed to –ene for alkenes and to –yne for alkynes.
Naming Alkenes and Alkynes
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When the carbon chain has 4 or more C atoms, the chain is numbered to give the lowest number to the double or triple bond.1 CH2=CH—CH2—CH3 1-butene
2CH3—CH=CH—CH2—CH3 2-pentene
3CH3—CH2—C≡C—CH2—CH3 3 -hexyne
13.2Naming Alkenes and Alkynes
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Write the IUPAC name for each:A. CH3—CH2—C≡C—CH3
CH3|
B. CH3—C=CH—CH3 C. CH3
Learning Check
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Write the IUPAC name for each:A. CH3—CH2—C≡C—CH3
2-pentyne
CH3|
B. CH3—C=CH—CH3 C. 2-methyl-2-butene 3-methylcyclopentene
CH3
Solution
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There is no rotation around the double bond in alkenes.Groups attached to the double bond are fixed relative to each other. You can make a “double bond” with your fingers with both thumbs on the same side or opposite from each other.
13.3Cis-Trans Isomers
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Two isomers are possible when groups are attached to the double bond.In a cis isomer, groups are attached on the same side of the double bond. In the trans isomer, the groups are attached on opposite sides.
Cis-Trans Isomers
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Cis-Trans Isomers in NatureInsects emit tiny quantities of pheromones, which are chemicals that send messages.The silkworm moth attracts other moths by emitting bombykol, which has one cis and one trans double bond.
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Naming Cis-Trans Isomers
The prefixes cis or trans are placed in front of the alkene name when there are cis-trans isomers.
cis-1,2-dibromoethene trans-1,2-dibromoethene
C C
Br H
BrHC C
Br Br
H H
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Cis-Trans IsomerismAlkenes cannot have cis-trans isomers if a carbon atom in the double bond is attached to identical groups.
Identical Identical
2-bromopropene 1,1-dibromoethene
C C
H Br
H CH3
C C
H Br
BrH
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Learning Check
Name each, using cis-trans prefixes when needed.
C C
CH3 H
CH3H
C C
Br Br
H H
A.
B.
C C
CH3 Cl
ClH
C.
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Solution
cis-1,2-dibromoethene
trans-2-butene
1,1-dichloropropene
C C
CH3 H
CH3H
C C
Br Br
H H
A.
B.
C C
CH3 Cl
ClH
C.
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13.6 Addition Reactions
Chapter 13 Unsaturated Hydrocarbons
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Addition ReactionsThe pi (π) bond is easily broken, which makes double and triple bonds very reactive.In the additionreaction, reactants are added to the carbon atoms in the double or triple bond.
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In hydrogenation, hydrogen atoms add to the carbon atoms of a double bond or triple bond.A catalyst such as Pt or Ni is used to speed up the reaction.
Hydrogenation
HC CH + 2H2
NiHC CH
H H
H H
H2C CH2
H HPt
H2H2C CH2 +
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When hydrogen adds to the double bonds in vegetable oils, the products are solids at room temperature.
Hydrogenation of Oils
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Write the equation for the addition of hydrogen to 1-butene using a Ni catalyst.
Learning Check
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Write the equation for the addition of hydrogen to 1-butene using a Ni catalyst.
NiCH2=CH—CH2—CH3 + H2
CH3—CH2—CH2—CH3
Solution
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In halogenation, halogen atoms add to the carbon atoms of a double bond or triple bond.
Halogenation
+ HC C CH3 2Cl2 C C
Cl Cl
Cl Cl
CH3H
H2C CH2
Br Br
Br2H2C CH2 +
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Testing for Double and Triple Bonds
When bromine (Br2) is added to an alkane, the red color of bromine persists.When bromine (Br2) is added to an alkene or alkyne, the red color of bromine disappears immediately.
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Write the product of each addition reaction:
PtCH2=CH—CH3 + H2
+ Br2
Learning Check
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Write the product of each addition reaction:
PtCH2=CH—CH3 + H2 CH3—CH2—CH3
Solution
Br
Br
+ Br2
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In hydrohalogenation, the atoms of a hydrogen halide add to the carbon atoms of a double bond or triple bond.
Hydrohalogenation
CH3 CH CH CH3
H Cl+ HClCH3 CH CH CH3
H
Br
+ HBr
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When an unsymmetrical alkene undergoes hydrohalogenation, the H in HX adds to the carbon in the double bond that has the greater number of H.
CH3 CH CH2
Cl H
Markovnikov’s Rule
CH3 CH CH2 + HCl
CH3 CH CH2
H Cl
Does not form
C with the most H
Product that forms
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In hydration, H and OH from water add to the carbon atoms of a double bond or triple bond to form alcohols (OH).The reaction is catalyzed by acid H+.
Hydration Adds Water
+ HOHH
OH
CH3 CH CH2 + HOH
CH3 CH CH2
OH H
H+
H+
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Learning CheckWrite the products of each reaction.
+ H2
CH3 CH CH2 + Cl2
Pt
H+
CH3 CH CH CH3 + HOH
A.
B.
C.
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SolutionWrite the products of each reaction.
CH3 CH CH CH3
H OH
C.
B.
A.
