Ch3.1 – Scientific Measurement Qualitative Measurements – no #’s color, texture, shape,...

Ch3.1 – Scientific Measurement Qualitative Measurements – no #’s

color, texture, shape, anything you experience with your senses.

Quantitative Measurements – usually #’smass, volume, amount of something, temp, time, etc

Scientific Measurements- Require the correct units Mass = grams

volume = liters (milliliters)distance = meterstemp = Celsius or Kelvintime = secondsmole = # of particles

Metric Conversions

“ King Henry David Usually Drinks Chocolate Milk.”

Mega . . Kilo Hecta Deka Basic deci centi milli . . micro . . nano Units

M . . K H D U d c m . . µ . . n

#6 a) 6.1 mm = cm b) 7.1mm = m i) 3.6 km = cm l) 8 L = mL o) 2 mg = kg r) 5.5 megabytes = bytes t) 12 km = µm

Ch3 HW#1 1 – 6 1. Qualitative or quantitative?

a. Basketball is brown b. Surface of ball has indented seamsc. The diameter is 31 cm d. Air pressure is 12 psi

2. Qual or quant?a. Flame is hot b. A candle has a mass of 90 gc. Wax is soft d. Candle height decreases by 4.2cm

every hour3. Name each quantity measured

a. Mole b. Second c. Meter d. Kilogram4. Order these:

cm, Km, m, μm, mm, Dm5. Which is best to measure:

a. Height of letter I b. Width of this classroomc. Height of a piece of paper

M . . K H D U d c m . . μ . . n6. a) o)

b) p) 2.3 μg = _____ gc) 0.1 mm = __ km q) 3.8 cg = _____ μgd) 0.7 cm = mm r)e) 8.8cm = _ m s) 680 nm = _____ mf) 5.8 cm = _____ km t) g) 3.4 m = _____ km u) 355 nm = _____ mh) 1.2 km = _____ mmi)j) 4.8 mL = _ Lk) 7.9 mL = _____ kLm) 5.7 kL = _____ mLn) 4.9 mg = cg

M . . K H D U d c m . . μ . . n6. a) o)

b) p) 2.3 μg = _____ gc) 0.1 mm = 0.0000001 km q) 3.8 cg = _____ μgd) 0.7 cm = 7 mm r)e) 8.8cm = 0.0088 m s) 680 nm = _____ mf) 5.8 cm = 0.000058 km t) g) 3.4 m = 0.0034 km u) 355 nm = _____ mh) 1.2 km = 1200000 mmi)j) 4.8 mL = _____ Lk) 7.9 mL = _____ KLm) 5.7 KL = _____ mLn) 4.9 mg = cg

M . . K H D U d c m . . μ . . n6. a) o)

b) p) 2.3 μg = _____ gc) 0.1 mm = 0.0000001 km q) 3.8 cg = _____ μgd) 0.7 cm = 7 mm r)e) 8.8cm = 0.0088 m s) 680 nm = _____ mf) 5.8 cm = 0.000058 km t) g) 3.4 m = 0.0034 km u) 355 nm = _____ mh) 1.2 km = 1200000 mmi)j) 4.8 mL = 0.0048 Lk) 7.9 mL = 0.0000079 KLm) 5.7 KL = 5700000 mLn) 4.9 mg = 0.49 cg

M . . K H D U d c m . . μ . . n6. a) o)

b) p) 2.3 μg = 0.0000023 gc) 0.1 mm = 0.0000001 km q) 3.8 cg = 3800 μgd) 0.7 cm = 7 mm r)e) 8.8cm = 0.0088 m s) 680 nm = 0.000680 mf) 5.8 cm = 0.000058 km t) g) 3.4 m = 0.0034 km u) 355 nm = 0.000000355 mh) 1.2 km = 1200000 mmi)j) 4.8 mL = 0.0048 Lk) 7.9 mL = 0.0000079 KLm) 5.7 KL = 5700000 mLn) 4.9 mg = 0.49 cg

