Ch 9.1 thru 9.5 Review

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Ch 9.1 thru 9.5 Review Standard: various Learning Target: I will be able to use proportions to determine similarity and parallel line segments of a triangle. Ch 9.Rev

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Ch 9.Rev. Learning Target: I will be able to use proportions to determine similarity and parallel line segments of a triangle. Standard: various. Ch 9.1 thru 9.5 Review. Ch 9.1. Concept. a b. a b. c d. c d. =. =. Ch 9.1. Theorem 9-1. Property of Proportions. - PowerPoint PPT Presentation

Transcript of Ch 9.1 thru 9.5 Review

Page 1: Ch 9.1 thru 9.5 Review

Ch 9.1 thru 9.5Review

Standard: various

Learning Target:I will be able to use proportions to determine similarity and parallel line segments of a triangle.

Ch 9.Rev

Page 2: Ch 9.1 thru 9.5 Review

Ch 9.1

Page 3: Ch 9.1 thru 9.5 Review

Ch 9.1

Property of Proportions

Theorem 9-1

For any numbers a and c and any nonzero numbers b and d,

if , then ad = bc.

Likewise, if ad = bc, then

ab

cd=

ab

cd=

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Ch 9.1

9) x = 49Answers:

10) x = -15

11) x = ± 10 12) x = 4.5

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Ch 9.2

Definition of Similar Polygons

Page 6: Ch 9.1 thru 9.5 Review

Ch 9.2

Theorem 9-10

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Ch 9.2

15) not similar 4 10

≠ 6 16

16) PQRS~WXYZ15 9

= 10 6

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Ch 9.2

13) 5x + 8x + 10x = 276; x = 12; 10(12) = 120

Answers:

14) 3x + 2x = 12; x = 2 ⅖; 3(2 ⅖) = 7⅕, 2(2 ⅖) = 4 ⅘

Page 9: Ch 9.1 thru 9.5 Review

Ch 9.2

3 50

= 15 + 10 + 13 x

x = 633 ⅓

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Ch 9.3

Postulate 9-1

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Ch 9.3

9-2

9-3

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Ch 9.3

not similar(shapes arenot the same)

IJK ~ HFGSSS Similarity

not similar(angles are not congruent) TUV ~ TSR

AA Similarity

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Ch 9.4

Theorem 9-5

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Ch 9.5

Theorem 9-6

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Ch 9.4

4 x

= 5 12

x = 9.6

8 18

=10 x

x = 22.5

240 200

=300 x

x = 250

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Ch 9.5

Theorem 9-7

Page 17: Ch 9.1 thru 9.5 Review

Ch 9.5(Justify your answer)

IJ = 10.5

• Since FI = IG, then I is the midpoint.• Since FJ = JH, then J is the midpoint.• By definition, IJ is the midsegment.• By the Triangle Midsegment Theorem, IJ = ½ GH