HOH +CH3 CH CH CH3
H+
Pt
CH3 CH CH2
Cl Cl
+ Cl2 CH3 CH CH2
H
H
+ H2
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13.8 Polymerization
Chapter 13 Unsaturated Hydrocarbons
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Polymers
Polymers are: Long-chain molecules.Found in nature, including cellulose in plants, starches in food, proteins and DNA in the body.Also synthetic such as polyethylene and polystyrene, Teflon, and nylon.
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Common Synthetic Polymers
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PolymerizationIn polymerization, small repeating units called monomers are bonded to form a long chain polymer.
Repeating monomer
chain continues chain continues
Polyethylene
Ethylene monomers
C C C C C C
H H
HH
H
H
H
H
H
H
H
H
++ C C
H H
HH
C C
H H
HH
C C
H H
HH
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Polymers from Addition Reactions
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More Monomers and Polymers
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Recycling PlasticsRecycling is simplified by using codes on plastic items.
1 PETE Polyethyleneterephtalate2 HDPE High-density polyethylene3 PV Polyvinyl chloride4 LDPE Low-density
polyethylene5 PP Polypropylene6 PS Polystyrene
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Learning CheckWhat is the starting monomer for polyvinyl chloride (PVC)?
C C C C C C
H Cl
HH
H
H
Cl
H
H
H
Cl
H
Polyvinyl chloride
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SolutionWhat is the starting monomer for polyvinyl chloride (PVC)?
Chloroethene monomers
++ C C
H Cl
HH
C C
H Cl
HH
C C
H Cl
HH
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Chapter 13 Unsaturated Hydrocarbons
13.9 Aromatic Compounds
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Benzene isAn aromatic compound.A ring of 6 C atoms and 6 H atoms.A flat ring structure drawn with double bonds. Represented by two structures because the electrons move among the C atoms.
Aromatic Compounds
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Because the pi electrons in benzene are shared equally among the 6 C atoms, benzene can also be represented as a hexagon with a circle drawn inside.
13.9Benzene Structure
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Aromatic Compounds in Nature and Medicine
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A benzene with a single substituent is often named as a benzene derivative.
Methylbenzene Chlorobenzene
13.10Naming Aromatic Compounds
ClCH3
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Some substituted benzene rings have common names that have been in use for many years.
Some Common Names
CH3 NH2 OH
Toluene Aniline Phenol(Methylbenzene) (Benzenamine) (Hydroxybenzene)
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A benzene ring with two or more substituentsis numbered to give the lowest numbers to the side groups. Common names use the prefixes ortho- (1,2-), meta- (1,3-) and para- (1,4-).
Br
Br
Naming Aromatic Compounds
Cl
Cl
CH3
Cl
1,2-dimethylbenzene 1,3-dichlorobenzene 4-chloromethylbenzene(o-dibromobenzene) (m-dichlorobenzene) (p-chlorotoluene)
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Select the correct name for each structure:
1) chlorocyclohexane2) chlorobenzene3) 1-chlorobenzene
1) 1,3-dichlorobenzene2) o-dichlorobenzene3) m-dichlorobenzene
Cl
Learning Check
Cl
Cl
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Select the correct name for each structure:
2) Chlorobenzene
1) 1,3-dichlorobenzene
3) m-dichlorobenzene
Cl
Solution
Cl
Cl
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Write the structural formula for each:A. 1-bromo-4-chlorobenzene
B. o-chlorotoluene
Learning Check
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Write the structural formula for each:
A. 1-bromo-4-chlorobenzene
B. o-chlorotolueneCH3
Cl
Solution
Cl
Br
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Chapter 13 Unsaturated Hydrocarbons
13.11 Properties of Aromatic Compounds
ChlorobenzeneBenzene
FeCl3 HCl+
Cl
Cl2+
H
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Properties of Aromatic Compounds
Aromatic compounds:Have a stable aromatic bonding system.Are resistant to many reactions. Undergo substitution reactions, which retains the stability of the aromatic bonding system.
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Substitution ReactionsIn a substitution reaction, a hydrogen atom on a benzene ring is replaced by an atom or group of atoms. Type of substitution H on benzene replaced by
Halogenation chlorine or bromine atom
Nitration nitro group (—NO2)
Sulfonation —SO3H group
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Halogenation
Halogenation replaces a H on benzene by a chlorine or bromine atom.A catalyst such as FeCl3 is used in chlorination; FeBr3 in bromination.
ChlorobenzeneBenzene
FeCl3 HCl+
Cl
Cl2+
H
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Nitration
Nitration replaces a H on benzene by a nitro (—NO2) group from HNO3. An acid catalyst such as H2SO4 is used in nitration.
NitrobenzeneBenzene
H2SO4 HOH+
NO2
HNO3+
H
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Sulfonation
Sulfonation replaces a H on benzene by a —SO3H group from SO3. An acid catalyst such as H2SO4 is used in sulfonation.
Benzenesulfonic acidBenzene
H2SO4
SO3H
SO3+
H
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Learning Check
Write the equation for the bromination of benzene, including catalyst.
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Solution
Write the equation for the bromination of benzene, including catalyst.
HBr+
FeBr3
Br
Br2+
H