Ch3.2 – Significant Digits

Value Lifter Diameter Instrument Measure Sig Dig

1) Stick ~ 1“ 1

2) Ruler .8” 1

3) Machinist Scale

.84” 2

4) Dial Calipers

.843” 3

5) Micrometer

.8428 4

Value Lifter Diameter Instrument Measure Sig Dig

1) Stick ~ 1“ 1

2) Ruler .8” 1

3) Machinist Scale

.84” 2

4) Dial Calipers

.843” 3

5) Micrometer

.8428 4

Accuracy – how good the measuring device is. (Is it broken?)Precision – how many sig digs the device can give

(Triple beam balance vs bathroom scale) From lab 1.1 : Candle - 63.1 g ( )

63.10 g ( )More sig digs = better measurement (in general)

# of sig digs relates to precision

Significant Digits – Indicate precision of measureEx: Candle – 63g → 62 – 64g

63.00 g → 62.99 – 63.01g Rules: 1. All non zero digits are sig digits.2. Trapped zeros, and final zeros after decimal are significant3. Zeros used as placeholders are not significantReminder: These are not just #’s, they are measurements. They have a degree of

uncertainty associated with them.Examples Sig Digs Exs Sig Digs

2 70200 .702.00 .00702.02 1.00702020 10,0701.00280 1007.0100,28020.0

Ch3 HW#2 7 – 11

Ch3 HW#2 7 – 11 7) When is a measurement precise but inaccurate?

8) Comment on accuracy & precisiona) 99 out of 100 shots made.b) 99 out of 100 hit front rim but bounce off.c) 33 out of 100 made, rest miss.

9) Sig Digs a) 143g b) 0.074 c) 8.750x10-2 Ng

d) 1.072 km e) 10800 cm f) 5.00 dm3


Ex: triple beam balance that is broken8) Comment on accuracy & precision

a) 99 out of 100 shots made.b) 99 out of 100 hit front rim but bounce off.c) 33 out of 100 made, rest miss.

9) Sig Digs a) 143g b) 0.074 c) 8.750x10-2 Ng

d) 1.072 km e) 10800 cm f) 5.00 dm3



a) 99 out of 100 shots made. Acc and precb) 99 out of 100 hit front rim but bounce off. Prec, not accc) 33 out of 100 made, rest miss. Not acc, not prec

9) Sig Digs a) 143g b) 0.074 c) 8.750x10-2 Ng

d) 1.072 km e) 10800 cm f) 5.00 dm3




9) Sig Digs a) 143g b) 0.074 c) 8.750x10-2 Ng 3 2 4d) 1.072 km e) 10800 cm f) 5.00 dm3




9) Sig Digs a) 143g b) 0.074 c) 8.750x10-2 Ng 3 2 4d) 1.072 km e) 10800 cm f) 5.00 dm3 4 3 3

10) Round to 3 sig digs a) 98.473 L b) 0.00076321 g c) 57.048 m

d) 12.17 0c e) 0.0074983x104 mm

11) Round to 3 sig digsa) 87.073 m b) 4.3621x108 m c) 0.01552 m

d) 9009 m e) 1.7777x10-3 m

10) Round to 3 sig digs a) 98.473 L b) 0.00076321 g c) 57.048 m 98.5 0.000763 57.0 d) 12.17oC e) 0.0074983x104 mm


d) 9009 m e) 1.7777x10-3 m

10) Round to 3 sig digs a) 98.473 L b) 0.00076321 g c) 57.048 m 98.5 0.000763 57.0 d) 12.17oC e) 0.0074983x104 mm 12.2 0.000750x104


d) 9009 m e) 1.7777x10-3 m

10) Round to 3 sig digs a) 98.473 L b) 0.00076321 g c) 57.048 m 98.5 0.000763 57.0 d) 12.17oC e) 0.0074983x104 mm 12.2 0.000750x104

11) Round to 3 sig digsa) 87.073 m b) 4.3621x108 m c) 0.01552 m 87.1 4.36x108 0.0155d) 9009 m e) 1.7777x10-3 m 9010 1.78x10-3

Ch3.3 Scientific Notation

In your HW: Mass of 1 gold atom: 0.000 000 000 000 000 000 000 327 g

1 gram of H2 gas: 301 000 000 000 000 000 000 000 molecules

1 wavelength of red light: 0.000 000 780 meters

Ex 1) Standard to sci not Ex 2) Sci not to Standard

3750 = 4.72x10-3 =

12,472 = 3.70x10-6 =

0.000510 = 4.97X104 =

0.0000200 =

CalculationsEx 3) (4.44x104)(3.72x103) (5.76x10-10)(1.03x105)

= 2.9535x1022 or 2.784x1012 ?

