Center of Gravity Method in Distribution Center Location (1)

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    Center of Gravity Methodin Distribution Center

    Location

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    Step 1:

    Place existing warehouse ful!ll"entcenter and distribution centerlocations in a coordinate grid#

    Place the grid on an ordinary "ap#

    $he relative distances "ust benoted#

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    Step %

    $hen using the e&uations below

    Cx' ( dix )i* ( )i

    Cy' ( diy )i* ( )i

    +e calculate the , and - coordinates usingthese e&uations where Cx is the , .hori/ontalaxis0 coordinate for the new facility# Cy is the -.vertical axis0 coordinate for the new facility dix

    is the , coordinate of the existing location diyis the - coordinate of the existing location and)i is the volu"e of goods "oved to or fro" theith location#

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    Step

    2nce you have obtained the , and -coordinates place that location onthe "ap#

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    3xa"ple

    Let4s assu"e the following:

    +arehouse 1 has a daily outboundgoods volu"e of %566 units

    +arehouse % has a daily outboundgoods volu"e of 166 units

    +arehouse has a daily outboundgoods volu"e of 5666 units

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    $he current coordinates of the

    existing facilities:

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    Given the assu"ptions and gridcoordinates above we get the following:

    d1x' %66

    d%x' 66

    dx' 166

    d1y' 56

    d%y' 166

    dy' 156

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    7nd

    )1' %566

    )%' 166 )' 5666

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    +hich gives us

    Cx' .%66 x %5660 8 .66 x 1660 8.166 x 56660 * .%566 8 166 856660 ' 159

    Cy' .56 x %5660 8 .166 x 1660 8.156 x 56660 * .%566 8 166 856660 ' 11

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    plot the new suggested warehousecoordinates on the grid we would get: