Chapter 12 Section 1 - Slide 1 Copyright © 2009 Pearson Education, Inc. AND.
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Transcript of Chapter 12 Section 1 - Slide 1 Copyright © 2009 Pearson Education, Inc. AND.
Chapter 12 Section 1 - Slide 1Copyright © 2009 Pearson Education, Inc.
AND
Copyright © 2009 Pearson Education, Inc. Chapter 12 Section 1 - Slide 2
Unit 7
Probability
Chapter 12 Section 1 - Slide 3Copyright © 2009 Pearson Education, Inc.
WHAT YOU WILL LEARN• Empirical probability and theoretical
probability• Compound probability, conditional
probability, and binomial probability• Odds against an event and odds in
favor of an event• Expected value• Tree diagrams
Chapter 12 Section 1 - Slide 4Copyright © 2009 Pearson Education, Inc.
WHAT YOU WILL LEARN• Mutually exclusive events and
independent events• The counting principle,
permutations, and combinations
Copyright © 2009 Pearson Education, Inc. Chapter 12 Section 1 - Slide 5
Section 1
The Nature of Probability
Chapter 12 Section 1 - Slide 6Copyright © 2009 Pearson Education, Inc.
Definitions
An experiment is a controlled operation that yields a set of results.
The possible results of an experiment are called its outcomes.
An event is a subcollection of the outcomes of an experiment.
Chapter 12 Section 1 - Slide 7Copyright © 2009 Pearson Education, Inc.
Definitions (continued)
Empirical probability is the relative frequency of occurrence of an event and is determined by actual observations of an experiment.
Theoretical probability is determined through a study of the possible outcomes that can occur for the given experiment.
Chapter 12 Section 1 - Slide 8Copyright © 2009 Pearson Education, Inc.
Empirical Probability
Example: In 100 tosses of a fair die, 19 landed showing a 3. Find the empirical probability of the die landing showing a 3.
Let E be the event of the die landing showing a 3.
P(E)
number of timesevent E has occurred
total number of times theexperiment has been performed
P(E)
19100
0.19
Slide 12 - 9Copyright © 2009 Pearson Education, Inc.
Of 12 children playing at the playground, 4 are playing on the swing set. Determine the empirical probability that the next child to the playground will play on the swing set.
a.
c.
12
13
b.
d. 14
16
Slide 12 - 10Copyright © 2009 Pearson Education, Inc.
Of 12 children playing at the playground, 4 are playing on the swing set. Determine the empirical probability that the next child to the playground will play on the swing set.
a.
c.
12
13
b.
d. 14
16
Chapter 12 Section 1 - Slide 11Copyright © 2009 Pearson Education, Inc.
The Law of Large Numbers
The law of large numbers states that probability statements apply in practice to a large number of trials, not to a single trial. It is the relative frequency over the long run that is accurately predictable, not individual events or precise totals.
Copyright © 2009 Pearson Education, Inc. Chapter 12 Section 1 - Slide 12
Section 2
Theoretical Probability
Chapter 12 Section 1 - Slide 13Copyright © 2009 Pearson Education, Inc.
Equally likely outcomes
If each outcome of an experiment has the same chance of occurring as any other outcome, they are said to be equally likely outcomes.
For equally likely outcomes, the probability of Event E may be calculated with the following formula.
P(E)
number of outcomes favorable to E total number of possible outcomes
Chapter 12 Section 1 - Slide 14Copyright © 2009 Pearson Education, Inc.
Example
A die is rolled. Find the probability of rolling a) a 2. b) an odd number. c) a number less than 4. d) an 8. e) a number less than 9.
Chapter 12 Section 1 - Slide 15Copyright © 2009 Pearson Education, Inc.
Solutions: There are six equally likely outcomes: 1, 2, 3, 4, 5, and 6. a)
b) There are three ways an odd number can occur: 1, 3 or 5.
c) Three numbers are less than 4.
P(2)
number of outcomes that will result in a 2total number of possible outcomes
16
P(odd)
36
12
P(number less than 4)
36
12
Chapter 12 Section 1 - Slide 16Copyright © 2009 Pearson Education, Inc.
d) There are no outcomes that will result in an 8.
e) All outcomes are less than 9. The event must occur and the probability is 1.
Solutions: There are six equally likely outcomes: 1, 2, 3, 4, 5, and 6 (continued)
P(number greater than 8)
06
0
Slide 12 - 17Copyright © 2009 Pearson Education, Inc.
Each of the numbers 0-9 is written on a sheet of paper and the ten sheets of paper are placed in a box. If one sheet of paper is selected at random from the box, determine the probability that the number selected is less than 3.
a.
c.
12
13
b.
d. 3
10 7
10
Slide 12 - 18Copyright © 2009 Pearson Education, Inc.
Each of the numbers 0-9 is written on a sheet of paper and the ten sheets of paper are placed in a box. If one sheet of paper is selected at random from the box, determine the probability that the number selected is less than 3.
a.
c.
12
13
b.
d. 3
10 7
10
Chapter 12 Section 1 - Slide 19Copyright © 2009 Pearson Education, Inc.
Important Facts
The probability of an event that cannot occur is 0. The probability of an event that must occur is 1. Every probability is a number between 0 and 1
inclusive; that is, 0 P(E) 1. The sum of the probabilities of all possible
outcomes of an experiment is 1.
Chapter 12 Section 1 - Slide 20Copyright © 2009 Pearson Education, Inc.
Example
A standard deck of cards is well shuffled. Find the probability that the card is selected.a) a 10.b) not a 10.c) a heart.d) an ace, 2, or 3.e) diamond and spade.f) a card greater than 4 and less than 7.
Chapter 12 Section 1 - Slide 21Copyright © 2009 Pearson Education, Inc.
Example (continued)
a) a 10There are four 10’s in a deck of 52 cards.
b) not a 10
P(10)
452
1
13
P(not a 10) 1 P(10)
11
13
1213
Chapter 12 Section 1 - Slide 22Copyright © 2009 Pearson Education, Inc.
Example continued
c) a heart
There are 13 hearts in the deck.
d) an ace, 2 or 3
There are 4 aces, 4 twos and 4 threes, or a total of 12 cards.
P(heart)
1352
14 = =12 3
(A, 2, or 3)52 13
P
Chapter 12 Section 1 - Slide 23Copyright © 2009 Pearson Education, Inc.
Example continued
d) diamond and spadeThe word and means both events must occur. This is not possible.
e) a card greater than 4 and less than 7 The cards greater than 4 and less than 7 are 5’s and 6’s (or a total of 8 cards).
P > 4 and < 7 P 5 or 6
852
2
13
P(diamond and spade)
052
0
Copyright © 2009 Pearson Education, Inc. Chapter 12 Section 1 - Slide 24
Section 3
Odds
Chapter 12 Section 1 - Slide 25Copyright © 2009 Pearson Education, Inc.
Odds Against
Odds against event P event fails to occur
P event occurs
P failure P success
Chapter 12 Section 1 - Slide 26Copyright © 2009 Pearson Education, Inc.
Example: Odds Against
Example: Find the odds against rolling a 5 on one roll of a die.
The odds against rolling a 5 are 5:1.
P 5 1
6 P fails to roll a 5 5
6
5616
56
61
51
odds against rolling a 5
Chapter 12 Section 1 - Slide 27Copyright © 2009 Pearson Education, Inc.
Odds in Favor
Odds in favor of event P event occurs
P event fails to occur
P success P failure
Chapter 12 Section 1 - Slide 28Copyright © 2009 Pearson Education, Inc.
Example
Find the odds in favor of landing on blue in one spin of the spinner.
The odds in favor of spinning blue are 3:5.
P blue 3
8 P not blue 5
8
odds in favor
3858
38
85
35
Slide 12 - 29Copyright © 2009 Pearson Education, Inc.
Five red apples and six yellow apples are placed in a bag. If one apple is selected at random, determine the odds in favor of the apple being red.
a. 5:11
b. 6:11
c. 5:6
d. 6:5
Slide 12 - 30Copyright © 2009 Pearson Education, Inc.
Five red apples and six yellow apples are placed in a bag. If one apple is selected at random, determine the odds in favor of the apple being red.
a. 5:11
b. 6:11
c. 5:6
d. 6:5
Chapter 12 Section 1 - Slide 31Copyright © 2009 Pearson Education, Inc.
Probability from Odds
Example: The odds against spinning a blue on a certain spinner are 4:3. Find the probability that
a) a blue is spun. b) a blue is not spun.
Chapter 12 Section 1 - Slide 32Copyright © 2009 Pearson Education, Inc.
Solution
Since the odds are 4:3 the denominators must be 4 + 3 = 7.
The probabilities ratios are:
( )=3blue
7P
( )=4not blue
7P