CalculationsEx 3) (4.44x104)(3.72x103) (5.76x10-10)(1.03x105)

(If it’s on the bottom DIVIDE!)With Sig Digs: 2.78x1012

= 2.9535x1022 or 2.784x1012 ?

(Ch5.3 – Spectra)Light travels like a wave

(Ch5.3 – Spectra)Light travels like a wave

All light travels at the speed of light: 300,000,000 m/s

The different colors have different wavelengths and different frequencies and follow the same equation:

Lamda Nu speed of light → c = λ · ν (3x108m/s) wavelength ↑ ↖ frequency

Ex 4) Red light has a wavelength of 780 nm, what is its frequency?

Ex 5) Blue light has a wavelength of 460 nm, what is its frequency?

Ch3 HW#3 12 – 15

Ch3 HW#3 12 – 15 12. (In class)13. Write each measurement in scientific notation and determine

the number of significant figures in each.a. 0.05730 m b. 8765 dm c. .00073

d. 12 basketball players e. 0.010 km f. 507 thumbtacks

14. Find the frequency of each of these colors of light, given their wavelengths: use the formula: c = λνa. Orange light with a wavelength of 6.00x10-7 mb. Yellow light with a wavelength of 580x10-9 mc. Violet light with a wavelength of 400 nm



4 4 2d. 12 basketball players e. 0.010 km f. 507 thumbtacks

2 2 314. Find the frequency of each of these colors of light, given their

wavelengths: use the formula: c = λνa. Orange light with a wavelength of 6.00x10-7 mb. Yellow light with a wavelength of 580x10-9 mc. Violet light with a wavelength of 400 nm



4 4 2d. 12 basketball players e. 0.010 km f. 507 thumbtacks

2 2 314. Find the frequency of each of these colors of light, given their

wavelengths: use the formula: c = λνa. Orange light with a wavelength of 6.00x10-7 mb. Yellow light with a wavelength of 580x10-9 mc. Violet light with a wavelength of 400 nm

a. 3x108 = (6x10-7).ν ν = 5.00x1014 Hzb. 3x108 = (580x10-9).ν ν = 5.17x1014 Hzc. 3x108 = (400x10-9).ν ν = 7.50x1014 Hz

15. Solve the following problems and give your answer to the correct number of significant figures.a. (8.3m)(2.22m) b. (1.8x10-3m)(2.9x10-2m) c.

d. e. f.

5.12

)8432( m

)56.4)(45.3(

)34.2)(23.1(

35.2g NaCl 1 mole CaO 1 mole CaO 56.1g CaO

58.5g NaCl 2 moles NaCl 1 mole CaO

g.

2

669

)3.0(

)103)(104)(109( xxx

)12)(255.0(

)103.5( 2x


d. e. f.

5.12

)8432( m

)56.4)(45.3(

)34.2)(23.1(



g.

a. 18.426 18 b. 5.22x10-5 5.2x10-5 c. 674.56 675

2

669

)3.0(

)103)(104)(109( xxx

)12)(255.0(

)103.5( 2x


d. e. f. )12)(255.0(

)103.5( 2x

5.12

)8432( m

)56.4)(45.3(

)34.2)(23.1(



g.

a. 18.426 18 b. 5.22x10-5 5.2x10-5 c. 674.56 675d. 0.0173202614 0.017 e. 1.2 1 f. 0.1829519451

0.183

2

669

)3.0(

)103)(104)(109( xxx


d. e. f. )12)(255.0(

)103.5( 2x

5.12

)8432( m

)56.4)(45.3(

)34.2)(23.1(



g.

a. 18.426 18 b. 5.22x10-5 5.2x10-5 c. 674.56 675d. 0.0173202614 0.017 e. 1.2 1 f. 0.1829519451

0.183g. 16.87794872 16.9

2

669

)3.0(

)103)(104)(109( xxx

Ch5.3 – Atomic Spectra Provides another way to ID elements. Each has a unique “ Fingerprint. ”

e-

e-


e- Electrons jump to excited states when they absorb photons of energy. They drop back to their base states and

e- release photons of energy.




