Chapter 12 Fluid Flow
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Transcript of Chapter 12 Fluid Flow
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Chapter 12 Fluid Flow
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12-1 The Basic Equation of Steady-Flow
12-1-1 The Conversation of Mass
A : Cross section area of flow duct
c : Velocity of fluid
v : Specific volume of fluid
v
Acm
v
dv
c
dc
A
dA
Differential form:
const
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12-1-2 The Conversation of Energy
2
2
1ch
)2
1( 2cddh
cdcdh
Differential form:
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12-1-3 Process EquationUsually the fluid flows too fast in a duct to exchange heat with its surroundings, so it undergoes an adiabatic process, then:
pv k= const
0v
dvk
p
dp
Differential form:
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12-1-4 Velocity of Sound and Mach Number
From
Then
p
av
pv
2
0v
dvk
p
dp
v
dvk
p
dp
v
pk
v
p
kpva
The Velocity of Sound is denoted by a
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Mach Number Ma is defined as :
a
cMa
kpv
c
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Ernst Mach was born on Feb. 18, 1838, d. Vaterstetten. He found an experimental proof for the Doppler Effect (Christian Doppler) and by inspection of fast moving projects proposed the Mach's principle. The "Mach Number" named after him describes the relation of a body's velocity to sonic speed. His attitude was characterized by empirical thinking based on scientific findings. One of his strictest opponents and critics was M. Planck. After retiring from the University in 1901 he was appointed to the upper chamber of the Austrian Parliament, a post he held for 12 years. He died in 1916
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12-2 The Fluid Flow in DuctDuring the fluid flow in a duct, the properties of fluid changes along the stream line. In most situations this can be treated as a one-dimensional flow
12-2-1 The Pressure and VelocityFrom conservation of energy
dh= - cdc
du +d(pv)= - cdc
du+pdv+vdp= -cdc
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From the first law of thermodynamics:
δq=du+pdv
=0
Then: du+pdv+vdp= -cdc
vdp= - cdc
- vdp= cdc
To increase the velocity of fluid(dc>0), the pressure must be decreased. This kind of duct is called Nozzle
Or to decrease the velocity (dc<0) of fluid to obtain a high pressure in a duct flow. This kind of duct is called diffuser
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12-2-2 Velocity and The Cross Section Area of Duct
From conservation of mass :
v
dv
c
dc
A
dA
c
dc
v
dv
A
dA
0v
dvk
p
dp
kp
dp
v
dv
kpv
vdp
v
dv
v
dvk
p
dp
From the process equation
c dc- vdp
kpva
2a
cdc
v
dv
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2a
cdc
v
dv
c
dc
a
c
v
dv2
2
c
dcMa
v
dv 2
c
dc
v
dv
A
dA c
dc
c
dcMa
A
dA 2
c
dcMa
A
dA)1( 2
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As to a nozzle dc>0
c
dcMa
A
dA)1( 2
(1)If the fluid velocity is subsonic, then (Ma2-1)<0
Therefore: dA<0
The nozzle’s shape should be as following:
Subsonic flow
Subsonic flow
convergent nozzle
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0)( dcc
dcMa
A
dA)1( 2
(2)If the fluid velocity is ultrasonic, then (Ma2-1)>0
Therefore: dA>0
The nozzle’s shape should be as following:
Ultrasonic flow
Ultrasonic flow
divergent nozzle
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0)( dcc
dcMa
A
dA)1( 2
(3)If the nozzle’s inlet velocity is subsonic, but outlet velocity ultrasonic, then:
dA<0 → dA=0 → dA>0
The nozzle’s shape should be as following:
Subsonic flow Ultrasonic flow
convergent-divergent nozzle
throat
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As to a diffuser dc<0
c
dcMa
A
dA)1( 2
(1)If the fluid velocity is subsonic, then (Ma2-1)<0
Therefore: dA>0
The diffuser’s shape should be as following:
Subsonic flowSubsonic flow
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0)( dcc
dcMa
A
dA)1( 2
(2)If the fluid velocity is ultrasonic, then (Ma2-1)>0
Therefore: dA<0
The diffuser’s shape should be as following:
Ultrasonic flow Ultrasonic flow
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0)( dcc
dcMa
A
dA)1( 2
(2) If the diffuser’s inlet velocity is ultrasonic, but outlet velocity subsonic, then:
dA<0 → dA=0 → dA>0
The diffuser’s shape should be as following:
Ultrasonic flow
Subsonic flow
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12-2-3 Applications
Ram-jet engine
Diffuser(compressor)
combustion chamber
nozzle
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Rocket
Space Shuttle
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12-3 The Calculation of Nozzle
12-3-1 The Flux of Subsonic Nozzle
)(2 212 hhc
k
k
p
p
k
kRT1
1
21 11
2
We define P2 /P1 as compression ratio ε
k
k
k
kRTc
11
2 11
2
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k
k
k
kRT
v
A
v
Acm
11
2
2 11
2
12-3-2 The Critical Compression Ratio For convergent-divergent nozzle, the velocity at throat keeps as sound-velocity. This state is called critical state. The flux of this kind of nozzle is depend on that of throat.
The Compression Ratio which is low enough to make the air flow at sound-velocity at the exit of nozzle is called the critical compression Ratio.
It is denoted by εc
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1
1
2
k
k
c k
εc=
0.528 for air
0.546 for saturated steam
0.577 for superheated steam
1
11
2
1
2
12
v
p
kk
kAm
k
throat
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The End of This Book
Thank You