CBP 2004-5Comp 1017 Digital Technologies1 Let’s make a Computer … at least the CPU … Pentium 4...
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Transcript of CBP 2004-5Comp 1017 Digital Technologies1 Let’s make a Computer … at least the CPU … Pentium 4...
CBP 2004-5 Comp 1017 Digital Technologies 1
Let’s make a Computer
… at least the CPU …
Pentium 4
Pentium 3
Opteron
Ultra Sparc 1
21364Itanium 2 McKinley
CBP 2004-5 Comp 1017 Digital Technologies 2
Pentium
Data Cache Code Cache
Instruction Fetch
Instruction Decode
Execution Unit
CBP 2004-5 Comp 1017 Digital Technologies 3
Minimalist Computer
What do we need to build a computer ?
“Execution Unit” (Intel)
ALU (Arithmetic Logic Unit)
Memory
Input Output
A good Name
CBP 2004-5 Comp 1017 Digital Technologies 4
Arithmetic Logic Unit
Input A Input B
Output
ALU
Integer Execution Unit
5
3 2
add 1
3 2
sub
CBP 2004-5 Comp 1017 Digital Technologies 5
Input A Input B
Output
ALU
ALU
MMX instructions add bits of images together! Useful for multimedia
Multimedia MMX
CBP 2004-5 Comp 1017 Digital Technologies 6
5
3 2
add
0
1
2
3
4
3
2
5
Processing Idea Nr. 1
Move data from memory
Move data into memory3.
2.
1.
Memory DRAM, Hard Disk ..
Move data in and out of data memory
CBP 2004-5 Comp 1017 Digital Technologies 7
5
3 2
add
0
1
2
3
4
3
2
5
Processing Idea Nr.2
IP
(Code Memory)
mov 3 in from memory
mov 2 in from memory
add the two numbers
mov the result to memory
Instruction Memory
Program
Move instructions into CPU from code memory
CBP 2004-5 Comp 1017 Digital Technologies 8
Registers
0
1
4
6 8
6
8
4
Registers are high-speed memory on the CPU chip
Parking places for data on the move
AX and BX are used for ALU operations
MAR is memory address register, here 4. So result, 6+8=14 will go into memory cell address 4
AX BX
MAR
CBP 2004-5 Comp 1017 Digital Technologies 9
Program Memory
2. High Level Language like ‘C’
3. Assembler Instructions
mov ax,[x]
mov bx,[y]
add ax, bx
mov [w],ax
w = x + y ;
1. Application
Let’s consider a spreadsheet cell which
adds two numbers x + y. This cell and its instruction
is in memory. But it is REPRESENTED in
different ways
CBP 2004-5 Comp 1017 Digital Technologies 10
ip
Data Memory
Instruction
Memory
0
1
4
mar
Our computer so far …
CBP 2004-5 Comp 1017 Digital Technologies 12
Moving data into Registers
Instruction
Memory
0
1
2
mar 3
4
mov ax , [1]
85
8
7
6
1
BXAXmov ax , [1] mov bx , [2]mov bx , [2] 7
For example …
CBP 2004-5 Comp 1017 Digital Technologies 13
Moving data into Memory
Instruction
Memory
0
1
2
mar 3
4
mov [3] , ax
85
8
7
6
1
BXAXmov [3] , axmov [0], bx
mov [0] , bx 7
For example …
8
7
CBP 2004-5 Comp 1017 Digital Technologies 14
Adding Numbers
Instruction
Memory
0
1
2
mar 3
4
add ax , bx
85
7
6
1
BXAXAdd ax,bx
7
For example …
… this means ‘ add ax to bx,
put the answer in ax’8
8 7
15
CBP 2004-5 Comp 1017 Digital Technologies 15
I’ve never wrestled with
such a complex
problem before
It must take a lot of organization and control !
CBP 2004-5 Comp 1017 Digital Technologies 17
Fetch-Execute Cycle
1. Fetch instruction from memory
2. Decode the instruction and read any
registers
3. Do any ALU operations (execute units)
5. Write back results to registers
(Organization and Control)
add ax , bx
4. Do any Memory Access
ALU <- ax ALU <- bx
ax + bx
(Data cache)
ax <- ALU
None needed
CBP 2004-5 Comp 1017 Digital Technologies 18
add ax , bx
add ax,bx
add ax
0
1
4
3
2
bx
Fetch-Exec : State 1Instruction Fetch
8
3
7
1
9
3 1
AX BX
CBP 2004-5 Comp 1017 Digital Technologies 19
0
1
4
3
2
Fetch-Exec : State 2Decode, Register Operations
8
3
7
1
9
add ax , bx
add ax,bx
add ax bx
3 1
3 1
AX BX
CBP 2004-5 Comp 1017 Digital Technologies 20
0
1
4
3
2
Fetch-Exec : State 3ALU Operation
8
3
7
1
9
add ax , bx
add ax,bx
add ax bx
AX BX
3 1
4
CBP 2004-5 Comp 1017 Digital Technologies 21
0
1
4
3
2
Fetch-Exec : State 4Memory Access
8
3
7
1
9
add ax , bx
add ax,bx
add ax bx
AX BX
3 1
4
CBP 2004-5 Comp 1017 Digital Technologies 22
0
1
4
3
2
Fetch-Exec : State 5Register Write
8
3
7
1
9
add ax , bx
add ax,bx
add ax bx
BX
3 1
4
4
CBP 2004-5 Comp 1017 Digital Technologies 23
Fetch-Execute Cycle
1. Fetch instruction from memory
2. Decode the instruction and read any
registers
3. Do any ALU operations (execute units)
5. Write back results to registers
(Organization and Control)
mov ax , [1]
4. Do any Memory Access
Read the ‘1’
Put ‘1’ into MAR
Data into ax
Read memory at addr ‘1’
CBP 2004-5 Comp 1017 Digital Technologies 24
mov ax , [1]
mov ax , [1]mov ax
0
1
4
3
2
1
Fetch-Exec : State 1Instruction Fetch
8
3
7
1
9
CBP 2004-5 Comp 1017 Digital Technologies 25
mov ax , [1]
mov ax , [1]mov ax
0
1
4
3
2
1
Fetch-Exec : State 2Decode, Register Operations
8
3
7
1
9
CBP 2004-5 Comp 1017 Digital Technologies 26
mov ax , [1]
mov ax , [1]mov ax
0
1
4
3
2
1
Fetch-Exec : State 3ALU Operation
1
8
3
7
1
9
CBP 2004-5 Comp 1017 Digital Technologies 27
mov ax , [1]
mov ax , [1]mov ax
0
1
4
3
2
1
Fetch-Exec : State 4Memory Access
1
8
3
7
1
9
8
CBP 2004-5 Comp 1017 Digital Technologies 28
mov ax , [1]
mov ax , [1]mov ax
0
1
4
3
2
1
Fetch-Exec : State 5Register Write
1
8
3
7
1
9
88
CBP 2004-5 Comp 1017 Digital Technologies 29
Pentium
5
1
2
3
4
1. Fetch
2. Decode
3. ALU
4. Mem Ops
5. Reg Write
CBP 2004-5 Comp 1017 Digital Technologies 30
The first microprocessor
KeypadLots of
ElectronicsLCD Display
Keypad LCD Display
Code Memory
Programmable Electronics
A dedicated design ...
... or a re- usable design