Photon – a small bundle of energySometimes the photon released is visible light




Photon – a small bundle of energySometimes the photon released is visible light

Light is a very small portion of a much larger set of waves called The Electromagnetic Spectrum. These waves differ in wavelength and frequency but they all travel at the Speed of light, c = 3x108 m/s.

The different waves of the Electromagnetic Spectrum differ in energy. As the frequency goes up, the energy goes up. E/M Spectrum

Radio waves Infrared Visible light UV X-rays Gamma

λ Long Middle Short

ν Low freq Mid freq Hi freq

E Low energy Mid energy Hi energy

c = 3x108 m/sc = λ · ν

Ex 1) What is the frequency of red light with a wavelength of 700 nm?

Energy of a photon: E = h · ν

Plank’s Constant = 6.62 x 10-34 J·s

Ex 2) What is the energy associated with a photon of red light, with a frequency of 4.3 x 1014Hz?

Energy of a photon: E = h · ν

Plank’s Constant = 6.62 x 10-34 J·s

Ex 2) What is the energy associated with a photon of red light, with a frequency of 4.3 x 1014Hz?

E = ?

v = 4.3 x 1014Hzh = 6.62 x 10-7m

= (6.62 x 10-34 J·s) · (4.3 x 1014 ⅟sec)E = h · v

= 2.84 x 10-19J

HW #5) A hydrogen lamp emits visible light with a wavelength of 6.56 x 10-7m. What is the frequency associated

with this radiation?

v = ?

λ = 6.56 x 10-7m

Ch5 HW #5 1-7

Ch5 HW#51. What is meant by the term frequency? What are its units?

2. Describe the relationship between wavelength and frequency.

3. What is the frequency of radiation with a wavelengthof 5.0x10-8 m?

Ch5 HW#51. What is meant by the term frequency? What are its units?

2. Describe the relationship between wavelength and frequency.

3. What is the frequency of radiation with a wavelengthof 5.0x10-8 m?

c = λ · ν 3x108m/s = (5.0x10-8m) . ν

ν = 6.0x10-15 Hz

4. Visible light is a small portion of the EM spectrum and it is commonly broken down to the colors ROYGBIV. Complete the table:Color: Red Orange Yellow Green Blue Indigo Violet λ: 650x10-9 550x10-9 450x10-9 350x10-9

ν: 4.3x1014 6.0x1014 7.5x1014

c = λ · ν

4. Visible light is a small portion of the EM spectrum and it is commonly broken down to the colors ROYGBIV. Complete the table:Color: Red Orange Yellow Green Blue Indigo Violet λ: 6.98x10-7650x10-9 550x10-9 5x10-7 450x10-9 4x10-7 350x10-9

ν: 4.3x1014 6.0x1014 7.5x1014

c = λ · ν

4. Visible light is a small portion of the EM spectrum and it is commonly broken down to the colors ROYGBIV. Complete the table:Color: Red Orange Yellow Green Blue Indigo Violet λ: 6.98x10-7650x10-9 550x10-9 5x10-7 450x10-9 4x10-7 350x10-9

ν: 4.3x1014 4.6x1014 5.5x1014 6.0x10146.7x1014 7.5x10148.6x1014

c = λ · ν

5. A hydrogen lamp emits several lines in the visible spectrum including one with a wavelength of 6.56x10-7 m.What is the associated frequency?

6. What is the energy of a photon whose frequency is 3.0x1012Hz?



c = λ · ν 3x108m/s = (6.56x10-7m) . ν

ν = 4.57x1014 Hz6. What is the energy of a photon whose frequency is 3.0x1012Hz?



c = λ · ν3x108m/s = (6.56x10-7m) . ν


E = h · ν = (6.62x10-34Js)(3.0x1012Hz) = 2.0x10-21 J



c = λ · ν3x108m/s = (6.56x10-7m) . ν


E = h · ν = (6.62x10-34Js)(3.0x1012Hz) = 2.0x10-21 J

7. What is the energy of a photon whose frequency is 5.90x1012Hz?E = h · ν = (6.62x10-34Js)(5.90x1012Hz) = 3.91x10-21 J

Ch. 3.3 – Volumetric Conversions

1 mL = 1 cm3

1 L = 1 dm3

K H D U d c m

“Count the moves, multiply by the power.”

