PROBLEM 2.23 KNOWN: Temperature distribution in a one-dimensional wall with prescribed thickness and thermal onductivity. c

FIND: (a) The heat generation rate, in the wall, (b) Heat fluxes at the wall faces and relation to q, q. SCHEMATIC: ASSUMPTIONS: (1) Steady-state conditions, (2) One-dimensional heat flow, (3) Constant

roperties. p ANALYSIS: (a) The appropriate form of the heat equation for steady-state, one-dimensional conditions with constant properties is Eq. 2.19 re-written as

d dTq=-kdx dx

⎡ ⎤⎢ ⎥⎣ ⎦

Substituting the prescribed temperature distribution,

( ) [ ]2d d dq=-k a+bx k 2bx 2bkdx dx dx

⎡ ⎤ = − = −⎢ ⎥⎣ ⎦

< ( )2 5q=-2 -2000 C/m 50 W/m K=2.0 10 W/m .× ⋅ × 3

(b) The heat fluxes at the wall faces can be evaluated from Fourier’s law,

( )xx

dTq x k .dx

⎤′′ = − ⎥⎦

Using the temperature distribution T(x) to evaluate the gradient, find

( ) 2x

dq x k a+bx 2kbx.dx

⎡ ⎤′′ = − = −⎢ ⎥⎣ ⎦

T he fluxes at x = 0 and x = L are then

( )xq 0 0′′ = < ( ) ( )2

xq L 2kbL=-2 50W/m K -2000 C/m 0.050m′′ = − × ⋅ × < ( ) 2

xq L 10,000 W/m .′′ = COMMENTS: From an overall energy balance on the wall, it follows that, for a unit area,

( ) ( )

( ) ( )in out g x x

2x x 5 3

E E E 0 q 0 q L qL=0q L q 0 10,000 W/m 0q= 2.0 10 W/m .

L 0.050m

′′ ′′− + = − +′′ ′′− −

= = ×

Nancy Proyect

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