Ex 1) 100 mm2 = _________m2

Ex 2) 100 cm2 = _________mm3

Ex 3) 275 cm3 =__________m3

Ex 4) 475 m2 =__________cm2

Ex 5) 500 mL=__________cm3

Ch. 3.3- Volumetric Conversions

1 mL = 1 cm3

1 L = 1 dm3

K H D U d c m

“Count the moves, multiply by the power.”

Ex 1) 100 mm2 = .0001 m2 (3 Moves left)(Power of 2)6 Moves left

Ex 2) 100 cm2 = 100000 mm3 (1 Right)(3)=3 Right

Ex 3) 275 cm3 =.000275 m3 (2 left)(3)=6 left

Ex 4) 475 m2 =4750000 cm2 (2 right)(2)=4 right

Ex 5) 500 mL=500 cm3

Temperature ConversionsTemperature – measure of the degree of hotness

or coldness of a substanceo F o C K

Water boils 212 100 373

Body temp 98.6 37 310

Room temp 65 20 293

Water freezes 32 0 273

Absolute zero -454 -273 0

1o C = 1o KKelvin and Celsius differ by 273, K is always bigger

Examples:

307o C = _____ K

417 K = _____ o C

187 K = _____ o C

Examples:

307o C = 580 K +273

417 K = 144 o C -273

187 K = -86 o C -273

273 – 187 = –____

Ch 3 HW # 4 16-18

Ch3 HW#4 16-1816) Convert 170o to K

17) B.P. of Ar is 87K, convert to C:

18) Metric conversions: KHDUdcma) 6.1 mm = _____ cmb) 0.1 mm2 = _____ km2

c) 0.7 cm2 = _____ mm2

d) 8.8 cm3 = _____ m3

e) 5.8 cm3 = _____ km3

f) 5.7 cm3 = _____ km3

g) 1 cm3 = _____ mLh) 1000 cm3 = _____L

Ch 3 HW # 4 16-1816) Convert 170o to K: 443K

+27317) B.P. of Ar is 87K, convert to C:

-27318) Metric conversions: KHDUdcm

a) 6.1 mm = _____ cmb) 0.1 mm2 = _____ km2

c) 0.7 cm2 = _____ mm2

d) 8.8 cm3 = _____ m3

e) 5.8 cm3 = _____ km3

f) 5.7 cm3 = _____ km3

g) 1 cm3 = _____ mLh) 1000 cm3 = _____L


+27317) B.P. of Ar is 87K, convert to C: -186o C


a) 6.1 mm = _____ cmb) 0.1 mm2 = _____ km2

c) 0.7 cm2 = _____ mm2

d) 8.8 cm3 = _____ m3

e) 5.8 cm3 = _____ km3

f) 5.7 cm3 = _____ km3

g) 1 cm3 = _____ mLh) 1000 cm3 = _____L




a) 6.1 mm = _____ cm .61b) 0.1 mm2 = _____ km2 0.(12 zeros)1c) 0.7 cm2 = _____ mm2 70d) 8.8 cm3 = _____ m3 .(5 zeros 88)e) 5.8 cm3 = _____ km3 f) 5.7 cm3 = _____ km3 g) 1 cm3 = _____ mLh) 1000 cm3 = _____L ↓ 1000 mL




a) 6.1 mm = _____ cm .61b) 0.1 mm2 = _____ km2 0.(12 zeros)1c) 0.7 cm2 = _____ mm2 70d) 8.8 cm3 = _____ m3 .(5 zeros 88)e) 5.8 cm3 = _____ km3 5.8x10-15 .(14 zeros)58f) 5.7 cm3 = _____ km3 5.7x10-9 .(8 zeros)57g) 1 cm3 = _____ mL 1h) 1000 cm3 = _____L 1 ↓ 1000 mL = 1 L

Ch 3.4 – Density

Units: g/cm3 or g/mL

Ex 1) A copper penny has a mass of 3.1 g and a volume of 0.35 cm3. What is the density of copper

Volume

massDensity

Ch 3.4 – Density


HW #19) The density of silver is 10.5 g/cm3 at 20oC.What happens to the density of a 68g bar that is cut in half?

Ex 2) A piece of wood has a mass of 130g. It has a volume of 174cm3? Will it sink or float in ethanol.

Volume

massDensity

Ch 3.4 – Density


HW #19) The density of silver is 10.5 g/cm3 at 20oC.What happens to the density of a 68g bar that is cut in half?

Ex 2) A piece of wood has a mass of 130g. It has a volume of 174cm3? Will it sink or float in ethanol.m= 130gV= 174 cm3 D= m/V = 130g/174cm3 = .74 g/cm3

Density of ethanol = .789 g/cm3 FloatsSpecific Gravity – density of material compared to density of water.

Volume

massDensity

Lab 3.1 – Density H20 = 1.00 g/cm3 Glycerin = 1.26 g/cm3

Density of unknown = g/cm3



Percent Error: accepted value – experimental value

accepted value

Ex) Water has a density of 1.00 g/cm3

You get .995 g/cm3 in lab. Find % error.

Ex) Glycerin has a density of 1.26 g/cm3 .You get 1.31 g/cm3. Find % error.

x 100%



Percent Error: accepted value – experimental value

accepted value

Ex) Water has a density of 1.00 g/cm3 1.00 - .995 You get .995 g/cm3 in lab. Find % error. 1.00

= .5%Ex) Glycerin has a density of 1.26 g/cm3 . 1.26 – 1.31

You get 1.31 g/cm3. Find % error. 1.26 = 3.97%

Ch3 HW#5 19 – 25

x 100%

x 100%

x 100%

Ch3 HW #5 19 – 25 19. (In class)20. A student finds a shinny peace of metal that she thinks is aluminum. In the lab, she determines that the metal has a volume of 245 cm3 and a mass of 612 g. Is the metal Al? Al : 2.7 g/cm3

21. A plastic ball with a volume of 19.7 cm3 has a mass of 15.8 g. Would this ball sink or float in gasoline that has a density of 0.66 g/cm3?


(Probably)


33

/50.2245

612cmg

cm

g

V

mD


(Probably)


(Sink)

33

/50.2245

612cmg

cm

g

V

mD

33

/802.07.19

8.15cmg

cm

g

V

mD

22. A shiny, gold-colored bar of metal weighing 57.3 g has a volume of 4.7 cm3. Is the metal bar pure gold?

23. A weather balloon is inflated to a volume of 2.2 x 103 L with 37.4 g of helium. What is the density of the helium in grams per liter?

22. A shiny, gold-colored bar of metal weighing 57.3 g has a volume of 4.7 cm3. Is the metal bar pure gold? Au : 19.3 g/cm3

(No)


33

/127.4

3.57cmg

cm

g

V

mD

22. A shiny, gold-colored bar of metal weighing 57.3 g has a volume of 4.7 cm3. Is the metal bar pure gold? Au : 19.3 g/cm3

(No)


33

/127.4

3.57cmg

cm

g

V

mD

LgLx

g

V

mD /017.0

102.2

4.373

24. Why is the reported value of the percent error of a measurement always positive?

25. A student estimated the volume of a liquid in a beaker as 200 mL. When she poured the liquid into a graduated cylinder she measured the volume as 208 mL. What is the percent error of the estimated volume from the beaker, taking the graduated cylinder measurement as the accepted value?

accepted value – experimental value accepted value

x 100%

24. Why is the reported value of the percent error of a measurement always positive?

25. A student estimated the volume of a liquid in a beaker as 200 mL. When she poured the liquid into a graduated cylinder she measured the volume as 208 mL. What is the percent error of the estimated volume from the beaker, taking the graduated cylinder measurement as the accepted value?

accepted value – experimental value accepted value

x 100%

208mL – 200mL 208mL

x 100% = 3.85%

Ch3.6 – Problem SolvingDon’t copy this:“ Sally is twice as old as Sara, who is 3 years younger than Suzy. What will Sally’s age be in one year from now if Suzy is 1/3 as old as 12-year-old Sonya will be nine years from now?”Copy this:Solving Chemistry Problems:

Let the units guide you thru to the answer. These are not #’s, they are measurements!

Ex1) When I go to Vegas, I like to play the quarter slots. On my last trip, all I had was a bag of dimes. I counted the dimes, and there were 1000 of them in that bag! How many quarters is that?

Ex2) The directions of an experiment ask each student to measure out 1.84g of copper (Cu) wire. The only Cu wire available is a spool with a mass of 50.0g. How many students can do the experiment before they run out of Cu wire?

Ex3) What is the volume of a pure silver coin that has a mass of 14.0g? The density of pure silver is 10.5 g/cm3.

HW#28a) How many cm3 is 14.8g of Boron? ( density of 2.34 g/cm3 )

Ch3 HW#6 26 – 28

Ch3 HW#6 26 – 28 26. A 1.0° increase on the Celsius scale is equivalent to a 1.8° increase in the Fahrenheit scale. If the temp increases by 48°C, what is the corresponding F temp?

27. Have you ever found yourself sitting through a terrible movie counting minutes? If a movie has 0.20 hours left, how many seconds is that?

28b) 2.8L Ar to grams of Ar. (D = 1.78g/L)

28c) 4.62g Hg to cm3 of Hg. (D = 13.5 g/cm3)

Ch3 Review1. How many significant digits in the following:

1.) 3.070 2.) 00.003070 3.) 3070 4.) 200 5.) 0.0020

2. Metric conversion: M . . K H D U d c m . . µ . . N1.) 17.6 mm = m 2.) 400 cm = km3.) 5280 µs = s4.) 4.72 cm3 = dm3 5.) 7.00 dm3 = mm3

3. Convert the following numbers from standard notation to scientific notation:

1.) 678,000 =

2.) 0.0000102 =

4. Convert from scientific to standard:

1.) 3.050 x 106

2.) 1.99 x 10-3

5. Solve these calculations. Give the answers with the correct number of sig digs.

1.) (5386)(220)

2.) (3.4)(121) (4.44)(56.2)

3.) (4.0x105)(1.31x106) (8.1x108)(4.4x102)

6. The density of an unknown, non–polar oil is wished to be found. A lab group gets the following measurements: 8.98g, 9.01 mLs. Will this oil float on water?

7. A lab group determines the density of iron to be 7.50 g/cm3. The actual density is 7.78 g/cm3. what is the percent error?

8. Temp conversions: a) 23oC = _______K

b) 100K = _______oC

Sig Digs1. 3.070 2. 0.003070 3. 3070 4. 200 5. 0.0020

Metric Conversions

Standard to Sci Not1. 67800 = 2. 0.0000102 =

Sci Not to Standard3. 3.050x106 = 4. 1.99x10-3 =

Sig Digs in Calculations5. 5386x 220 = 6. (3.4)(121) (4.44)(56.2) =3. (4.0x105)(1.31x106) (8.1x108)(4.4x102) =

4. 1.214 + 2.95 + 11.11 =

1. 17.6 mm = ___m 2. 400 cm = ___ km3. 5280 µs = ___ s4. 4.72 cm3 = ___ dm3

5. 7.00 dm3 = ___ mm3

Sig Digs1. 3.070 4 2. 0.003070 4 3. 3070 3 4. 200 1 5. 0.0020 2 Metric Conversions1. 17.6 mm = .0176 m 2. 400 cm = .00400 km3. 5280 µs = .00528 s4. 4.72 cm3 = .00472 dm3

5. 7.00 dm3 = 7000000 mm3

Standard to Sci Not1. 67800 = 6.78x105

2. 0.0000102 = 1.02x10-5

Sci Not to Standard3. 3.050x106 = 30500004. 1.99x10-3 = .00199

Sig Digs in Calculations5. 5386x 220 = 12000006. (3.4)(121) (4.44)(56.2) = 1.63. (4.0x105)(1.31x106) (8.1x108)(4.4x102) = 1.5

4. 1.214 + 2.95 + 11.11 = 15.27

Ch3.1 – Scientific Measurement Qualitative Measurements – no #’s color, texture, shape,...

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